Chapter 1 Introduction - URI Department of Chemistry 01 notes F12.pdf · Combination of 2 or more...

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1 Chapter 1 Introduction

Transcript of Chapter 1 Introduction - URI Department of Chemistry 01 notes F12.pdf · Combination of 2 or more...

Page 1: Chapter 1 Introduction - URI Department of Chemistry 01 notes F12.pdf · Combination of 2 or more substances . ... Base Units of Measurement ... volume = m . V . Density . SI derived

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Chapter 1 Introduction

Page 2: Chapter 1 Introduction - URI Department of Chemistry 01 notes F12.pdf · Combination of 2 or more substances . ... Base Units of Measurement ... volume = m . V . Density . SI derived

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Why Learn Chemistry? To better understand the environment around us Medicine Understanding disease Develop new drugs

Environmental Science Ozone layer Global warming Acid rain

Agriculture Bioengineered food Fertilizers

Criminal Justice Forensics

Material Science Better built houses More efficient cars Plastics, composites

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Learning the Language

Composition Mass percent of molecules present Molecular ratios within material Stoichiometry

Structure Molecular arrangement Phase: s, l, g

Properties Specific to a particular material (boiling point, color, odor, reactivity) Used for identification

Chemistry defines materials and predicts molecular reactions based on 3 concepts

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The Scientific Method Series of steps that explain an observation Define the

problem

Perform experiments Develop hypothesis

Perform Experiments

Support or refute hypothesis

Develop scientific laws

Develop theory

A balloon pops if overheated

Perform experiments Gas expands when heated

Heat balloon and observe V change

Quantitatively measure ∆V vs. ∆T.

Charles’ Law: V1/T1 =V2/T2

Kinetic Molecular Theory

Molecules move faster when heated requiring more space, causing balloon to pop.

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Classifications of Matter

What is in the material you are investigating?

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Pure materials Atom: Smallest distinctive unit Molecule: 2 or more atoms together Substance: Group of identical molecules

Element: atoms identical Compound: atoms vary

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Mixtures Mixture: Combination of 2 or more substances

Homogeneous Mixture Substances stay mixed

No distinct layers Also called a “solution”

14 karat gold Mixture of gold and silver

Heterogeneous Mixture Substances separate

Distinct layers often seen Iron filings and sand

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Matter Summary

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Physical and Chemical Properties of Matter

Means of identification & separation

of substances

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Physical Properties of Matter No change to molecular composition

All changes are at the substance level eg: smashing a window, melting ice

Phase changes: solid to liquid to gas etc. Melting, freezing, boiling, etc.

ID a substance without damage Color, odor, solubility, conductivity

molecular mass, density, boiling/melting points Original compound can be recovered

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Chemical Properties of Matter All chemical reactions

Heat or light generated: Burning, explosions Decomposing:Rusting, rotting

Compositional changes to molecules Often called a chemical change Original material changed on an atomic level

Molecules of original compound no longer present Compound cannot be restored to its original form without

another chemical change

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Extensive Property: Varies on amount of matter present mass, length, volume, heat, intensity of color or odor Intensive Property: Independent of amount of matter present Temperature, boiling point, color, odor Often a calculated ratio Density (mass/vol ratio) Molar mass Specific heat Can be used to identify a material

Extensive and Intensive Properties

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Measurements

Determining how much matter is present

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Base Units of Measurement International System of Units (SI)

Memorize Chart!

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SI Base Prefixes Memorize Chart!

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16 Volume SI derived unit for volume is a cubic meter (m3)

Common unit is a “Liter (L)”

1 mL = 1 cm3 1cm

1cm

1cm

333 101100

1100

1100

11

11

11

100010001 mxcm

mxcm

mxcm

mxcmxcmxcmcmL −===

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Density: Ratio of mass to volume of a material

1 g/cm3 = 1 g/mL = 1000 kg/m3

density = mass volume = m

V

Density

SI derived unit for density is kg/m3

Intensive property Can be used to identify a material

Units of mass and volume may vary

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Handling Numbers

Math Review

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Scientific Notation Displaying very large or small numbers 1700000 → 1.7 x 106

0.0000017 → 1.7 x 10-6 2 parts: significant values & a multiplier Significant: 17 for both values Multiplier: 100000 or 0.000001 Keep all significant numbers Place decimal after 1st significant figure (1.7) Multiplier used as exponent: 10 x or 10 -x 1700000 =1.7x 106 0.0000017 =1.7x10-6 Use EXP, SCI or EE keys on calculator

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Significant Figures: Number of Digits in Final Answer

1. All non-zero digits are significant 2. Use decimal point to determine significance of zeros Between 2 numbers significant 50.002 5 Before decimal point not significant 0.502 3 Before the first digit not significant 0.0052 2 End of # after decimal significant 0.0200 3 No decimal point: can’t tell 500 ? 3. Exact numbers have unlimited number of significant figures Inherently an integer: 4 sides to a square Inherently a fraction: ½ of a pie Obtained by counting: 47 people in a class Defined quantity: 12 eggs in a dozen

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Determine the correct number of significant figures (2.45 + 0.26800) x 3.575 = 9.71685

Addition/subtraction Sigfigs based on decimal (12.45 + 9.2680 ) = 3.182 2 sigfigs after decimal 3 sigfigs overall in final answer

Multiplication/Division Use all significant digits 3.182 x 3.575 = 9.71685 3 sigfigs in final answer Addition limits sigfigs Rounding Based on number after sigfigs 9.71685 = 9.72 If < 5 Use number as written round up 6>5 If ≥ 5 Round up 1 digit

12.45XX - 9.2680 3.1820

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Accuracy – how close a measurement is to the true value Precision – how close measurements are to each other

accurate &

precise

precise but

not accurate

not accurate &

not precise

Precision and Accuracy

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Percent Error Comparison of experimental results to expected or real values Usually reported without a + or - sign % error = Deviation x 100 Real value Deviation Experimental value - real value Often reported with a + or – sign Real value: Widely accepted, often an industry standard value Average of several experiments if real value unknown

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Dimensional Analysis Algebra and canceling units

Look at question: How many kilograms of methanol will fill a 15.5 gallon fuel

tank of a car modified to run on methanol? What unit do you want to solve for: kilograms (kg)

What information do you need? Data in problem: Volume = 15.5 gallons Data to look up: Density of methanol= 0.791 g / mL Gallon to Liter conversion: 1gal= 3.785L Data to know: 1000mL = 1L 1000g = 1kg

kggalxgal

LxL

mLxg

kgxml

gkg 4.4615.15

1785.31000

10001

1791.0

1==