CHAPTER 3 Linear Equations and Functions SECTION 3-1 Open Sentences in Two Variables.
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Transcript of CHAPTER 3 Linear Equations and Functions SECTION 3-1 Open Sentences in Two Variables.
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CHAPTER 3
Linear Equations and Functions
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SECTION 3-1
Open Sentences in Two Variables
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Open sentences in two variables– equations and inequalities containing two variables
DEFINITIONS
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9x + 2y = 15
y = x2 – 4
2x – y ≥ 6
EXAMPLES
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Solution– is a pair of numbers (x, y) called an ordered pair.
DEFINITIONS
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Solution set– is the set of all solutions satisfying the sentence. Finding the solution is called solving the open sentence.
DEFINITIONS
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Solve the equation: 9x + 2y = 15
if the domain of x is {-1,0,1,2}
EXAMPLE
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SOLUTION
x (15-9x)/2 y Solution
-1 [15-9(-1)]/2 12 (-1,12)
0 [15-9(0)]/2 15/2 (0,15/2)
1 [15-9(1)]/2 3 (1,3)
2 [15-9(2)]/2 -3/2 (2,-3/2)
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the solution set is{(-1,12), (0, 15/2), (1,3), (2,-3/2)}
SOLUTION
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Roberto has $22. He buys some notebooks costing $2 each and some binders costing $5 each. If Roberto spends all $22 how many of each does he buy?
EXAMPLE
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n = number of notebooksb = number of binders(n and b must be whole
numbers)2n + 5b =22n = (22-5b)/2
SOLUTION
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If n is odd then 22-5b is odd and n is not a whole number
SOLUTION
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SOLUTION
b (22-5b)/2 n Solution
0 [22-5(0)]/2 11 (0,11)
2 [22-5(2)]/2 6 (2,6)
4 [22-5(4)]/2 1 (4,1)
6 [12-5(6)]/2 -4 Impossible
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the solution set is{(0,11), (2, 6), (4,1)}
SOLUTION
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SECTION 3-2
Graphs of Linear Equations in Two Variables
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COORDINATE PLANE consists of two
perpendicular number lines, dividing the plane into four regions called
quadrants
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COORDINATE PLANE
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X-coordinate (abscissa)- the horizontal number line
Y-coordinate (ordinate) - the vertical number line
ORIGIN - the point where the x-coordinate and
y-coordinate cross
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ORDERED PAIR - a unique assignment of real
numbers to a point in the coordinate plane
consisting of one x-coordinate and one y-
coordinate(-3, 5), (2,4), (6,0), (0,-3)
DEFINITION
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1.There is exactly one point in the coordinate plane associated with each ordered pair of real numbers.
ONE-TO-ONE CORRESPONDENCE
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2. There is exactly one ordered pair of real numbers associated with each point in the coordinate plane.
ONE-TO-ONE CORRESPONDENCE
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GRAPH – is the set of all points in the coordinate plane whose coordinates
satisfy the open sentence.
DEFINITION
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The graph of every equation of the form
Ax + By = C (A and B not both zero) is a line. Conversely, every line in the coordinate
plane is the graph of an equation of this form
THEOREM
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LINEAR EQUATIONis an equation whose
graph is a straight line.
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SECTION 3-3
The Slope of a Line
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SLOPE
is the ratio of vertical change to the horizontal
change. The variable m is used to represent slope.
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m = change in y-coordinate change in x-coordinate
Or m = rise
run
FORMULA FOR SLOPE
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SLOPE OF A LINEm = y2 – y1
x2 – x1
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HORIZONTAL LINE
a horizontal line containing the point
(a, b) is described by the equation y = b and has slope
of 0
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VERTICAL LINE
a vertical line containing the point (c, d) is described by
the equation x = c and has no slope
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Find the slope of the line that contains the given points.
M(4, -6) and N(-2, 3)
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The slope of the line Ax + By = C (B ≠ 0) is
- A/B
THEOREM
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Let P(x1,y1) be a point and m a real number. There is one and
only one line L through P having slope m. An equation
of L is
y – y1 = m (x – x1)
THEOREM
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Write an equation of a line with the given slope and through a given point
m= -2P(-1, 3)
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SECTION 3-4
Finding an Equation of a Line
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POINT-SLOPE FORM
y – y1 = m (x – x1)
where m is the slope and (x1
,y1) is a point on the line.
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Write an equation of a line with the given slope and passing through a given point in standard form
m= -2P(-1, 3)
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Y-Intercept
is the point where the line intersects the y -
axis.
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X-Intercept
is the point where the line intersects the
x -axis.
