CHAPTER 3b

30
CHAPTER 3B Stoichiometry

description

CHAPTER 3b . Stoichiometry . Counting Atoms. Amu – atomic mass unit 1 amu = 1.66 x 10 -24 g Ex. 1 carbon atom = 12 amu 1 Fe atom = 55.85 amu 1 Na atom = ??? Amu. Counting Atoms. Calculate the mass, in amu, of a sample of Fe that contains 15 atoms. - PowerPoint PPT Presentation

Transcript of CHAPTER 3b

Page 1: CHAPTER 3b

CHAPTER 3B Stoichiometry

Page 2: CHAPTER 3b

Counting AtomsAmu – atomic mass unit1 amu = 1.66 x 10-24 g

Ex. 1 carbon atom = 12 amu 1 Fe atom = 55.85 amu1 Na atom = ??? Amu

Page 3: CHAPTER 3b

Counting Atoms Calculate the mass, in amu, of a sample

of Fe that contains 15 atoms.

Calculate the mass, in amu, of a sample of carbon that contains 62 atoms.

Page 4: CHAPTER 3b

Counting Atoms Calculate the number of copper atoms

present in a sample that has a mass of 1779.4 amu.1 Cu atom = ??? Amu

Calculate the number of argon atoms present in a sample that has a mass of 3755.3 amu.

Page 5: CHAPTER 3b

MolesAn amount of matter that contains as

many objects as the number of atoms in exactly 12 grams of pure carbon 12. This number is 6.02 x 1023.

Avogadro's number = 6.02 x 1023

Page 6: CHAPTER 3b

Moles

1 dozen eggs = 12 eggs1 mole eggs = 6.02 x 1023 eggs1 mole of elephants = 6.02 x 1023

elephants1 mole of Al = 6.02 x 1023 Al atoms

Page 7: CHAPTER 3b

MolesBut they all have different masses.

1 mol of C and 1 mol of Mg have the same number of particles

but C has a mass of 12 amu and Mg a mass of 24 amu

If C has a mass of 12 g by definition then Mg = 24 grams.

Page 8: CHAPTER 3b

So….. 1 mole of the element = 6.02 x 1023 atoms of that

element and…1 amu of an element = grams of 1 mole of element

Element # of atoms Mass (g) MolesAl 6.02 x 1023 26.98 1 moleAu 6.02 x 1023 196.97 1 moleS 6.02 x 1023 32.07 1 moleFe 6.02 x 1023 55.85 1 mole

Page 9: CHAPTER 3b

Mass/Mole1 mol of an atom= average atomic mass

of the element

Ex. 1mol H = 1.008 g H 1mol C = 12.01 g C 1mol Na = 22.99 g Na

Can then use this as a conversion factor

Page 10: CHAPTER 3b

Mass/MoleCompute the number of moles of

atoms in a 25.0g sample of calcium.1mol Ca = 40.08 g

Page 11: CHAPTER 3b

Mass/Mole Calculate the number of moles of atoms

in 57.7 g sample of sulfur. Calculate the number of moles in 43.15

g of carbon. Calculate the mass in grams of 0.251

moles of sodium. Calculate the mass in grams of 5.58

moles of copper.

Page 12: CHAPTER 3b

Molar MassThe total mass of a compound.What is the mass of H20?1 atom H2O = 1 atom O and 2 atoms HSo…1 mol H20 = 1 mol O and 2 mols H

Mass of 1 mole of O = 1 x 16.00g = 16.00gMass of 2 moles of H = 2 x 1.008g = 2.016gMass of 1 mole of H2O = 18.12g

Page 13: CHAPTER 3b

Molar Mass What is the molar mass of C3H8?

What is the molar mass of NH3?

Page 14: CHAPTER 3b

Molar Mass What is the mass in grams of 1.48 moles

of potassium oxide? Calculate the mass of 4.85 mol of acetic

acid, HC2H3O2. How many moles of formaldehyde

(H2CO) does a 7.55 g sample represent? How many moles of tetraphosphorus

dioxide does a 250.0 gram sample represent?

Page 15: CHAPTER 3b

Percent Mass CompositionDetermining the percentage of how much

of the total weight each element weighs.

Ex. Determine the mass percent of each element in sulfuric acid (H2SO4).

% H =% S =% O =

Page 16: CHAPTER 3b

Percent Mass CompositionEx. Determine the mass percent of each

element in C3H7OH

Page 17: CHAPTER 3b

Formulas Empirical formula – a formula of a compound

that has the smallest whole-number ration of atoms present.

