Ansys Lab Manual

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Experiment 1

STRUCTURAL ANALYSIS OF A CANTILEVER BEAM OF UNIFORMLY

VARYING I-SECTION

Aim:-

To model and analyze a uniform varying I-section beam for stress and deflection for cantilever condition with different loading conditions.

Tools Required:- 1) Pc with Pentium IV processor. 2) Ansys software.

Procedure:- The modules available in ANSYS are,

i. Preferences

ii. Pre-Processor

iii. Solution iv. General Post -Processor

1. In pre-processor module, the element type for analysis is chosen by, Pre-Processor > Element Type > Add > Beam 2D elastic.

2. The area, moment of inertia Izz are given by,

Pre-Processor > Real Constants > Add 3. Define the I-section by,

Section > Beam > Common Sections > Define the I- Section. 4. A line is created between two nodes which represents the beam by,

Modeling > Create > Nodes > In Active Cs Modeling > Create > Elements > Auto Numbered > Thru Nodes > Define the Two Nodes.

5. The Isection is created through nodes by, Section > Tapered Section > By Picked Nodes > Define I-Section.

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6. In cantilever beam one end is fixed. It is defined by, Solution > Loads > Structural > Displacement > All D.O.F > Pick location at the Node1.

7. The load is applied at another end of the beam so the load is applied on the node2 by, Solution > Loads > Structural > Force > On Nodes > Pick- the Node2.

8. Now the system is ready to solve the problem. It can be done by, Solution > Solve > Current LS.

9. The deflection is found at end which is maximum by, General Post-Processor > Plot Results > Contour Plot > Nodal- Solution > DOF Solution > Y- Component Displacement.

10. The bending moment diagram is also obtained by defining a element table by,

General Post-Processor > Element Table > Define Table. General Post-Processor > Plot Results > Contour Plot >Line

Element Table. 11. The maximum bending stress diagram is also obtained by defining a element

table.

Problem Specification:-

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Calculation:- Where

P-Load Applied = 100 N L-Length of the Beam = 500 mm B-Breadth of the Beam H-Height of the Beam

E-Young Modulus

BENDING MOMENT M=P*L =100*500 =50000 N-mm

MOMENT OF INERTIA

I = (bh3-b1h13) /12 = ((75*753)-(67.5*603)) /12 =1421718.75 mm4

MAXIMUM DEFLECTION OF CANTILEVER BEAM

=PL3 /3EI

= (100*5003) /(3*2*105*1421718.75) =0.01465 mm MAXIMUM BENDING STRESS OF CANTILEVER BEAM

b= My /I

=50000*37.5 / 1421718.75 =1.3188 N / mm2

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Cantilever Beam with Varying I-Section Deflection

Bending Moment Diagram

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Maximum Bending Stress

Results Comparison:-

Cantilever beam of varying I-section with Point Load

Result Deflection (mm) Bending moment

(N-mm) Maximum Stress

(N/mm2)

Analytical 0.01469 50000 1.3188

FEA 0.014671 50000 1.32

Result:-

Thus a uniformly varying I-section beam with cantilever condition is analyzed for stress, deflection values by using ANSYS.

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Experiment 2 STRUCTURAL ANALYSIS OF SIMPLY SUPPORTED BEAM

Aim:- To model and analyze a rectangular beam for stress, strain and deflection for simply supported condition with different loading conditions.

Tools Required:- 1) PC with Pentium IV 2) ANSYS 10.0 software

Procedure:- The modules available in ANSYS are

i. Preferences ii. Pre- Processor

iii. Solution iv. General Post Processor module

1. In Pre Processor module, element type for analysis in chosen by Pre- Processor > Element type > Add > Beam.

2. The Area, Moment of Inertia Izz are given by Pre Processor > Real constants > Add.

3. A line is created between two key points which represent the beam by Modeling > create > Key point > In creative C.S Modeling >create > Lines >between key points.