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SLOPE-INTERCEPT FORM
y = mx + bwhere m is the slope and b
is the y -intercept
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Write an equation of a line with the given y-intercept and slope
m=3 b = 6
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Let L1 and L2 be two different lines, with slopes m1 and m2 respectively.
1. L1 and L2 are parallel if and only if m1=m2
THEOREM
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and2. L1 and L2 are
perpendicular if and only if m1m2 = -1
THEOREM
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Write an equation of a line passing through the given points
A(1, -3) B(3,2)
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Find the slope of a line parallel to the line containing points M and N.
M(-2, 5) and N(0, -1)
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Find the slope of a line perpendicular to the line
containing points M and N.
M(4, -1) and N(-5, -2)
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Write an equation of a line parallel to y=-1/3x+1 containing the point (1,1)
m=-1/3
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Write an equation of a line perpendicular to y= -1/3x+1 containing the point (1,1)
m=-1/3P(1, 1)
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SECTION 3-5
Systems of Linear Equations in Two Variables
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SYSTEM OF EQUATIONS
Two linear equations with the same two variable form
a system of equations.
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SOLUTION
The ordered pair that makes both equations true.
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The SOLUTION to the system of equations is
a point (point of intersection of the two
lines).
INTERSECTING LINES
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There is NO SOLUTION to the system of
equations (no intersection of the two
lines).
PARALLEL LINES
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The graph of each equation is the same. The lines coincide and
any point on the line is a solution.
COINCIDING LINES
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EQUIVALENT SYSTEMS
Systems that have the same solution.
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METHODS FOR SOLVING SYSTEM OF EQUATIONS
GraphingSubstitutionLinear-Combination
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SOLVE BY GRAPHING
4x + 2y = 8
3y = -6x + 12
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SOLVE BY GRAPHING
y = 1/2x + 3
2y = x - 2
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SUBSTITUTION
A method for solving a system of equations by
solving for one variable in terms of the other variable.
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SOLVE BY SUBSTITUTION
3x – y = 6x + 2y = 2
Solve for y in terms of x.3x – y = 63x = 6 + y
3x – 6 = y then
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SOLVE BY SUBSTITUTION
Substitute the value of y into the second equation
x + 2y = 2x + 2(3x – 6) = 2x + 6x – 12 = 2
7x = 14x = 2 now
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SOLVE BY SUBSTITUTION
Substitute the value of x into the first equation
3x – y = 6y = 3x – 6
y = 3(2 – 6)y = 3(-4)y = -12
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SOLVE BY SUBSTITUTION
2x + y = 0x – 5y = -11
Solve for y in terms of x.2x + y = 0
y = -2xthen
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SOLVE BY SUBSTITUTION
Substitute the value of y into the second equation
x – 5y = -11x – 5(-2x) = -11x+ 10x = -11
11x = -11x = -1
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SOLVE BY SUBSTITUTION
Substitute the value of x into the first equation
2x + y = 0y = -2x
y = -2(-1)y = 2
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LINEAR-COMBINATION
Another method for solving a system of equations where one of the variables is eliminated by adding or subtracting the two
equations.
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If the coefficients of one of the variables are opposites, add the equations to eliminate one of the variables. If the coefficients of one of the variables are the same, subtract the equations to eliminate one of the variables.
LINEAR COMBINATION
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Solve the resulting equation for the remaining variable.
LINEAR COMBINATION
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Substitute the value for the variable in one of the original equations and solve for the
unknown variable.
LINEAR COMBINATION
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Check the solution in both of the original equations.
LINEAR COMBINATION
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This method combines the multiplication property of
equations with the addition/subtraction method.
LINEAR COMBINATION
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3x – 4y = 103y = 2x – 7
SOLVE BY LINEAR-COMBINATION
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SOLUTION
3x – 4y = 10-2x +3y = -7
Multiply equation 1 by 2Multiply equation 2 by 3
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SOLUTION
6x – 8y = 20-6x +9y = -21
Add the two equations.
y = -1
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SOLUTION
Substitute the value of y into either equation and solve for
3x – 4y = 103x – 4(-1) = 10
3x + 4 = 103x = 6x = 2
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CONSISTENT SYSTEM
The system of equations has at least one solution.
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INCONSISTENT SYSTEM
The system of equations has no solution.
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DEPENDENT SYSTEM
The graph of each equation is the same. The lines
coincide and any point on the line is a solution.
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SECTION 3-6
Problem Solving: Using Systems
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If 8 pens and 7 pencils cost $3.37 while 5 pens and 11 pencils cost $3.10, how much does each pen and each pencil cost?
