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Transcript of Chapter Menu
![Page 1: Chapter Menu](https://reader035.fdocuments.in/reader035/viewer/2022062408/56813283550346895d991e97/html5/thumbnails/1.jpg)
Chapter Menu
Stoichiometry
Section 11.1 Defining Stoichiometry
Section 11.2 Stoichiometric Calculations
Section 11.3 Limiting Reactants
Section 11.4 Percent Yield
Click a hyperlink or folder tab to view the corresponding slides. Exit
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Section 11-1
Section 11.1 Defining Stoichiometry
• Describe the types of relationships indicated by a balanced chemical equation.
reactant: the starting substance in a chemical reaction
stoichiometry
mole ratio
• State the mole ratios from a balanced chemical equation.
The amount of each reactant present at the start of a chemical reaction determines how much product can form.
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Section 11-1
Particle and Mole Relationships
• Chemical reactions stop when one of the reactants is used up.
• Stoichiometry is the study of quantitative relationships between the amounts of reactants used and amounts of products formed by a chemical reaction.
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Section 11-1
Particle and Mole Relationships (cont.)
• Stoichiometry is based on the law of conservation of mass.
• The mass of reactants equals the mass of the products.
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Section 11-1
Particle and Mole Relationships (cont.)
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Section 11-1
Particle and Mole Relationships (cont.)
• A mole ratio is a ratio between the numbers of moles of any two substances in a balanced equation.
• The number of mole ratios that can be written for any equation is (n)(n – 1) where n is the number of species in the chemical reaction.
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A. A
B. B
C. C
D. D
Section 11-1
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Section 11.1 Assessment
Which of the following is a correct mole ratio for the following equation?
2Al(s) + 3Br2(l) → 2AlBr3(s)
A. 2 mol Al : 3 mol Br
B. 3 mol Br2 : 2 mol Al
C. 2 mol AlBr3 : 1 mol Br2
D. 2 mol Br : 2 mol Al
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A. A
B. B
C. C
D. D
Section 11-1
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Section 11.1 Assessment
How many mole ratios can be written for the following reaction?
4H2(g) + O2(g) → 2H2O(l)
A. 6
B. 4
C. 3
D. 2
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Section 11-2
Section 11.2 Stoichiometric Calculations
• List the sequence of steps used in solving stoichiometric problems.
chemical reaction: a process in which the atoms of one or more substances are rearranged to form different substances
• Solve stoichiometric problems.
The solution to every stoichiometric problem requires a balanced chemical equation.
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Section 11-2
Using Stoichiometry
• All stoichiometric calculations begins with a balanced chemical equation.
4Fe(s) + 3O2(g) 2Fe2O3(s)
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Section 11-2
Using Stoichiometry (cont.)
• Steps to solve mole-to-mole, mole-to-mass, and mass-to-mass stoichiometric problems
1. Complete Step 1 by writing the balanced chemical equation for the reaction.
2. To determine where to start your calculations, note the unit of the given substance.
• If mass (in grams) of the given substance is the starting unit, begin your calculations with Step 2.
• If amount (in moles) of the given substance is the starting unit, skip Step 2 and begin your calculations with Step 3.
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Section 11-2
Using Stoichiometry (cont.)
3. The end point of the calculation depends on the desired unit of the unknown substance.
• If the answer must be in moles, stop after completing Step 3.
• If the answer must be in grams, stop after completing Step 4.
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Section 11-2
Using Stoichiometry (cont.)
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A. A
B. B
C. C
D. D
Section 11-2
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Section 11.2 Assessment
A chemical reaction equation must be ____ in order to make stoichiometric calculations.
A. measured
B. controlled
C. balanced
D. produced
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A. A
B. B
C. C
D. D
Section 11-2
Section 11.2 Assessment
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How many moles of CO2 will be produced in the following reaction if the initial amount of reactants was 0.50 moles?
2NaHCO3 → Na2CO + CO2 + H2O
A. 0.25
B. 0.3
C. 0.5
D. 1.0
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Section 11-3
Section 11.3 Limiting Reactants
• Identify the limiting reactant in a chemical equation.
molar mass: the mass in grams of one mole of any pure substance
• Identify the excess reactant, and calculate the amount remaining after the reaction is complete.
