AToTHePIsNotRegular(EquivalenceClasses)r

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Consider Σ = {a} and L = {a  p  : p is a positive prime integer}. If m is prime and n is not prime, then a m  and a n  are in different equivalence classes. What about and !" #he strin g a dis tinguishes them. ! and $" %ot disting uished b& a '  for '=( , ), , !. *ut a +  does distinguish them. Is it the case that a  p  and a q  p-q are al/a&s in different equivalence classes" I claim that for some '0(, the string a 'q1p distinguishe s a  p  and a q . Lemma. #here is no infinit e arithmetic sequence of p rimes. Proof of theorem using the lemma We ' no/ that p 2 )q1p is prime. Let ' be the smallest positive integer such that p 2 '2)q1p is not  prime. #hen a  p a  p2'q1p  is in L, and a q a  p2'q1p  = a  p2q1p a  p2'q1p  = a  p2'2)q1p is not in L Proof of lemma. Let n be the difference bet/een t/o consecutive terms in an arithmetic sequence. Consider n2)3 2 ). #he ne4t n consecutive integers are compos ite. 54amples: n2)3 2 is d ivisible b& . n2)3 2 ! is d ivisible b& ! 6 n2)3 2 n is divisible b& n n2)3 2 n2) is divisible b& n. 7o none of these n consecutive numbers is prime. Final conclusion. #he language L has infinitel& man& equivalence classes.

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Consider Σ = {a} and L = {a p : p is a positive prime integer}.

If m is prime and n is not prime, then am and an are in different equivalence classes.

What about and !" #he string a distinguishes them.

! and $" %ot distinguished b& a'  for '=(, ), , !. *ut a+ does distinguish them.

Is it the case that a p and aq p-q are al/a&s in different equivalence classes"

I claim that for some '0(, the string a'q1p distinguishes a p and aq.

Lemma.  #here is no infinite arithmetic sequence of primes.

Proof of theorem using the lemma

We 'no/ that p 2 )q1p is prime. Let ' be the smallest positive integer such that p 2 '2)q1p is not

 prime.

#hen a pa p2'q1p is in L, and aqa p2'q1p  = a p2q1pa p2'q1p = a p2'2)q1pis not in L

Proof of lemma. Let n be the difference bet/een t/o consecutive terms in an arithmetic sequence.

Consider n2)3 2 ). #he ne4t n consecutive integers are composite.

54amples: n2)3 2 is divisible b& . n2)3 2 ! is divisible b& ! 6

n2)3 2 n is divisible b& n n2)3 2 n2) is divisible b& n.

7o none of these n consecutive numbers is prime.

Final conclusion. #he language L has infinitel& man& equivalence classes.