Ch 9 Simple Interest Simple Discount Notes. Notes Notes are short term loans. Simple Interest Notes...
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Transcript of Ch 9 Simple Interest Simple Discount Notes. Notes Notes are short term loans. Simple Interest Notes...
![Page 1: Ch 9 Simple Interest Simple Discount Notes. Notes Notes are short term loans. Simple Interest Notes Section 1 Simple Discount Notes This section…](https://reader035.fdocuments.in/reader035/viewer/2022062305/5697c0071a28abf838cc63f0/html5/thumbnails/1.jpg)
Ch 9 Simple Interest
Simple Discount Notes
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Notes
Notes are short term loans. Simple Interest Notes
Section 1
Simple Discount Notes This section…
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$2000
Simple Interest Notes One year simple interest note @ 6.25% for
$2000. Borrower receives the face value = $2000
Interest is computed to be $125.
Borrower must pay back $2125 on the maturity date of the loan.
$2,000 $$2,125
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Simple Discount Notes One year simple discount note @ 6.25% for
$2000.
Borrower walks out with: $1,875
Interest is computed and immediately deducted (discounted) from the face value: $125
Borrower must pay back $2,000 on the maturity date of the loan.$1,875 $
$2,000
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Comparison
Simple Interest Note
Simple Discount Note
Face Value
Cost
Amount Borrowed
Maturity Value
1-year loan of $2,000 loan at 6.25%.
$2,000 $2,000
Interest: $125
I = PRT
Bank Discount: $125
B = MDT$2,000
Principle
$1,875
Proceeds
$2,125 $2,000
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Using the Terminology 1 of 2
Simple discount note of $4300. Bank Discount is $285
Face Value = __________
Proceeds = __________
Bank Discount = __________
Maturity Value = __________
$4,300
$4,300 - $285$4,015
$285
$4,300
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Using the Terminology 2 of 2
Simple discount note of $12,500. Bank discount is $750
Face Value = __________
Proceeds = __________
Bank Discount = __________
Maturity Value = __________
$12,500
$12,500 - $750$11,750
$750
$12,500
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Ch 9 Simple Discount Notes
Determine the bank discount and the proceeds.
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Bank Discount Sample Problem 1
Bank Discount = Maturity Value x Discount Rate x Time
B = MDT
Maturity Value
Discount Rate
Time (years)
B = $2000 x .06 x
B = $30
$30
90360
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Proceeds Sample Problem 1 Continued
Proceeds = Maturity Value - Bank Discount
P = M - B
P = $2000 - $30
P = $1970_____ proceeds$1970
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Bank Discount Practice Problem
Determine the bank discount:
Simple Discount Note
$800
4.5% discount rate
120 days
$______ discount
B = MDT
B = $800 x .045 x
B = $12
12
$______ proceeds
120 360
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Sample Practice Problem
Determine the proceeds:
Simple Discount Note
$800
4.5% discount rate
120 days
$12 discount
$_____ proceeds
P = M - B
P = $800 - $12
P = $788 788
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Compute Discount and Proceeds 1 of 1 Simple discount note with a face value of $14,250.
It is an 8 month note at 8%. Discount = _______ Proceeds = _______ B = MDT
P = M - B
B = 14,250 x 0.08 x = $760
P = 14,250 – 760 = $13,490
812
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Practice
Ch 9, Section 3 – Simple Discount Notes
Textbook Exercise 9.3 (pages 371 – 374)
_____ #3 – 6, 8 – 12, 14
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Ch 9 Simple Discount Notes
Computing the face value
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Finding Face Value
A person needs to borrow $5800 to pay for home improvements.
Would a simple discount note with a face value of $5800 meet their needs?
Simple Discount Note
$5800
5.75% discount rate180 days
$166.75 discount
$5633.25 proceeds
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1 – DT1 – DT
Deriving the Formula for MB =
P = M – P = M – MDTB
MDT
P = M(1 – DT)
1 – DTP = M
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Computing Face Value to Achieve Desired Proceeds
DT
PM
1
Proceeds received by the borrower.
Discount rate used by the bank (%)Time of the loan (years)
Simple Discount Note
$5800
5.75% discount rate180 days
$________ discount
$________ proceeds
360180
0575.1
5800M
69.971,5$M
$5,971.69
171.69
5800
02875.01
5800
M
97125.0
5800M
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Computing Face Value 1 of 2
#20, page 372 Lane Engineering needs $120,000 to install
computers and network. The simple discount note has a 9.5% rate and matures in 80 days.
Find the face value of the loan.
DT
PM
1
36080
095.01
000,120
M
021111.01
000,120
9788888.0
000,120 97.587,122$
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Computing Face Value 2 of 2
#26 part (a), page 373 A Malaysian electric company requires
proceeds of $720,000 and borrows from a bank in Thailand at 12% discount for 45 days.
Find the face value of the loan.
DT
PM
1
36045
12.01
000,720
M
015.01
000,720
985.0
000,720 47.964,730$
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Practice
Ch 9, Section 3 – Simple Discount Notes
Textbook Exercise 9.3 (pages 371 – 374)
_____ #20, 25, 26