Automorphisms, cubes and the Robinson tiling · Automorphisms, cubes and the Robinson tiling based...
Transcript of Automorphisms, cubes and the Robinson tiling · Automorphisms, cubes and the Robinson tiling based...
Automorphisms, cubes and the Robinson tilingbased on a joint work with Wenbo Sun and on a joint work with
Fabien Durand, Alejandro Maass and Samuel Petite
Sebastian Donoso F.
The Hebrew University of Jerusalem
June 2016
Sebastian Donoso Fuentes
Brief “introduction” to topological dynamics
Sebastian Donoso Fuentes
A topological dynamical system is a pair (X ,G) where X is acompact metric space and G is a group of homeomorphisms.In this talk, G is Z or Z2.
When T is a homeomorphism of X , we write (X ,T ) to denote Zdynamical system (X ,{T n ∶ n ∈ Z}).
Let G = Z2 and let S,T ∈ G be two generators. We say that(X ,S,T ) is a system with commuting transformations S and T .
In this talk we assume that (X ,S,T ) is a minimal system,meaning that the G-orbit of any point is dense in X . This isequivalent to say that the only closed invariant sets are X and∅.
Sebastian Donoso Fuentes
A factor map π is a continuous onto map
Y Y
X X
π
g
π
g
π ○ g = g ○ π.
Remark: Even if Y is a subshift, it may be convenient to consider factors which are not
subshifts.
Sebastian Donoso Fuentes
An equivalent way to think of a factor map of (X ,G) is throughrelations.
Let R ⊆ X ×X be a relation:● closed;● invariant (g × g)R =R for all g ∈ G.● of equivalence.
We can define the canonical projection
X → X/R
Conversely, if π∶X → Y is a factor map, Y can be identified withX/Rπ where Rπ = {(x ,x ′) ∈ X ×X ∶ π(x) = π(x ′)}.
Sebastian Donoso Fuentes
In general, if R is only a relation, we can considerσ(R) to be the smallest closed, invariant, equivalence relationcontaining R.
Sebastian Donoso Fuentes
Automorphisms in topological dynamics
An automorphism of (X ,G) is an homeomorphism φ∶X → Xsuch that
φ ○ g = g ○ φ. for all g ∈ G
We write
Aut(X ,G) = {φ automorphism of (X ,G)}.
If G is abelian
G ⊂ Z(Aut(X ,G)).
Sebastian Donoso Fuentes
LemmaLet (X ,G) be a minimal topological dynamical system. ThenAut(X ,G) acts freely on X (elements different from the identityhave no fixed points).
Proof: For φ ∈ Aut(X ,G)
Fix(φ) ∶= {x ∈ X ∶ φx = x}
is closed (φ is continuous) and invariant (φ commutes with G).By minimality Fix(φ) is equal to X or ∅.
Sebastian Donoso Fuentes
Automorphisms through factor maps
A factor map π∶ (X ,G)→ (Y ,G) is compatible with Aut(X ,G) if
π(x) = π(x ′)⇐⇒ π(φ(x)) = π(φ(x ′)) for every φ ∈ Aut(X ,G)
In this case, we can define the projection
π∶Aut(X ,G)→ Aut(Y ,G).
π(φ)π(x) = π(φx).
Sebastian Donoso Fuentes
In terms of relations, X → X/R is compatible with Aut(X ,G) if
(x ,x ′) ∈R if and only if (φx , φx ′) ∈R
for every φ ∈ Aut(X ,G).
Fact: Many important factors in topological dynamics arecompatible!
Sebastian Donoso Fuentes
A useful criterion
DefinitionLet π∶ (X ,G)→ (Y ,G) be a factor map. The factor π is almostone-to-one if there exists y ∈ Y such that ∣π−1(y)∣ = 1.
Proposition
Let π∶ (X ,G)→ (Y ,G) be an almost one-to-one extension withπ compatible with Aut(X ,G). Then
π∶Aut(X ,G)→ Aut(Y ,G)
is an injection.
Sebastian Donoso Fuentes
A useful criterion
DefinitionLet π∶ (X ,G)→ (Y ,G) be a factor map. The factor π is almostone-to-one if there exists y ∈ Y such that ∣π−1(y)∣ = 1.
Proposition
Let π∶ (X ,G)→ (Y ,G) be an almost one-to-one extension withπ compatible with Aut(X ,G). Then
π∶Aut(X ,G)→ Aut(Y ,G)
is an injection.
Sebastian Donoso Fuentes
Proof: It suffices to analyse φ ∈ Ker(π).
Take y ∈ Y with π−1(y) = {x}.
