CALCULUS CHAPTER 6 NOTES SECTION 6-1 (Day 1...

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CALCULUS CHAPTER 6 NOTES SECTION 6-1 (Day 1) Indefinite Integrals Indefinite Integrals: If F is the antiderivative of f: ∫ () = + - C is called Some key antiderivatives: ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = ∫ = Key Reminder: REMEMBER TO BRING ALL CONSTANTS AND NEGATIVES

Transcript of CALCULUS CHAPTER 6 NOTES SECTION 6-1 (Day 1...

Page 1: CALCULUS CHAPTER 6 NOTES SECTION 6-1 (Day 1 ...mrbashore.weebly.com/.../calculus_chapter_6_notes.pdfCALCULUS CHAPTER 6 NOTES SECTION 6-1 (Day 3) Slope Fields SLOPE FIELDS: Definition:

CALCULUS CHAPTER 6 NOTES

SECTION 6-1 (Day 1) Indefinite Integrals

Indefinite Integrals: If F is the antiderivative of f:

∫ 𝒇(𝒙)𝒅𝒙 = +

- C is called

Some key antiderivatives:

∫ 𝒙𝒏 = βˆ«π’…π’™

𝒙=

∫ 𝒆𝒙 = ∫ π’†π’Œπ’™ =

∫ π’”π’Šπ’ 𝒙 𝒅𝒙 = ∫ π’”π’Šπ’ π’Œπ’™ 𝒅𝒙 =

∫ 𝒄𝒐𝒔 𝒙 𝒅𝒙 = ∫ 𝒄𝒐𝒔 π’Œπ’™ 𝒅𝒙 =

∫ π’”π’†π’„πŸ 𝒙 𝒅𝒙 = ∫ π’„π’”π’„πŸ 𝒙 𝒅𝒙 =

∫ 𝒔𝒆𝒄 𝒙 𝒕𝒂𝒏 𝒙 𝒅𝒙 = ∫ 𝒄𝒔𝒄 𝒙 𝒄𝒕𝒏 𝒙 𝒅𝒙 =

Key Reminder:

REMEMBER TO BRING ALL CONSTANTS AND NEGATIVES

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Examples:

∫(πŸ‘ 𝒄𝒐𝒔 𝒙 βˆ’ 𝒄𝒐𝒔 πŸ‘π’™) 𝒅𝒙 =

∫(𝟏

𝒙 βˆ’ 𝟐+ π’”π’Šπ’ πŸ“π’™ βˆ’ π’†βˆ’πŸπ’™) 𝒅𝒙 =

∫ 𝒄𝒐𝒔 𝟐 𝒙 𝒅𝒙 =

ASSIGNMENT: Page 312 #3 – 6, 9, 10, 13, 15, 17, 19, 22,

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CALCULUS CHAPTER 6 NOTES

SECTION 6-1 (Day 2) Solving Differential Equations

Recall what the differential form is of an equation:

π’…π’š

𝒅𝒙= πŸ’π’™πŸ βˆ’ π’”π’Šπ’ πŸπ’™ +

𝟏

𝒙

Initial Conditions – when a point is given that lies

Example: Solve this differential equation:

π’…π’š = (π’™βˆ’πŸ

πŸ‘β„ ) 𝒅𝒙

Given the initial condition: y(-1) = -5, find the original equation.

Example: Given 𝒂 = π’”π’Šπ’ 𝜽, find s(t) when v(0) = 0 and s(0) = -3.

ASSIGNMENT: Page 313 #25 - 27, 29, 31 – 34, 36, 41, 42

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CALCULUS CHAPTER 6 NOTES

SECTION 6-1 (Day 3) Slope Fields

SLOPE FIELDS:

Definition: A Slope Field is plot of short line segment with slopes f(x, y) such that:

π’…π’š

𝒅𝒙= 𝒇(𝒙, π’š)

This is what a slope field looks like.

Sketch the possible solution to slope field given f(0) = 2.

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On the axis below, sketch the slope field of the following differential equation:

π’…π’š

𝒅𝒙=

𝒙

π’š

Now, solve the possible differential equation by separation of variables.

