Calculus Review. Slope Slope = rise/run = y/ x = (y 2 – y 1 )/(x 2 – x 1 ) Order of points 1...
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Transcript of Calculus Review. Slope Slope = rise/run = y/ x = (y 2 – y 1 )/(x 2 – x 1 ) Order of points 1...
Slope
• Slope = rise/run • = y/x • = (y2 – y1)/(x2 – x1)
• Order of points 1 and 2 abitrary, but keeping 1 and 2 together critical
• Points may lie in any quadrant: slope will work out
• Leibniz notation for derivative based on y/x; the derivative is written dy/dx
Derivative of a line
• y = mx + b• slope m and y axis intercept b• derivative of y = axn + b with respect to x:• dy/dx = a n x(n-1) • Because b is a constant -- think of it as bx0 -- its
derivative is 0b-1 = 0 • For a straight line, a = m and n = 1 so• dy/dx = m 1 x(0), or because x0 = 1, • dy/dx = m
Derivative of a polynomial
• In differential Calculus, we consider the slopes of curves rather than straight lines
• For polynomial y = axn + bxp + cxq + …
• derivative with respect to x is
• dy/dx = a n x(n-1) + b p x(p-1) + c q x(q-1) + …
Example
a 3 n 3 b 5 p 2 c 5 q 0
0
2
4
6
8
10
12
14
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1
x
y
y = axn + bxp + cxq + …
-5
0
5
10
15
20
25
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1
x
y
dy/dx = a n x(n-1) + b p x(p-1) + c q x(q-1) + …
Derivative of Sine and Cosine
• sin(0) = 0 • period of both sine and cosine is 2• d(sin(x))/dx = cos(x) • d(cos(x))/dx = -sin(x)
-1.5
-1
-0.5
0
0.5
1
1.5
0 1 2 3 4 5 6 7
Sin(x)
Cos(x)
Partial Derivatives
• Functions of more than one variable• Example: h(x,y) = x4 + y3 + xy
1 4 7
10 13 16 19S1
S7
S13
S19
-1.5
-1
-0.5
0
0.5
1
1.5
2
2.5
3
X
Y
2.5-3
2-2.5
1.5-2
1-1.5
0.5-1
0-0.5
-0.5-0
-1--0.5
-1.5--1
Partial Derivatives
• Partial derivative of h with respect to x at a y location y0
• Notation ∂h/∂x|y=y0
• Treat ys as constants• If these constants stand alone, they drop
out of the result• If they are in multiplicative terms involving
x, they are retained as constants
Partial Derivatives
• Example: • h(x,y) = x4 + y3 + x2y+ xy • ∂h/∂x = 4x3 + 2xy + y
• ∂h/∂x|y=y0 = 4x3 + 2xy0+ y0
1 4 7
10 13 16 19
S1
S7
S13
S19
-1.5
-1
-0.5
0
0.5
1
1.5
2
2.5
3
X
Y
Earth’s Water
• Covers approximately 75% of the surface
• Volcanic emissions
http://earthobservatory.nasa.gov/Library/Water/
One estimate of global water distribution
Volume
(1000 km3)
Percent of Total Water
Percent of Fresh Water
Oceans, Seas, & Bays 1,338,000 96.5 -
Ice caps, Glaciers, & Permanent Snow
24,064 1.74 68.7
Groundwater 23,400 1.7 -
Fresh (10,530) (0.76) 30.1
Saline (12,870) (0.94) -
Soil Moisture 16.5 0.001 0.05
Ground Ice & Permafrost 300 0.022 0.86
Lakes 176.4 0.013 -
Fresh (91.0) (0.007) .26
Saline (85.4) (0.006) -
Atmosphere12.9 0.001 0.04
Swamp Water 11.47 0.0008 0.03
Rivers 2.12 0.0002 0.006
Biological Water 1.12 0.0001 0.003
Total 1,385,984 100.0 100.0
Source: Gleick, P. H., 1996: Water resources. In Encyclopedia of Climate and Weather, ed. by S. H. Schneider, Oxford University Press, New York, vol. 2, pp.817-823.http://earthobservatory.nasa.gov/Library/Water/
Fresh Water
Ice caps, Glaciers, & PermanentSnow
Groundwater
Soil Moisture
Ground Ice & Permafrost
Lakes
Atmosphere
Swamp Water
Rivers
Biological Water
Hydrologic Cycle
• Powered by energy from the sun• Evaporation 90% of atmospheric water• Transpiration 10% • Evaporation exceeds precipitation over oceans• Precipitation exceeds evaporation over
continents• All water stored in atmosphere would cover
surface to a depth of 2.5 centimeters• 1 m average annual precipitation
http://earthobservatory.nasa.gov/Library/Water/
Hydrologic Cycle
http://earthobservatory.nasa.gov/Library/Water/
In the hydrologic cycle, individual water molecules travel between the oceans, water vapor in the atmosphere, water and ice on the land, and underground water. (Image by Hailey King, NASA GSFC.)
