Chap_10_2_hw_10.pdf

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CIVL 4135 HOMEWORK SET 10 206 CIVL 4135 Anchorage and Development Length 1. The short beam shown below cantilevers from a supporting column at the left. It must carry calculated dead load of 1.0 kips/ft including its own weight, and service live load of 1.3 kips/ft. Tensile flexural reinforcement consists of two No. 11 bars at 21 inch effective depth. Assume a number 4 bar is used for stirrups and stirrups are at 4 inch spacing throughout the beam. If the material for the beam provide f y = 60,000 psi and fc = 5,000 psi, check to see if proper development length can be provided in the beam for the no. 11 bars. 20120” 24212 No. 11 3clear 29” 181.5clear

Transcript of Chap_10_2_hw_10.pdf

  • CIVL 4135HOMEWORK SET 10 206

    CIVL 4135 Anchorage and Development Length

    1. The short beam shown below cantilevers from a supporting column at the left. It must carry

    calculated dead load of 1.0 kips/ft including its own weight, and service live load of 1.3

    kips/ft. Tensile flexural reinforcement consists of twoNo. 11 bars at 21 inch effective depth.

    Assume a number 4 bar is used for stirrups and stirrups are at 4 inch spacing throughout the

    beam.

    If thematerial for the beam provide fy= 60,000 psi and fc = 5,000 psi, check to see if proper

    development length can be provided in the beam for the no. 11 bars.

    20 120

    2421

    2 No. 11

    3 clear

    2

    9

    18

    1.5 clear

  • CIVL 4135HOMEWORK SET 10 207

    CIVL 4135 Anchorage and Development Length

    2. An area of top flexural steel equal to 2.36 in2 is required to carry the negative moment in thebeam at support B. If two No. 10 bars are used as reinforcement, is sufficient embedmentlength available in the cantilever to satisfy ACI Code requirements for anchorage length?If your answer is no, what would you suggest to do to provide adequate anchorage length?

    Two No. 5 bars in the bottom of the compression zone are used to anchor and to position theNo. 3 stirrups, which have been sized to carry the shear produced by concentrated load at C.Main reinforcement has 2 in of clear cover.

    20

    15--0

    fc = 3 kipsin2

    fy = 60 ksi

    5--2

    #3 stirrups at 8 o.c.

    2

    2 clear

    2 clear

    12

    62

    pu=36 kips

    2--#10 bars

    A

    BC