4. The line is divided into finite no. of elements by Meshing > mesh tool > lines > set and meshing > mesh tool > mesh.

5. The boundary condition is defined at the both end after beam by arresting displacements in Y- direction by

Solution > loads > structural > displacement > on nodes >arrest UY.

Case (i):- With Load Acting at the Centre of the Beam.

a) Center load is applied on the nodes at the centre by solution> loads > Structural force > on nodes.

b) Now the system is ready to solve and is done by solution > solve > current L.S. c) The deflection is found at centre which is maximum by general post processor >

Plot result > counter plot > nodal solution.> DOF solution > displacement vector sum.

d) The bending moment diagram is also obtained by defining the element table by General post processor > plot result > counter plot > line element table.

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Case (ii):- With Offset Load

a) For offset loading. The work plane is shifted at the required position on the line and the load is applied .

b) Results are taken for this condition.

Case (iii):- With Uniformly Distributed Load.

a) The beam is now subjected to UDL by solve > loads > apply > structural >beam. b) The system is now solved and the results are obtained.

Problem Definition:-

Case (i):- center load

Cross sectional dimensions of the beam b=d=10mm

Bending Moment:

M max = W L / 4 = (1000 100) / 4 M max = 25000 N-mm.

M.O.I, ( I ) = bd3 / 12 = (10 103) / 12 = 833.33 mm4 Y = 10/2 = 5mm.

Max. Bending Stress: max = ( M max Y) / I

max = (25000 5 ) / 833.33 = 150 N/mm2.

Deflection, Y max = WL3 / 48EI

= (1000 1003) / (48 2 105 833.33)

Y max = 0.125 mm.

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Case (ii):- Offset Load

M max = W a b / L = (1000 25 75) / 100

M max = 18750 N-mm.

max = (M max Y ) / I = (18750 5) / 833.33 max = 112.5 N/mm2

Ymax = (W a ) [ b2 + 2ab] /(9 3 E I L) = 100 25 [ 752 + (2 25 75)] /(9 3 2 105833.33 100) Ymax = 0.087mm.

Case (iii):- Uniformly Distributed Load:

M max = Wl2 / 8 = (100 1002) / 8

M max = 125000 N-mm.

max = M max x Y / I = (125000 5) / 833.33

max = 750 N/mm2.

Y max = 5 WL4 / 384 EI = (5 100 1004) / (384 2 105 833.33)

Y max = 0.78125 mm.

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Case (i):- Simply Supported Beam with Point Load at Midpoint

1. Deflection

2. Bending Moment Diagram

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3. Maximum Bending Stress

Results Comparison

Simply Supported Beam with Point Load at Midpoint



(N/mm2)

Analytical 0.125 25000 150

FEA 0.125 25000 150

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Case (ii):- Simply Supported Beam with Point Load Acting Offset

1. Deflection


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Results Comparison

Simply Supported Beam with Point Load Acting Offset



(N/mm2)

Analytical 0.087 18750 112.5

FEA 0.087 18750 112.5

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Case (iii):- Simply Supported Beam with Uniformly Distributed Load

1. Deflection


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Results Comparison

Simply Supported Beam with Uniformly Distributed Load



(N/mm2)

Analytical 0.78125 125000 750

FEA 0.78125 125000 750

RESULTS: Thus a rectangular beam for simply supported condition with different loading condition is analyzed for stress, strain and deflection.

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Experiment3 STRUCTURAL ANALYSIS OF A FIXED BEAM

Aim:- To model and analyze a rectangular beam for stress, strain and deflection for fixed condition with load acting at center.

Tools Required:- 1) PC with Pentium IV 2) ANSYS 10.0 software




1. In Pre Processor module, element type for analysis in chosen by Pre- Processor > Element type > Add > Beam.


2. A line is created between two key points which represent the beam by Modeling > create > Key point > In creative C.S Modeling >create > Lines >between key points.


