Chapter 8 RX and Elimination Rxns. The E2 Mechanism.

Chapter 8 RX and Elimination Rxns

The E2 Mechanism

Energy Diagram for the E2 Mechanism

Effect of the Substrate on E2 Reactivity

Effect of the LG on E2 Reactivity

The E2 and SN2 mechanisms share many of the same characteristics

Here are four characteristics that theE2 / SN2 mechanisms have in common.

Good LGs

Aprotic Solvents

2nd Order

One Step

E2 SN2

= faster rxns

The E1Mechanism

CH3

I

CH3

CH3

H2O

CH3

CH3

CH2 H3O+ + I

Let ‘s look at an E1 reaction mechanismusing the rxn shown below.

The E1 Mechanism CH3

I

CH3

CH3

H2O

CH3

CH3

CH2 H3O+ + I

The first step of the E1 and SN1 mechanisms are identical.

The E1 Mechanism CH3

I

CH3

CH3

H2O

CH3

CH3

CH2 H3O+ + I

Energy Diagram for E1

CH3

I

CH3

CH3

H2O

CH3

CH3

CH2 H3O+ + I

The E1 and SN1 mechanisms share many of the same characteristics

Here are four characteristics that the E1 / SN1mechanisms have in common.

Good LGs Protic SolventsRX R3X

1st Order

Two Steps

E1 SN1

= faster rxns

What about dehydrohalogenations involving RX with hydrogen atoms on different carbon atoms

The Zaitsev Rule

Cl

KOC(CH3)3 ?

The Zaitsev Rule- A Regioselective Rxn

Cl

KOC(CH3)3

+

Two possible organic products.Which is the major product?

The Zaitsev Rule (Z-rule)

According to the Z-rule, the major productin a dehydrohalgenation is the …..

most stable product.

Let’s ask a different question about the products.

Cl

KOC(CH3)3

+

Which is the most stable product?

+

trans-2-Butene is more stable than1-butene because it has moreR groups attached at the sp2 C atoms.

More R groups increase the stability of the T.S.

Let look at another example from the Smith text.

The Zaitsev (Saytzeff) Rule – A Stereoselective RXN

E2 Stereochemistry

The LG and the H atom can be syn or

anti to each other

Bases Used in Elimination Rxns

Sterically Hindered Strong Bases

KOC(CH3)3,

LiN(CH(CH3)2)2 or LDA (lithium diisopropyl amide)

Exam II Review Problems

Br EtOH

NaNH2

Br

CH2CH3

Cl

H2O

Predict the organic product(s) and name the mechanism

CH3 -OH

Cl

Methylenecyclohexane is not the majorproduct in this rxn. Give the chemical structure of the major product and explain why it would be the major product.

Alkyl Halides and Elimination Reactions

• Elimination reactions involve the loss of elements from the starting material to form a new bond in the product.

General Features of Elimination


• Equations [1] and [2] illustrate examples of elimination reactions. In both reactions a base removes the elements of an acid, HX, from the organic starting material.



• Removal of the elements HX is called dehydrohalogenation.

• Dehydrohalogenation is an example of elimination.

• The curved arrow formalism shown below illustrates how four bonds are broken or formed in the process.



• The most common bases used in elimination reactions are negatively charged oxygen compounds, such as HO¯ and its alkyl derivatives, RO¯, called alkoxides.



• To draw any product of dehydrohalogenation—Find the carbon. Identify all carbons with H atoms. Remove the elements of H and X form the and carbons and form a bond.



• Recall that the double bond of an alkene consists of a bond and a bond.

Alkenes—The Products of Elimination


• Alkenes are classified according to the number of carbon atoms bonded to the carbons of the double bond.



• Recall that rotation about double bonds is restricted.



• Because of restricted rotation, two stereoisomers of 2-butene are possible. cis-2-Butene and trans-2-butene are diastereomers, because they are stereoisomers that are not mirror images of each other.



• Whenever the two groups on each end of a carbon-carbon double bond are different from each other, two diastereomers are possible.



