Chapter 22: Electric Charge and Electric Field
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Transcript of Chapter 22: Electric Charge and Electric Field
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Chapter 22: Electric Charge and Electric Field
Electric ChargeAncient Greeks ~ 600 BC Static electicity: electric charge via friction(Attempted) pith ball demonstration:
2 kinds of properties2 objects with same property repel each other2 objects with different properties attract each otherboth properties are always created together
Benjamin Franklin:kinds of charges are positive and negativeby convention, negative charge associated with amber
Conservation of Charge: The algebraic sum of all the electric charges in any closed system is constant.
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Conductors and Insulators
(Objects are usually “charged” by moving electric charge around, rather than creating or destroying charge.)
Conductor:
charge passes easily through the material
=> conductors contain charges which are free to move
Insulator:
charge cannot move (easily) through material
Semiconductor:
transition between insulator and conductor, usually of interest because of exotic electrical properties
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Charging by induction.
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Quantization and Conservation of Charge
Microscopic structure of matter: Atoms
Nucleus
most of mass
positive charge
composed of protons (each has charge = +e) and neutrons (no electric charge)
“orbitting” electrons (each has charge = e)
Atoms tend to be charge neutral
charge quantized: e = 1.6x10-19 C
Charge transfer usually in the form of addition or removal of electrons.
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Coulomb’s Law
A description of the interaction between two (point) charges
The magnitude of the Force exerted by one charge on the other
is proportional to the magnitude of each of the charges
is inversely proportional to the square of the distance between the charges
acts along a line connecting the charges
F kQq
r 2 k 1
4 0
8.988109 N m2
C2 9109 N m2
C2
Unit of charge is the Coulomb, a new type of quantity.
How big is 1 coulomb?
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Another form of Coulomb’s Law
the force exerted by Q (“source charge”) on q (“test charge”)
q toQ from
distance,
q toQ from
r,unit vectoˆ
qon Force
ˆ2
r
r
F
rrQq
kF
ˆ r
F
Q
q
r
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rrQq
kF ˆ2
ˆ r
F
Q
q
r
Coulomb’s Law: the force exerted by Q on q
Electric Charge and Electric Field (cont’d)
i i
i
i rr
qQk
rr
qQkr
r
qQk
FFF
ˆ
ˆˆ
2
222
212
1
1
21
r2
1F
Q1
q
r1
ˆ r 1
2F
Q2ˆ r 2
F
For several Sources
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•Analyze geometry/draw diagram
•calculate magnitude of each contribution
•calculate components of each contribution
•add contributions as vectors (add component by component)
Fi kQiq
ri2
A charge q = 5.0 nC is at the origin. A charge Q1 = 2.0 nC is located 2cm to the right on the x axis and and Q2 = 3.0 nC is located 4 cm to the right on the x axis. What is the net force on q?
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.3m
.3m
.4m
Q1 = 2.0 µC
Q2 = 2.0 µC
q = 4.0 µC
Geometry
Magnitudes
Components
Net Force
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Example: Compare the electric repulsion of two electrons to theirgravitational attraction
F kQq
r 2 k 9109 N m2
C2 F GMm
r 2 G 6.6710 11 Nm2
kg2
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Electric Field and Electric forcesElectric field is a “disturbance” in space resulting from the presence of (source) charge, which exerts a force on a (test) charge.
ˆ r
F
Q
q
r
ˆ r Q
P
r
ˆ r
qPF
PE
/)at (
)at (
Q
q
r )at (
) o(
qEq
qnF
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2
2
P toQ from
distance,
P toQ from
r,unit vectoˆ
Pat Field
ˆ
r
QkE
r
r
E
rrQ
kE
ˆ r Q
P
r
E
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r2
Q1r1
ˆ r 1
Q2ˆ r 2
For several Sources
i i
i
i rr
Qk
rr
Qkr
r
Qk
EEE
ˆ
ˆˆ
2
222
212
1
1
21
E
Force Law: F = qE
1E2E
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Elementary Electric Field Examples:•What is the electric field 30 cm from a +4nC charge?
•When a 100 volt battery is connected across two parallel conducting plates 1 cm apart, the resulting charge configuration produces a nearly uniform electric field of magnitude E = 1.00 E4 N/C.
Compare the electric force on an electron in this field with its weight.
What is the acceleration of the electron?
The electron is released from rest at the top plate.
What is the final speed of the electron as it hits the second plate?
How long does it take the electron to travel this distance?
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Electric Field Calculations
•Analyze geometry/draw diagram
Electric Field Contributions are directed away from positive charges, toward negative charges
•calculate magnitude of each contribution
•calculate components of each contribution
•add contributions as vectors (add component by component)
Ei kQi
ri2
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a
x
+Q
Q
Geometry
Magnitudes
Components
Net Force
a
Electric Dipole: two equal size(Q), opposite sign charges separated by a distance (l = 2a).
Determine the electric field on the x-axis
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a
x
+Q
Q
a
Ex 0
Ey k2aQ
x 2 a2 3 2
kp
x 2 a2 3 2
xa k
p
x 3
Field of an electric dipole
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a
x
Geometry
Magnitudes
Components
a
Line of charge: uniform line of charge (charge Q, l = 2a oriented along y-axis).Determine the electric field on the x-axis
y
dQ=dy
2222
222
22
cos
cossin
22
yx
xyx
dyk
EddE
yxdy
krdQ
kEd
yxr
rx
ry
aQ
ady
QdQ
x
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Add Components
Ex dEx
all charge
kdy
x 2 y 2 3 2
y a
ya
2ka
x x 2 a2
kQ
x x 2 a2
Ex kQ
x 2, x a
Ex k2k
x, x a
infinite line of charge: Er k2k
r
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Next: infinite sheet of charge is composed of of a series of infinite lines of charges
Look carefully at related textbook examples of a ring of charge, and a disk of charge.
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sheet of charge composed of a series of infinite lines of charge = charge per area
Electric Field due to an infinite sheet of charge
z
y
Geometry
Magnitudes
Components
2222
22
22
2
cos
22
cossin
yz
y
yz
dzkk
EddE
yz
dzkk
rk
Ed
yzr
ry
rz
dz
y
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Add Components
Ey dEy
all charge
2kydz
z 2 y 2z
z
2ky1
yarctan
z
y z
2k 2 2
2k
2 0
k 1
4 0
uniform electric field!!
z
y
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Interaction of an electric dipole with an electric field
dipole in a uniform electric field
x
y
zq
q
l
F=qE
F=qE
Ep
pE
lqE
Fl
Fl
RHRFr
F
z
iii
i
sin
sin
sin2
sin2
dipole ofcenter about torque
0
p
F = F = qE
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Work done rotating dipole in an electric field
watch directions of , an d
x
y
z
l
Ep
pEU
UpEpE
dpEW
dpEddW
cos)(
coscos
sin
sin
12
2
1p
d
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“Lines of Force”
Electric Field Lines: a means of visualizing the electric field=A line in space always tangent to the electric field at each point in space
concentration give indication of field strength
direction give direction of electric field
•start on positive charges, end on negative charges
•electric field lines never cross
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+ + + + + + + + + + + + + +