C++ CODES PART#03

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C++ CODES PART#03 1 COPY RIGHT@ ENGR.SABA MUGHAL FROM COMPUTER SYSTEMS DEPARTMENT

description

C++ CODES PART#03. SETW AND IOMANIP.H. # include < constream.h > # include< iomanip.h > void main() { clrscr (); long pop1=2425785, pop2=47, pop3=9761; cout

Transcript of C++ CODES PART#03

Page 1: C++ CODES PART#03

C++ CODES

PART#03

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SETW AND IOMANIP.H# include <constream.h># include<iomanip.h>void main(){clrscr();long pop1=2425785, pop2=47, pop3=9761;cout<<setw(9)<<"LOCATION"<<setw(12)<<

"POPULATION"<<endl

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CONTINUE…

<<setw(9)<<"Hyderabad"<<setw(12)<<pop1<<endl

<<setw(9)<<"Karachi"<<setw(12)<<pop2<<endl <<setw(9)<<"Lahore"<<setw(12)<<pop3<<endl;

cout<<"\a";getche();}

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OUTPUT….

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SETW

#include<iostream.h>#include<conio.h>#include<iomanip.h>void main(){ clrscr(); cout<<setw(40)<<"ENGR.SABA

MUGHAL";5

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CONTINUE…

cout<<setw(10)<<"ITC"<<endl; cout<<setw(10)<<123; getch();}

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OUTPUT…..

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QUADRATIC EQUATION IN PROGRAM

#include<constream.h>#include<math.h>#define sqrtvoid main(void){clrscr();float a,b,c,x1,x2;cout<<"Enter values for a, b& c " ;

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CONTINUE….

cin>>a>>b>>c;x1=(-b+sqrt(b*b-4*a*c))/(2*a);x1=(-b-sqrt(b*b-4*a*c))/(2*a);cout<<"The roots of Qudratic Equation are

"<<x1;cout<<"\n And\t"<<x2;getche();}

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OUTPUT….

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ENDL AND ADDING NUMBERS

#include<iostream.h>#include<conio.h>void main(){ clrscr(); int a=10; int b=a+20;

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CONTINUE….

float d=3.24; int ans=b+d; cout<<a<<endl<<b<<endl<<ans; getch();}

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OUTPUT…..

103033

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USING \t# include<constream.h>void main(){clrscr();int a=1234;int b=56;cout<<"\n"<<a<<"\t"<<b;getche();} 14

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Output……………..

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IF AND ELSE STATEMENT

#include <iostream.h>#include <conio.h>void main(){clrscr();int agep1,agep2;cout<<"Input Age of first person";cin>>agep1;

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CONTINUE….

cout<<"Input Age of 2nd person";cin>>agep2;clrscr(); if(agep1>agep2) { cout<<"First Person in Elder "; cout<<(agep1-agep2)<<" Years"; }

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CONTINUE….

else { cout<<"2nd Person is Elder"; cout<<(agep2-agep1)<<" Years"; }getch();}

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OUTPUT….

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FIBONACCI SERIES#include<iostream.h>#include<conio.h>void main(){ clrscr(); int a=1,b=1,ans=0; cout<<a<<" "<<b<<" "; for (int i=1;i<=10;i++)

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CONTINUE….

{ //int a=1,ans=0; //cout<<a<<" "; ans=a+b; cout<<ans<<" "; a=b; b=ans; } getche();}

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OUTPUT…

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IF/ELSE STATEMENT#include<iostream.h>#include<conio.h>void main(){ clrscr(); int m1,m2,m3,m4,m5; float perc,tot; cin>>m1>>m2>>m3>>m4>>m5;

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CONTINUE….

tot=m1+m2+m3+m4+m5; perc=tot/550*100; if (perc>=90 && perc<=100) { cout<<"A1 Grade";cout<<'\t'<<perc;} else if(perc<90 && perc>=80){ cout<<"A grade";cout<<'\t'<<perc;}

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CONTINUE….

else if(perc<80 && perc>=70){ cout<<"B grade";cout<<'\t'<<perc;} else { cout<<"Improve";cout<<'\t'<<perc;} getch();}

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OUTPUT….

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Nice wordings

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