Average Mass Activity Find the average mass of all the spheres in the tray. You may: -Make no more...

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Mass Activity average mass of all the spheres in th no more than 3 mass measurements. only 1 sphere at a time ll measurements and show your work. what you did and all assumptions.

Transcript of Average Mass Activity Find the average mass of all the spheres in the tray. You may: -Make no more...

Page 1: Average Mass Activity Find the average mass of all the spheres in the tray. You may: -Make no more than 3 mass measurements. -Mass only 1 sphere at a time.

Average Mass Activity  

Find the average mass of all the spheres in the tray.  You may:

-Make no more than 3 mass measurements.-Mass only 1 sphere at a time

 Record all measurements and show your work.  Explain what you did and all assumptions.

Page 2: Average Mass Activity Find the average mass of all the spheres in the tray. You may: -Make no more than 3 mass measurements. -Mass only 1 sphere at a time.

63.5 amu

23. Calculate Copper has two isotopes: Cu-63 (abundance=69.2%, mass=62.930 amu) and Cu-65 (abundance= 30.8%, mass=64.928 amu) Calculate the atomic mass of copper..692 x 62.930 =

43.5 .308 x 64.928 = 20.0

Page 3: Average Mass Activity Find the average mass of all the spheres in the tray. You may: -Make no more than 3 mass measurements. -Mass only 1 sphere at a time.

23.985 x .7899 = 18.95 24.986 x .1000 = 2.49925.982 x .1101 = 2.861 24.31 amu

24. Three magnesium isotopes have atomic masses and relative abundances of 23.985 amu (78.99%), 24.986 amu (10.00%), and 25.982 (11.01%). Calculate the atomic mass of magnesium

Page 4: Average Mass Activity Find the average mass of all the spheres in the tray. You may: -Make no more than 3 mass measurements. -Mass only 1 sphere at a time.

Practice Problem  Silver is found in two isotopes with atomic masses 106.9041 amu and 108.9047 amu, respectively. The first isotope represents 51.82% and the second 48.18%. Determine the average atomic mass of silver.106.9041(0.5182) + 108.9047(0.4818) = 107.87 amu

55.40 + 52.47