Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom...

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ECE-305: Spring 2015 Carrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA [email protected] 2/2/15 Pierret, Semiconductor Device Fundamentals (SDF) pp. 74-89 carrier concentration review Fig. 2.22 from R.F. Pierret, Semiconductor Device Fundamentals Freeze out Extrinsic Intrinsic n i = N C N V e E G /2 k B T n 0 = N D + = N D p 0 = n i 2 n 0

Transcript of Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom...

Page 1: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

Lundstrom ECE 305 S15

ECE-305: Spring 2015

Carrier Action: I

Professor Mark Lundstrom Electrical and Computer Engineering

Purdue University, West Lafayette, IN USA [email protected]

2/2/15

Pierret, Semiconductor Device Fundamentals (SDF) pp. 74-89

carrier concentration review

2 Fig. 2.22 from R.F. Pierret, Semiconductor Device Fundamentals

Freeze out

Extrinsic

Intrinsic ni = NCNV e−EG /2kBT

n0 = N D+ = N D

p0 = ni2 n0

Page 2: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

key equations in equilibrium

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p0 = NVeEV −EF( ) kBT

NV = 2mp*kBT( )2π!2

⎣⎢⎢

⎦⎥⎥

3/2

n0 = NCeEF−EC( ) kBT

NC = 2

mn*kBT( )2π!2

⎣⎢⎢

⎦⎥⎥

3/2

n0 = ni eEF−Ei( ) kBT

p0 = nieEi−EF( ) kBT

n0p0 = ni2

ni = NCNV e−EG /2kBT

ni = 1.00 ×1010 cm-3

p − n + ND+ − NA

− = 0

f0 E( ) = 11+ e E−EF( ) kBT

Question: Why does np = ni2 ?

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n0 = N D+ = N D

p0 = ni2 n0

n0 = ni eEF−Ei( ) kBT

p0 = nieEi−EF( ) kBT

Page 3: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

Why is np = ni2 ?

5

E

x

EC

EV

Ei

G T( ) cm-3-s-1

G = R

R = Cnp

np = GC

= ni2

Lundstrom ECE 305 S15 6

outline

1.  Current (drift)

2.  Mobility, resistivity, etc.

Page 4: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

Lundstrom ECE 305 S15 7

outline

1.  Current (drift)

2.  Mobility, resistivity, etc.

semiconductor in equilibrium

8

uniform n-type semiconductor

Lcross-sectional

area, A

“ideal” contacts

KE =

32

kBT

υ 2 = υrms =

3kBTmn

*

KE =

12

mn* υ 2

υrms ≈ 107 cm/s

Page 5: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

current flow

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uniform n-type semiconductor

Lcross-sectional

area, A

“ideal” contacts

−V +

I

1) random walk with a small bias from left to right

2) assume that electrons “drift” to the right at an average velocity, υd

3) what is I ?

drift current and velocity

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I = −Q tt

Q = −qnAL

tt = L υd

I = nqυd An-type semiconductor

Lcross-sectional

area, A

“ideal” contacts

−V +

I

υd = −µnE x Jnx = −nqυdx A/cm2

J px = pqυdx A/cm2

x

Page 6: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

velocity and electric field

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υdn = −µnE

µn =

qτmn

*

⎝⎜⎞

⎠⎟cm2 V-s

υdp = +µ pE

µ p =

qτmp

*

⎝⎜

⎠⎟ cm2 V-s

“high-field transport” υdn

E

υdn = µn E

“low-field” or “near-equilibrium” or “linear” transport

velocity vs. field

12

from R.F. Pierret, Semiconductor Device Fundamentals, Fig. 3.4

Page 7: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

drift current

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υdn = −µnE

υdp = +µ pE

Jnx = −nqυdx A/cm2

J px = pqυdx A/cm2

Jnx = nqµnE x A/cm2

J px = pqµ pE x A/cm2

mobility vs. doping

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from R.F. Pierret, Semiconductor Device Fundamentals, Fig. 3.5 (a)

µ = qτ

m*

⎝⎜⎞

⎠⎟cm2 V-s

Page 8: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

mobility vs. temperature

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µn

increasing mobility suggests the presence of charged impurity scattering

decreasing mobility suggests the presence of lattice scattering.

µn ∝T 3/ 2

µn ∝T −3/ 2

T µ = qτ

m*

⎝⎜⎞

⎠⎟cm2 V-s

re-cap

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Jn = −nqυd A/cm2

J p = + pqυd A/cm2

υdn = −µnE

υdp = +µ pE

n-type semiconductor

L

−V +

I

υd = −µnE x

x

E = − dV

dxV/cm

E = −V

LV/cm

Page 9: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

current, conductivity, resistivity

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Jnx = nqµnE x A/cm2

J px = pqµ pE x A/cm2

Jnx =σ nE x A/cm2

σ n = nqµn units?( )

σ p = pqµ p

J px =σ pE x A/cm2

E x =

Jx = ρJx V/cm

Jx = Jnx + J px = σ n +σ p( )E x =σE x A/cm2

Jx =σE x A/cm2

ρ = 1

σ= 1σ n +σ p

= 1nqµn + pqµ p

Ω-cm

resistivity vs. doping density

18 from R.F. Pierret, Semiconductor Device Fundamentals, Fig. 3.8

ρ = 1

nqµn + pqµ p

Ω-cm

Page 10: Carrier Action: I - nanoHUBCarrierActionI_S15.pdfCarrier Action: I Professor Mark Lundstrom Electrical and Computer Engineering Purdue University, West Lafayette, IN USA lundstro@purdue.edu

resistance

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n-type semiconductor

L

−V +

I

υd = −µnE x

Jn = σ nE A/cm2

I = −AJn =σ n AE Amps

I = σ n AV

L

I = σ n

AL

⎛⎝⎜

⎞⎠⎟

V = GV =1R

V

R = ρn

LA

Lundstrom ECE 305 S15 20

outline

1.  Current (drift)

2.  Mobility, resistivity, etc.