• In general, trans alkenes are more stable than cis alkenes because the groups bonded to the double bond carbons are further apart, reducing steric interactions.



• The stability of an alkene increases as the number of R groups bonded to the double bond carbons increases.


• The higher the percent s-character, the more readily an atom accepts electron density. Thus, sp2 carbons are more able to accept electron density and sp3 carbons are more able to donate electron density.

• Consequently, increasing the number of electron donating groups on a carbon atom able to accept electron density makes the alkene more stable.


• trans-2-Butene (a disubstituted alkene) is more stable than cis-2-butene (another disubstituted alkene), but both are more stable than 1-butene (a monosubstituted alkene).



• There are two mechanisms of elimination—E2 and E1, just as there are two mechanisms of substitution, SN2 and SN1.

• E2 mechanism—bimolecular elimination

• E1 mechanism—unimolecular elimination

• The E2 and E1 mechanisms differ in the timing of bond cleavage and bond formation, analogous to the SN2 and SN1 mechanisms.

• E2 and SN2 reactions have some features in common, as do E1 and SN1 reactions.

Mechanisms of Elimination


• The most common mechanism for dehydrohalogenation is the E2 mechanism.

• It exhibits second-order kinetics, and both the alkyl halide and the base appear in the rate equation i.e.

Mechanisms of Elimination—E2

rate = k[(CH3)3CBr][¯OH]

• The reaction is concerted—all bonds are broken and formed in a single step.

The Zaitsev (Saytzeff) Rule

Zaitsev Rule in an E1 Type Reaction


• There are close parallels between E2 and SN2 mechanisms in how the identity of the base, the leaving group and the solvent affect the rate.

• The base appears in the rate equation, so the rate of the E2 reaction increases as the strength of the base increases.

• E2 reactions are generally run with strong, negatively charged bases like¯OH and ¯OR. Two strong sterically hindered nitrogen bases called DBN and DBU are also sometimes used.



• The increase in E2 reaction rate with increasing alkyl substitution can be rationalized in terms of transition state stability.

• In the transition state, the double bond is partially formed. Thus, increasing the stability of the double bond with alkyl substituents stabilizes the transition state (i.e. lowers Ea, which increases the rate of the reaction according to the Hammond postulate).



• Increasing the number of R groups on the carbon with the leaving group forms more highly substituted, more stable alkenes in E2 reactions.

• In the reactions below, since the disubstituted alkene is more stable, the 30 alkyl halide reacts faster than the 10 alkyl halide.



• Recall that when alkyl halides have two or more different carbons, more than one alkene product is formed.

• When this happens, one of the products usually predominates.

• The major product is the more stable product—the one with the more substituted double bond.

• This phenomenon is called the Zaitsev rule.



• When a mixture of stereoisomers is possible from a dehydrohalogenation, the major product is the more stable stereoisomer.

• A reaction is stereoselective when it forms predominantly or exclusively one stereoisomer when two or more are possible.

• The E2 reaction is stereoselective because one stereoisomer is formed preferentially.



• The dehydrohalogenation of (CH3)3CI with H2O to form (CH3)C=CH2 can be used to illustrate the second general mechanism of elimination, the E1 mechanism.

• An E1 reaction exhibits first-order kinetics:


rate = k[(CH3)3CI]

• The E1 reaction proceed via a two-step mechanism: the bond to the leaving group breaks first before the bond is formed. The slow step is unimolecular, involving only the alkyl halide.

• The E1 and E2 mechanisms both involve the same number of bonds broken and formed. The only difference is timing. In an E1, the leaving group comes off before the proton is removed, and the reaction occurs in two steps. In an E2 reaction, the leaving group comes off as the proton is removed, and the reaction occurs in one step.


• The rate of an E1 reaction increases as the number of R groups on the carbon with the leaving group increases.


