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Transcript of [email protected] MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 1 Bruce Mayer, PE Chabot...
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 1
Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Chabot Mathematics
§8.3 TrigIntegral
Apps
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 2
Bruce Mayer, PE Chabot College Mathematics
Review §
Any QUESTIONS About• §8. → Trigonometric
Derivatives
Any QUESTIONS About HomeWork• §8.2 → HW-11
8.2
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 3
Bruce Mayer, PE Chabot College Mathematics
§8.3 Learning Goals
Derive and use integration formulas for trigonometric functions
Apply integrals of periodic functions
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 4
Bruce Mayer, PE Chabot College Mathematics
Trigonometric AntiDerivatives
Recall the Trig Derivs
Then the Trig AntiDerivatives
uudu
duu
du
dsincoscossin
uuudu
duu
du
dsectansecsectan 2
CuduuCuduu cossinsincos
CuduuuCuduu secsectantansec2
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 5
Bruce Mayer, PE Chabot College Mathematics
Quick Example Trig AnitDeriv
FindAntiDerivative:
SOLUTION:• There is no formula available for the
immediate AntiDifferentiation of this function, but we observe that the argument of the secant function (i.e., the expression 1/t) has a derivative which is present in the integrand. – This makes SUBSTITUTION a likely choice
dt
ttR t
sec2
12
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 6
Bruce Mayer, PE Chabot College Mathematics
Quick Example Trig AnitDeriv
For the Substitution, let: Next Isolate dt
tu 1
tdt
du
dt
d
tu
dt
d
tu
111
dtt
dudu
tdt
du
tdt
du222
1
1
11
dtduttdtt
du
22
2
1
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 7
Bruce Mayer, PE Chabot College Mathematics
Quick Example Trig AnitDeriv
Substitute for t & dt then Take AntiDerivative
dutt
udt
tt 2
2
2
2
12 sec
sec
duu sec2
Cu tan
Ct 1tan
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 8
Bruce Mayer, PE Chabot College Mathematics
Example Cyclical Sales
A product is initially quite popular and then settles into cyclical demand. The demand now changes at an instantaneous rate of
• Where– R is the Sales Rate in kUnits per week– t is time in the number of weeks after Product
Introduction
112.0sin1
3
tt
tR
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 9
Bruce Mayer, PE Chabot College Mathematics
Example Cyclical Sales
Use the Model to determine How many units are sold in the second month after release (assuming 4.5-week months)
SOLUTION: To find an expression for the total sales
during the second month, find the value of the definite integral over Month-2
9
5.4
2 dttRtS
9
5.4
112.0sin1
3dtt
t
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 10
Bruce Mayer, PE Chabot College Mathematics
Example Cyclical Sales
Integrate Term-by-Term
Use TWO Separate Substitutions
9
5.4
9
5.4
9
5.4
1 12.0sin 1
3dtdttdt
t
9
5.4
112.0sin1
32 dtt
tS
dtdudt
dutu 11
dtdv
dt
dvtv
12.012.012.0
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 11
Bruce Mayer, PE Chabot College Mathematics
Example Cyclical Sale
Then
Performing the Integrations
9 5.4
9
5.4
9
5.4
12.0
sin
32 tdv
vdu
uS
t
t
t
t
5.4912.0
cosln32
9
5.4
9
5.4
t
t
t
t
vuS
5.4
12.0
12.0cos1ln32
9
5.4
9
5.4
t
t
t
t
ttS
5.45.412.0cos912.0cos12.0
115.4ln19ln3
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 12
Bruce Mayer, PE Chabot College Mathematics
Example Cyclical Sale
Doing the Calculations
So Finally
Thus During the second month, approximately 9,513 items are sold
5.48577.04713.012.0
1705.1302.232 S
513.9 29
5.4
dttRS
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 13
Bruce Mayer, PE Chabot College Mathematics
Check by MATLAB MuPADIntegrand := 3/(t+1) + sin(12*t/100) + 1
S_of_t := int(Integrand, t)
Snum := numeric::int(3/(t+1) + sin(0.12*t) + 1, t=4.5..9)
Plot the AREA under the Integrand Curve fArea := plot::Function2d(Integrand, t = 4.5..9, GridVisible = TRUE):plot(plot::Hatch(fArea), fArea, Width = 320*unit::mm, Height = 180*unit::mm,AxesTitleFont = ["sans-serif", 24], TicksLabelFont=["sans-serif", 16],LineWidth = 0.04*unit::inch,BackgroundColor = RGB::colorName([0.8, 1, 1]) )
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 14
Bruce Mayer, PE Chabot College Mathematics
Exponential·Trigonometric
Integration formulas for the Products of Exponentials and Sinusoids:
Cbubbuaba
edubue
auau
cossinsin
22
Cbubbunaba
edubue
auau
sincoscos
22
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 15
Bruce Mayer, PE Chabot College Mathematics
Example Periodic-Fund F.V.
