AUTHOR GCSE LINEAR EXAM QUESTIONS (FOUNDATION) .

AUTHOR

GCSE LINEAR EXAM QUESTIONS

(FOUNDATION)

www.mistrymaths.co.uk

http://www.mistrymaths.co.uk/

GCSE FOUNDATION EXAM QUESTIONS WITH ANSWERS

Perimeter is the length around the shape. 16

Count the numbers of squares inside the shape.

12cm2


Count the number of cubes. 15


What the 3D shape looks like from the side.


Scale goes up in ones.

33

Scale goes up in tens.

180

110Scale goes up in fives.

0.27Scale goes up in 0.01s.


£1 = €1.68x325 x325

£325 = €546

546

£1 = €1.50x78 x78

£78 = €117

€117 ÷ €1.50 = 78 Multiplier

78


8.4510.24 – 6.51

=8.453.73

2.26541555

2.2654155 2


Midpoint

3

9

15

21

27

FX

45

225

300

252

216

Total = 80 1038

Mean = 1038 80 = 13.0 mins (1d.p.)

(Total 3 marks)


Circumference is the full length around a circle

Circumference = π x diameter

Diameter

Circumference = 3.14 x 8 Circumference = 25.12cm

Length of arc (semi-circle) = 25.12 ÷ 2 = 12.56cm

Perimeter = 12.56cm + 8cm = 20.56cm (2 d.p.)

(Total 3 marks)


70°

70°

Because triangle is isosceles

Angles add up to 180° in a triangle. y = 180° - 70° - 70°y = 40°

y = 40°

(Total 2 marks)


4

5

6

Smallest number = 43 Biggest number = 62

3

/

5

/

7

/

7

/

0

/

3

/

3

/

5

/

6

/

7

/

8

/

8

/

8

/

1

/

2

/

2

/

5 /3 means 53

(Total 3 marks)


Volume of prism = area of cross-section x lengthVolume of prism = area of triangle x length

Volume of prism = base x height 2

x length

Volume of prism = 4 x 3

2x 20

Volume of prism = 6 x 20

120


Kite


10:10

14

This is where the line is horizontal:10:40 to 11:10

30 (1)


Does not take into account those who do not buy DVDs.

Answer response section overlaps.


y = 3 x -2 + 4 = -2 -2

y = 3 x 0 + 4 = 4

4

y = 3 x 1 + 4 = 7

7

x

x

x

x

x


68°

y = 180° - 68° 112

Alternate angles (Z angles) are the same and angles on a straight line

add up to 180°.


𝑥 High or Low1 1 + 10 x 1 = 113

25103 xx

Replace x with 1

Too low

2 2 + 10 x 2 = 283 Too high

1.5 1.5 + 10 x 1.5 = 18.38 3 Too low

1.8 1.8 + 10 x 1.8 = 23.83 3 Too low

1.9 1.9 + 10 x 1.9 = 25.86 3 Too high1.85 1.85 + 10 x 1.85 = 24.83 3 Too low

ANSWER = 1.9 (closest to 25)1.9


Probability adds up to 1.

P(Yellow) = 1 – 0.15 – 0.30 – 0.35

0.2

Red ribbons = 0.30 of 500

Red ribbons = of 500 30 100

÷

x

150


Base angles in an isosceles triangle are always the same.

+10 +10

÷2 ÷2

20


base x height 2Area of a triangle =

Area of a triangle = 14 x 6 2 42

Have to use Pythagoras’ Theorem. Only works in right-angled triangles

232

15.23


7 x 20 0.5 =

140 0.5 =

Dividing by 0.5 is the same as multiplying by 2

280


hkmmph /6.11 LEARN OFF BY HEART

(Total 2 marks)

120mph x 1.6 = 192km/h

Therefore, Car B has a greater maximum speed by 8km/h


H = 2 x 5 + 3 x -1H = 10 - 3

7

P = 3 x (-4)2

P = 3 x 16

48


(Total 3 marks)

FILM A FILM B

8 3

=

40%

100 40

= 5

2

8 3

5 2 +

= 40 15

40 16 +

= 40 31

FILM C

1 - 40 31

40 9


Mass Volume

Density =

Mass = Density x Volume

5cm2 x 5= 10cm2

2 x 7 = 14cm 2 Total Area =10cm + 14cm2 2

Total Area = 24cm 2

200cm Volume = 24cm x 200cm2

Volume = 4800cm 3

Mass =

38400g

8 x 4800


Area of big circle =Area of big circle = 3.14 x 6 x 6Area of big circle = 113.04m2

Area of small circle =Area of small circle = 3.14 x 5 x 5Area of small circle = 78.5m2

Area of path = 113.04m -2 78.5m2

Area of path = 34.45m 2

34.5


066Bearings must be written as 3 figures

xC

(Total 3 marks)


2kg = £1.72÷2 ÷2

1kg = £0.86

SMALL BOX LARGE BOX

9kg = £7.65÷9 ÷9

1kg = £0.85

Large box is 1p cheaper per kilogram

Large Box


10% of £360 = £36 5% of £360 = £18

2.5% of £360 = £9

17.5% of £360 = £63

Total cost = £360 + £63

423

(Total 3 marks)


y = 6 (x + y must sum to equal 4)

y = 4 y = 2

(-2,6)

(0,4)(2,2)

x

x

x


(Total 2 marks)


£1 = $1.84x175 x175

£175 = $322

$322 ÷ $1.84 = 175 Multiplier

175

Distance Time

Speed =

87120

Speed =

890

Simplify fully 7x − 2(x − 3y) − 4y Solve 4x + 1 = 2x + 12

Express 72 as a product of its prime factors.

Use the information that322 × 48 = 15 456to find the value of(a) 3.22 × 4.8.....................................(1)

(b) 0.322 × 0.48.....................................(1)

(c) 15 456 ÷ 4.8.....................................(1)


- 2x = 7x + 6y - 4y

= 5x + 2y

72

8 9

4 2 3 3

2 2

ANSWER = 2 X 2 X 2 X 3 X 3

=23 32

15.456

0.15456

3220

Expand and simplify (y + 4)(y + 5)


x5 x5

Solve 4(2x – 3) = 5x + 7

15

+ 4y = + 5y + 20 y2

+ 9y = + 20 y2

8x – 12 = 5x +73x – 12 = 73x = 19

3 1 6

6

8

1

8

0

6

3

6

2

4

8

0

8

4

8

8

1

4

11

12


Work out 3.16 × 68 without a calculator

Answer = 214.88

TRANSFORMATIONS EXAM QUESTIONS

A reflection in the line x = -1

Centre of enlargement

Enlargement of scale factor one half from centre (1,3)


Rotation of 90° clockwise from centre (1,1)

On graph

A reflection in the line y = x

QR

Rotation of 180° from centre (0,0)



x = 5

5

0

180 5 2.5

1 3

-41


AUTHOR GCSE LINEAR EXAM QUESTIONS (FOUNDATION) .

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