Then φ(x) = x , and since the action is free
φ = id.
Example: If (X , σ) is a Toeplitz subshift, then Aut(X ,G) isabelian.
Sebastian Donoso Fuentes
Proof: It suffices to analyse φ ∈ Ker(π).
Take y ∈ Y with π−1(y) = {x}.
Then φ(x) = x , and since the action is free
φ = id.
Example: If (X , σ) is a Toeplitz subshift, then Aut(X ,G) isabelian.
Sebastian Donoso Fuentes
Proof: It suffices to analyse φ ∈ Ker(π).
Take y ∈ Y with π−1(y) = {x}.
Then φ(x) = x , and since the action is free
φ = id.
Example: If (X , σ) is a Toeplitz subshift, then Aut(X ,G) isabelian.
Sebastian Donoso Fuentes
How to create compatiblefactors/relations?
Sebastian Donoso Fuentes
Some special relations
Product systems appear a lot in ergodic theory.
Let (Y , σ) and (W , τ) be minimal topological dynamicalsystems. The system
(Y ×W , σ × id, id × τ)
is the the product of (Y , σ) and (W , τ).
In terms of the dynamics, we can think that these systems (andtheir factors) have “simple” behavior.
Sebastian Donoso Fuentes
A relation:
Definition (A cube for two commuting transformations)
Let (X ,S,T ) be a minimal system with commutingtransformations. We define the set of cubes QS,T to be the set
{(x ,Snx ,T mx ,SnT mx) ∶ x ∈ X ,n,m ∈ Z} ⊆ X 4.
An element in QS,T is called a dynamical cube.
T mx SnT mx
x Snx
Sebastian Donoso Fuentes
Example
Let (Y ×W , σ × id, id × τ) be a minimal product system.
A typical cube has the form
(y , τmw) (σny , τmw)
(y ,w) (σny ,w)
Sebastian Donoso Fuentes
(y ,w ′) ?
(y ,w) (y ′,w)
Sebastian Donoso Fuentes
(y ,w ′) (y ′,w ′)
(y ,w) (y ′,w)
Conclusion: The last coordinate of a point in QS,T isdetermined by the other ones.
Sebastian Donoso Fuentes
Theorem (D., Sun (2014))
Let (X ,S,T ) be a minimal system with commutingtransformations. The following are equivalent:
1 (X ,S,T ) is a factor of a product system;2 One can deduce the last coordinate of a dynamical cube.
Sebastian Donoso Fuentes
“Cubes induce factors”. We define relations using the cubes:
RS = {(x ,y) ∈ X ×X ∶ (x ,y ,a,a) ∈ QS,T for some a ∈ X}
a a
x y
x and y are RS related
Sebastian Donoso Fuentes
RT = {(x ,y) ∈ X ×X ∶ (x ,b,y ,b) ∈ QS,T for some b ∈ X}
y b
x b
x and y are RT related
Finally we defineRS,T =RS ∩RT .
Sebastian Donoso Fuentes
Example: RS in a product system.
(y ,w ′) (y ′,w ′)
(y ,w) (y ′,w)
Hence (y ,w) = (y ′,w) and
RS = ∆Y×W =RT =RS,T .
Sebastian Donoso Fuentes
Example: RS in a product system.
(y ,w ′) (y ′,w ′)
(y ,w) (y ′,w)
=
Hence (y ,w) = (y ′,w) and
RS = ∆Y×W =RT =RS,T .
Sebastian Donoso Fuentes
Example: RS in a product system.
(y ,w ′) (y ′,w ′)
(y ,w) (y ′,w)
=
Hence (y ,w) = (y ′,w) and
RS = ∆Y×W =RT =RS,T .
Sebastian Donoso Fuentes
TheoremLet (X ,S,T ) be a minimal system with commutingtransformations. Then (X ,S,T ) has a product extension if andonly if RS,T = ∆X .
Sebastian Donoso Fuentes
Example: Morse
Consider the Morse substitution:
Sebastian Donoso Fuentes
One can iterate this substitution in a natural way:
first, second and third iteration of the substitution
Sebastian Donoso Fuentes
Example
Iterating the process we get a point in x ∈ {0,1}Z2. We let X
denote orbit closure of x under translations. We have that(X , σ(1,0), σ(0,1)) is a minimal system with commutingtransformations. (From now S = σ(1,0), T = σ(0,1)).
Sebastian Donoso Fuentes
Example
Proposition
We have that RS,T (X) = ∆X . Subsequently (X ,S,T ) has aproduct extension.
In fact, (unsurprisingly) the Theorem gives that the “cover” isthe product of two one dimensional Thue-Morse sequences.