A study suggests that investment in equity funds varies in part according to the effects of Seasonal Affect Disorder.
ttI
6cos4
A model for the continuous rate of
Investment in a particular market
Where• I(t) ≡ investment
rate in $M/year• t ≡ time in years
after the Spring of Calendar Year 2010
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 16
Bruce Mayer, PE Chabot College Mathematics
Example Periodic-Fund F.V.
For this Fund Model find the future value of the market’s investments after 10 years for a prevailing interest rate of 4%
SOLUTION: The future value of a continuous income
stream f(t) invested for T years at an annual rate-of-return, r :
Tt
t
rtrT dtetfeTFV0
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 17
Bruce Mayer, PE Chabot College Mathematics
Example Periodic-Fund F.V.
For T = 10 and r = 0.04 (4%)
10
0
04.0)10(04.0 6
cos410t
t
t dteteFV
10
0
04.004.04.0 6
cos4 dtteee tt
10
0
26
2
04.004.04.0
6sin
66cos04.0
)04.0(04.0
4
tt
eee
tt
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 18
Bruce Mayer, PE Chabot College Mathematics
Example Periodic-Fund F.V.
Continuing the Calculation
Doing the Arithmetic find:• Thus After 10 years of continuous
investment, the market will accrue about $47,682,000 (compared to the ~$38.3M of its own money that was invested).
10
6sin
610
6cos04.0
)04.0(04.0
42
62
)10(04.0)10(04.04.0
eee
0
6sin
60
6cos04.0
)04.0(04.0
42
62
)0(04.0)0(04.04.0
eee
682.47FV
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 19
Bruce Mayer, PE Chabot College Mathematics
WhiteBoard Work
Problems From §8.3• P8.3-51 →
Heating Degree Days
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 20
Bruce Mayer, PE Chabot College Mathematics
All Done for Today
Trig Anti
Derivs2
2
1. sin cos
2. cos sin
3. tan ln cos
4. cot ln sin
5. sec ln sec tan
6. csc ln csc cot
7. sec tan
8. sec tan sec
9. cot csc csc
10. csc cot
udu u c
udu u c
udu u c
udu u c
udu u u c
udu u u c
udu u c
u udu u c
u udu u c
udu u c
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 21
Bruce Mayer, PE Chabot College Mathematics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Chabot Mathematics
Appendix
–
srsrsr 22
a2 b2
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 22
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 23
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 24
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 25
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 26
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 27
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 28
Bruce Mayer, PE Chabot College Mathematics
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 29
Bruce Mayer, PE Chabot College Mathematics
Plot FunctionHoft := 25 + 22*cos(2*PI*(t-35)/365) plot(Hoft, t =0..365, GridVisible = TRUE,LineWidth = 0.04*unit::inch, Width = 320*unit::mm, Height = 180*unit::mm,AxesTitleFont = ["sans-serif", 24],TicksLabelFont=["sans-serif", 16])
[email protected] • MTH16_Lec-12_sec_8-3_TrigFcn_Integrals.pptx 30
Bruce Mayer, PE Chabot College Mathematics
Verify Average Calculation Hoft := 25 + 22*cos(2*PI*(t-35)/365)
Have := int(Hoft, t=0..90)/90
Havenum := float(Have) Plot the H(t) Function over 0→365 daysplot(Hoft, t =0..365, GridVisible = TRUE,LineWidth = 0.04*unit::inch, Width = 320*unit::mm, Height = 180*unit::mm,AxesTitleFont = ["sans-serif", 24],TicksLabelFont=["sans-serif", 16])