Water (Mass) Balance
• In – Out = Change in Storage– Totally general– Usually for a particular time interval– Many ways to break up components– Different reservoirs can be considered
Water (Mass) Balance
• Principal components:– Precipitation– Evaporation– Transpiration– Runoff
• P – E – T – Ro = Change in Storage
• Units?
Ground Water (Mass) Balance
• Principal components:– Recharge– Inflow– Transpiration– Outflow
• R + Qin – T – Qout = Change in Storage
DBHydroRainfall Stations
• Approximately 600 stations
0
200000
400000
600000
800000
1000000
1200000
1400000
1600000
1800000
2000000
0 200000 400000 600000 800000 1000000 1200000
Spatial Distribution of Average Rainfall
http://sflwww.er.usgs.gov/sfrsf/rooms/hydrology/compete/obspatialmapx.jpg
Evaporation Pan
www.photolib.noaa.gov/ historic/nws/wea01170.htm
Pan Evaporation
• Pan Coefficients: 0.58 – 0.78
• Transpiration
• Potential Evapotranspiration– Thornwaite Equation
0
200000
400000
600000
800000
1000000
1200000
1400000
1600000
1800000
0 200000 400000 600000 800000 1000000 1200000
River Hydrograph
http://cires.colorado.edu/lewis/epob4030/Figures/UseandProtectionofWaters/figures/ColoradoRiverHydrograph.gif
Stream Gauging• Measure
velocity at 2/10 and 8/10 depth
• Q = v*A
• Rating curve:– Q vs. Stage
http://www.co.jefferson.wa.us/naturalresources/Images/StreamGauging.jpg
Porosity Basics
• Porosity n (or )
• Volume of pores is also the total volume – the solids volume
total
pores
V
Vn
total
solidstotal
V
VVn
Porosity Basics
• Can re-write that as:
• Then incorporate:• Solid density: s
= Msolids/Vsolids
• Bulk density: b
= Msolids/Vtotal • bs = Vsolids/Vtotal
total
solidstotal
V
VVn
total
solids
V
Vn 1
s
bn
1
Cubic Packings and Porosity
http://members.tripod.com/~EppE/images.htm
Simple Cubic Body-Centered Cubic Face-Centered Cubic n = 0.48 n = 0. 26 n = 0.26
FCC and BCC have same porosity
• Bottom line for randomly packed beads: n ≈ 0.4
http://uwp.edu/~li/geol200-01/cryschem/
Smith et al. 1929, PR 34:1271-1274
Aquifer Material Aquifer Material (Miami)(Miami)
Image provided courtesy of A. Manda, Florida International University and the United States Geological Survey.
Karst (MN)
http://course1.winona.edu/tdogwiler/websitestufftake2/SE%20Minnesota%20Karst%20Hydro%202003-11-22%2013-23-14%20014.JPG
Ground Water Flow
• Pressure and pressure head
• Elevation head
• Total head
• Head gradient
• Discharge
• Darcy’s Law (hydraulic conductivity)
• Kozeny-Carman Equation
Pressure
• Pressure is force per unit area• Newton: F = ma
– Fforce (‘Newtons’ N or kg ms-2)– m mass (kg)– a acceleration (ms-2)
• P = F/Area (Nm-2 or kg ms-2m-2 =
kg s-2m-1 = Pa)
Pressure and Pressure Head
• Pressure relative to atmospheric, so P = 0 at water table
• P = ghp
– density– g gravity
– hp depth
P = 0 (= Patm)
Pre
ssur
e H
ead
(incr
ease
s w
ith d
epth
bel
ow s
urfa
ce)
Pressure Head
Ele
vati
on
Head
Ele
vatio
n H
ead
(incr
ease
s w
ith h
eigh
t ab
ove
datu
m)
Eleva
tion
Head
Ele
vati
on
Head
Elevation datum
Total Head
• For our purposes:
• Total head = Pressure head + Elevation head
• Water flows down a total head gradient
P = 0 (= Patm)
Tot
al H
ead
(con
stan
t: h
ydro
stat
ic e
quili
briu
m)
Pressure Head
Eleva
tion
Head
Ele
vati
on
Head
Elevation datum
Head Gradient
• Change in head divided by distance in porous medium over which head change occurs
• A slope
• dh/dx [unitless]
Darcy’s Law
• q = -K dh/dx– Darcy ‘velocity’
• Q = K dh/dx A– where K is the hydraulic
conductivity and A is the cross-sectional flow area
• Transmissivity T = Kb– b = aquifer thickness
• Q = T dh/dx L– L = width of flow field
www.ngwa.org/ ngwef/darcy.html
