Chapter 3 – Graphing Linear Equations · 08/11/2017 · 3.2 Graphing Linear Equations Ex: List...
Transcript of Chapter 3 – Graphing Linear Equations · 08/11/2017 · 3.2 Graphing Linear Equations Ex: List...
Chapter3–GraphingLinearEquationsRectangularCoordinateSystemCartesianCoordinateSystemOriginQuadrantsy-axisx-axisScaleCoordinates
Ex:Ploteachpoint:(0,0),(-1,3),(1,3),(1,-3),(-1,-3)
D location
Descartes} "GaPhig
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o•; > × Ordvetpair :( X. y )
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v
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→• =\
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'QuadrantsIT ✓ Up 3
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attendto Trig
Right Angle
Me't nd}#rectangleatstart
Ex:Givethecoordinatesofeachpoint:
Ex:(#22)Giventhefollowinggraphthatgivestheheartrateofawomanbefore,duringandafteranaerobicworkout.
a)Whatwasthewoman’sheartratehalfanhourafterbeginningtheworkout?b)Forhowlongdidthewomanworkoutathertrainingzone?
I
IAC 5,0 )
F¢5,-3.5 )
B( 1,4 )< :
: cf4,-3 )
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# - : .
"D( 0,0 )
I ✓ ¥EC -5,5 )
P1015209530;
: :
"::#: :
.
Half an hour = 30 min
( 30,140 ) -→ 140 beatspermin .
10mi -→ 40mm 30 minutes
3.2GraphingLinearEquationsEx:Listpairsofnumbersthatsatisfytheequationy=x+1byconstructingatableofvalues:c)Does(4,4)satisfythatequation?Howabout(5,-5)?d)Plotthosepairsonarectangularcoordinatesystem.Doyouseeapattern?
if"
'Ff¥¥I26 } 22+1=3
66+1=7
I¥,÷¥t¥u "
•
.l¥I¥¥¥÷¥±i)
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6 - T5- ( 1,2 )
34µW( z ,} )
-43.44'D
i - • ( 6,7 )i•<viii.
t.tt ; > ×
• (5. ' 5). .
Ex:Graph2x–y=-3bysolvingforyfirstandthensettingupatableofvalues.
2×-4=-3 y= 2×+3
zxtI.IT#fEIEetfE5+ 3 +3-
2 2 # 3=4+3--72×+3 = Y 3 2C3) +3--6+3=9yY=21¥- 1 2ft )+3= -2+3=1
8
:.5 - •H•< I.
iiiz's ; > ×
.
3.3InterceptsEx:Graphtheliney=3x–6byfindingthex-andy-interceptsandusingonemorepointasacheck.
HorizontalandVerticalLinesEx:Graphy=3bysettingupatableofvalues.
← Math English
Running into something -- intersect t¥¥.
.←y.int#Y )
4=3×-6y.int :×=o
{•#y=3(o)-6
y =O - 6
Y=- 6 X - int :* 0.
Y ( o ,- 6)
n 0=3×-6
" ,×
:* IFby 64 - §= 3¥2 -
z=X
6 @
*< >-2 - ( 2,0 )-4 - Pick one point :x=4;
✓ ¥3,466 ( 4,6 )= 6
yY=3 Horizontal ^
( 2,3)
¥5line <••<> x
- it 3
Y48ow| }
v
Ex:Graphx=-3bysettingupatableofvalues.
Ex:(Ex8)Usinginformationabouta2010ToyotaPriusHybrid,wecansetuptheequation 12m+600g=7200wheremrepresentsthenumberofmilesdriven,andgrepresentsthenumberofgallonsofgasleftinthetank.Findtheinterceptsforthislineandexplainwhattheyrepresent.
*s
§fyf¥¥EFI< :p},
" ?}Eop.VerticalGm
§o±⇒a so
m=O 120+6009=7200 ToOt 6009=7200 §
s( MB )600g 7200 # °
=( 0,12) 60-0=60-0 or
g=R 3 ?
Before you drive anywhere ,
the car has 11 J12 gallons of gas .= size of the
gas tank . TWO
go.rmt.fm?ey=wnooo7#mI6Fo
.( m , g) = ( 600,0 )
3.4SlopeandRateofChangeEx:Pretendyouaregoingtogoskiingdownamountain.Drawexamplesofthefollowing:a)averysteepslopeb)aslightlysteepslopec)aflatslopeQuestion:Howcouldwedifferentiatebetweengoingupamountainandgoingdownamountain?Question:Howcouldwequantifyhowsteeptheslopesare?
YI.
¥f¥#Fit÷- 1
←.#tIf¥a¥ea
Slope=!"#$!%& =
)*+&,$"&-)*+&,$"&.
Ex:Graphy=2x–1andthen,usingtriangles,calculatetheslopebetween:
a)x=0andx=2 b)x=2andx=6 c)x=-5andx=1Whatdoyounoticeaboutallthreeslopes?
Rie=Y 's
Fun Fnx 's~
sin't
•µ)y=2x. I
I
;Y÷•l.ie#bnionionsii.t.IAY.imSEE'¥o¥'s 'm- 1 •516 z 2.2-1=4 - k ) ( 3,5)ai#¥¥II÷f¥¥E2i5)g-y5z=XRR¥n=z4=z
⇒× . '
iE÷da¥=zT¥¥¥a
-2 zfz ) - 1
= - 5a.al
2k¥ .
