INSTITUT KEMAHIRAN MARA LUMUT

KFC 2044 NETWORK FUNDAMENTAL

MOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK

950226-10-6035

1401123

EN. MOHD SHUKRI BIN MUHAMAD HUSIN

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 1

ASSIGNMENTKFC 2044 NETWORK FUNDAMENTAL

UNIT 1 COMPUTER NETWORKING FUNDAMENTALS

TABLE OF CONTENTS

NO. TITLE PAGE

1 IP ADDRESS CLASSESCALCULATION

3 – 5

2 PROBLEM 1 6 – 7

3 PROBLEM 2 8 – 9

4 PROBLEM 3 10 – 11

5 PROBLEM 4 12 – 13

6 PROBLEM 5 14 – 15

7 PROBLEM 6 16 – 17

8 SUBNETTINGCALCULATION

18 – 20

9 PROBLEM 1 21 – 23

10 PROBLEM 2 24 – 26

11 PROBLEM 3 27 – 29

12 PROBLEM 4 30 – 32

13 PROBLEM 5 33 – 35

14 PROBLEM 6 36 - 38

15 REFERENCE 39

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 2

IP ADDRESS CLASSES

STEP TO CALCULATION IP ADDRESS CLASSESKFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 3

IP ADDRESS

Task 1 : For a given Ip Address, Determine Network Information.Given :

Host IP Address 172.25.114.250Network Mask 255.255.0.0 (/16)

Find :

Network Address 172.25.0.0Network Broadcast Address 172.25.255.255Total Number Of Host Bits 16Number Of Hosts 65534Step 1 : Translate Host IP Address And Network mask into binary notation:Network Address: 172.25.0.0

17227 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 = 17225

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 1 0 0 1

16 + 8 + 1 = 250 0 0 0 0 0 0 00 0 0 0 0 0 0 0

= 00 0 0 0 0 0 0 00 0 0 0 0 0 0 0

= 0Network Broadcast Address : 172.25.255.255

17227 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 = 17225

27 26 25 24 23 22 21 20

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 4

128 64 32 16 8 4 2 10 0 0 1 1 0 0 1

16 + 8 + 1 = 25255

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

128 + 64 + 32 + 16 + 8 + 4 + 2 +1 =255255

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = 255FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.0.0=11111111.11111111.00000000.00000000Host = 2^16 = 65536 – 2 = 65534Hosts = 16Total Number Of Host = 216

65536 – 2 = 65534

Host Ip Address 172.25.114.250Network Mask 255.255.0.0(/16)Network Address 172.25.0.0Network broadcast Address 172.25.255.255Total Number Of Host Bits 16Number Of Hosts 65534

TASK 2 : PROBLEM 1 :Host IP Address 172.30.1.33

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 5

Network mask 255.255.0.0

ANSWERHost IP Address 172.30.1.33Network Mask 255.255.0.0Network Address 172.30.0.0Network Broadcast Address 172.30.255.255Total Address of Host Bits 65534Number of Host 216

Network Address : 172.30.0.0172

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 =17230

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 1 1 1 0

16 + 8 + 4 + 2 = 300

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 00

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 0Network Address = 172.30.0.0Network Broadcast Address : 172.30.255.255

172

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 6

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 =17230

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 1 1 1 0

16 + 8 + 4 + 2 = 30255

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 +2 + 1 = 255255

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 +2 + 1 = 255

FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.0.0=11111111.11111111.00000000.00000000Host = 2^16 = 65536 – 2 = 65534Hosts = 16Total Number Of Host = 216

65536 – 2 = 65534

Problem 2:Host IP Address 172.30.1.33

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 7

Network mask 255.255.255.0

ANSWERHost IP Address 172.30.1.33Network Mask 255.255.255.0Network Address 172.30.1.0Network Broadcast Address 172.30.1.255Total Address of Host Bits 254Number of Host 28

Network Address : 172.30.1.0172

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 =17230

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 1 1 1 0

16 + 8 + 4 + 2 = 301

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 1

= 10

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 0Network Address = 172.30.1.0

Network Broadcast Address : 172.30.255.255

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 8

17227 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 =172

3027 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 1 1 1 0

16 + 8 + 4 + 2 = 30

127 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 1

= 1

25527 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 +2 + 1 = 255

FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.255.0=11111111.11111111.11111111.00000000Host = 2^8 = 256 – 2 = 256Hosts = 8

Problem 3:

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 9

Host IP Address 192.168.10.234Network mask 255.255.255.0

ANSWERHost IP Address 192.168.10.234Network Mask 255.255.255.0Network Address 191.168.10.0Network Broadcast Address 191.168.10.255Total Address of Host Bits 254Number of Host 28

Network Address : 192.168.10.0 192

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192168

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 0 0 0

128 + 32 + 8 =16810

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 1 0 1 0

= 100

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 0Network Address = 192.168.10.0Network Broadcast Address : 192.168.10.255

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 10

19227 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192

16827 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 0 0 0

128 + 32 + 8 =168

1027 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 1 0 1 0

= 10

25527 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 + 2 +1 = 255

FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.255.0=11111111.11111111.11111111.00000000Host bits = 8 Total Number of Hosts = 28

256 – 2 = 254

Problem 4:

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 11

Host IP Address 172.17.99.71Network mask 255.255.0.0

ANSWERHost IP Address 172.17.99.71Network Mask 255.255.0.0Network Address 172.17.0.0Network Broadcast Address 172.17.255.255Total Address of Host Bits 65534Number of Host 216

Network Address : 172.17.0.0172

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 = 17217

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 0 0 0 1

16 + 1 = 170

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 00

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 0Network Address = 172.17.0.0Network Broadcast Address : 172.17.255.255

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 12

17227 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 1 0 0

128 + 32 + 8 + 4 = 172

1727 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 1 0 0 0 1

16 + 1 = 17

25527 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 + 2 +1 = 255

25527 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 + 2 +1 = 255

FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.0.0=11111111.11111111.00000000.00000000Host = 2^16 = 65536 – 2 = 65534Hosts = 16

Problem 5:

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 13

Host IP Address 192.168.3.219Network mask 255.255.0.0

ANSWERHost IP Address 192.168.3.219Network Mask 255.255.0.0Network Address 192.168.0.0Network Broadcast Address 192.168.255.255Total Address of Host Bits 65534Number of Host 216

Network Address : 192.168.0.0192

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192168

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 0 0 0

128 + 32 + 8 = 1680

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 00

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 0 0

= 0Network Address = 192.168.0.0

Network Broadcast Address : 192.168.255.255KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 14

19227 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192

16827 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 0 0 0

128 + 32 + 8 = 168

25527 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 + 2 +1 = 255

25527 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 1 1 1 1 1 1

= 128 + 64 + 32 + 16 + 8 + 4 + 2 +1 = 255

FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.0.0=11111111.11111111.00000000.00000000Host = 2^16 = 65536 – 2 = 65534Hosts = 16

Problem 6:

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 15

Host IP Address 192.168.3.219Network mask 255.255.255.224

ANSWERHost IP Address 192.168.3.219Network Mask 255.255.0.0Network Address 191.168.3.192Network Broadcast Address 191.168.3.223Total Address of Host Bits 30Number of Host 25

Network Address : 192.168.3.192192

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192168

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 0 0 0

128 + 32 + 8 = 1683

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 1 1

2 + 1 = 3192

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192

Network Address = 192.168.3.192

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 16

Network Broadcast Address : 192.168.3.223192

27 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 0 0 0 0 0

128 + 64 = 192

16827 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 0 1 0 1 0 0 0

128 + 32 + 8 = 168

327 26 25 24 23 22 21 20

128 64 32 16 8 4 2 10 0 0 0 0 0 1 1

2 + 1 = 3

22327 26 25 24 23 22 21 20

128 64 32 16 8 4 2 11 1 0 1 1 1 1 1

128 + 64 +16 + 8 + 4 + 2 + 1 = 223

FORMULA:Host (0) = perlu ditolak (-) dengan 2

255.255.255.224=11111111.11111111.11111111.11100000Host bits = 5Total numbers of hosts = 25

32 – 2 = 30

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 17

Task 1: For a Given IP Address and Subnet Mask, Determine Subnet Information.

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 18

SUBNETTING

Given:Host IP Address 172.25.114.250Network Mask 255.255.0.0(/16)Subnet Mask 255.255.255.192(/26)

Find:Number of subnet bits 10Number of subnets 210 = 1024 subnetNumber of Host Bits per Subnet 6Number of usable Hosts per subnet 26 = 64 – 2 = 62 bit per subnetSubnet Address for this IP Address 172.25.114.192IP Address of first host on this Subnet 172.25.114.193IP Address of last host on this Subnet 172.25.114.254Broadcast Address for this Subnet 172.25.114.255

Step 1: Translate host IP Address and subnet mask into binary notation.172 25 114 250

10101100 00011001 01110010 11111010 IP Address11111111 11111111 11111111 11000000 Subnet Mask

10101100 00011001 01110010 11000000Subnet Address

172 25 114 192

Subnet address for this IP address: 172.25.114.192

Determine the bit rangers for subnets and hosts.