ASSIGNMENT: SLOPE FIELDS HANDOUT #1 – 16

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CALCULUS CHAPTER 6 NOTES

SECTION 6-2 (Day 1) Substitution Method

Substitution Method -

Examples:

∫(πŸπ’™ + πŸ‘)πŸ• 𝒅𝒙 =

∫ πŸ”βˆšπŸ‘π’™ βˆ’ 𝟏 𝒅𝒙 =

βˆ«π’…π’™

(πŸ“ βˆ’ 𝒙)πŸ‘=

βˆ«π’π’ 𝒙

𝒙 𝒅𝒙 =

REMINDERS:

1. All Constants

2. No Variables brought out

3. Never bring any variables (x’s) over to the du

ASSIGNMENT: Page 321 – 322 #2 – 4, 6, 8, 9, 13, 17, 24

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CALCULUS CHAPTER 6 NOTES

SECTION 6-2 (Day 2) Substitution w/ Trig Functions

Examples:

∫ πŸ•π’”π’Šπ’πŸ” 𝒙 𝒄𝒐𝒔 𝒙 𝒅𝒙 =

∫ π’•π’‚π’πŸ‘

π…πŸ’β„

𝟎

𝒙 π’”π’†π’„πŸπ’™ 𝒅𝒙 =

Making a U-Substitution:

Example:

∫ π’„π’π’”βˆ’πŸ‘

π…πŸ”β„

𝟎

𝟐𝜽 π’”π’Šπ’ 𝟐𝜽 π’…πœ½ =

ASSIGNMENT: Page 321 – 322 #11, 14, 16, 18, 19, 21, 22, 34, 36, 37

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CALCULUS CHAPTER 6 NOTES

SECTION 6-2 (Day 3) Separating Variables

Recall Solving a Differential Equation:

π’…π’š

𝒅𝒙= (π’š + πŸ“)(𝒙 + 𝟐)

1. Separate

2. Integrate

3. Add

4. Solve

5. Find C (If possible)

Solve the differential equation below by separating variables and find C given the initial value given by y(0) = 1.

π’…π’š

𝒅𝒙= (𝒄𝒐𝒔 𝒙)π’†π’š+π’”π’Šπ’ 𝒙

ASSIGNMENT: Page 322 #42, 43, 44

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CALCULUS CHAPTER 6 NOTES

SECTION 6-3 Integration by Parts

Integration by Parts is derived by integrating the Product Rule.

When to Use:

Evaluate:

∫ 𝒙 𝒄𝒐𝒔 𝒙 𝒅𝒙

Choose: Derivative Antiderivative

Multiple Integration by Parts: (Called

∫ π’™πŸπ’†βˆ’π’™ 𝒅𝒙 =

Choose: Derivative Antiderivative

ASSIGNMENT: Page 328 # 2, 15, 16, 19

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CALCULUS CHAPTER 6 NOTE

SECTION 6-4 Exponential Growth and Decay

Recall the equation used to calculate an amount compounded continuously:

Substituting: y for A; and y0 for P:

The derivative of this equation with respect to t is:

π’…π’š

𝒅𝒕= π’Œ βˆ™ π’š

So, anytime you see this equation, its antiderivative is:

Also, recall calculating the amount compounded using a fixed rate:

𝑨 = ( +

)

Example: Suppose you deposit $1200 in an account that pays 4% annual interest. How much will you have 6 years later if the interest is:

a.) Compounded Continuously:

b.) Compounded Quarterly:

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Radioactive Decay (Half-Life)

The half-life of a certain element is 25 days. If 100 grams of the substance is present

initially, use π’š = π’šπŸŽ π’†π’Œπ’• (where t is measured in days) law of exponential change formula to find the following:

a. Find the exact value of k.

b. How much of the substance remains after 42 days.

c. When will there only be 20 grams remaining?

ASSIGNMENT: Page 338 #1-4, 9, 12, 13, 25

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CALCULUS CHAPTER 6 ASSIGNMENT SHEET

SECTION 6-1 (Day 1) Indefinite Integrals

ASSIGNMENT: Page 312 #3 – 6, 9, 10, 13, 15, 17, 19, 22

SECTION 6-1 (Day 2) Solving Differential Equations

ASSIGNMENT: Page 313 #27, 29, 31 – 34, 36, 41, 42

SECTION 6-1 (Day 3) Slope Fields

ASSIGNMENT: Slope Fields Handout #1-16

SECTION 6-2 (Day 1) Substitution Method

ASSIGNMENT: Page 321 – 322 #2 – 4, 6, 8, 9, 13, 17, 24

SECTION 6-2 (Day 2) Substitution w/ Trig Functions

ASSIGNMENT: Page 321 – 322 #11, 14, 16, 18, 19, 21, 22, 34, 36, 37

SECTION 6-2 (Day 3) Separating Variables

ASSIGNMENT: Page 322 #42, 43, 44

SECTION 6-3 Integration by Parts

ASSIGNMENT: Page 328 # 2, 15, 16, 19

SECTION 6-4 Exponential Growth and Decay

ASSIGNMENT: Page 338 #1-4, 9, 12, 13, 25

CHAPTER SIX REVIEW SHEET

CHAPTER SIX REVIEW SHEET

CHAPTER SIX TEST