Applying a Force. Impulse Momentum Conservation of Momentum Collisions Momentum.

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Applying a Force

Transcript of Applying a Force. Impulse Momentum Conservation of Momentum Collisions Momentum.

Page 1: Applying a Force. Impulse Momentum Conservation of Momentum Collisions Momentum.

Applying a Force

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ImpulseMomentum

Conservation of MomentumCollisions

Momentum

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ImpulseThe product of force and contact time

Vector quantity, Symbol: JDirection is the same as the net or

average force appliedUnits: N-s, kg-m-s-1

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Momentum

Product of mass and velocityVector quantity, Symbol: p

Direction is the same as the velocity

Units: kg-m-s-1

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Large Force, Short Contact Time

Can you give other examples?

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Small Force, Long Contact TimeAirbags

Seatbelt

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Small Force, Long Contact TimeCatching a baseball

Bungee Jumping

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Example

A cricket ball, mass 0.5 kg, was bowled at50 m s-1 at a batsman who misreads theball and the 5 kg bat is knocked out ofhis hands, the ball rebounds at 25 ms-1.

What is the change in momentum of the ball?If the bat was in contact with the ball for 2.0

ms, how much force did the batsman apply on the ball?

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Conservation of Momentum

Total momentum before is equal to total momentum after

In a closed system (external forces are negligible)

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Inelastic CollisionOnly momentum is conserved

Perfectly inelastic collision(The colliding bodies couple after

the collision)

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Example

A railway wagon travelling at 1.0 m s–1 catches up with and becomes coupled to another wagon travelling at 0.5 m s–1 in the same direction. The faster moving wagon has 1.7 times the mass of the slower one. Immediately after impact, what is the speed of the coupled wagons?

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Elastic Collision

Momentum is conserved.Kinetic Energies are conserved.

(Relative Velocities) are conserved.Analyzing billiard balls

Simulation

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ExampleA trolley of mass 1 kg rolls along a level,

frictionless ramp at a speed of 6 m s-1. It collides with a second trolley of mass 2 kg which is initially at rest. The first trolley rebounds at a speed of 2 m s-1.Find, by conservation of momentum, the

velocity of the second trolley after the collision.

Compare the kinetic energy before and after the collision. Is the collision elastic?

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ExampleA ball of mass 0.20 kg is dropped from a

height of 3.2 m onto a flat surface which it hits at 8.0 m s-1. It rebounds to 1.8 m. (g = 9.8 m s-2)What is the rebound speed just after impact?What is the change in energy of the ball?What momentum change has the ball between

just touching the surface and leaving it?

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