4. The boundary condition is defined at the both end after beam by arresting displacements in All-DOF by

Solution > loads > structural > displacement > on nodes >arrest All DOF 5. Center load is applied on the nodes at the centre by

Solution> loads >structural force > on nodes. 6. Now the system is ready to solve and is done by

Solution > solve > current L.S. 7. The deflection is found at centre which is maximum by

General post processor >Plot result > counter plot > nodal solution.> DOF solution > displacement vector sum.

8. The bending moment diagram is also obtained by defining the element table by General post processor > plot result > counter plot > line element table.

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Where as b=d=10mm.

Calculations:- Bending Moment:

M max = W L / 8 = (1000 100) / 8 M max = 12500 N-mm.

M.O.I, (I) = bd3 / 12 = (10 103) / 12 = 833.33 mm4

Y = 10/2 = 5mm.

Max. Bending Stress: max = ( M max Y) / I

max = (12500 5 ) / 833.33 = 75 N/mm2.

Deflection:- Y max = WL3 / 192EI

= (1000 1003) / (192 2 105 833.33)

Y max = 0.031 mm.

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FIXED BEAM WITH CENTRE LOAD 1. Maximum Deflection


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Fixed Beam With Centre Load

Max. Deflection ( mm)

Bending Moment ( N- mm )

Max. Stress ( N/mm2 )

Analytical Result 0.031 12500 75

FEA Result 0.03125 12500 75

Results:- Thus a rectangular beam for fixed condition with centre load condition is analyzed for stress, strain and deflection by using ANSYS.

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Experiment 4 STRESS ANALYSIS OF A PLATE WITH HOLE

Aim:-

To analyze a finite width plate with a circular transverse hole by FEA method and compare the results with those of mathematical analysis by Howland. Tools:-

1) PC with Pentium IV processor 2) ANSYS 10.0 Software

Procedure:- 1. A new ANSYS analysis file is opened at the required directory with job name. 2. For modeling the plate PLANE 82 element (i.e) a plate element with thickness

is chosen and axi-symmetric option is enabled. 3. In real constants step, the thickness of the plate is given.

4. The material is specified in material models (i.e) Youngs modulus and Poissons ratio.

5. The quarter portion of plate is modeled as an area using Modeling > Create > Area > by lines.

6. FEA model is created by meshing the area by free mesh option with a reasonable element size.

7. The material conditions are applied by Loads > Apply > Structural > Displacement on lines.

8. The pressure is applied by using Loads > Apply > Pressure on lines.

9. The FEA model with all boundary and loading conditions is then solved by Solution > Solve > Current LS.

10. The Y-directional stress results are listed and maximum stress results are tabulated.

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11. The analysis is repeated by varying the hole diameters 10mm, 15mm, 20mm and 25mm.

12. The graphs with FEA results ant that of Howlands mathematical results are compared.

13. The stress concentrated value Kt is calculated by formula given and the graph is drawn against Kt and a/w ratio.

Problem Specifications:-

Calculations:- Stress concentration factor Kt = max /nom. Where,

max - Maximum stress from FEA method. nom - Nominal stress.

nom = PA/ (w-a) t Where,

w- Width of plate a- Diameter of hole

P- Applied load A- Area of the plate

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Case 1:-

When a= 10mm nom = 100*100*10\ (100-10)*10

= 111.11 N\mm2

From ANSYS, FEA results,

max = 304.99 N\mm2

Stress concentration factor Kt = 304.99/111.11 = 2.7449 a/w ratio = 10/100

= 0.1 Stress Analysis of a Plate with a Hole

FEA Model

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Stress Results (Zoomed):

FEA Results:-

Node Maximum Stress ( Mpa ) Diameters 5 Dia. 10 Dia. 15 Dia. 20 Dia.

Max Sress(Mpa) 303.178 346.609 403.384 499.612

Tabulation:-

Diameter (mm) a/w Nominal Stress(Mpa) Max Stress(Mpa) Kt 5 0.05 55.55 303.178 5.45

10 0.1 111.11 346.609 3.11 15 0.15 166.66 403.384 2.42 20 0.2 222.22 499.612 2.24

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Result:-

Thus the plate with hole, the stress results are obtained and the FEA results and mathematical results are compared.