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 19

IP ADDRESS172 25 114 250

10101110 00011001 01110010 11111010

SUBNET MASK11111111 111111111 00000000 00000000

255 255 0 0

Total NumberSUBNET MASK = 11111111.11111111.00000000.00000000

= network : 2^8 = 256Number of Host Bits per Subnet

= 16 bitsNumber of Usable Hosts per Subnet

= host : 2^16 = 65536 – 2 = 65534

Problem 1KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 20

IP ADDRESS 172.30.1.33SUBNET MASK 255.255.255.0

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

Total number of Subnet Mask= 11111111.11111111.11111111.00000000= network = 2^8 = 256

Number of Hosts Bits per Subnet = 8 bits

Number of Usable Hosts per Subnet= hosts = 2^8 = 256 – 2 = 254

NETWORK

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK10101110 00011110 00000001 00000000

172 30 1 0 NETWORK = IP ADDRESS + SUBNET MASK172= 10101110 30=00011110 1= 00000001 33= 00100001 11111111 11111111 11111111 00000000 10101110 00011001 00000001 00000000NETWORK = 10101110.00011001. 00000001.00000000

=172.30.1.0

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 21

BROADCAST

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK10101110 00011110 00000001 00000000

172 30 1 0

BROADCAST10101110 00011110 00000001 11111111

172 30 1 255

BROADCAST = replace the number 0 to number 1 appearing on network address

NETWORK10101110 00011110 00000001 00000000

172 30 1 0

BROADCAST10101110 00011110 00000001 11111111

172 30 1 255

FIRST HOST

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK10101110 00011110 00000001 00000000

172 30 1 0

BROADCAST10101110 00011001 00000001 11111111

172 30 1 255

FIRST HOST172 30 1 1

10101110 00011110 00000001 00000001

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast

BROADCAST10101110 00011110 00000001 11111111

172 30 1 255

FIRST HOST172 30 1 1

10101110 00011110 00000001 00000001

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 22

LAST HOST

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK10101110 00011110 00000001 00000000

172 30 1 0

BROADCAST10101110 00011110 00000001 11111111

172 30 1 255

FIRST HOST172 30 1 1

10101110 00011110 00000001 00000001

LAST HOST172 30 1 254

10101110 00011110 00000001 11111110

Last Host = replace the number 0 be the number 1 at 17-31 bits in the Broadcast

FIRST HOST172 30 1 1

10101110 00011110 00000001 00000001

LAST HOST172 30 1 254

10101110 00011110 00000001 11111110

RESULTHOST IP ADDRESS 172.30.1.33SUBNET MASK 255.255.255.0NUMBER OF SUBNET BITS 8 BITSNUMBER OF SUBNET 2^8 = 256NUMBER OF HOST BITS PER SUBNET 256NUMBER OF USABLE HOSTS PER SUBNET 2^8 – 2 = 256 – 2 = 254SUBNET ADDRESS FOR THIS IP ADDRESS 172.30.1.0IP ADDRESS OF FIRST HOST ON THIS SUBNET 172.30.1.1IP ADDRESS OF LAST HOST ON THIS SUBNET 172.30.1.254BROADCAST ADDRESS FOR THIS SUBNET 172.30.1.255

Problem 2

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 23

IP ADDRESS 172.30.1.33SUBNET MASK 255.255.255.252

IP ADDRESS172 30 1 33

10101110 00011001 00000001 00100001

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

Total number of Subnet Mask = 11111111.11111111.11111111.11111100

Network = 2^14 = 16384

Number of Hosts Bits per Subnet = 2 bits

Number of Usable Hosts per Subnet= hosts = 2^2 = 4 – 2 = 2

NETWORK

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK10101110 00011110 00000001 00100000

172 30 1 32NETWORK = IP ADDRESS + SUBNET MASK172= 10101110 30=00011110 1= 00000001 33= 00100001 11111111 11111111 11111111 11111100 10101110 00011001 00000001 00100000NETWORK = 10101110.00011001. 00000001.00100000

=172.30.1.32

FIRST HOST

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 24

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK10101110 00011110 00000001 00100000