1803 - 1858
More on gradients1 2 3 4 5 6 7 8 9 10 11
2.445659 2.445659 2.937225 3.61747 4.380528 5.182307 5.999944 6.817582 7.619361 8.382418 9.062663 9.554228 9.5542283.399753 3.399754 3.685772 4.152128 4.722335 5.348756 5.99989 6.651023 7.277444 7.847651 8.314006 8.600023 8.6000234.067833 4.067834 4.253985 4.582937 5.007931 5.490497 5.999838 6.509179 6.991744 7.416737 7.745689 7.931838 7.9318384.549766 4.549768 4.679399 4.917709 5.235958 5.605464 5.999789 6.394115 6.76362 7.081868 7.320177 7.449806 7.4498064.902074 4.902077 4.99614 5.172544 5.412733 5.695616 5.999745 6.303874 6.586756 6.826944 7.003347 7.097408 7.0974085.160327 5.160329 5.230543 5.363601 5.546819 5.764526 5.999705 6.234885 6.452591 6.635808 6.768864 6.839075 6.8390755.348374 5.348377 5.402107 5.504502 5.646422 5.815968 5.999672 6.183375 6.35292 6.494838 6.597232 6.650959 6.6509595.482701 5.482704 5.52501 5.605886 5.718404 5.853259 5.999644 6.146028 6.280883 6.393399 6.474273 6.516576 6.5165765.574732 5.574736 5.609349 5.675635 5.768053 5.879029 5.999623 6.120216 6.231191 6.323607 6.389891 6.424502 6.424502
5.63216 5.632163 5.662024 5.719259 5.799151 5.895187 5.999608 6.10403 6.200064 6.279955 6.337188 6.367045 6.3670455.659738 5.659741 5.68733 5.740232 5.814114 5.902965 5.999601 6.096237 6.185087 6.258968 6.311867 6.339453 6.339453
5.659741 5.68733 5.740232 5.814114 5.902965 5.999601 6.096237 6.185087 6.258968 6.311867 6.339453 6.339453
1 2 3 4 5 6 7 8 9 10 11
S1
S2
S3
S4
S5
S6
S7
S8
S9
S10
S11
S12
10.5-11
10-10.5
9.5-10
9-9.5
8.5-9
8-8.5
7.5-8
7-7.5
6.5-7
6-6.5
5.5-6
5-5.5
4.5-5
4-4.5
3.5-4
3-3.5
2.5-3
2-2.5
1.5-2
More on gradients
• Three point problems:– (2 equal heads)
h = 10m
h = 10m
h = 9m
400 m
412 m
100 m
CD • Gradient = (10m-9m)/CD
• CD?– Scale from map– Compute
More on gradients
• Three point problems:– (3 unequal heads)
h = 10m
h = 11m
h = 9m
400 m
412 m
100 m
CD • Gradient = (10m-9m)/CD
• CD?– Scale from map– Compute
Best guess for h = 10m
Layered media (horizontal conductivity)
M
ii
M
ihii
h
b
KbK
1
1
Q1
Q2
Q3
Q4
Q = Q1 + Q2 + Q3 + Q4
K1
K2
b1
b2
Flow
Layered media(vertical conductivity)
M
ihii
M
ii
v
Kb
bK
1
1
/
Controls flow
Q1
Q2
Q3
Q4
Q ≈ Q1 ≈ Q2 ≈ Q3 ≈ Q4
R1
R2
R3
R4
R = R1 + R2 + R3 + R4
K1
K2
b1
b2
Flow
The overall resistance is controlled by the largest resistance: The hydraulic resistance is b/K
Aquifers
• Lithologic unit or collection of units capable of yielding water to wells
• Confined aquifer bounded by confining beds
• Unconfined or water table aquifer bounded by water table
• Perched aquifers
LeakanceLeakage coefficient, resistance (inverse)
• Leakance
• From below:
• From above:
d
k
1
11
i
iiiv d
khhq
1
11
i
iiiv d
khhq
Boundary Conditions
• Constant head: h = constant
• Constant flux: dh/dx = constant– If dh/dx = 0 then no flow– Otherwise constant flow
Poisson Equation
• Add/remove water from system so that inflow and outflow are different
• R can be recharge, ET, well pumping, etc.• R can be a function of space• Units of R: L T-1
x y
qx|x qx|x+xb
R
x y
qx|x qx|x+x
x yx yx y
qx|x qx|x+xb
R
Derivation of Poisson Equation
x y
qx|x qx|x+xb
R
x y
qx|x qx|x+x
x yx yx y
qx|x qx|x+xb
R(qx|x- qx|x+x)byρt + Rxyρt =0
x
hKq
xRbx
hK
x
hK
xxx
T
R
x
xh
xh
xxx
T
R
x
h
2
2
General Analytical Solution of 1-D Poisson Equation
AxT
R
x
h
xAxT
Rx
x
h
BAxxT
Rh 2
2
T
R
x
h
2
2
xT
Rx
x
h2
2
BAxxT
Rh 2
2
Water balance
• Qin + Rxy – Qout = 0• qin by + Rxy – qout by = 0• -K dh/dx|in by + Rxy – -K dh/dx|out by = 0• -T dh/dx|in y + Rxy – -T dh/dx|out y = 0• -T dh/dx|in + Rx +T dh/dx|out = 0
BAxxT
Rh 2
2
x y
qx|x qx|x+xb
R
x y
qx|x qx|x+x
x yx yx y
qx|x qx|x+xb
R