Chapter 2 –...
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1 ● Chapter 2 – Trigonometry
Pre-Calculus 11
Angles in Standard Position An angle consists of two rays joined together called the vertex. An angle in standard position (θ) is
one of the arm or ray is always on the positive x-axis (called the initial arm) and its vertex (corner
where the 2 rays meet) is always at the origin (0, 0) (called the terminal arm).
The graph is broken into 4 different Quadrant. Angles are measured from the initial arm to the
terminal arm. If rotated counter-clockwise the angle is ____________. If rotated clockwise the
angle is _________________.
Example 1: Without measuring, draw each angle, in standard position and state which quadrant the terminal arm lies in.
a) 175° b) 200° c) −75°
You Try…
page 83 #1-2, 3-4(alt. letters)
y
x
y
x
Chapter 2 – Trigonometry ● 2
Pre-Calculus 11
Reference Angles
The reference angle (θR) is the angle between the terminal arm and the CLOSEST x-axis. The reference angle is always positive (no matter the direction of rotation) and measures between 0° and 90°.
Example 2: Determine the quadrant and the reference angle for each angle in standard position?
a) 215° b) 300°
3 ● Chapter 2 – Trigonometry
Pre-Calculus 11
Example 3: Determine the measure of the three other angles in standard position, 0° < θ < 360°, that have the reference angle of
a) 65° b) 15°
=
You Try…
page 83-84 #5-7
Special Triangles
Recall
Pythagoras Theorem and Sine, Cosine and Tangent of a right triangle
sin _______ cos ________
tan ________
a c
θ
b
Chapter 2 – Trigonometry ● 4
Pre-Calculus 11
Example 1: Solve each triangle. Round to the nearest tenth when appropriate.
a) b)
Right triangles are pretty special in their own right. But there are two extra-special right triangles They are 30-60-90 triangles and 45-45-90 triangles.
45-45-90 Triangle
45sin _______ 45cos _______ 45tan _______
45°
45°
18 cm 30 cm 27 cm
55°
x r Y
X
S
t
5 ● Chapter 2 – Trigonometry
Pre-Calculus 11
30-60-90 Triangle
Example 2: Determine the exact lengths for each of the following a) b)
30sin _______
30cos _______
30tan _______
60sin _______
60cos _______
60tan _______
30°
6 cm
x cm
45° 3 cm x cm
Chapter 2 – Trigonometry ● 6
Pre-Calculus 11
Example 3: Determine the exact lengths for each of the following
a)
b)
i. What is DE?
ii. What is the exact vertical distance between A and C?
You Try…
Special Right Triangle Worksheet
AB = BC = 10
30 m
7 ● Chapter 2 – Trigonometry
Pre-Calculus 11
Trigonometric Ratios of Any Angle Suppose θ is any angle in standard position, and P(x, y) is any
point on its terminal arm, at a distance r from the origin. Then
by the Pythagorean Theorem, ________________________
You can use the reference angle to determine the three primary trigonometric ratios in terms of x, y and r.
hypotneuse
oppositesin
hypotneuse
adjacentcos
adjacent
oppositetan
The chart below summarizes the signs of the trigonometric ratios in each quadrant
P(x, y)
θ
y
x
r
Chapter 2 – Trigonometry ● 8
Pre-Calculus 11
The sign of the trigonometric ratios is determined by the quadrant that the terminal side is in. This means that if 0sin (sine ratio is positive), then θ must terminate in either quadrant _____ or _____ , or if 0cos (cosine ratio is positive), then θ must terminate in either quadrant _____ or _____. Finding the trigonometric Ratios of Angles Example 1: The point P(5, −3) lies on the terminal side of the angle θ. Determine the exact trigonometric ratios for sin θ, cos θ and tan θ.
You Try … The point P(−5, −12) lies on the terminal side of the angle θ. Determine the exact trigonometric ratios for sin θ, cos θ and tan θ.
Finding the exact value of a Trigonometric Ratios (using special triangles
Example 2: Determine the exact value of 120cos
9 ● Chapter 2 – Trigonometry
Pre-Calculus 11
You Try… Determine the exact value of
Example 3: Given that 7
4cos and that θ terminates in Quadrant IV, determine the exact values of
the other trigonometric ratios.
Example 4: If 4
3cos
and
3
7tan , determine the exact value of sin .
You Try…
page 96 #1, 2(a-c), 3-6, 8, 11, 16
Chapter 2 – Trigonometry ● 10
Pre-Calculus 11
The Trigonometric Ratios of the Quadrantal Angles
The quadrantal angles are any rotation angle which is a multiple of 90° (ie. 0°, 90°, 180°, 270°, 360°). Another way of describing them is to say that their terminal arm is on either __________________.
It is important to know that Quadrantal angles DO NOT form a triangle, but by the definition of angles in standard position we have…
siny
r
cosx
r
tany
x
siny
r cos
x
r tan
y
x
0
90
180
270
, 0r
0 , r
, 0r
0 , r
11 ● Chapter 2 – Trigonometry
Pre-Calculus 11
Solving for more than one angle
Example 5: Without a calculator, solve for 2
3sin and 0 360 .