EXAMPLE
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Let x = cost of a peny = cost of a pencil8x + 7y = 3.375x + 11y = 3.10
SOLUTION
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Solve the system of equations.
x = 29y = 15
SOLUTION
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To use a certain computer data base, the charge is $30/hr during the day and $10.50/hr at night. If a research company paid $411 for 28 hr of use, find the number of hours charged at the daytime rate and at the nighttime rate.
EXAMPLE
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Let x = number of hrs at daytime rate
y = number of hrs at nighttime rate
30x + 10.50y = 411x + y = 28
SOLUTION
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Solve the system of equations.
x = 6y = 22
SOLUTION
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SECTION 3-7
Linear Inequalities in Two Variables
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Linear equations that have the equal sign replaced by
one of these symbols <, ≤, ≥, >
SYSTEM OF INEQUALITIES
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SYSTEM OF LINEAR INEQUALITIES
The SOLUTION of an inequality in two variables is an ordered pair of numbers that satisfies
the inequality.
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SYSTEM OF LINEAR INEQUALITIES
A system of linear inequalities can be solved by graphing each
associated equation and determining the region where
the inequality is true.
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HALF-PLANE
Graphically its the region on either side of the line.
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BOUNDARY
is the line separating the half-planes
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OPEN HALF-PLANE
is the region on either side of the boundary line (illustrated by a dashed-
line).
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CLOSED HALF-PLANE
is the solution that includes the boundary
line.
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is a graph of all the solutions of the inequality and includes a boundary,
either a solid line or dashed line and a shaded
area.
GRAPH of an INEQUALITY
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is a point that does not lie on the boundary, but
rather above or below it.
TEST POINT
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x + y ≥ 4
(0,4),(4,0)
GRAPHING INEQUALITIES
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Shade the region above a dashed line if y > mx +
b.
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Shade the region above a solid line if
y mx + b.
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Shade the region below a dashed line if y < mx +
b.
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Shade the region below a solid line if
y ≤ mx + b.
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SOLVE BY GRAPHING THE INEQUALITIES
x + 2y < 52x – 3y ≤ 1
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SOLVE BY GRAPHING THE INEQUALITIES
4x - y 58x + 5y ≤ 3
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SECTION 3-8
Functions
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MAPPING DIAGRAM
A picture showing a correspondence between two sets
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MAPPING – the relationship between the elements of the domain and range
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DOMAIN – the set of all possible x-coordinates
RANGE – the set of all possible y-coordinates
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FUNCTION
A correspondence between two sets, D and R, that assigns to each member of D exactly one member of R.
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Introduction to Functions
Definition – A function f from a set D to a set R is a relation that assigns to each element x in the set D exactly one element y in the set R. The set D is the domain of the function f, and the set R contains the range
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Characteristics of a Function
1. Each element in D must be matched with an element in R.
2. Some elements in R may not be matched with any element in D.
3. Two or more elements in D may be matched with the same element in R.
4. An element in D (domain) cannot be match with two different elements in R.
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Example
A = {1,2,3,4,5,6} and B = {9,10,12,13,15}
Is the set of ordered pairs a function?
{(1,9), (2,13), (3,15), (4,15), (5,12), (6,10)}
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Given f: x→4x – x2 with domain D= {1,2,3,4,5}
Find the range of f.f, the function that assigns to x the number 4x – x2
EXAMPLE
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SOLUTION
x 4x-x2 (x,y)1 4(1) – 1 = 3 (1,3)2 4(2) – 4 = 4 (2,4)3 4(3) – 9 = 3 (3,3)4 4(4) – 16 = 0 (4,0)5 4(5) – 25 = -5 (5,-5)
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FUNCTIONAL NOTATION
f(x) denotes the value of f at x
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VALUES of a FUNCTION
The members of its range.
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SECTION 3-9
Linear Functions
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Linear FunctionIs a function f that can be
defined by f(x) = mx + bWhere x, m and b are real
numbers. The graph of f is the graph of y = mx +b, a line with slope m and y -intercept b.
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Constant Function
If f(x) = mx + b and m = 0, then f(x) = b for all x and its graph is a horizontal line y = b
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Rate of Change m
Rate of Change m =
change in f(x)Change in x
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EXAMPLE
Find equations of the linear function f using the given information.
f(4) = 1 and f(8) = 7
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SOLUTION
m = f(8) – f(4) 8 – 4m = 3/2
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SECTION 3-10
Relations
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RELATION
Is any set of ordered pairs. The set of first coordinates in the ordered pairs is the domain of the relation, and
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RELATION
and the set of second coordinates is the range.
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FUNCTION
is a relation in which different ordered pairs have different first coordinates.
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VERTICAL LINE TEST
a relation is a function if and only if no vertical line intersects its graph more than once.
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Determine if Relation is a Function
{2,1),(1,-2), (1,2)}
{(x,y): x + y = 3}
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