Chapter 20: Electromagnetic · PDF filePHY2054: Chapter 20 11 Faraday’s Law of Induction...

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PHY2054: Chapter 20 1 Chapter 20: Electromagnetic Induction

Transcript of Chapter 20: Electromagnetic · PDF filePHY2054: Chapter 20 11 Faraday’s Law of Induction...

PHY2054: Chapter 20 1

Chapter 20: Electromagnetic Induction

PHY2054: Chapter 20 2

TopicsElectromagnetic Induction

Magnetic fluxInduced emf

Faraday’s Law Lenz’s LawMotional emf

Magnetic energyInductanceRL circuitsGenerators and transformers

PHY2054: Chapter 20 3

Reading Quiz 1Magnetic flux through a wire loop depends on:

1) thickness of the wire2) resistivity of the wire3) geometrical layout of the wire4) material that the wire is made of5) none of the above

Flux depends only on geometrical properties cosB BA θΦ =

PHY2054: Chapter 20 4

Reading Quiz 2An induced emf produced in a motionless circuit is due to

1) a static (steady) magnetic field2) a changing magnetic field3) a strong magnetic field4) the Earth’s magnetic field5) a zero magnetic field

Faraday’s law

PHY2054: Chapter 20 5

Reading Quiz 3Motional emf relates to an induced emf in a conductor which is:

1) long2) sad3) stationary4) insulated5) moving Potential difference proportional to velocity

PHY2054: Chapter 20 6

Reading Quiz 4Faraday’s law says that1. an emf is induced in a loop when it moves through an electric

field2. the induced emf produces a current whose magnetic field

opposes the original change3. the induced emf is proportional to the rate of change of magnetic

flux

Faraday’s law

PHY2054: Chapter 20 7

Reading Quiz 5A generator is a device that:

a) transforms mechanical into electrical energyb) transforms electrical into mechanical energyc) transforms low voltage to high voltage

PHY2054: Chapter 20 8

Magnetic FluxDefine magnetic flux ΦB

θ is angle between B and the normal to the plane

Flux units are T-m2 = “webers”

When B field is not constant or area is not flat

Integrate over area

Won’t cover this case here

cosB BA θΦ = ⋅ =B A

B AdΦ = ⋅∫ B A

PHY2054: Chapter 20 9

0BΦ = 12B BAΦ = B BAΦ =

cosB BA θΦ = ⋅ =B A

PHY2054: Chapter 20 10

This effect can be quantified by Faraday’s Law

Experimental Observation of Induction

PHY2054: Chapter 20 11

Faraday’s Law of Induction

inducedemf

number of loops

rate of changeof flux with time

The faster the change, the larger the induced emfFlux change caused by changes in either B, area, orientationMinus sign explained next slide

BNt

ε ΔΦ= −

Δ

PHY2054: Chapter 20 12

Faraday’s Law of Induction

inducedemf

number of loops

rate of changeof flux with time

Minus sign from Lenz’s Law:Induced current produces a magnetic field which opposes the original change in flux

BNt

ε ΔΦ= −

Δ

PHY2054: Chapter 20 13

Comment on Lenz’s LawWhy does the induced current oppose the change in flux?

Consider the alternativeIf the induced current reinforced the change… then the change would get bigger… which would then induce a larger current… and then the change would get even bigger… and so on . . .

A clear violation of conservation of energy!!

PHY2054: Chapter 20 14

Bar magnet moves through coilCurrent induced in coil

Reverse poleInduced current changes sign

Coil moves past fixed bar magnetCurrent induced in coil as in (A)

Bar magnet stationary inside coilNo current induced in coil

Direction of Induced Current

S N

vS N

vN S

S N

A

B

C

D

v

PHY2054: Chapter 20 15

ConcepTest: Lenz’s Law If a North pole moves towards the loop from above the page, in what direction is the induced current?

