DataUsing flow and pressure data shown in the above flow sheet,at figure (1)

Required prove that flow rates in the following flow sheets are the right ones to flow

Solution

At Figure (1) Hd= Ht +HsNO data is available about suction head ,so assume Hd= HtHd ,ft = 59.97Take the average pressure drop for valvesP,psi = 2.1225 Calculate the pressure drop through Ex & valves for one branchP,psi = 8.6035Drop head,ft 18.9233 This means that pressure gradient is (8.6035/18.92335) = 0.45465 psi/ft

which is wrong as it equals (20.43-20) = 0.43 psi/ftPressure gradient, ps 0.43Drop head,ft 20.008

calculate head loss through tubingHf,ft = 39.962Hf,psi = 17.184Q, gpm 400 Hf = K Q^2k , psi/gpm^2 0.0001074

At Figure (2)Averag pressure drop through valves , psi= 7.859Total pressure drop through Ex, valves,psi 13.153drop head ,ft = 30.588Hd ,ft = 63.01Hf ,ft 32.422Hf, psi 13.941 Hf = k*Q^2calculated Q ,gpm 360.3Given Q, gpm 360.0Error % 0.081 %

At Figure (3)average pressure drop through valves ,psi 18.9275Total pressure drop through Ex& valves,psi 21.6815Drop head ,ft 50.422Hd .ft 67.39Hf ,ft 16.968Hf, psi 7.296calculated Q ,gpm 260.646Given Q, gpm 260.0 Error % 0.248 %

At Figure (4)

Average drop pressure through valves ,psi 0.5815Total pressure drop through Ex& valves ,psi 7.0625Drop head ,ft 16.424Hd ,ft 56.41Hf ,ft 39.986Hf, psi 17.194calculated Q ,gpm 400.119Given Q, gpm 400.0 Error % 0.030 %

At Figure (5)Total Q, gpm 220Hf in tubing, psi 5.198TH, ft 13.770TH, psi 5.921Given pressure drop each valve, psi 0Pressure drop through each H.E, psi 0.723

Figure (1)

This means that pressure gradient is (8.6035/18.92335) = 0.45465 psi/ft which is wrong as it equals (20.43-20) = 0.43 psi/ft

Figure (2)

Figure (3)

Figure (4)

Figure (5)

Sheet1