Example 6: Given 20
17sin where 3600 , determine the value(s) of θ to the nearest tenth
of a degree.
Note: sometimes the trigonometric ratio is given as a decimal number (for example: sin 0.8228 ), you will solve exactly like example #6.
You Try…
page 96-97 #2d, 7, 9, 10, 13, 19
Step 1: Determine which quadrants the solutions will be in by looking at the sign (+ or −) of the given ratio.
Step 2: Solve for the reference angle, either by special triangle or inverse trigonometric |ratio| (absolute value).
Step 3: Sketch out which quadrants will the terminal arm will be (from step 1) in with the reference angle (step 2).
Step 4: determine the standard position angle.
Chapter 2 – Trigonometry ● 12
Pre-Calculus 11
The Sine Law Recall:
Example 1: Solve for x.
Method 1: Using Primary Trigonometric Ratios
Method 2: Using Sine Law
The Sine Law for non-right triangles
In any triangle
c
C
b
B
a
A sinsinsin
or
C
c
B
b
A
a
sinsinsin
The ratio of the sine of any angle to its opposite side is the same for all three angles in any triangle.
B
C A
a
b
c
Where does the Sine Law come from? See this YouTube Video
https://www.youtube.com/watch?v=4_yQZgjFYy8
x
20° 55°
6.4
13 ● Chapter 2 – Trigonometry
Pre-Calculus 11
Example 2: Determine the indicated lengths in the triangles below using sine law:
Example 2: Determine the size of the missing angles in the diagram:
12 cm y
x
42° 61°
18 km
8.7 km
P
N M 162°
When solving for an angle, don’t forget to apply inverse sine (sin−1)
Chapter 2 – Trigonometry ● 14
Pre-Calculus 11
Example 3: Solve the triangle KGB with 37K , 84G and cmk 12 .
Example 4: Pudluk’s family and his friend own cabins on the Kalit River in Nunavut. Pudluk and his friend wish to determine the distance from Pudluk’s cabin to the store on the edge of town. They know that the distance between their cabins is 1.8 km. Using a transit, they estimate the measures of the angles between their cabins and the store, as shown in the diagram. Determine the distance from Pudluck’s cabin to the store, to the nearest tenth of a kilometre.
You Try…
page 108-109 #1(c, d), 3, 4(b-d), 5, 10, 12
Store
15 ● Chapter 2 – Trigonometry
Pre-Calculus 11
The Ambiguous Case When solving a triangle, you must analyse the given information to determine if a solution exists. If
you are given the measures of two angles and one side (ASA), then the triangle is uniquely defined.
However, if you are given 2 sides and an angle opposite one of those sides (SSA), the triangle may not
be unique. It is possible that there is _______________,_________________, or
______________ with the given measurements.
In triangles where A is acute No triangle possible
Condition
Aba
ha
sin
Example
Exactly one triangle
Aba
ha
sin
Or
ba
Two possible triangles
baAb
bah
sin
or
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Pre-Calculus 11
If A is obtuse and ba , then there is one solution. If ba then there is no solution.
Example 5: For each of the following, determine whether there is no solution, one solution or two solutions.
a) In ABC with 128A , cma 36 and cmb 45
b) In PQR with 36P , 24.8p cm and 23.4q cm Example 6: In ABC , 34A and cmb 250 . Determine the range of values of a for which there is
a) one triangle b) no triangle c) two triangles
If A is an acute angle, then Find sinh b A
ba = one solution
ha = one solution (right Δ)
a < h = no solution
h < a < b = two solutions
If A is an obtuse angle, then
ba = no solution
a b = one solution
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Pre-Calculus 11
Solving a Triangle with Two Possible Solutions Example 7: Solve the triangle ABC with 40A , cma 24 and cmb 30 . You Try… page 108-109 #4(a),6, 8, 9, 11, 13
Chapter 2 – Trigonometry ● 18
Pre-Calculus 11
The Cosine Law The Cosine Law is a rule relating the three sides of a triangle with the cosine of one of the angles.
For any triangle, ABC , Abccba cos2222
Or
Cabbac
Baccab
cos2
cos2222
222
Determining Side Length using Cosine Law Example 1: Determine the distance x in the diagram below.
A
C
B
b a
c
x
35 km
26 km
21°
Where does the Cosine Law come from? See this YouTube Video
https://www.youtube.com/watch?v=lPP-pABvwdA
19 ● Chapter 2 – Trigonometry
Pre-Calculus 11
Determining Angles using Cosine Law To solve for the angle in cosine law, you must do some algebra or memorize the following formula.
bc
acbA
2cos
2221
Example 2: Determine the size of A . You Try… page 119-122 #1, 2, 4, 6 Example 3: An aircraft-tracking station determines the distance from a helicopter to two aircraft as 50 km and 72 km. The angle between those two distances is 49°. Determine the distance between the two aircraft.
22 cm
10 cm
14 cm
A
B
C
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Example 4: Solve the triangle ABC with 36B , cma 14 and cmc 21 . Which one to use? Use Sine Law if you are given the measurement of
two angles and one side.
Two sides and an opposite one of the given sides (check for the ambiguous case) Use Cosine Law if you are given the measurement of
When all 3 sides
Two sides with an angle in between.