Judith S. Olson and Gary M. Olson University of California ...
April 2010 (1) Prediction of Breed Composition & Multibreed Genomic Evaluations K. M. Olson and P....
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Transcript of April 2010 (1) Prediction of Breed Composition & Multibreed Genomic Evaluations K. M. Olson and P....
April 2010 (1)
Prediction of Breed Composition &
Multibreed Genomic Evaluations
K. M. Olson and P. M. VanRaden
April 2010 (2)
Background - Prediction of Breed 200 Breed specific SNP were used to
verify an animal received the correct breed code in the quality control data step
Several animals had fewer breed-specific SNPs and lower genomic relationships and inbreeding
Wanted to investigate a more precise way to look at breed composition
April 2010 (3)
Materials & Methods – Prediction of Breed
Y- Variable was breed of animal
Used both females and males
3 different sizes of SNP sets were used for the genomic evaluation
The Full 43,385 SNP set
The proposed 3 K SNP set
The 600 breed specific set
− Each breed has ~ 200 – used for the basic check currently not a genomic evaluation
April 2010 (4)
Materials & Methods – Prediction of Breed
Training data set – animal reliability set to 99% and parent average reliability set to 50%
Proven as of July 2009
Total of 14,039 animals across all breeds
Validation data set – reliabilities set to 0%
Unproven as of July 2009
15,809 animals across all breeds
April 2010 (5)
Results – Prediction of Breed
All three tests were able to determine a Holstein that was by pedigree 1/8 (12.5%) Jersey
43 K test predicted her as 85.9% Holstein and 13.3% Jersey
3 K predicted she was 84.4% Holstein and 15.5% Jersey
600 SNP set she was 83.0% Holstein and 16.6% Jersey
April 2010 (6)
Results – Prediction of Breed
SNP set/ Breed
43 K 3 K 600
Holstein(N = 14,794)
1.000±0.008 1.004±0.031 1.002±0.019
Jersey(N = 919)
0.996±0.028 0.978±0.063 0.989±0.036
Brown Swiss(N = 96)
0.994±0.021 0.989±0.036 0.992±0.051
Means and standard deviations for given breed of the validation data set
April 2010 (7)
Conclusions – Prediction of Breed The 43 K chip was the most accurate at
prediction of breed composition
The 3 K chip could identify individuals that had large amounts (> 13%) of foreign DNA
April 2010 (8)
Obstacles – Prediction of Breed
There is a patent
Located at http://www.patentstorm.us/patents/7511127/fulltext.html
May not be accurate for animals from different populations
foreign animals
older animals
April 2010 (9)
Background - Multibreed
Multibreed methods are currently used in traditional methods
Only within breed methods are used for genomics evaluations
Previous research has shown little improvement in accuracy from using all breeds with the 50K SNP chip however, little research has been done using multi-trait methodology
April 2010 (10)
Objectives – Multibreed genomic evaluations
To investigate three different methods of multibreed genomic evaluations using Holsteins, Jerseys, and Brown Swiss genotypes
April 2010 (11)
Materials & Methods – Multibreed (Animals)
The training data set - animals were proven by Nov. 2004 Holsteins – 5,331 Jerseys – 1,361 Brown Swiss – 506
The validation data set - animals were unproven as of Nov. 2004 and proven by June 2009 Holsteins – 2,477 Jerseys – 410 Brown Swiss - 182
April 2010 (12)
Material & Methods – Multibreed (Methods)
Method 1 estimated SNP effects within breed then applied those effects to the other breeds
Method 2 (across-breed) used a common set of SNP effects from the combined breed genotypes and phenotypes
Method 3 (multi-breed) used a correlated SNP effects using a multitrait method ( as explained by VanRaden and Sullivan, 2010)
April 2010 (13)
Results – P – Values for Protein Yield
Holstein Jersey Brown Swiss
Traditional
PTA < 0.001 < 0.001 0.061
GPTA < 0.001 < 0.001 0.086
R2adj 0.5045 0.4874 0.1030
Method 1
HOL GPTA < 0.001 0.668 0.344
JER GPTA 0.873 < 0.001 0.844
BSW GPTA 0.813 0.473 0.107
PTA < 0.001 < 0.001 0.054
R2adj 0.5041 0.4854 0.0978
April 2010 (14)
Results – P-values for protein yield
Holstein Jersey Brown Swiss
Method 2
PTA < 0.001 < 0.001 0.088
GPTA < 0.001 < 0.001 0.316
ABGPTA 0.002 0.290 0.007
R2adj 0.5063 0.4876 0.1337
Method 3
PTA < 0.001 < 0.001 0.080
GPTA 0.742 0.324 0.140
MBGPTA < 0.001 < 0.001 0.060
R2adj 0.5060 0.4916 0.1127
April 2010 (15)
Results – P-Values for protein yield
Holstein Jersey Brown Swiss
Method 2
PTA <0.001 < 0.001 0.2016
ABGPTA < 0.001 < 0.001 0.0023
R2adj 0.4742 0.4742 0.1336
Method 3
PTA < 0.001 < 0.001 0.055
MBGPTA < 0.001 < 0.001 0.081
R2adj 0.5060 0.4916 0.1067
The traditional GPTA was not included in these analyses
April 2010 (16)
Conclusions – Multibreed Genomic Evaluation
Method 1 did not help the estimates for genomic evaluations
Method 2 increased the predictive ability, however the traditional GPTA accounted for more variation than the across-breed GPTA
Method 3 increased the predictive ability and the multi-breed GPTA accounted for more variation than the traditional GPTA
April 2010 (17)
Implications
The multibreed genomic evaluations do slightly increase the accuracy of the evaluations, but may not warrant the increased computational demands
A higher density SNP chip would most likely increase the gains in accuracy for multibreed genomic evaluations
Multibreed would be needed for genomic selection in crossbred herds
Not much demand for that yet