(a) clockwise (b) counter-clockwise (c) no induced current

Must counter flux change indownward direction with upward B field

PHY2054: Chapter 20 16

ConcepTest: Induced Currents A wire loop is being pulled through a uniform magnetic field. What is the direction of the induced current?

(a) clockwise (b) counter-clockwise (c) no induced current

x x x x x x x x x x x x xx x x x x x x x x x x x xx x x x x x x x x x x x xx x x x x x x x x x x x xx x x x x x x x x x x x xx x x x x x x x x x x x xx x x x x x x x x x x x x

No change in flux, no induced current

PHY2054: Chapter 20 17

ConcepTest: Induced Currents

In the cases above, what is the direction of the induced current?

x x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x x x x x x

1

2

Counterclockwise None

PHY2054: Chapter 20 18

ConcepTest: Lenz’s Law If a coil is shrinking in a B field pointing into the page, in what direction is the induced current?

(a) clockwise (b) counter-clockwise (c) no induced current

Downward flux is decreasing,so need to create downwardB field

PHY2054: Chapter 20 19

Induced currents A circular loop in the plane of the paper lies in a 3.0 T magnetic field pointing into the paper. The loop’s diameter changes from 100 cm to 60 cm in 0.5 s

What is the magnitude of the average induced emf?What is the direction of the induced current?If the coil resistance is 0.05Ω , what is the average induced current?

Direction = clockwise (Lenz’s law)

Current = 3.016 / 0.05 = 60.3 A

( )2 20.3 0.53.0 3.016 Volts

0.5BV

t

π −ΔΦ= = × =

Δ

PHY2054: Chapter 20 20

ConcepTest: Induced Currents A wire loop is pulled away from a current-carrying wire. What is the direction of the induced current in the loop?

(a) clockwise (b) counter-clockwise (c) no induced current

I

Downward flux through loopdecreases, so need to createdownward field

PHY2054: Chapter 20 21

ConcepTest: Induced Currents A wire loop is moved in the direction of the current. What is the direction of the induced current in the loop?

(a) clockwise (b) counter-clockwise (c) no induced current

I

Flux does not change whenmoved along wire

PHY2054: Chapter 20 22

ConcepTest: Lenz’s Law If the B field pointing out of the page suddenly drops to zero, in what direction is the induced current?

(a) clockwise (b) counter-clockwise (c) no induced current

If a coil is rotated as shown, in a B field pointing to the left, in what direction is the induced current?

(a) clockwise (b) counter-clockwise (c) no induced current

Upward flux through loopdecreases, so need to createupward field

Flux into loop is increasing, soneed to create field out of loop

PHY2054: Chapter 20 23

ConcepTest: Induced CurrentsWire #1 (length L) forms a one-turn loop, and a bar magnet is dropped through. Wire #2 (length 2L) forms a two-turn loop, and the same magnet is dropped through. Compare the magnitude of the induced currents in these two cases.

(a) I1 = 2 I2

(b) I2 = 2 I1

(c) I1 = I2 ≠ 0(d) I1 = I2 = 0(e) Depends on the strength of the magnetic field

Voltage doubles, but R alsodoubles, leaving current the same

PHY2054: Chapter 20 24

Motional EMFConsider a conducting rod moving on metal rails in a uniform magnetic field:

( ) ( )ε Φ= = = =Bd d BA d BLx dxBL

dt dt dt dt

x

x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x xx x x x x x x x x

v L ε = BLv

Current will flow counter-clockwise in this “circuit”. Why?

PHY2054: Chapter 20 25

Force and Motional EMFPull conducting rod out of B field

Current is clockwise. Why?

