Chapter1 Basic Concepts of Thermodynamics
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Transcript of Chapter1 Basic Concepts of Thermodynamics
LEARNING OUTCOMES OF CHAPTER 1
Students should have thoseunderstandings of:
Applications of thermodynamics.
Basic consepts of system, energy,properties, state, process and cycles.
Units and dimensions in SI (SystemInternational).
2 important thermodynamic properties:temperature (T) and pressure (P) andhow to measure them.
THERMODYNAMICS & ENERGY
Definition of “thermodynamics” (Greekword):
– The ability to convert heat to power.– All aspects of energy and energy transfer
including power production / generation,refrigeration and property relation ofsubstances.
therme
(heat)
dynamics
(power)
BASIC LAWS OF THERMODYNAMICS
1st Law of Thermodynamics(=Conservation of Energy Principles)
2nd Law of Thermodynamics
Energy can change fromone form to anotherform with the amountof the energy keptconstant
Energy has its qualityand quantity: a realprocess occurs in thedecreasing quality ofenergy.
APPLICATIONS AREAS OF THERMODYNAMICS
Power plants
The human bodyAir-conditioning
systemsAirplanes
Car radiators Refrigeration systemsPower plants
The human bodyAir-conditioning
systemsAirplanes
Car radiators Refrigeration systems
Human body
Air conditioner / heater
Car radiator
Power PlantsRefrigeration system
Airplanes
DIMENSIONS & UNITS
DIMENSIONS
(= measure of physical quatity)
FUNDAMENTAL / PRIMARY
DIMENSIONS
DERIVED / SECONDARY DIMENSIONS
*
Mass (m), Length (L),Time (t), Temperature(T), Current (I) &Amount of matter (mol)
Velocity (v), Energy (E),Volume (V), Force (F),Power (P), etc.
* Derived dimensions = combination of a few primary dimensions. Eg: Velocity = Distance/Time = L/t
UNITS
(= magnitudes assigned to the dimensions)
UNIT ASAS / PRIMER
DERIVED / SECONDARY
UNITS*
-accompany primarydimensions
-accompany deriveddimensions
2 types of unit systems widely used:
i) English System / United States CustomarySystems (USCS)
ii) Metric System, SI (International System)
FUNDAMENTAL / PRIMARY
UNITS
Differences of Unit Systems
Fundamnetal / Derived Dimensions
SI Unit ES Unit
Mass (m) kg lbm, oz
Length (L) m ft, in
Time (t) s s
Temperature (T) K oC, oF, R
Ammount of matter (mol)
kmol lb mol
Velocity (v) ms-1 ft s-1
Energy (E) J (Joule) Btu, cal
Volume (V) m3 gal
Force (F) N (Newton) lbf
Power (P) W (Watt) hp
Pressure N/m2 (Pascal) psia, psig
Standard prefixes in SI units
Prefix Multipletera, T 1012
giga, G 109
mega, M 106
kilo, k 103
deci, d 10-1
centi, c 10-2
milli, m 10-3
macro, 10-6
nano, n 10-9
pico, p 10-12
Differences between SI and ES1) Force (F) = Mass x acceleration
F = ma (kgms-2)SI unit: newton (N). 1 N = force required to accelerate 1 kgmass at a rate of 1 m/s2.ES unit : pound-force (lbf). 1 lbf = force required to accelerate32.174 lbm (pound-mass) at a rate of 1 ft/s2.
1 N = 1 kgms-2 ; 1 lbf = 32.174 lbm. ft/s2
2) Weight (W) = a type of force W=mg (N)Weight (W) Mass (m)
(derived) (fundamental)Mass of a body is constant, but its weight can change dependingon gravitational acceleration (g) that varies with the placementof the body.
3) Work (W) = a form of energy = Force x Distance1 N.m = 1 J SI unit
ES unit: Btu (British Thermal Unit). 1 Btu = energy required toincrease the temperature of 1 lbm of water at 68oF by 1oF.Other unit : calorie (cal). 1 cal = energy required to increasethe temperature of 1 kg of water at 15oC by 1oC.
1 cal = 4.1868 J ; 1 Btu = 1.055 kJ
Dimensional HomogeneityIn engineering world, all equations must be dimensionallyhomogeneous every term in an equation must have thesame unit.
