Chapter 18 Acid Base Equilibria - Linn-Benton Community...

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Chapter 18 Acid Base Equilibria

Transcript of Chapter 18 Acid Base Equilibria - Linn-Benton Community...

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Chapter 18

Acid Base Equilibria

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Properties of Acids and Bases

Acids Bases

Release H+ Release OH-

Neutralize OH- Neutralize H+

Proton Donors Proton Acceptors

Electron Pair Acceptors Electron Pair Donors

pH < 7 pH > 7

Taste Sour Taste Bitter, Feel Slippery

Litmus Paper (turns pink) Litmus paper (turns blue)

Reacts with most metals

to form H2(g)

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Neutralization Reaction

Acid + Base Salt + H2O(l)

Strong acids and bases dissociate approximately

100%

Strong Acids: HCl, HBr, HI, HNO3, HClO4, HClO3,

H2SO4

Strong Bases: Soluble metal hydroxides

Weak acids and bases dissociate << 100%

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Fig.

18.1

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Weak Acid Equilibrium Expression

HA H+ + A-

Ka = [H+][A-] or

[HA]

Ka = [H3O+][A-]

[HA]

HA + H2O(l) H3O+ + A-

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Fig.

18.2

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Example

Write the equilibrium expression for the following

dissociation of benzoic acid:

Note: A 2 M solution only dissociates about 0.6%

O

O H

O

O

+ H

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Fig.

18.3

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Weak Base Characteristics

Weak bases, such as insoluble metal

hydroxides, dissociate << 100% in water---

releasing few OH- ions.

Weak bases, such as ammonia, amines and

amides, slightly react with water to release

OH- ions. This process is also called

dissociation.

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Weak Base Equilibrium Expression

Kb = [HB+][OH-]

[B]

B + H2O(l) HB+ + OH-

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Example

Write the equilibrium expression for the following

dissociation:

NH3 + H2O(l) NH4+ + OH-

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Autoionization of Water

Water self-ionizes. Pure water dissociates, but very

little. It is a very weak electrolyte.

Write equilibrium expressions for the following

dissociations:

H2O(l) + H2O(l) H3O+ + OH-

H2O(l)H+ + OH-

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Autoionization of Water Cont.

Using your equilibrium table/problem solving

technique learned in the last chapter,

determine the [H+] and [OH-] in water.

Kw = 1.0 X 10-14

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Fig.

18.4:

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Problem Solving

1. If HNO3 is added to H2O, the [H3O+] is

2.0 X 10-5M, what is the [OH-]?

2. If LiOH is added to water, the [OH-] is 2.0 X 10-5 M, what is the [H+]?

3. If H+ is added to water in which direction will the equilibrium shift?

4. If OH- is added to water in which direction will the equilibrium shift?

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pH

The following relationships are often used to determine the pH and pOH of a solution.

pH = - log [H+] pOH = - log [OH-]

pKw = -log Kw 14 = pH + pOH

If the pH = 7, the solution is neutral; [H+] = [OH-]

If the pH < 7, the solution is acidic; [H+] > [OH-]

If the pH > 7, the solution is basic; [H+] < [OH-]

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Fig. 18.5

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Fig.

18.6

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Fig. 18.7

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Problem Solving

Determine the pH, pOH, [H+], [OH-] as appropriate for the following problems.

a. A sample of blood has a pH of 7.40.

b. A household ammonia solution has a [OH-]=7.94X10-3 M.

c. A sample of rain water has a pH of 5.40.

d. A 0.0400 M HBr solution.

e. A 0.0250 M NaOH solution.

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More Problem Solving

1. What is the pH, pOH, [H+], [OH-] of a 0.20 M

Ba(OH)2 solution?

2. Consider a 3.00 L 0.00100 M HCl solution.

If 50.0 mL of 0.00900 M NaOH is added,

what is the pH of the solution?

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Bronsted-Lowry Acids and Bases

Recall: Acids are proton donors and bases are

proton acceptors.

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Fig.

18.8

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An acid-base conjugate pair: Two species of an

acid-base reaction that differ by the loss or gain of a

proton (H+).

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Application Time!