Current within B field causes force

Force opposes pull (RHR)Also follows from Lenz’s law

We must pull with this forceto maintain constant velocity

ε= =

BLviR R

2 2= =

B L vF iLBR

PHY2054: Chapter 20 26

Power and Motional EMFForce required to pull loop:

Power required to pull loop:

Energy dissipation through resistance

Same as pulling power! So power is dissipated as heatKinetic energy is constant, so energy has to go somewhereRod heats up as you pull it

2 2= =

B L vF iLBR

2 2 2= =

B L vP FvR

2 2 2 22 ⎛ ⎞= = =⎜ ⎟

⎝ ⎠BLv B L vP i R R

R R

PHY2054: Chapter 20 27

ExamplePull a 30cm x 30cm conducting loop of aluminum through a 2T B field at 30cm/sec. Assume it is 1cm thick.

Circumference = 120cm = 1.2m, cross sectional area = 10-4 m2

R = ρL/A = 2.75 x 10-8 * 1.2 / 10-4 = 3.3 x 10-4 Ω

EMF

Current

Force

Power

2 0.3 0.3 0.18Vε = = × × =BLv

4/ 0.18 / 3.3 10 545Aε −= = × =i R

2 98W= =P i RAbout 0.330 C per sec(from specific heat, density)

545 0.3 2 327 NF iLB= = × × = 74 lbs!

PHY2054: Chapter 20 28

Electric GeneratorsRotate a loop of wire in a uniform magnetic field:

changing θ ⇒ changing flux ⇒ induced emfΦB = B A cos θ = B A cos(ωt)

Rotation: θ = ωt

PHY2054: Chapter 20 29

Electric GeneratorsFlux is changing in a sinusoidal manner

Leads to an alternating emf (AC generator)

cos( ) sin( )Bd d tN NBA NBA tdt dt

ω ω ωε Φ= = =

This is how electricity is generated

Water or steam (mechanical power) turns the blades of a turbine which rotates a loop

Mechanical power converted to electrical power

PHY2054: Chapter 20 30

ConcepTest: GeneratorsA generator has a coil of wire rotating in a magnetic field. If the B field stays constant and the area of the coil remains constant, but the rotation rate increases, how is the maximum output voltage of the generator affected?

(a) Increases (b) Decreases (c) Stays the same(d) Varies sinusoidally

sin( )ω ωε = NBA t

PHY2054: Chapter 20 31

Induction in Stationary CircuitSwitch closed (or opened)

Current induced in coil B (direction shown is for closing)

Steady state current in coil ANo current induced in coil B

A

B

PHY2054: Chapter 20 32

Self - InductanceConsider a single isolated coil:

Current (red) starts to flow clockwise due to the batteryBut the buildup of current leads to changing flux in loopInduced emf (green) opposes the change

d diN Ldt dt

ε Φ=− =−

L is the self-inductanceunits = “Henry (H)”

induced emf

This is a self-induced emf (also called “back” emf)

12V

PHY2054: Chapter 20 33

Inductance of SolenoidTotal flux (length l)

( )( ) 20μΦ = =BN nl B A n A li

0μ=B in

20

Bd di diN n Al Ldt dt dt

με Φ= − = − = −

20L n Alμ=

To make large inductance:Lots of windingsBig areaLong

PHY2054: Chapter 20 34

LR CircuitsInductance and resistor in series with battery of EMF V

Start with no initial current in circuitClose switch at t = 0Current is initially 0 (initial increasecauses voltage drop across inductor)

Find i(t)Resistor: ΔVR = RiInductor: ΔVL = L di/dtUse back emf of inductor

VR

L

( ) /LV V V Ldi dti tR R−Δ −

= =

PHY2054: Chapter 20 35

Analysis of LR CircuitGeneral solution

( )( )// 1 −= − tR Li V R e

Final current (maximum)

Rise from 0 withtime constant τ = L / R

PHY2054: Chapter 20 36

L-R Circuits (2)Switch off battery: Find i(t) if current starts at i0

/0

tR Li i e−= Exponential fall to 0 withtime constant τ = L / R

Initial current (maximum)