172 30 1 32

FIRST HOST10101110 00011110 00000001 00100001

172 30 1 33

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast

NETWORK10101110 00011110 00000001 00100000

172 30 1 32

FIRST HOST10101110 00011110 00000001 00100001

172 30 1 33

LAST HOST

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK10101110 00011110 00000001 00100000

172 30 1 32

LAST HOST10101110 00011110 00000001 00100010

172 30 1 34

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

NETWORK10101110 00011110 00000001 00100000

172 30 1 32

LAST HOST10101110 00011110 00000001 00100010

172 30 1 34

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 25

BROADCAST

IP ADDRESS172 30 1 33

10101110 00011110 00000001 00100001

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK10101110 00011110 00000001 00100000

172 30 1 32

BROADCAST10101110 00011110 00000001 00100011

172 30 1 35

BROADCAST = replace the number 0 to number 1 appearing on network address

NETWORK10101110 00011110 00000001 00000000

172 30 1 0

BROADCAST10101110 00011110 00000001 00000011

172 30 1 35

RESULTHOST IP ADDRESS 172.30.1.33SUBNET MASK 255.255.255.252NUMBER OF SUBNET BITS 14 BITSNUMBER OF SUBNET 2^14 = 16384NUMBER OF HOST BITS PER SUBNET 4NUMBER OF USABLE HOSTS PER SUBNET 2^2 – 2 =4 – 2 = 2 host per subnetSUBNET ADDRESS FOR THIS IP ADDRESS 172.30.1.32IP ADDRESS OF FIRST HOST ON THIS SUBNET 172.30.1.33IP ADDRESS OF LAST HOST ON THIS SUBNET 172.30.1.34BROADCAST ADDRESS FOR THIS SUBNET 172.30.1.35

PROBLEM 3

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 26

IP ADDRESS 192.192.10.234SUBNET MASK 255.255.255.0

IP ADDRESS192 192 10 234

11000000 11000000 00001010 11101010

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

Total number of Subnet Mask = 11111111.11111111.11111111.00000000

Network = 2^8 = 256

Number of Hosts Bits per Subnet = 8 bits

Number of Usable Hosts per Subnet= hosts = 2^8 = 256 – 2 = 254

NETWORK

IP ADDRESS192 192 10 234

11000000 11000000 00001010 11101010

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK11000000 11000000 00001010 00000000

192 192 10 0NETWORK = IP ADDRESS + SUBNET MASK192= 11000000 192=11000000 10= 00001010 234= 11101010 11111111 11111111 11111111 11111100 11000000 11000000 00001010 00000000NETWORK = 110000001100000000001010 00000000

=192.192.10.234

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 27

FIRST HOST

IP ADDRESS192 192 10 234

11000000 11000000 00001010 11101010

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK11000000 11000000 00001010 00000000

192 192 10 0

FIRST HOST11000000 11000000 00001010 00000001

192 192 10 1

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast

NETWORK11000000 11000000 00001010 00000000

192 192 10 0

FIRST HOST11000000 11000000 00001010 00000001

192 192 10 1

LAST HOST

IP ADDRESS192 192 10 234

11000000 11000000 00001010 11101010

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK11000000 11000000 00001010 00000000

192 192 10 0

LAST HOST11000000 11000000 00001010 11111110

192 192 10 254

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

NETWORK11000000 11000000 00001010 00000000

192 192 10 0

LAST HOST11000000 11000000 00001010 11111110

192 192 10 254

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 28

BROADCAST

IP ADDRESS192 192 10 234

11000000 11000000 00001010 11101010

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK11000000 11000000 00001010 00000000

192 192 10 0

BROADCAST11000000 11000000 00001010 11111111

192 192 10 255

BROADCAST = replace the number 0 to number 1 appearing on network address

NETWORK11000000 11000000 00001010 00000000

192 192 10 0

BROADCAST11000000 11000000 00001010 11111111

192 192 10 255

RESULTHOST IP ADDRESS 192.192.10.234SUBNET MASK 255.255.255.0NUMBER OF SUBNET BITS 8 BITSNUMBER OF SUBNET 2^8 = 256NUMBER OF HOST BITS PER SUBNET 8 BITSNUMBER OF USABLE HOSTS PER SUBNET 2^8 – 2 =256 – 2 = 254 host per subnetSUBNET ADDRESS FOR THIS IP ADDRESS 192.192.10.0IP ADDRESS OF FIRST HOST ON THIS SUBNET 192.192.10.1IP ADDRESS OF LAST HOST ON THIS SUBNET 192.192.10.254BROADCAST ADDRESS FOR THIS SUBNET 192.192.10.255

