Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10...

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Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2
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Transcript of Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10...

Page 1: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Ch12-1 Newton’s Law of Universal Gravitation

Chapter 12: Gravity

Fg = Gm1m2/r2 G = 6.67 x 10-11 Nm2/kg2

Page 2: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Figure 12-2Dependence of the Gravitational Force

on Separation Distance, r

Page 3: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT1: Suppose Earth had no atmosphere and a ball were fired from the top of Mt. Everest in a direction tangent to the ground. If the initial speed were high enough to cause the ball to travel in a circular trajectory around Earth, the ball’s acceleration would

A. be much less than g (because the ball doesn’t fall to the ground).

B. be approximately g.C. depend on the ball’s speed.

Page 4: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

1.5 x 1011 m

3.84 x 108 m

Not to scale!

1.5 x 1011 m

FEM

FSM

F

P12.8 (p.389)

Page 5: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT2: It is best to say that the Moon orbits the

A. Earth.

B. Sun.

Page 6: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.
Page 7: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Ch12-2 Gravitational Attraction of Spherical Bodies

Chapter 12: Gravity

Page 8: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT3: Two satellites A and B of the same mass are going around Earth in concentric orbits. The distance of satellite B from Earth’s center is twice that of satellite A. What is the ratio of the centripetal force acting on B to that acting on A? (FB/FA)

A. 2B. 1/4C. 1/2D. 1/2E. 4

Page 9: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT4: In addition to using kinematics, the big picture principle in P12.20 (p.390) will be

A. Newton’s laws.

B. conservation of energy.

C. conservation of momentum.

D. the work-kinetic energy theorem.

Page 10: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.
Page 11: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Ch12-3 Kepler’s Laws

Chapter 12: Gravity

Page 12: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Kepler’s First Law: The planets orbit the Sun in ellipses with the Sun at one of the foci.

Semi-major axis = a.

2a

2a = 2r

2a

Page 13: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Kepler’s Second Law: The orbits sweep out equal areas in equal times.

Page 14: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

greater v smaller v

L = mvr is constant. Angular momentum is conserved

because the central force of the Sun produces net = 0.

Page 15: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Kepler’s Third Law: T a3/2, where a is the semi-major axis of the ellipse. For a circle, a = r.

Page 16: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT5: In addition to using kinematics, the big picture principle in P12.28 (p.390) will be

A. Newton’s laws.

B. conservation of energy.

C. conservation of momentum.

D. the work-kinetic energy theorem.

Page 17: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT6: For P12.31 (p.390), the period depends on

A. the mass of the Earth.

B. the mass of the satellite.

C. both the mass of the Earth and the satellite.

D. neither the mass of the Earth nor the mass of

the satellite.

Page 18: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

Ch12-4 and 5 Potential Energy and Energy Conservation

Ug = -GMm/r for two masses M and m separated by r

E = K + Ug is conserved when only the gravitational force is acting because the universal gravitational force is a conservative force

Chapter 12: Gravity

Page 19: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT7: In addition to using kinematics, the big picture principle in P12.41 (p.391) will be

A. Newton’s laws.

B. conservation of energy.

C. conservation of momentum.

D. the work-kinetic energy theorem.

Page 20: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

P12.66 (p.392)

Page 21: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT8: In addition to using kinematics, the big picture principle in P12.67 (p.392) will be

A. Newton’s laws.

B. conservation of energy.

C. conservation of momentum.

D. the work-kinetic energy theorem.

Page 22: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT9:System A has masses m and m separated by r; system B has masses m and 2m separated by 2r; system C has masses 2m and 3m separated by 2r; and system D has masses 4m and 5m separated by 3r. Which system has the smallest attraction between the two masses?

A. A

B. B

C. C

D. D

Page 23: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT10:System A has masses m and m separated by r; system B has masses m and 2m separated by 2r; system C has masses 2m and 3m separated by 2r; and system D has masses 4m and 5m separated by 3r. Which system has the next smallest attraction between the two masses?

A. A

B. B

C. C

D. D

Page 24: Ch12-1 Newton’s Law of Universal Gravitation Chapter 12: Gravity F g = Gm 1 m 2 /r 2 G = 6.67 x 10 -11 Nm 2 /kg 2.

CT11:System A has masses m and m separated by r; system B has masses m and 2m separated by 2r; system C has masses 2m and 3m separated by 2r; and system D has masses 4m and 5m separated by 3r. Which system has the greatest attraction between the two masses?

A. A

B. B

C. C

D. D