1) Addition, Subtraction & Equality OperationsEg : 4 s + 1.9 s - direct
1 kg + 2 lb - have to change to the same2 m + 1.5 ft unit10.6 N + 1.4 kgms-2 ?
2) Multiplication & Division OperationsEg : N X m2 = Nm2
kg x m2 m2
s
N x 1 ?m
SYSTEMSSystem = a quantity of matter or a region inspace chosen for study. It consists of:
– Surroundings = mass or region outside the system.
– Boundary = real or imaginary surface that separatesthe system from its surroundings – fixed or movable.
2 types of systems:– Closed systems / control mass
– Open systems/ control volumes
CLOSED SYSTEMSAlso known as control mass.Characteristics of closed systems:
– Contains a fixed amount of mass and no masscan cross its boundary.
– Energy in the form of heat or work can crossthe boundary.
– Volume of closed systems does not have tobe fixed.
In special case, when energy is notallowed to cross the boundary of closedsystems isolated system.2 common examples of closed systems:
– Closed/rigid tank– Piston-cylinder device
CLOSED SYSTEMS
Mass cannot cross theboundaries of a closedsystem, but energy can
An example of closed system witha moving boundary piston-cylinder device
OPEN SYSTEMSAlso known as control volumes.
Characteristics of control volumes:– Both mass and energy can cross its boundary called as
boundary surface.
– Its volume always fixed but its mass not necessarilyfixed.
Examples of control volumes:– Pumps, compressor, valves, heat exchangers, turbines.
Both mass and energycan cross theboundaries of controlvolume
ENERGY Exist in variable forms : heat, mechanical, kinetic,
potential, electric, magnetic, chemical and nuclear. Definition: Energy = Force x Distance (Unit = N.m = J) Total energy, E = amount of all forms of energies that
exist in a system.– Total energy based on a unit mass, e (kJ/kg):
Total energy can be divided into 2 groups:1) Macroscopic energies – related to motion and the influence
of some external effects such as gravity, magnetism,electricity, surface tension, kinetic and potential energies.
2) Microscopic energies – related to the molecular structure ofa system. Eg : chemical, nuclear, latent heat, sensible heat.The sum of microscopic energies internal energy, U.
mEe
Microscopic Energy The sum of microscopic energies internal
energy, U.
- Phase change of a system such asliquid phase changes to gas phase.
- Atom bonding in a molecule inchemical reactions.
- Strong bonds within the nucleus ofatoms.
Macroscopic Energy 2 main forms of macroscopic energies:
1) Kinetic energy – a system possesses as a result of itsmotion relative to some reference frame:
(kJ)
or, on a unit mass basis,(kJ kg-1)
with, V = velocity of the system relative to a fixedreference frame.
2) Potential energy – a system possesses as a result of itselevation in a gravitational field.
(kJ)
with, g = gravitational acceleration, z = elevation of thegravity centre of a system.
Other forms of macroscopic energies:– gravity, magnetism, electricity, surface tension.
2
2
KE mV
2
2
ke V
mgzPE
Total Energy By ignoring the effects of gravity, magnetism,
electricity and surface tension, hence the totalenergy is the sum of kinetic enery, potentialenergy and internal energy:
(kJ)
or, on a unit mass basis,(kJ kg-1)
Almost all closed systems remain stationary(KE=PE=0) during a process (unless stated) stationary systems. Hence, the change in totalenergy of a stationary system is equal to thechange of its internal energy:
mgzUUE mV 2
2
PEKE
gzuue V 2
2
peke
UE
Summary of Total Energy
ENERGY TOTALE=U+KE+PE
Microscopicenergy
Macroscopicenergy
Internal energyU
Kinetic energy, KEPotential energy, PE
Summary of Systems
SYSTEMS
CLOSED SYSTEMS
CONTROL VOLUMES
Isolated systemsE=0
Stationary systemsKE=PE=0
PROPERTIES OF A SYSTEM Any characteristic of a system property.
Eg of properties: pressure P, temperature T, volume V,mass m, viscosity, thermal conductivity, thermalexpansion coefficient, elevation etc.
PROPERTY
IntensiveProperty
ExtensiveProperty
-independent of themass of a system
Eg: Temperature TPressure PDensity
-depend on the sizeof a system
Eg: Mass mVolume VTotal Energy E
Definations of few properties Density, = mass per unit volume.