Finite Width with a Transverse Hole

01

234

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0 0.05 0.1 0.15 0.2 0.25a/w

Kt

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Experiment 5 STRESS ANALYSIS OF AN AXI-SYMMETRIC COMPONENT

Aim:- To analyze a cylindrical pressure vessel (axi-symmetric) for hoop stress and longitudinal stress results.

Tools:- 1) PC with Pentium IV 2) ANSYS 10.0 software

Procedure:- 1. The element type is chosen to be PLANE A2 and the axi-symmetric option is

enabled to avoid modeling the whole vessel. 2. The material properties are specified such as youngs modulus, Poissons

ratio. 3. The areas are created and meshed by mapped mesh option. 4. The constraints are specified at the required locations. 5. The pressure load is applied at the inner side of the area. 6. The model is now solved by solution >solve> current LS 7. The results of Hoop stress, longitudinal stress are plotted and are tabulated,

compared with theoretical results.


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Where:- P =10MPa E =2105 N/mm2 d = 200mm t = 3mm

Calculation:

1. Hoop stress 2 = )t2(Pd

= (10200) (23) = 333.33 N/mm2

2. Longitudinal stress 1= )t4(Pd = (10200) (43) = 166.66 N/mm2

Analysis of an Axi-Symmetric Cylindrical Pressure Vessel

Hoop Stress Result

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Longitudinal Stress Result

Hoop Stress Result

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Longitudinal Stress Result

Analysis of a Cylindrical Pressure Vessel

Hoop Stress(N/mm2) Longitudinal stress(N/mm2) FEA Results 342.23 168.52

Theoretical Results 333.33 166.66

Results:- Thus the axi-symmetric pressure vessel is analyzed for hoop and longitudinal stress and the results are obtained and are compared with theoretical calculation.

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Experiment 6 HEAT TRANSFER IN A FIN

Aim:- To analyze heat transfer from the extended surfaces for temperature and heat flux through fin of given dimensions.

Tools:- 1) PC with Pentium IV 2) ANSYS 10.0 Software

Procedure:- 1. A new ANSYS file is opened and the element type is chosen as solid brick

node. 2. The analysis type is chosen to be thermal the material is specified with values

of thermal conductivity. 3. The fin with required dimension is modeled. 4. After meshing the base temperature Tb is specified at one surface and of the

fine. 5. The ambient temperature T2 and film coefficient is specified at the remaining

surface area of the fin. 6. The system is now solved for temperature distribution, total heat flux. 7. The results were compared with theoretical results and tabulated.


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Calculation:- At the end of the fin: Temperature Perimeter P = 2(b+t) = 2(20.2*10^-2) m. Area A = (b*t) = (20*0.2*10^-4) m2 m= (hp/ka) 1/2 = ((10*2*20.2*10^-2)/ (204*20*0.2*10^-4)) 1/2 =7.036 Temperature at end T = (T-25)/ (350-25) =cosh [m(l-l)] / cosh (ml) = cosh (0)/cosh (7.036*0.5) T-25 = 0.0593*325 Therefore T = 44.3oC.

Convective heat transfer of a fin 1. Temperature Result

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2. Thermal Gradient Result

3. Total Thermal Flux Result

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Result for convective heat transfer of a fin at varying distance

Sl. No. Distance from base (mm) Node No. FEA Result for

Temperature(C) Theoretical Result for

Temperature(C)

1 0 1 350 350

2 100 17 186.01 186.246

3 200 14 105.46 105.665

4 300 11 66.575 66.694

5 400 8 49.119 49.228

6 500 5 44.054 44.3

Results:- Thus the temperature and flux results of heat temperature transfer through a fin is obtained and compared with theoretical results.

