CHAPTER TWO REVIEW. QUESTION ONE Is the relation a function? Why or why not?
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Transcript of CHAPTER TWO REVIEW. QUESTION ONE Is the relation a function? Why or why not?
CHAPTER TWO REVIEW
QUESTION ONE
Is the relation a function? Why or why not?
QUESTION ONE
Is the relation a function? Why or why not?No, (2,2) and (2,1) havethe same input, but different outputs. For a function, each input can only have one output.It does not pass the vertical line test.
Q UESTION TWO
Is the relation a function? Why or why not?
(1,2), (2,3), (3,4), (4,5), (5,6)
Q UESTION TWO
Is the relation a function? Why or why not?
(1,2), (2,3), (3,4), (4,5), (5,6)
Yes, for each input, there is exactly one output.
QUESTION THREE
Find the domain and range of the relation.
(5,0),(8,3), (1,3), (-5,2), (3,8)
QUESTION THREE
Find the domain and range of the relation.
(5,0),(8,3), (1,3), (-5,2), (3,8)
Domain: -5, 1, 3, 5, 8
Range: 0, 2, 3, 8
QUESTION FOUR
Given f(x) = -2x – 4 and g(x) = -x – 6.Find f(2) + g(-6)
QUESTION FOUR
Given f(x) = -2x – 4 and g(x) = -x – 6.Find f(2) + g(-6)
f(2) + g(-6) = -8
QUESTION FIVE
Are the lines parallel or perpendicular? Why?
y = 2x + 62x – y = 7
QUESTION FIVE
Are the lines parallel or perpendicular? Why?
y = 2x + 62x – y = 7
The lines are parallel, because the slopes are the same.
QUESTION SIX
Are the lines parallel or perpendicular? Why?
3x + 6y = 12y = 2x + 8
QUESTION SIX
Are the lines parallel or perpendicular? Why?
3x + 6y = 12y = 2x + 8
The lines are perpendicular, because the slopes are negative reciprocals of each other.
QUESTION SEVEN
Write the equation of the line given m = 2 andthrough (3,4) in point-slope form, slope-intercept form and standard form.
QUESTION SEVEN
Write the equation of the line given m = 2 andthrough (3,4) in point-slope form, slope-intercept form and standard form.
(y – 4) = 2(x – 3)y = 2x – 2-2x + y = -2
QUESTION EIGHT
Write the equation of the line through (-4, 6) and perpendicular to y = -2x + 7 in point-slope form, slope-intercept form and standard form.
QUESTION EIGHT
Write the equation of the line through (-4, 6) and perpendicular to y = -2x + 7 in point-slope form, slope-intercept form and standard form.
(y – 6) = ½(x + 4)y = ½ x + 8-½x + y = 8
QUESTION NINE
Given 2y = -4x – 12, find the slope, x-intercept, y-intercept and then graph.
QUESTION NINE
Given 2y = -4x – 12, find the slope, x-intercept, y-intercept and then graph.
Slope is -2x-intercept is (-3,0)y-intercept is (0, -6)
QUESTION TEN
Graph: 2x – 3y > -12
QUESTION TEN
Graph: 2x – 3y > -12
QUESTION ELEVEN
Graph: y = |x – 4| + 2
QUESTION ELEVEN
Graph: y = |x – 4| + 2
QUESTION TWELVE
Graph: 4y = -2x - 8
QUESTION TWELVE
Graph: 4y = -2x - 8
QUESTION THIRTEEN
Graph: y ≥ -4 x - 2
QUESTION THIRTEEN
Graph: y > -4 x - 2
QUESTION FOURTEENAt the beginning of week 7, the math teacher has 250 pencils. At the beginning of week 10, the teacher has 220 pencils.
a)Write an equation to model the number of pencils the teacher has after x weeks.
b)How many pencils will the teacher have after 18 weeks?
QUESTION FOURTEENAt the beginning of week 7, the math teacher has 250 pencils. At the beginning of week 10, the teacher has 220 pencils.
a)Write an equation to model the number of pencils the teacher has after x weeks.
y= -10x +320
b)How many pencils will the teacher have after 18 weeks?
140 pencils
RETEST REVIEWQUESTION ONE
Solve and graph: -16 < -3x – 5 < 4
RETEST REVIEWQUESTION ONE
Solve and graph: -16 < -3x – 5 < 4
−3<x<
113
−3
113
RETEST REVIEWQUESTION TWO
Solve and graph: -3|4x – 1| - 6 = -9
RETEST REVIEWQUESTION TWO
Solve and graph: -3|4x – 1| - 6 = -9
x = 0,
12
0
12