(kgm-3)
Reciprocal of density specific volume, v (=volume per unit mass)
Relative density, s or specific gravity (SG) = ratio of the density
of a substance to the density of some standard substance at a
specified temperature (usually water at 4oC, H2O = 1000 kg/m3).
All extensive properties per unit mass specific properties Eg:
Specific volume v=V/m
Specific total energy e=E/m
Specific internal energy u=U/m
Vmρ
O2Hρ
ρ
sρSG
m
Vv
1
STATE & EQUILIBRIUM
For a system not undergoing any change, at this pointall the properties can be measured or calculatedthroughout the entire system a set of propertiesthat completely describes the condition the state ofthe system.
At a given state, all the properties of a system havefixed values. If the value of even one property changes,the state will change to a different state.
m = 2 kgT1 = 20oC
V1 = 1.5 m3
m = 2 kgT2 = 20oC
V2 = 2.5 m3
State 1 State 2
State
Equilibrium The word equilibrium implies a state of balance. In an
equilibrium state there are no unbalanced potentials (ordriving forces) within the system experiences nochanges when it is isolated from its surroundings.
Types of equilibrium states:– thermal equilibrium if the temperature is the same
throughout the entire system.– Mechanical equilibrium if there is no change in pressure
at any point of the system with time.– Phase equilibrium when the mass of each phase reaches
an equilibrium level and stays there such as water and iceinequilibrium.
– chemical equilibrium if its chemical composition does notchange with time, that is, no chemical reactions occur.
A closed system achieves thermal equilibrium
Any change that a system undergoes from one equilibriumstate to another process, and the series of statesthrough which a system passes during a process theprocess path.
When a process proceeds in an equilibrium state at alltimes, it is called a quasi-equilibrium process can beviewed as a sufficiently slow process that allows thesystem to adjust itself internally so that properties inone part of the system do not change any faster thanthose at other parts.
PROCESS & CYCLES
Process
A compression process in a piston-cylinder device:
Processes in which one thermodynamic property is keptconstant:
Process Constant propertyIsobaric pressureIsothermal temperatureIsochoric/isometric volumeIsentropic entropy
Example of Process
Cycles A system is said to have undergone a cycle if
it returns to its initial state at the end ofthe process for a cycle the initial andfinal states are identical.
Process A
Process B1
2P
V
PRESSURE Pressure = normal force exerted by a
fluid per unit area.
Pressure only deals with gas or liquid.Pressure in solids normal stress.
Unit SI : Pascal (Pa) = Nm-2
English System : psi = lbf/in2 (pound-force per square inch), psia, psig. Otherunits: bar, standard atmosphere (atm).
AFP
Area
ForcePressure
P1
Pa
Pb
Pc P2
P3
P1=P2P3
Pa=Pb=Pc
Pressure at any point in a fluid is the same in alldirections.
Pressure varies in vertical directions due to gravityeffects but does not vary in the horizontal directions.
Absolute pressure, Gage pressure & Vacuum pressure The actual pressure at a given position absolute pressure -
measured relative to absolute vacuum (i.e., absolute zeropressure).
Most pressure-measuring devices are calibrated to read zero inthe atmosphere, and so they indicate the difference between theabsolute pressure and the local atmospheric pressure gagepressure.
Gage pressure = Absolute pressure – Atmospheric pressure
Pressures below atmospheric pressure vacuum pressures -measured by vacuum gages that indicate the difference betweenthe atmospheric pressure and the absolute pressure:
Vacuum pressure = Atmospheric pressure – Absolute pressure
Absolute, gage, and vacuum pressures are all positive quantities. Must use absolute pressures in thermodynamic problems. In ES unit, gage pressure and absolute pressure are
differentiated by their respective units:– psig (pounds force per square inch gage) and– psia (pounds force per square inch absolute),– but SI unit gives identical units.
