ch2_brief (2)
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Economy, 6th Edition, 2005
© 2005 by McGraw-Hill, New York, N.Y All Rights Reserved2-1
Developed By:Dr. Don Smith, P.E.
Department of IndustrialEngineering
Texas A&M University
College Station, Texas
Executive Summary Version
Chapter 2Factors: How Timeand Interest Affect
Money
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LEARNING OBJECTIVES
1. F/P and P/Ffactors
2. P/A and A/Pfactors
3. Interpolate forfactor values
4. P/G and A/G
factors
5. Geometricgradient
6. Calculate i
7. Calculate n
8. Spreadsheets
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Sct 2.1 Single-Payment Factors(F/P and P/F)
Objective:Derive factors to determine the present or future
worth of a cash flow
Cash Flow Diagram – basic format
0 1 2 3 n-1 n
P0
Fn
i% / period
P0 = Fn1/(1+i)n →(P/F,i%,n) factor: Excel: =PV(i%,n,,F)
Fn = P0(1+i)n →(F/P,i%,n) factor: Excel: =FV(i%,n,,P)
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Sct 2.2 Uniform-Series: Present WorthFactor (P/A) and
Capital Recovery Factor(A/P) Cash flow profile for P/A factor
. . . .0 1 2 3 n-2 n-1 n$A per interest period
i% per interest period
Required: To find P given A
Cash flows are equal, uninterrupted and flow at the end ofeach interest period
Find P
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(P/A) Factor Derivation
Setup the following:
Multiply by to obtain a second equation…
Subtract (1) from (2) to yield…
1 2 1
1 1 1 1..
(1 ) (1 ) (1 ) (1 )n n P A
i i i i
2 3 1
1 1 1 1..
1 (1 ) (1 ) (1 ) (1 )n n
P A
i i i i i
1
(1+i)
(1)
(2)
1
1 1
1 (1 ) (1 )n
i P A
i i i
(3)
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(P/A) and (A/P) Factor Formulas
Simplify (3) to yield…
Solve (4) for A to get(A/P) factor
(1 ) 1 0
(1 )
n
n
i P A for i
i i
(4)
(1 )
(1 ) 1
n
n
i i A P i
(P/A,i%,n) factor
Excel: =PV(i%,n,A)
(A/P,i%,n) factorExcel: =PMT(i%,n,P)
(5)
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ANSI Standard Notation forInterest Factors
Standard notation has been adopted torepresent the various interest factors
Consists of two cash flow symbols, theinterest rate, and the number of time periods
General form: (X/Y,i%,n)
X represents what is unknown Y represents what is known
i and n represent input parameters; can be known orunknown depending upon the problem
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Notation - continued
Example: (F/P,6%,20) is read as:
To find F, given P when the interest rate is 6% and
the number of time periods equals 20. In problem formulation, the standard notation
is often used in place of the closed-formequivalent relations (factor)
Tables at the back of the text providetabulations of common values for i% and n
S t 2 3 Si ki F d F t d U if
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Sct 2.3 Sinking Fund Factor and UniformSeries Compound Amount Factor
(A/F and F/A)
Cash flow diagram for (A/F) factor
Start with what has already been developed1 (1 )
(1 ) (1 ) 1
n
n n
i i A F
i i
. . . .0 1 2 3 n-2 n-1 nA=? per interest period
i% per interest period
F = given
Find A, given F
(1 ) 1n
i A F
i
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(F/A) factor from (A/F)
Given:
Solve for F in terms of A to yield
(1 ) 1ni A F i
(1 ) 1ni F A
i
(A/F,i%,n) factorExcel: =PMT(i%,n,,F)
(F/A,i%,n) factor
Excel: =FV(i%,n,A)
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Sct 2.4 Interpolation in Interest Tables
When using tabulated interest tables onemight be forced to approximate a factor that isnot tabulated
Can apply linear interpolation to approximate
See Table 2-4
Factors are nonlinear functions, hence linearinterpolation will yield errors in the 2-4% range
Use a spreadsheet model to calculate the factorprecisely
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Sct 2.5 Arithmetic Gradient Factors(P/G) and (A/G)
Cash flow profile
0 1 2 3 n-1 n
A1+G
A1+2G
A1+(n-2)G
A1+(n-1)G
Find P, given gradient cash flow G
CFn = A1 ± (n-1)G
Base amount= A
1
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Gradient Example
0 1 2 3 4 5 6 7
$100$200
$300
$400
$500
$600
$700
Gradients have two components:
1. The base amount and the gradient
2. The base amount (above) = $100/time period
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Gradient Components
……..