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Experiment 7 MODAL ANALYSIS OF A CANTILEVER BEAM

Aim:- To perform modal analysis of a cantilever beam using ANSYS

Tools:- 1) PC with Pentium IV Processor 2) ANSYS Software

Procedure:-

Modulus of Elasticity (E) = 206800(106) N/m2 Density = 7830 kg/m3

1. The modules available in ANSYS are i. Preferences

ii. Pre-Processor iii. Solution iv. General post processor module

2. In the pre-processor module the element type for the analysis of the cantilever beam is chosen

Pre-processor > element type > add > beam3 > 2DELASTIC 3

3. The area, moment of inertia Izz, height is given. Main menu > Pre-processor > real constants > add

4. Create two keypoints and a line to connect the points. Modeling > create > key points > increative c.s Modeling > create > lines > between keypoints.

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5. Mesh the line using mesh tool. Main menu > Pre-processor > Meshing > mesh tool > line > mesh.

6. The boundary condition is defined for the beam. Solutions > load > structural > displacement > on Keypoints > all DOF.

7. Solution: Assigning loads and solving, Define analysis type Solution > analysis type > new analysis > modal ANTYPE, 2

8. Set options for analysis type: Solution > Analysis type > Analysis options. Enter 5 for no. of modes to extract and no. of modes to expand in subspace and

Expand mode shapes.

9. Reduced method is chosen.

10. Apply constrains Solution > Define loads > Apply > Structural > Displacement < On Keypoints.

11. Solve the system Solution > Solve > Current LS

12. Postprocessing: Viewing the results General postproc > Result Summary.

13. To view mode shapes General postproc > Read results > First set General postproc > Plot results > Deformed shape Repeat the process for the next set to view the next mode shapes.

14. To Animate mode shapes Utility menu > Plot ctrls > Animate > Mode shapes

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Modal Analysis of a Cantilever Beam

First Mode Shape

Second Mode Shape

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Third Mode Shape

Fourth Mode Shape

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FEA Result:-

Mode Set Frequency

1 1 8.30

2 2 52.009

3 3 145.6

4 4 285.25

5 5 471.39

Result:- Thus the cantilever beam is modeled and analyzed in ANSYS for Modal analysis. Various mode shapes and respective frequencies are obtained.

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Experiment 8 MODEL ANALYSYS OF A CANTILEVER -2D PLATE

Aim:- To perform modal analysis of a cantilever plate using ANSYS

Tools:- 1) PC with Pentium IV 2) ANSYS software

Problem specification:-

Modulus of Elasticity = 206800(106) N/m2 Poisson Ratio = 0.27 Density = 7830 kg/m3

Procedure:- 1. The modulus available in ANSYS are

i. Preferences ii. Pre-processor

iii. Solution iv. General Post processor

2. In pre-processor module, the element type for analysis is chosen by Preprocessor> Element type >Add>Beam 2D.

3. The area, moment of inertia are given by Pre-processor>real constant>Add.

4. A line is created between two key points which represent the beam by Modeling> Create>Key point > Inactive C.S and create > lines >b/n Key points.

5. The line is divided into a finite number of elements by Meshing > mesh tool> lines >set and mesh > free mesh.

6. The constraint is given by Solution>Define loads> apply> Structural > Displacement > On Lines.

7. Then specify the analysis type as static by using Solution > Analysis type > New analysis > Model

8. Activate the pre-stress effects by Solution > Analysis type > Analysis option.

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9. The constraint is given by Solution>Define loads> apply> Structural > Displacement > on key point and fix the

key point 1. 10. Then, Solution> Solve > Current L.S. 11. In post-processing, General post processing > Result Summary. 12. To view the mode shape, General post processing > Read result > First Set. 13. To view the result, General post processing > Plot results > Deformed and

Undeformed shape.

Modal Analysis of Cantilever 2D-Plate

First Mode Shape

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Second Mode Shape

FEA Results:-

Mode Set Frequency

1 1 356.01

2 2 1289.3

3 3 1363.5

4 4 2859.1

5 5 3669.1

Result:- Thus the cantilever plate is modeled and analyzed in ANSYS for Modal analysis. Various mode shapes and respective frequencies are obtained. .

