Chapter 11 Rotational Dynamics and Static Equilibrium
-
Upload
bernadine-wolf -
Category
Documents
-
view
80 -
download
4
description
Transcript of Chapter 11 Rotational Dynamics and Static Equilibrium
![Page 1: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/1.jpg)
Chapter 11 Rotational Dynamics and
Static Equilibrium
![Page 2: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/2.jpg)
Chapter 11: Rotational Dynamics and Static Equilibrium
Torque: The ability of a force to rotate a body
about some axis. rF Note: F r
The torque is larger if the force is applied farther from the axis of rotation.
![Page 3: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/3.jpg)
By convention, the sign of torque is:
is negative clockwise (cw)
is positive counter-clockwise (ccw)
![Page 4: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/4.jpg)
General Definition of TorqueOnly the component of the force that is perpendicular to the radius causes a torque.
= r(Fsin)
Equivalently, only the perpendicular distance between the line of force and the axis of rotation, known as the moment arm r, can be used to calculate the torque.
= rF = (rsin)F
F
Fsin
![Page 5: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/5.jpg)
Each force that acts on an object may cause a torque.F1
When discussing torques, we must identify a pivot point (or axis of rotation).
In this figure, the three forces have equal magnitude.
• Which forces cause a torque?
• Which force causes the biggest magnitude torque?
• Which forces, if any, causes a positive torque?
r1r2
F2
F3
pivot point
The net torque about a point O is the sum of all torques about O:
![Page 6: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/6.jpg)
A person holds a 1.42 N baseball in his hand, a distance of 2L = 34 cm from the elbow joint, as shown in the figure. The biceps, attached at a distance of d = 2.75 cm from the elbow, exert an upward force of 12.8 N on the forearm. Consider the forearm and hand to be a uniform rod with a mass of 1.39 kg.
(a) Calculate the magnitude of the net torque acting on the forearm and hand. Use the elbow joint as the axis of rotation. [2.44 N.m]
(b) If the net torque obtained in part (a) is nonzero, in which direction will the forearm and hand rotate?[clockwise]
HW 11 problem # 1
![Page 7: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/7.jpg)
Moment of InertiaRecall that mass (inertia) is an object’s resistance to
acceleration. Similarly an object’s resistance to rotation (angular acceleration) is known as moment of inertia. For a point mass m:
I = mr2
I = moment of inertiar = distance from the axis of rotationFor an extended object:
I =miri2
Mass near the axis of rotation resists rotation less than mass far from the axis of rotation.
![Page 8: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/8.jpg)
Solid Sphere
Spherical Shell
Hoop orCylindrical Shell
Solid Cylinderor Thin Disk
Thin Rod or Bar
Thin Rod about its end
![Page 9: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/9.jpg)
For circular motion, the distance (arc length) s, the radius r, and the angle are related by:
r
s
DEGRAD 180
Note that is measured in radians:
Angular Position,
> 0 for counterclockwise rotation from reference line
1 rev = 360° = 2 rad
![Page 10: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/10.jpg)
Consider a rotating disk:
t = 0
O P
r
t > 0
O
Pr s
![Page 11: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/11.jpg)
Notice that as the disk rotates, changes. We define the angular displacement, , as:
= f - i
which leads to the average angular speed av
if
ifav ttt
Angular Velocity,
![Page 12: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/12.jpg)
PeriodThe period of rotation is the time it takes to complete one revolution.
T
2 T = period
Rearranging we have2
T
What is the period of the Earth’s rotation about its own axis?
What is the angular velocity of the Earth’s rotation about its own axis?
![Page 13: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/13.jpg)
We can also define the average angular acceleration av:
and
if
ifav ttt
tt
lim0
Angular Acceleration,
The SI units of are: rad/s2 = s-2
We will skip any detailed discussion of angular acceleration, except to note that angular acceleration is the time rate of change of angular velocity
![Page 14: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/14.jpg)
Torque and Angular Acceleration
Recall Newton’s Second Law: F = ma
The net force on an object of mass m causes a (linear) acceleration a.
Similarly, the net torque on an object with moment of inertia I causes an angular acceleration .
= I
![Page 15: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/15.jpg)
HW11 - Problem
When a ceiling fan rotating with an angular speed of 2.15 rad/s is turned off, a frictional torque of 0.241 N m slows it to a stop in 6.25 s. What is the moment of inertia of the
fan? [0.701] kg m2
![Page 16: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/16.jpg)
Consider the wheel shown below. Two forces of equal magnitude are acting on the wheel. Will the wheel remain at rest?
The net force is zero, so there will be no linear acceleration.
Zero Torque and Static Equilibrium
However, the sum of the torques is not zero, so there will be an angular acceleration.
The wheel is not in static equilibrium.
F1
F2
![Page 17: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/17.jpg)
Conditions for Static Equilibrium
For true static equilibrium, two conditions must be satisfied:
For an object in equilibrium, the axis of rotation is arbitrary (But all torques must be evaluated about a common axis).
0
0
F 0
0
y
x
F
F
![Page 18: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/18.jpg)
Angular Momentum
For linear momentum:
p = mv
For rotational motion, we define an angular momentum:
L = I
The SI units of angular momentum are kg·m2/s
![Page 19: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/19.jpg)
Angular Momentum - Problem
A 0.013 kg record with a radius of 15 cm rotates with an angular speed of 29 rpm. Find the angular momentum of
the record. [4.44E-4] kg m2/s
![Page 20: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/20.jpg)
Kinetic energy of rotation
What is the kinetic energy of a mass m traveling at speed v in a circle of radius r?K = (1/2) m v2 = (1/2) mr2 (v/r) 2 = (1/2) I 2
Kinetic energy of rotation = (1/2) I 2
This is not a new form of energy, just a re-labeling (or alternate formula) for kinetic energy.
![Page 21: Chapter 11 Rotational Dynamics and Static Equilibrium](https://reader033.fdocuments.in/reader033/viewer/2022061520/568134c0550346895d9be439/html5/thumbnails/21.jpg)
Calculate the rotational kinetic energy of the Earth as it (a) orbits the sun (b) rotates about its axis.
Mass of Earth = 5.98E24 kgRadius of Earth (ave) = 6.38E6 m
Average Earth-Sun distance = 1.50E11 m
Rotational Kinetic Energy - Problem