Sebastian Donoso Fuentes
More generally
Let (X , σX ) and (Y , σY ) be two one dimensional shift spaceswith alphabets AX and AY . Let x = (xi)i∈Z ∈ X , y = (yj)j∈Z ∈ Y .
Consider z = (zi,j)i,j∈Z where zi,j = (xi ,yj) and Z its closure orbitunder the shift transformations.
Let ϕ be a function defined on AX ×AY .
Sebastian Donoso Fuentes
⋱ ⋮ ⋮ ⋮ ⋰
⋯ (xi−1,yj+1) (xi ,yj+1) (xi+1,yj+1) ⋯
⋯ (xi−1,yj) (xi ,yj) (xi+1,yj) ⋯
⋯ (xi−1,yj−1) (xi ,yj−1) (xi+1,yj−1) ⋯
⋰ ⋮ ⋮ ⋮ ⋱
Sebastian Donoso Fuentes
⋱ ⋮ ⋮ ⋮ ⋰
⋯ ϕ(xi−1,yj+1) ϕ(xi ,yj+1) ϕ(xi+1,yj+1) ⋯
⋯ ϕ(xi−1,yj) ϕ(xi ,yj) ϕ(xi+1,yj) ⋯
⋯ ϕ(xi−1,yj−1) ϕ(xi ,yj−1) ϕ(xi+1,yj−1) ⋯
⋰ ⋮ ⋮ ⋮ ⋱
Sebastian Donoso Fuentes
Proposition
Any minimal Z2 subshift with a product extension is obtained inthis way.
A comment for some specialists: This can also be characterized in terms of enveloping
semigroups. A system has a product extension if and only if
E(X , ⟨S,T ⟩) = E(X ,S)E(X ,T) and E(X ,S) and E(X ,T) commute
Sebastian Donoso Fuentes
Proposition
Any minimal Z2 subshift with a product extension is obtained inthis way.
A comment for some specialists: This can also be characterized in terms of enveloping
semigroups. A system has a product extension if and only if
E(X , ⟨S,T ⟩) = E(X ,S)E(X ,T) and E(X ,S) and E(X ,T) commute
Sebastian Donoso Fuentes
Example: Robinson tiling
I refer to the work of Galher, Julien and Savinien.Consider the following set of tiles and their rotations andreflections :
Let ARob denote this set of tiles. Then #ARob = 28.
Sebastian Donoso Fuentes
Sebastian Donoso Fuentes
Sebastian Donoso Fuentes
Sebastian Donoso Fuentes
Sebastian Donoso Fuentes
Sebastian Donoso Fuentes
Sebastian Donoso Fuentes
We can continue this process and we get a point x ∈ AZ2
Rob.
Let X denote the orbit closure of this point under the shifttransformations.
The system (X ,S,T ) is a minimal system with commutingtransformations (it is the unique minimal inside the Robinsontiling).
Sebastian Donoso Fuentes
After some computations, the RS,T relation on X is “almosttrivial”.
Let π∶X → X/RS,T be the quotient map. Then π is an almostone-to-one extension and compatible.
“Regular” points (the ones with only one infinite order supertile)are no related to other points.
Therefore we can inject Aut(X ,S,T ) in Aut(X/RS,T ,S,T )
Sebastian Donoso Fuentes
Important property: the fiber with maximal cardinality is unique(up to shift).
It consists of the configurations with four infinite ordersupertiles.
Sebastian Donoso Fuentes
How two four infinite supertiles points are related
Sebastian Donoso Fuentes
Proposition
The group of automorphisms of (X ,S,T ) consists of the shifts.
Proof:Let φ be a automorphism of the Robinson tiling andπ∶X → X/RS,T be the quotient map. Let x with four infiniteorder supertiles. Then there exist n,m ∈ Z with
π(φ)(π(x)) = π(φ(x)) = SnT mπ(x)
Hence π(φ) = SnT m in X/RS,T and (by injectivity)
φ = SnT m in X
.
Sebastian Donoso Fuentes
Proposition
The group of automorphisms of (X ,S,T ) consists of the shifts.
Proof:Let φ be a automorphism of the Robinson tiling andπ∶X → X/RS,T be the quotient map. Let x with four infiniteorder supertiles. Then there exist n,m ∈ Z with
π(φ)(π(x)) = π(φ(x)) = SnT mπ(x)
Hence π(φ) = SnT m in X/RS,T and (by injectivity)
φ = SnT m in X
.
Sebastian Donoso Fuentes
Merci pour votre attention.
Sebastian Donoso Fuentes