• Calculate the mass of a product when the amounts of more than one reactant are given.
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Section 11-3
Section 11.3 Limiting Reactants (cont.)
limiting reactant
excess reactant
A chemical reaction stops when one of the reactants is used up.
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Section 11-3
Why do reactions stop?
• Reactions proceed until one of the reactants is used up and one is left in excess.
• The limiting reactant limits the extent of the reaction and, thereby, determines the amount of product formed.
• The excess reactants are all the leftover unused reactants.
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Section 11-3
Why do reactions stop? (cont.)
• Determining the limiting reactant is important because the amount of the product formed depends on this reactant.
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Section 11-3
Calculating the Product when a Reactant is Limiting
• S8(l) + 4Cl2(g) → 4S2Cl4(l)
• 200.0g S and 100.0g Cl2
• Determine which is the limiting reactant– mole of reactants: 1.1410 mol CI2; 0.7797 mol S8
– mole ratios determine that for every 1 mol of S8, 1.808 mol CI2 are available
– mole ratio from equation is 4 mol Cl2 : 1 mol S8
• Chlorine is limiting since there are less moles available than required by the equation.
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Section 11-3
Calculating the Product when a Reactant is Limiting (cont.)
• Calculating the amount of product formed
– Multiply the amount of limiting reactant (Cl2) by the mole ratio relating S2Cl2 to Cl2.
– 190.4g S2Cl2 form
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Section 11-3
Calculating the Product when a Reactant is Limiting (cont.)
• Analyzing the excess reactant
– Moles reacted
• Multiply the moles of Cl2 used by the mole ratio relating S8 to Cl2.
• 0.3525 mol S8
– Mass reacted.
• Multiply moles reacted by molar mass.
• 90.42g of S8
– Excess remaining.
• 200.0g – 90.42g = 109.6 g S8 in excess
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Section 11-3
Calculating the Product when a Reactant is Limiting (cont.)
• Using an excess reactant can speed up the reaction.
• Using an excess reactant can drive a reaction to completion.
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A. A
B. B
C. C
D. D
Section 11-3
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Section 11.3 Assessment
The mass of the final product in a chemical reaction is based on what?
A. the amount of excess reactant
B. the amount of limiting reactant
C. the presence of a catalyst
D. the amount of O2 present
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A. A
B. B
C. C
D. D
Section 11-3
Section 11.3 Assessment
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What is the excess reactant in the following reaction if you start with 50.0g of each reactant?
P4(s) + 5O2(g) → P4O10(s)
A. O2
B. P4
C. Both are equal.
D. unable to determine
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Section 11-4
Section 11.4 Percent Yield
• Calculate the theoretical yield of a chemical reaction from data.
process: a series of actions or operations
theoretical yield
actual yield
percent yield
• Determine the percent yield for a chemical reaction.
Percent yield is a measure of the efficiency of a chemical reaction.
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Section 11-4
How much product?
• Laboratory reactions do not always produce the calculated amount of products.
• Reactants stick to containers.
• Competing reactions form other products.
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Section 11-4
How much product? (cont.)
• The theoretical yield is the maximum amount of product that can be produced from a given amount of reactant.
• The actual yield is the amount of product actually produced when the chemical reaction is carried out in an experiment.
• The percent yield of a product is the ratio of the actual yield expressed as a percent.
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Section 11-4
Percent Yield in the Marketplace
• Percent yield is important in the cost effectiveness of many industrial manufacturing processes.
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A. A
B. B
C. C
D. D
Section 11-4
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Section 11.4 Assessment
The amount of product that can be produced from a given amount of reactants based on stoichiometric calculations is:
A. actual yield
B. percent yield
C. theoretical yield
D. stoichiometric yield
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A. A
B. B
C. C
D. D
Section 11-4
Section 11.4 Assessment
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You calculate the theoretical yield of a chemical reaction starting with 50.0g of reactant is 25.0g of product. What is the percent yield if the actual yield is 22.0g of product?
A. 88%
B. 44%
C. 50%
D. 97%