Biostatistics ANOVA.pptx

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ANOVA in biostatistics

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DefinitionMean corpuscular hemoglobin (MCH)

A measurement of the average weight of hemoglobin in a red blood cell.

It was the calculated value derived from the measurement of haemoglobin and the red cell count

Haemoglobin value was the amount of haemoglobin in a volume of blood while the red cell count was the number of red blood cell in a volume of bloodintroductionThe normal range for mean corpuscular haemoglobin(MCH) was MCH: 27-33 picograms (pg)/cell in adults and the mean corpuscular haemoglobin concentration(MCHC) was MCH: 33-36 g/dl in adults.High MCHIt was considered high when the value was in excess of 34 picograms

When the value was high it show that the person was in suffering from the macryotic anemia

This disorder was due to lacking of vitamin such as Folic Acid or vitamin B12.

This vitamin contain abundance of carbon and required for the body to perform the important chemical and also for the body to function at the peak level.

Those person that suffer from the macryotic anemia cant produce enough quantity of red blood cell which mean the person had more haemoglobin present than ordinary blood cell.Low MCHIt was considered low when the value was under 26 picograms

When the value was low it show that the person was in suffering from the micryotic anemia, blood loss, haemoglobinophaty and lack of acute iron

This disorder was due to lacking of iron

Those person that suffer from micryotic anemia do not had healthy transportation of oxygen in their bodies.Introduction To Analysis of Variance (ANOVA)ANOVA is a statistical method used to compare the means of two or more groups.ANOVA contains factors(variables)levelsTypes of ANOVA:One-way repeated-measuresFactorial Two way ANOVA

What need to do??Total sum of squares= sum of squares between groups + sum of squares within groupsDegree of freedomMean square= sum of square/degrees of freedomF square= mean square/(sum of square/d.f)Find critical value from t tableConstruct curve diagramThe acceptance of hypothesis

QUESTIONDetermine whether there is any significant difference in MCH values between gender (male and female) and between age group (20 years old).HYPOTHESIS Ho : Gender will have no significant effect on MCH values HA : Gender does have a significant effect on MCH values

Ho : Age group will have no significant effect on MCH values HA : Age group does have a significant effect on MCH values

Ho : Gender and age interactions will have no significant effect on MCH values HA : Gender and age interactions does have a significant effect on MCH valueWANTED DATAAGE20TOTALGENDERMALE12355401775FEMALE5179011418TOTAL175214413193TOTAL DATAUNWANTED (FLITERED)644WANTED DATA3193TOTAL3837METHOD0 AGEGENDER : NORMALZERO VALUES OF MCH

3subjects1subject640subjectsTotal of 644 subjects data is removedShow the filter data9ANOVA Find sum of squares Find degree of freedom, df Calculate the mean of square Calculate F score Refer table for Critical Value Draw Curve diagram Accept or reject the hypothesisMEANAGE20AVERAGEGENDERMALE29.9348130.0898130.01231FEMALE29.1835629.0915829.13757AVEARGE29.5591929.590729.57494SUM OF SQUARESAMOUNTDfMEAN OF SQUAREF SCORE1ST FACTOR : GENDER610.79700652-1=1610.797006559.985459772ND FACTOR : AGE GROUP0.7925467122-1=10.7925467120.077834826WITHIN (ERROR)32471.733193-4=318910.18241769BOTH64.189046791x1=164.189046796.303910208TOTAL33147.50861st Factor Gender : F(1,3189)= 59.98545977

2nd Factor Age : F(1,3189)= 0.077834826Both : F(1,3189)= 6.303910208

3.841st Factor Gender : F(1,3189)= 59.985459772nd Factor Age : F(1,3189)= 0.077834826Both : F(1,3189)= 6.3039102080.0778348266.30391020859.98545977ACCEPTREJECTESTABLISHED HYPOTHESIS Ho : Gender will have no significant effect on MCH values HA : Gender does have a significant effect on MCH values

Ho : Age group will have no significant effect on MCH values

Ho : Gender and age interaction will have no significant effect on MCH values HA : Gender and age interaction does have a significant effect on MCH valueREJECTEDREJECTEDACCEPTED