PROBLEM 4

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 29

IP ADDRESS 172.17.99.71SUBNET MASK 255.255.0.0

IP ADDRESS172 17 99 71

10101100 00010001 01100011 01000111

SUBNET MASK11111111 111111111 00000000 00000000

255 255 0 0

Total number of Subnet Mask = 11111111.11111111.00000000.00000000

Network = 2^0 = 1

Number of Hosts Bits per Subnet = 16 bits

Number of Usable Hosts per Subnet= hosts = 2^16 = 65536 – 2 = 65534

NETWORK

IP ADDRESS172 17 99 71

10101100 00010001 01100011 01000111

SUBNET MASK11111111 111111111 00000000 00000000

255 255 0 0

NETWORK10101100 00010001 00000000 00000000

172 17 0 0NETWORK = IP ADDRESS + SUBNET MASK172= 10101100 17=00010001 99= 01100011 234= 01000111 11111111 11111111 00000000 00000000 10101100 00010001 00000000 00000000NETWORK = 10101100 00010001 00000000 00000000

=172.17.0.0

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 30

FIRST HOST

IP ADDRESS172 17 99 71

10101100 00010001 01100011 01000111

SUBNET MASK11111111 111111111 00000000 00000000

255 255 0 0

NETWORK10101100 00010001 00000000 00000000

172 17 0 0

FIRST HOST10101100 00010001 00000000 00000001

172 17 0 1

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast

NETWORK10101100 00010001 00000000 00000000

172 17 0 0

FIRST HOST10101100 00010001 00000000 00000001

172 17 0 1

LAST HOST

IP ADDRESS172 17 99 71

10101100 00010001 01100011 01000111

SUBNET MASK11111111 111111111 00000000 00000000

255 255 0 0

NETWORK10101100 00010001 00000000 00000000

172 17 0 0

LAST HOST10101100 00010001 11111111 11111110

172 17 255 254

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

NETWORK10101100 00010001 00000000 00000000

172 17 0 0

LAST HOST10101100 00010001 11111111 11111110

172 17 255 254

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 31

BROADCAST

IP ADDRESS172 17 99 71

10101100 00010001 01100011 01000111

SUBNET MASK11111111 111111111 00000000 00000000

255 255 0 0

NETWORK10101100 00010001 00000000 00000000

172 17 0 0

BROADCAST10101100 00010001 11111111 11111111

172 17 255 255

BROADCAST = replace the number 0 to number 1 appearing on network address

NETWORK10101100 00010001 00000000 00000000

172 17 0 0

BROADCAST10101100 00010001 11111111 11111111

172 17 255 255

RESULTHOST IP ADDRESS 172.17.99.71SUBNET MASK 255.255.0.0NUMBER OF SUBNET BITS 0 BITSNUMBER OF SUBNET 2^0 = 1NUMBER OF HOST BITS PER SUBNET 16 BITSNUMBER OF USABLE HOSTS PER SUBNET 2^16 – 2 =65536 – 2 = 65534 host per

subnetSUBNET ADDRESS FOR THIS IP ADDRESS 172.17.0.0IP ADDRESS OF FIRST HOST ON THIS SUBNET 172.17.0.1IP ADDRESS OF LAST HOST ON THIS SUBNET 172.17.255.254BROADCAST ADDRESS FOR THIS SUBNET 172.17.255.255

PROBLEM 5KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 32

IP ADDRESS 192.168.3.219SUBNET MASK 255.255.255.0

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

Total number of Subnet Mask = 11111111.11111111. 11111111.00000000

Network = 2^8 = 256

Number of Hosts Bits per Subnet = 8 bits

Number of Usable Hosts per Subnet= hosts = 2^8 = 256 – 2 = 254

NETWORK

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK192 168 3 0

11000000 10101000 00000011 00000000NETWORK = IP ADDRESS + SUBNET MASK192= 11000000 168=10101000 3= 00000011 219= 11011011 11111111 11111111 00000000 00000000 11000000 10101000 00000011 00000000NETWORK = 11000000101010000000001100000000