Relation between absolute pressure, gage pressure & vacuum pressure
Pvac = Patm – Pabs
(for P<Patm)
Pgage = Pabs – Patm
(for P>Patm)
Manometer Consists of a glass or plastic U-tube containing one or
more fluids such as mercury, water, alcohol, or oil. Measures small and moderate pressure differences. The height of the fluid in the tube represents the
pressure difference between the system and thesurroundings of the manometer which is equal to the gagepressure:
PatmghPPP ρatm1
.m/s 9.8 onaccelerati nalgravitatiog
tube,- Uin the points obetween tw fluid ofheight the
tube,manometer in the fluid theofdensity ρ
tank,in the pressure gas
pressure, catmospheri
2
1
atm
h
P
P
ghPP
ghPPP
ρ
ρ
atmgas
atm21
Barometer Measures atmospheric pressure,
hence atmospheric pressure alsoknown as barometric pressure.
Consists of a mercury-filled tubeinverted into a mercury containerthat is open to the atmosphere.
Referring to Figure 1:
The height and cross-sectioanalarea of the tube does not affectthe height of the liquid in thebarometer tube (Figure 2).
tube.barometer in height mercury
,onaccelerati nalgravitatio
density,mercury ρ
tube,barometer of area sectional-crossA with,
ρ
ρ
todue Force A at ight Mercury we
atm
atm
atm
atm
h
g
ghP
APghA
APW
P
Merkuri
A1 A2 A3
Figure 2
Merkuri
A
C
B
h h
Pat
m
W=ghA
Figure 1
Bourdon Tubes Another type of commonly used
mechanical pressuremeasurement device.
Consists of a hollow metal tubebent like a hook whose end isclosed and connected to a dialindicator needle.
Calibrated to read zero, so itmeasures gage pressure.
Modern pressure sensors
pressure transducers - convertthe pressure effect to anelectrical effect such as achange in voltage, resistance,or capacitance.– smaller and faster, and they
can be more sensitive,reliable, and precise
Types of Bourdon Tubes
TEMPERATURE Temperature is one of the thermodynamic
properties - a measure of “hotness” or“coldness” or the energy content of a body.
When heat is transferred to a body, E
T. The temperature difference causes the heat
transfer from a hot body (with highertemperature) to another cold body (with alower temperature).
Two bodies are in thermal equilibrium whenboth of the bodies achieve similartemperature.
Similar to pressure, temperature applied inthermodynamic problems must be in absoluteunits. Absolute temperature scale in SI unit isKelvin and Rankine in unit ES.
Temperature scalesUnit
Property
SI ES
Temperature scale
oC oF
Absolute temperature scale
K R
Melting point 0oC 32oF
Boiling point 100oC 212oC
Relation between temperature scales:T(oF) = 1.8T(oC) + 32 (oC to oF)T(K) = T(oC) + 273.15 (oC to K)T(R) = T(oF) + 459.67 (oF to R)T(R) = 1.8T(K) (K to R)
Kelvin and Celcius Magnitude for each part of
1 K and 1C is similar, thesame case with 1 R and 1F(Figure 1).
And also,
Figure 1
T K T T
T T
T
= ( C + 273.15) - ( C + 273.15)
= C - C
= C
2 1
2 1
T R T F
SYSTEMATIC PROBLEM SOLVING Complicated thermodynamic problems can be solved by a systematic
approach. The followings are the systematic steps that can be taken to solve
thermodynamic problems:1. Read and understand the requirement of the problem.2. Draw a realistic sketch of the physical system involved, and list the
relevant information on the figure. Indicate any energy and massinteractions with the surroundings. List the given information on thesketch. Also, check for properties that remain constant during aprocess (such as temperature during an isothermal process), andindicate them on the sketch.
3. State any appropriate assumptions and approximations made tosimplify the problem to make it possible to obtain a solution. Assumereasonable values for missing quantities that are necessary. Forexample, in the absence of specific data for atmospheric pressure, itcan be taken to be 1 atm.
4. Determine the unknown properties at known states necessary to solvethe problem from property relations or tables, and hence the phaseof the substance can be determined.
5. Determine the process and sketch the process on property figuressuch as P-v or T-v.
6. Apply all the relevant basic physical laws and principles (such as theconservation of mass), and reduce them to their simplest form byutilizing the assumptions made.
7. Substitute the known quantities into the simplified relations andperform the calculations to determine the unknowns.
8. Reasoning, verification and discussion: Check to make sure that theresults obtained are reasonable and intuitive, and verify the validityof the questionable assumptions.