Molecular formula – the actual formula of a compound.

Ex. Determine the empirical formula for C4H10 H2O2 CCl4

Page 18: CHAPTER 3b

Calculating Empirical Formulas1. Find mass of each element2. Number of moles of each element3. Divide each elements moles by the

smallest number of moles.4. If the moles are not whole numbers,

multiply each element by the number that converts the fraction to whole numbers

Page 19: CHAPTER 3b

Calculating Empirical FormulasEx. A 1.500 gram sample of a compound

containing only carbon and hydrogen is found to contain 1.198 gram of carbon. Determine the empirical formula for this compound.

Page 20: CHAPTER 3b

Calculating Empirical FormulasEx. A sample of phosphoric acid contains

0.3086 grams of hydrogen, 3.161 grams of phosphorus, and 6.531 grams of oxygen. Determine the empirical formula for phosphoric acid.

Page 21: CHAPTER 3b

Calculating empirical Formulas

Ex. The simplest amino acid, glycine, has the following mass percents: 32.00% carbon, 6.714% hydrogen, 42.63% oxygen, and 18.66% nitrogen. Determine the empirical formula for glycine.

Page 22: CHAPTER 3b

Mole RatiosA balanced equation of a reaction gives a

ratio of moles of each compound involved in the reaction.

Remember a mole has no dimension until you add one.

Ex. NO + H2 → N2 + H2O

Ex. SiH4 + NH3 → Si3N4 + H2

Page 23: CHAPTER 3b

Mole RatiosMethane burns in oxygen to form carbon

dioxide and water.CH4 + 2O2 → CO2 + 2H2O

What number of moles of oxygen gas is required to react with 7.4 moles of methane?

How many moles of carbon dioxide will be produced by reacting 2.6 moles of oxygen with excess methane?

Page 24: CHAPTER 3b

Mole RatiosHydrogen sulfide gas reacts with oxygen

to produce sulfur dioxide gas and water.

How many moles of oxygen are required to react with 5.6 moles of hydrogen sulfide?

How many moles of sulfur dioxide gas will be produced by reacting 7.3 moles of hydrogen sulfide with excess oxygen?

How many moles of sulfur dioxide gas will be produced by reacting 7.3 moles of oxygen with excess hydrogen sulfide?

Page 25: CHAPTER 3b

Mole-Mass ConversionSolutions of sodium hydroxide absorb

carbon dioxide from the air, forming sodium carbonate and water.

Calculate the mass of carbon dioxide gas that is required to react with a solution containing 10.0 grams of sodium hydroxide.

Calculate the mass of sodium carbonate that is produced when 10.0 grams of sodium hydroxide reacts with an excess of carbon dioxide.

Page 26: CHAPTER 3b

Mass/Mole

Steps for calculating

Balance equation Convert mass of known compound to moles. Use mole ratios from balanced equation as a

conversion to moles of desired compound. Convert moles of desired compound to mass

Page 27: CHAPTER 3b

Limiting ReactantsA reactant that stops the reaction because it is

consumed.

Steps to calculating limiting reactants Balance the equation. Convert to moles. Use the mole ratios to determine limiting reagent. Using limiting reactant compute the number

moles of desired product. Convert to moles.

Page 28: CHAPTER 3b

Limiting reactantsIron(III) oxide reacts with carbon

monoxide to form iron metal and carbon dioxide gas. In a certain experiment 5.0 grams of Iron (III) oxide is reacted with 5.0 grams of carbon dioxide.

What mass of iron will be produced, assuming a complete reaction?

What mass of carbon dioxide will be produced, assuming a complete reaction?

Page 29: CHAPTER 3b

Limiting reactantsIodine reacts with chlorine gas to form

iodine chloride. In a certain experiment, 10.0 grams of iodine is reacted with 10.0 grams of chlorine gas.

What mass of aluminum chloride will be produced, assuming a complete reaction?

Page 30: CHAPTER 3b

Percent yield

In a certain experiment, the expected yield is 1.325 grams. The actual yield was 1.279 grams. Determine the percent yield.

2NH3 + CO2 → CN2H4O + H2OIf 100.0 grams of ammonia is reacted with 100.0 grams of carbon dioxide and 120.0 grams of urea are produced. Determine the percent yield.

yeild 100%Theoretical yeildactual x