=192.168.3.0

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 33

FIRST HOST

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK192 168 3 0

11000000 10101000 00000011 00000000

FIRST HOST11000000 10101000 00000011 00000001

192 168 3 1

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast

NETWORK192 168 3 0

11000000 10101000 00000011 00000000

FIRST HOST11000000 10101000 00000011 00000001

192 168 3 1

LAST HOST

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK192 168 3 0

11000000 10101000 00000011 00000000

LAST HOST11000000 10101000 00000011 11111110

192 168 3 254

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

NETWORK192 168 3 0

11000000 10101000 00000011 00000000

LAST HOST11000000 10101000 00000011 11111110

192 168 3 254

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 34

BROADCAST

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 00000000

255 255 255 0

NETWORK192 168 3 0

11000000 10101000 00000011 00000000

BROADCAST11000000 10101000 00000011 11111111

192 168 3 255

BROADCAST = replace the number 0 to number 1 appearing on network address

NETWORK192 168 3 0

11000000 10101000 00000011 00000000

BROADCAST11000000 10101000 00000011 11111111

192 168 3 255

RESULTHOST IP ADDRESS 192.168.3.219SUBNET MASK 255.255.255.0NUMBER OF SUBNET BITS 8 BITSNUMBER OF SUBNET 2^8 = 256NUMBER OF HOST BITS PER SUBNET 8 BITSNUMBER OF USABLE HOSTS PER SUBNET 2^8 – 2 =256 – 2 = 254 host per subnetSUBNET ADDRESS FOR THIS IP ADDRESS 192.168.3.0IP ADDRESS OF FIRST HOST ON THIS SUBNET 192.168.3.1IP ADDRESS OF LAST HOST ON THIS SUBNET 192.168.3.254BROADCAST ADDRESS FOR THIS SUBNET 192.168.3.255

PROBLEM 6

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 35

IP ADDRESS 192.168.3.219SUBNET MASK 255.255.255.252

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

Total number of Subnet Mask = 11111111.11111111. 11111111.11111100

Network = 2^14 = 16384

Number of Hosts Bits per Subnet = 2 bits

Number of Usable Hosts per Subnet= hosts = 2^2 = 4 – 2 = 2

NETWORK

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK192 168 3 216

11000000 10101000 00000011 11011000NETWORK = IP ADDRESS + SUBNET MASK192= 11000000 168=10101000 3= 00000011 216= 11011000 11111111 11111111 00000000 11111100 11000000 10101000 00000011 11011000NETWORK = 11000000101010000000001111011000

=192.168.3.216

FIRST HOST

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 36

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK192 168 3 216

11000000 10101000 00000011 11011000

FIRST HOST11000000 10101000 00000011 11011001

192 168 3 217

First Host = replace the number 0 be the number 1 at 32 bits in the Broadcast

NETWORK192 168 3 216

11000000 10101000 00000011 11011000

FIRST HOST11000000 10101000 00000011 11011001

192 168 3 217

LAST HOST

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK192 168 3 216

11000000 10101000 00000011 11011000

LAST HOST11000000 10101000 00000011 11011010

192 168 3 218

Last host = replace a number from 0 to 1 on the host range subnet add except on the last bit remains 0.

NETWORK192 168 3 216

11000000 10101000 00000011 11011000

LAST HOST11000000 10101000 00000011 11011010

192 168 3 218

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 37

BROADCAST

IP ADDRESS192 168 3 219

11000000 10101000 00000011 11011011

SUBNET MASK11111111 111111111 11111111 11111100

255 255 255 252

NETWORK192 168 3 216

11000000 10101000 00000011 11011000

BROADCAST11000000 10101000 00000011 11011011

192 168 3 219

BROADCAST = replace the number 0 to number 1 appearing on network address

NETWORK192 168 3 216

11000000 10101000 00000011 11011000

BROADCAST11000000 10101000 00000011 11011011

192 168 3 219

RESULTHOST IP ADDRESS 192.168.3.219SUBNET MASK 255.255.255.252NUMBER OF SUBNET BITS 14 BITSNUMBER OF SUBNET 2^14 = 16384NUMBER OF HOST BITS PER SUBNET 2 BITSNUMBER OF USABLE HOSTS PER SUBNET 2^2 – 2 =4 – 2 = 2 host per subnetSUBNET ADDRESS FOR THIS IP ADDRESS 192.168.3.216IP ADDRESS OF FIRST HOST ON THIS SUBNET 192.168.3.217IP ADDRESS OF LAST HOST ON THIS SUBNET 192.168.3.218BROADCAST ADDRESS FOR THIS SUBNET 192.168.3.219

REFERENCE

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 38

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 39

KFC 2044 NETWORK FUNDAMENTALSMOHAMED FAIRULRASULIZAM BIN ABDUL RAZAK Page 40