#2
UsingtheSlopeFormulaTheslopeofthelinepassingthrough(x1,y1)and(x2,y2)isgivenbytheformula:
slope=m=-/0-1./0.1
Ex:Usingtheslopeformula,findtheseslopes:1)Theslopeofthelinepassingthrough(-1,3)and(2,6)2)Theslopeoftheliney=33)Theslopeofthelinex=3
= ¥n¥÷fI÷¥¥E¥÷¥÷¥÷,
= ;5¥= IT -2
m=¥nII¥e ¥ 5*5=1or }I==÷= 1 #
m = II = YIXz - X
,
y =3
K¥3 m= #= 0=2--0
IT m=¥n¥¥=yg== f- oh no
!
Undefined
ParallelandPerpendicularLinesParallelLines:PerpendicularLines:Ex:Fillinthischart:
Slope ParallelSlope PerpendicularSlope
2
3
12
34
−56
-6
0
Same SlopeM
,= mz
¥ %\a
oppositeReciprocals"
<f€°°s #' • change the sign
M ,mz=- 1 or me #
" flip UpsideDown
2 - ±3 - st± - z
÷ - ¥- E + E
- 6 + I0 undefined
Ex:Determinewhetherthelinesthrougheachpairofpointsareparallel,perpendicular,orneither.1) (3,3)and(4,4) (3,3)and(2,4)2) (2,4)and(-1,-1) (8,0)and(11,5)
← Line I← Line 2
Line I m :
m.ir#=hxIx.I=3I4'- ¥=l Parallel ? No
" mm?Ir÷ey÷¥=¥e¥= . ,I ? YesDifferentSigns
• Flipped
mi¥n=k¥eIi¥F¥i÷ panel ?
me # =Ii¥=F÷F=¥ Yes=§
3.5Slope-InterceptFormIfyouhaveanequationofalineinthisform: 2x–y=5andyousolvefory:thenyouhaveSlope-InterceptForm,whereEx:Findtheslopeandthey-interceptofthelinewithequation 9x–3y=10Ex:Writeanequationofthelinewithslope=-2andy-intercept(0,5.4)
2×-4=5
ty+y×¥Iy¥fk2×'s
4=2×-5 ifmxtbp p in Tm y.int slope yint
( o ,. 5)
Solve try :
a*¥¥÷S¥E¥i¥÷¥fEEEI¥Coins )
Y= -2×+5.4
Ex:Useslope-interceptformtograph 2x+2y=-6
Ex:Determinewhetherthegraphsofy=4x+6andx+4y=-2areparallel,perpendicularorneither.
"
¥÷¥÷¥S*E±¥a⇒m= - 1
3= b= -30,-3 )
-3 -1-
< Toy:L ; > × m= - 1
%§i.ie:6#gg• •ig . ,
v ¥31 - 4Y 2 - 5
4 Same slope
1 Opposite reciprocal slope
4=4×+6 mi
4¥IiI¥j¥¥¥I, 'fP%¥y=-¥ . ÷ met- in
Ex:(#100)AnewPlaystation3costs$310.50andmembershipinanonlinevideogamemultiplayernetworkcosts$18.49permonth.a)Writealinearequationthatgivesthecostforsomeonetobuythemachineandbelongtotheonlinenetworkformmonths.b)Useyouranswerinpartatofindthecosttobuythemachineandbelongtothenetworkfor3years.
:8.49mi310.50- -
Variable Kxed
Y= 18.49 m + 310.50
m=# months
3 years = 36 months
Y= 18.49 ( 3 6) +310.50= $976.14
3.6Point-SlopeFormm=Point-SlopeForm:y–y1=m(x–x1)Ex:Findanequationofthelinethathasslope5andpassesthrough(-1,13).Writetheanswerinslope-interceptform.
You don't need to know this
Yz - Yl
Fx ,
Gzx ,)m=YIg¥4¥ )
( xz - × , )m= Yz - Yi
Yz - Y , = ( xz - ×, )m
yz - Y , = m ( xz - × , )
t
y . y , = m ( x - xD
m=5 C- I , 13 ) ← Not an
intercept
y - y ,=m ( x - x, )
y - 13=5 ( x - G) )
y- 13=5 ( xti ) Point . Slope
Form
Solve for y :
Y - 13=5×+5+ 13 + 13
y=5xt Slope - InterceptForm
Ex:Findanequationofthelinethathasslope0andpassesthrough(3,4).Ex:Findanequationofthelinethatpassesthrough(4,2)and(-1,12).Writetheanswerinslope-interceptform.
me 0 ( 3,4 ) ← Nfitvoinpt
y- Y ,=mCx - x
, )
y- 4=06 - 3) Point . Slope
for form
y- 4=0+4+4-4=4
Method I : Point Slope Form
Slept : Find the slope
m=YI¥=t}=¥= -2
Step 2 : Use Point . Slope form
Pick one point : ( 4 ,2) m= -
zY - Y ,=m( x - X )
y-
2=-2( X . 4)Step 3 : Solve Fry C if necessary )
a
y -2=-2 ( × - 4)
y . 2=-2×+8+ 2 + 2
y=2xt←s6pEIt
Method # 2 : Slope - Interceptform
( 4,2) t I
,1 2)
step 1 : find the Slope
m.IE#=Eg=Ef=Fo= -2
Step 2 : shove the points into
Slope . Intercept form
y=m×+b ( 4,2) ft,I 2)
y=- Zxtb T 9
Not intercepts
Pick One point : f bid in
y=- 2×+6
12=-2 fi ) + b12=2 + b4=-2*-2-210
= b