• The strength of the base usually determines whether a reaction follows the E1 or E2 mechanism. Strong bases like ¯OH and ¯OR favor E2 reactions, whereas weaker bases like H2O and ROH favor E1 reactions.


Table 8.3 summarizes the characteristics of the E1 mechanism.



• SN1 and E1 reactions have exactly the same first step—formation of a carbocation. They differ in what happens to the carbocation.

SN1 and E1 Reactions

• Because E1 reactions often occur with a competing SN1 reaction, E1 reactions of alkyl halides are much less useful than E2 reactions.


• The transition state of an E2 reaction consists of four atoms from an alkyl halide—one hydrogen atom, two carbon atoms, and the leaving group (X)—all aligned in a plane. There are two ways for the C—H and C—X bonds to be coplanar.

Stereochemistry of the E2 Reaction

• E2 elimination occurs most often in the anti periplanar geometry. This arrangement allows the molecule to react in the lower energy staggered conformation, and allows the incoming base and leaving group to be further away from each other.


• The stereochemical requirement of an anti periplanar geometry in an E2 reaction has important consequences for compounds containing six-membered rings.

• Consider chlorocyclohexane which exists as two chair conformers. Conformer A is preferred since the bulkier Cl group is in the equatorial position.


• For E2 elimination, the C-Cl bond must be anti periplanar to the C—H bond on a carbon, and this occurs only when the H and Cl atoms are both in the axial position. The requirement for trans diaxial geometry means that elimination must occur from the less stable conformer, B.


• Now consider the E2 dehydrohalogenation of cis- and trans-1-chloro-2-methylcyclohexane.


• This cis isomer exists as two conformers, A and B, each of which as one group axial and one group equatorial. E2 reaction must occur from conformer B, which contains an axial Cl atom.


• Because conformer B has two different axial hydrogens, labeled Ha and Hb, E2 reaction occurs in two different directions to afford two alkenes.

• The major product contains the more stable trisubstituted double bond, as predicted by the Zaitsev rule.



• The trans isomer of 1-chloro-2-methylcyclohexane exists as two conformers: C, having two equatorial substituents, and D, having two axial substituents.


• E2 reaction must occur from D, since it contains an axial Cl atom.


• Because conformer D has only one axial H, E2 reaction occurs only in one direction to afford a single product. This is not predicted by the Zaitzev rule.



• The strength of the base is the most important factor in determining the mechanism for elimination. Strong bases favor the E2 mechanism. Weak bases favor the E1 mechanism.

When is the Mechanism E1 or E2


• A single elimination reaction produces a bond of an alkene. Two consecutive elimination reactions produce two bonds of an alkyne.

E2 Reactions and Alkyne Synthesis


• Two elimination reactions are needed to remove two moles of HX from a dihalide substrate.

• Two different starting materials can be used—a vicinal dihalide or a geminal dihalide.



• Stronger bases are needed to synthesize alkynes by dehydrohalogenation than are needed to synthesize alkenes.

• The typical base used is ¯NH2 (amide), used as the sodium salt of NaNH2. KOC(CH3)3 can also be used with DMSO as solvent.



• The reason that stronger bases are needed for this dehydrohalogenation is that the transition state for the second elimination reaction includes partial cleavage of the C—H bond. In this case however, the carbon atom is sp2 hybridized and sp2 hybridized C—H bonds are stronger than sp3 hybridized C—H bonds. As a result, a stronger base is needed to cleave this bond.



• Good nucleophiles that are weak bases favor substitution over elimination—Certain anions always give products of substitution because they are good nucleophiles but weak bases. These include I¯, Br¯, HS¯, and CH3COO¯.

Predicting the Mechanism from the Reactants—SN1, SN2, E1 or E2.


• Bulky nonnucleophilic bases favor elimination over substitution—KOC(CH3)3, DBU, and DBN are too sterically hindered to attack tetravalent carbon, but are able to remove a small proton, favoring elimination over substitution.


Is it SN1, SN2, E1 or E2?

Chapter 8 RX and Elimination Rxns. The E2 Mechanism.

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