PHY2054: Chapter 20 37

Exponential Behaviorτ = L/R is the “characteristic time” of any RL circuit

Only t / τ is meaningful, just like for RC circuit

t = τCurrent falls to 1/e = 37% of maximum valueCurrent rises to 63% of maximum value

t =2τCurrent falls to 1/e2 = 13.5% of maximum valueCurrent rises to 86.5% of maximum value

t =3τCurrent falls to 1/e3 = 5% of maximum valueCurrent rises to 95% of maximum value

t =5τCurrent falls to 1/e5 = 0.7% of maximum valueCurrent rises to 99.3% of maximum value

PHY2054: Chapter 20 38

ConcepTest: Generators and MotorsA current begins to flow in a wire loop placed in a magnetic field as shown. What does the loop do?

(a) moves to the right (b) moves up (c) rotates around horizontal axis(d) rotates around vertical axis(e) moves out of the page

This is how a motor works !!

B

PHY2054: Chapter 20 39

Current is supplied from an external source of emf (battery or power supply)

Forces act to rotate the wire loop

A motor is essentially a generator operated in reverse!

Electric Motors

PHY2054: Chapter 20 40

MotorForces act to rotate the loop towards the vertical.

When loop is vertical, current switches sign and the forces reverse, in order to keep the loop in rotation.

This is why alternating current is necessary for a motor to operate.

PHY2054: Chapter 20 41

Motors Generators

Electrical ⇒ mechanical energy Mechanical ⇒ electrical energy

PHY2054: Chapter 20 42

Energy of an InductorEnergy is stored in inductor when current flows through it

Energy is stored in the B field

Similar to energy in charged capacitor

Energy is stored in the E field (between plates)

212LU Li=

221

22CqU CVC

= =

PHY2054: Chapter 20 43

Energy of SolenoidRecall B field of solenoid (current i, n turns per meter)

Inductance of solenoid

Energy of solenoid can be written in terms of B field and volume (V = lA)

0B niμ=

( )( )0 20

B nl niANL n Ali i

μμΦ

= = =

( )2 2

2 21 102 2

0 02LB BU Li n lA Al

μ μ⎛ ⎞

= = =⎜ ⎟⎝ ⎠

0B BA niAμΦ = =

Energy densityof B field

Volume

PHY2054: Chapter 20 44

Energy of Solenoid (2)Typical MRI magnet

B = 0.5 – 1.5 TR = 0.25 m, l = 2.5 m

Assume B = 1 T typically

This is a lot of energyNeeds to be held in by strong materials

2 30.5mV Al R lπ= = ≅

( )2 2

70

1 0.5 200 kJ2 2 4 10BBU Vμ π −= = ≈

× ×

PHY2054: Chapter 20 45

Gigajoule Magnet at CERNCMS experiment at CERN

p-p collisions at world’s highest energy in 2007Hope to discover new particles, find the origin of mass and new fundamental forces

Compact Muon Solenoid

PHY2054: Chapter 20 46

Human

PHY2054: Chapter 20 47

CMS Experiment MagnetLarge central solenoid magnet to study particle production

B = 4T, R = 3.15 m, l = 12.5 mUB = 2.6 x 109 J = 2.6 gigajoules!!

http://www.spacedaily.com/news/energy-tech-04b.html

( )( )2 2

27

0

4 3.15 12.52 2 4 10BBU Al πμ π −= = ×

× ×

PHY2054: Chapter 20 48

CMS Articles and PicturesHome page

http://cmsinfo.cern.ch/Welcome.html/

Pictures of detectorhttp://cmsinfo.cern.ch/Welcome.html/CMSdetectorInfo/CMSdetectorInfo.htmlhttp://cmsinfo.cern.ch/Welcome.html/CMSmedia/CMSmedia.html

Interesting article on solenoid, with pictureshttp://cmsinfo.cern.ch/Welcome.html/CMSdocuments/MagnetBrochure/MagnetBrochure.pdf

Other documents & pictures about CMShttp://cmsinfo.cern.ch/Welcome.html/CMSdocuments/CMSdocuments.html