0 1 2 3 n-2 n-1 n
Base amount = A / period
0G
1G2G
(n-3)G (n-2)G(n-1)G
Present worth point is 1 period to the left of the 0G cash flow
For present worth of the base amount, use the P/A factor (already known)
For present worth of the gradient series, use the P/G factor (to be derived)
Find P of gradient series
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Gradient Decomposition As we know, arithmetic gradients are
comprised of two components1. Gradient component
2. Base amount
When working with a cash flow containing agradient, the (P/G) factor is only for thegradient component
Apply the (P/A) factor to work on the baseamount component
P = PW(gradient) + PW(base amount)
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Derivation Summary for (P/G) Start with:
Multiply (1) by (1+i)1 to create a second equation
Subtract (1) from the second equation and simplify
Yields…
( / , , 2) 2 ( / , ,3) 3 ( / , , 4) ...
+[(n-2)G](P/F,i,n-1)+[(n-1)G](P/F,i,n)
P G P F i G P F i G P F i (1)
2
G (1 ) 1 (1 ) 1P=
i (1 ) (1 ) (1 )
n n
n n n
i n i in
i i i i i
(P/G,i,n) factor
No Excel relation exists
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Use of the (A/G) Factor
0 1 2 3 n-1 n
G
2G
(n-2)G
(n-1)G
Find A, given gradient cash flow G
CFn = (n-1)G
Equivalent A ofgradient series
A A A . . . A A
A = G(A/G,i,n)
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Sct 2.6 Geometric Gradient Series Factor
Geometric Gradient
Cash flow series that starts with a base amount A1
Increases or decreases from period to period by aconstant percentage amount
This uniform rate of change defines… A GEOMETRIC GRADIENT
Notation:g = the constant rate of change, in decimal form, by which
future amounts increase or decrease from one timeperiod to the next
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Typical Geometric Gradient
A1
A1(1+g) A1(1+g)2
. . . .
0 1 2 3 n-2 n-1 n
A1(1+g)n-1
Required: Find a factor (P/A,g%,i%,n) that will convert future
cash flows to a single present worth value at time t = 0
Given A1, i%, and g%
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Basic Derivation: Geometric Gradient2 1
1 1 1 1
1 2 3
(1 ) (1 ) (1 )...
(1 ) (1 ) (1 ) (1 )
n
g n
A A g A g A g P
i i i i
1 2 1
1 2 3
1 (1 ) (1 ) (1 )...
(1 ) (1 ) (1 ) (1 )
n
g n
g g g P A
i i i i
(1)
Subtract Eq. (2 ) from Eq. (3 ) to yield
1 11+g (1 ) 111+i (1 ) 1
n
g n
g P Ai i
Solve for Pg and simplify to yield….
Start with:
Factor out A1 out and re-write
(2)
1 2 1
1 2 3
(1+g) (1+g) 1 (1 ) (1 ) (1 )...
(1+i) (1+i) (1 ) (1 ) (1 ) (1 )
n
g n
g g g P A
i i i i
(3)
1
11
1 g i
n
g
g
i P A
i g
Multiply by (1+g)/(1+i) to obtain Eq. (3 )
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Two Forms to Consider…
1
(1 ) g
nA P i
1
1
1 1 g i
n
g
g
i P A
i g
Case: g = i Case: g = i
A1 is the starting cash flow
There is NO base amount associated with a geometric gradient
The remaining cash flows are generated from the A1 starting value
No tables available to tabulate this factor …too many combinations of i% and
g% to support tables
To use the (P/A,g%,i%,n) factor
S t 2 7 D t i ti f
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Sct 2.7 Determination ofUnknown Interest Rate
Class of problems where the interest rate, i%,is the unknown value
For simple, single payment problems (i.e., P
and F only), solving for i% given the otherparameters is not difficult
For annuity and gradient type problems,
solving for i% can be tediousTrial and error method
Apply spreadsheet models
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The IRR Spreadsheet Function
Define the total cash flow as a column ofvalues within Excel
Apply the IRR function:
=IRR(first_cell:last_cell, guess value) If the cash flow series is an A value then apply
the RATE function:
=RATE(number_years, A,P,F)
See examples 2.12 and 2.13
S t 2 8 D t i ti f
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Sct 2.8 Determination ofUnknown Number of Years
Class of problems where the number of timeperiods (years) is the unknown
In single payment type problems, solving forn is straight forward
In other types of cash flow profiles, solvingfor n requires trial and error or spreadsheet
In Excel, given A, P, and/or F, and i% values
apply:=NPER(i%,A,P,F) to return the value of n
S t 2 9 S d h t A li ti B i
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Sct 2.9 Spreadsheet Application – BasicSensitivity Analysis
Sensitivity Analysis is a process ofdetermining what input variables really matter
in a given problem formulation Sensitivity analysis aids in evaluating certain
what-If scenarios
Spreadsheet modeling is the best approach toformulate sensitivity analysis for a givenproblem
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Summary
Interest factors exist to aid in determiningeconomic equivalence of various cash flowpatterns
Notation is introduced that is appliedthroughout the remainder of the text
Introduction of important Excel spreadsheetfinancial functions to aid in evaluation ofengineering economy problems
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