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Experiment 9 MODAL ANALYSIS OF A SIMPLY SUPPORTED BEAM

Aim:- To perform modal analysis of a simply supported beam using ANSYS

Tools:- 1) PC with Pentium IV Processor 2) ANSYS Software

Procedure:- 1. The modules available in ANSYS are

i. Preferences ii. Pre-Processor

iii. Solution iv. General post processor module

2. In the pre-processor module the element type for the analysis of the cantilever beam is chosen

Pre-processor > element type > add > beam3 > 2DELASTIC 3

3. The area, moments of inertia Izz, height are given. Main menu > Pre-processor > real constants > add

4. Create two keypoints and a line to connect the points. Modeling > create > key points > inactive c.s Modeling > create > lines > between keypoints.

5. Mesh the line using mesh tool. Main menu > Pre-processor > Meshing > mesh tool > line > mesh.

6. The boundary condition is defined for the beam. Solutions > load > structural > displacement > on keypoints > UY

7. Solution: Assigning loads and solving Define analysis type Solution > analysis type > new analysis > modal ANTYPE, 2

8. Set options for analysis type: Solution > Analysis type > Analysis options. Enter 5 for no. of modes to extract and no. of modes to expand in subspace and

Expand mode shapes.

9. Reduced method is chosen.

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10. Apply constrains Solution > Define loads > Apply > Structural > Displacement < On keypoints.

11. Solve the system Solution > Solve > Current LS

12. Postprocessing: Viewing the results General postprocessing > Result Summary.

13. To view mode shapes General postprocessing > Read results > First set General postprocessing > Plot results > Deformed shape Repeat the process for the next set to view the next mode shapes.

14. To Animate mode shapes Utility menu > Plot ctrls > Animate > Mode shapes


Modulus of Elasticity (E) = 206800(106)N/m2 Density = 7830 kg/m3

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Modal Analysis of a Simply Supported Beam

First mode shape

Second mode shape

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Third mode shape

Fourth mode shape

Result:- Thus the simple supported beam is modeled and analyzed in ANSYS for Modal analysis. Various mode shapes and respective frequencies are obtained.

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Experiment 10 STRUCTURAL ANALYSIS OF A L BRACKET

Aim:- To model and analyze a rectangular beam for stress, strain and deflection for L-bracket with point load

Tools Required:- 1) PC with Pentium IV 2) ANSYS software




1. In Pre Processor module, element type for analysis in chosen by Pre- Processor > Element type > Add > Solid > Brick 8 node 82

2. The Material properties are given by Pre Processor > Material modal > Linear

3. A line is created between two key points which represent the beam by Modeling > create > Volume > Block > By Dimension Modeling >Operate > Boolean > Add > Areas.

4. The area is divided into finite no. of elements by Meshing > mesh tool > lines > set and meshing > mesh tool > mesh.

5. The boundary condition is defined at the both end after beam by arresting displacements in Y- direction by

Solution > loads > structural > displacement > on areas >arrest All DOF. 6. Load is applied on the nodes at the top edge by solution> loads >

Structural force > on nodes. 7. Now the system is ready to solve and is done by solution > solve > current L.S. 8. The deflection is found at centre which is maximum by general post processor >

Plot result > counter plot > nodal solution.> DOF solution > displacement vector sum

9. The stress is also obtained by General post processor > plot result > counter plot > Nodal solution

Calculation:- Where:-

b = 75mm; d = 20mm and t = 75mm.

Max. Stress: max =( 6*P*t)/ (b*d2) max = (6*2000*75)/(75*20^2)

= 30 N/mm2.

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Problem Definition:-

Stress Analysis of a L- Bracket 1. FEA Constrained

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2. Maximum Stress


Stress Analysis of a L- Bracket

Result Maximum Stress (N/mm2)

Analytical 30

FEA 32.667

Results:- Thus an L-bracket with load act at top edge condition is analyzed for stress, strain and deflection.

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Experiment 11 THERMAL ANALYSIS OF A BEAM

Aim:- To model and analyze a rectangular beam for thermal stress and strain by using ANSYS software.

