Chapter 12 12-5 Parabolas. Objectives Write the standard equation of a parabola and its axis of...
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Transcript of Chapter 12 12-5 Parabolas. Objectives Write the standard equation of a parabola and its axis of...
![Page 1: Chapter 12 12-5 Parabolas. Objectives Write the standard equation of a parabola and its axis of symmetry. Graph a parabola and identify its focus, directrix,](https://reader035.fdocuments.in/reader035/viewer/2022062300/56649dab5503460f94a996a7/html5/thumbnails/1.jpg)
Chapter 12 12-5 Parabolas
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Objectives Write the standard equation of a parabola
and its axis of symmetry.
Graph a parabola and identify its focus, directrix, and axis of symmetry.
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parabolas In Chapter 5, you learned that the graph
of a quadratic function is a parabola. Because a parabola is a conic section, it can also be defined in terms of distance.
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Parabolas A parabola is the set of all points P(x, y)
in a plane that are an equal distance from both a fixed point, the focus, and a fixed line, the directrix. A parabola has a axis of symmetry perpendicular to its directrix and that passes through its vertex. The vertex of a parabola is the midpoint of the perpendicular segment connecting the focus and the directrix.
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Parabola
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Example 1: Using the Distance Formula to Write the Equation of a Parabola
Use the Distance Formula to find the equation of a parabola with focus F(2, 4) and directrix y = –4.
Sol. PF = PD Distance Formula.
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solutionSubstitute (2, 4) for (x1, y1) and (x, –4) for (x2, y2).
Simplify.
(x – 2)2 + (y – 4)2 = (y + 4)2 Square both sides.
(x – 2)2 + y2 – 8y + 16 = y2 + 8y + 16
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solution (x – 2)2 – 8y = 8y
Subtract y2 and 16 from both sides.
(x – 2)2 = 16y Add 8y to both sides.
Solve for y
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Check It Out! Example 1
Use the Distance Formula to find the equation of a parabola with focus F(0, 4) and directrix y = –4.
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Parabolas Previously, you have graphed parabolas
with vertical axes of symmetry that open upward or downward. Parabolas may also have horizontal axes of symmetry and may open to the left or right.
The equations of parabolas use the parameter p. The |p| gives the distance from the vertex to both the focus and the directrix.
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Standard form for the equation
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Example 2A: Writing Equations of Parabolas
Write the equation in standard form for the parabola.
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solution Step 1 Because the axis of symmetry
is vertical and the parabola opens downward, the equation is in the form
Step 2 The distance from the focus (0, –5) to the vertex (0, 0), is 5, so p = –5 and 4p = –20.
y = 1/4p x2 with p < 0.
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solution Step 3 The equation of the parabola is
y = – 1/20 x2
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Example Write the equation in standard form
for the parabola. vertex (0, 0), directrix x = –6 Solution: Step 1 Because the directrix is a
vertical line, the equation is in the form . .
The vertex is to the right of the directrix, so the graph will open to the right.
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solution Step 2 Because the directrix is x = –6,
p = 6 and 4p = 24. Step 3 The equation of the parabola is
x = 1/24 y2
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Check It Out! Example 2a
Write the equation in standard form for the parabola.
vertex (0, 0), directrix x = 1.25
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Parabolas The vertex of a parabola may not
always be the origin. Adding or subtracting a value from x or y translates the graph of a parabola. Also notice that the values of p stretch or compress the graph.
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Standard form
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Example 3: Graphing Parabolas
Find the vertex, value of p, axis of symmetry, focus, and directrix of the parabola y + 3 = 1/8 (x – 2)2.Then graph.
Solution: Step 1 The vertex is (2, –3). Step 2 1/4p=1/8 , so 4p = 8 and p =
2.
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solution Step 3 The graph has a vertical axis of
symmetry, with equation x = 2, and opens upward.
Step 4 The focus is (2, –3 + 2), or (2, –1).
Step 5 The directrix is a horizontal line y = –3 – 2, or y = –5.
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solution
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Check it-out Example Find the vertex, value of p, axis of
symmetry, focus, and directrix of the parabola. Then graph.
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Parabolas Light or sound waves collected by a
parabola will be reflected by the curve through the focus of the parabola, as shown in the figure. Waves emitted from the focus will be reflected out parallel to the axis of symmetry of a parabola. This property is used in communications technology.
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Example 4: Using the Equation of a Parabola
The cross section of a larger parabolic microphone can be modeled by the equation What is the length of
the feedhorn? Solution:
x = y2. 1
132
The equation for the cross section is in the form
x = y2, 1 4p
so 4p = 132 and p = 33. The focus
should be 33 inches from the vertex of the cross section. Therefore, the feedhorn should be 33 inches long.
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Student Guided Practice Do problems 2-8 in your book page 849
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Homework Do problems 14-21 in your book page
849
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Closure Today we learned about parabolas Next class we are going to learn
Identifying conic sections