Look at the following acid-base reactions and

determine (a) the acid, (b) the base, and (c)

the acid-base conjugate pairs in each.

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CO32- + H2O(l) HCO3

- + OH-

C2H3O2- + HNO2 HC2H3O2 + NO2

-

HCO3- + H2O(l) H3O+ + CO3

2-

HCO3- + H2O(l) OH- + H2CO3

Note: A substance that can act as an acid or a base is said to be amphiprotic.

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Fig. 18.9: Strength relationship between acid-base conjugate pairs.

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Lewis Acids and Bases

Recall: An acid can also be an electron pair

acceptor and a base can be an electron pair

donor.

Example: See the next slide

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Label the Lewis acid and base. The product is

called an adduct.

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Acid-Base Pair Strength Relationships

The higher the Ka, the stronger the acid, the

weaker the conjugate base.

Note: pKa = -log Ka

The higher the Ka, the lower the pKa.

The stronger the acid, the weaker the

conjugate base.

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Weak Monoprotic Acid Problem

Solving

1. Determine the equilibrium constant for a 0.10 M phenol (HC6H5O) solution that has a pH of 5.43 at 250C. What is the degree of ionization of this weak acid?

2. What are the concentrations of nicotinic acid, hydogen ion, and nicotinate ion in a solution of 0.15 M nicotinic acid (HC6H4O2) at 25oC? What is the pH? What is the percent ionization?

Ka = 1.4 x 10-5

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3. Determine the percent ionization for each of the

following solutions: 0.10 M HC2H3O2 and 0.0010

M HC2H3O2. Ka = 1.7 x 10-5

4. When 5.00 grains of aspirin are dissolved in 0.500

liters of solution, 0.325 grams of acetylsalicylic

acid (HC9H7O4) are present. What is the pH of the

solution?

Ka = 3.3 x 10-4

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Polyprotic Acids

Polyprotic Acids are compounds that contain

more than one acidic hydrogen.

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General Equilibrium Expressions for a

Triprotic Acid

H3A H+ + H2A- Ka1 =[H+][H2A-]

[H3A]

H2A- H+ + HA2- Ka2 =[H+][HA2-]

[H2A-]

HA2- H+ + A3- Ka3 =[HA2-]

[H+][A3-]

Note: Ka3 < Ka2 < Ka1 Why?

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Problem Solving for Polyprotic Acids

1. Tartaric Acid, H2C4H4O6 is a diprotic acid.

What is the pH of a 0.10 M solution? What

is the concentration of C4H4O62-?

Ka1 = 9.2 x 10-4 and Ka2 = 4.3 x 10-5

2. What is the pH of a 0.10 M ascorbic acid

(H2Asc) solution?

Ka1 = 7.9 x 10-5 and Ka2 = 1.6 x 10-12

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Weak Base Equilibria

Relationships worth knowing:

Kw = KaKb for weak acid-base conjugate pairs.

Write equilibrium expressions for each of the following

reactions and prove the above statement.

HB H+ + B-

B- + H2O HB + OH-

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Weak bases include amines and amides such as

the following molecule.

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Conjugate Base of a Weak Acid

The conjugate base (anion) of a weak acid can

react with water. Write a general reaction and

the equilibrium expression for this process.

Would you use Ka or Kb?

If given Ka how would you determine Kb?

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Problem Solving for Weak Base

1. Determine Kb of a 6.0 M weak base having a

pH of 12.02.

2. Dissolved aniline, C6H5NH2, is used in

perfumes. What is the pH of a 0.035 M

solution?

Kb = 4.2 x 10-10

A- + H2O HA + OH-

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Acid-Base Properties of Salt Solutions

Hydrolysis of an ion with water can produce an acidic or basic solution.

Examples: Determine if the aqueous solutions below are acidic, basic, or neutral.

Ammonium chloride

Ammonium cyanide

Iron(III) nitrate

Sodium chloride

Ammonium hypochlorite

Aluminum chloride

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Problem Solving

1. What is the pH of a 0.10 M sodium acetate

solution? pKa = 4.74

2. If 3.00 g of KClO are added to 100 mL of

water, what is the pH of the solution.

Ka = 2.9 x 10-8