Tools Required:- 1) PC with Pentium IV 2) ANSYS software

Procedure:- 1. The modules available in ANSYS are



2. In Pre Processor module, element type for analysis in chosen by Pre- Processor > Element type > Add > link (Thermal mass) > link33.


4. A line is created between two key points which represent the beam by Modeling > create > Key point > In active C.S Modeling >create > Lines >between key points.


6. The material properties are given by Thermal > conductivity > isotropic.

7. Select preprocessor > physics > environment > write then choose thermal. 8. Select element type > switch element type > choose thermal to structural. 9. Give the material properties are given by

structural > linear > isotropic and then thermal expansion coef > isotropic > ALPX.

10. Solution > analysis > new analysis > static. 11. Select solution > physics > environment > read then choose thermal. 12. Temperature is given by

solution > apply > thermal > temperature>set temperature at keypoint1. 13. Solution > solve > current L.S. 14. Select solution > physics > environment > read then choose structural 15. The boundary condition is defined at the both end after beam by arresting

displacements in All-DOF by Solution > loads > structural > displacement > on keypoints >arrest All DOF at keypoint1and arrest UX direction for keypoint2.

16. Solution > loads > structural >temperature > thermal analysis. 17. Solution > loads > define loads > settings > reference temperatures

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18. Solution > solve > current L.S. 19. the thermal stress result is given by

general post-processor > element table > define table > add > LS1


Where = Thermal coefficient = 0.000012/ok E = Young modulus = 2x1011 N/m2 L = length of the beam = 1 m A = Area of the c/s = 4x10-4 m2 Kxx = Thermal conductivity = 60.5 W/mK T = Temperature = 348 K Ta = Reference temperature = 273 K ALPX = Thermal expansion coefficient = 12x10-6/ K

Calculation:- Thermal stress

= -ET = - 0.000012(200x109) (348-273) = -0.18x109 Pa = -180 Mpa

Result Comparison:-

Thermal Analysis Result Thermal stress (MPa) FEA -180 Analytical -180

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Thermal stress

Result:- Thus the model is thermal analyzed for the given temperature by using ANSYS software. Thermal stresses for the given conditions are obtained.

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Experiment 12 HARMONIC ANALYSYS OF A CANTILEVER BEAM

Aim:- This tutorial was created using ANSYS. The purpose of this tutorial is to explain the Harmonic Analysis of a cantilever beam..

Tools:- 1) PC with Pentium IV 2) ANSYS software

Procedure:-

1. The modulus available in ANSYS are i. Preferences

ii. Pre-processor iii. Solution iv. General Post processor

2. In pre-processor module, the element type for analysis is chosen by preprocessor> Element type >Add>Beam 2DELASTIC3 ( beam3).

3. The area, moment of inertia are given by Pre-processor>Real constant> Add/Edit/Delete.

4. A line is created between two key points which represent the beam by Modeling> Create>Key point > Inactive C.S and create > lines > straight line > b/n Key points.

5. The line is divided into a finite number of elements by Meshing > mesh tool> mesh.

6. Then specify the analysis type as static by using Solution > Analysis type > New analysis > Harmonic ANTYPE,3.

7. Activate the pre-stress effects by Solution > Analysis type > Analysis option.

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8. The constraint is given by Solution>Define loads> apply> Structural > Displacement > on nodes.

9. The constraint is given by Solution>Define loads> apply> Structural > Force /Moment > on nodes.

10. Set the frequency range by using Solution > Load step option> Time / Frequency > Frequency and sub steps.

11. Then, Solution> Solve > Current L.S. 12. Choose the Time Hist-postprocessor > define variable > add (green +sign in the

upper left corner) and get displacement values of Y- component. 13. Select the node point 2 and then choose the List option. 14. Then displays the plot diagram UY Vs frequency. 15. Select plot control > style > graphs > modify axis a dialogue box is displayed and

choose logarithmic mode. 16. Then select plot > replot.

This is response of Harmonic Analysis of the cantilever beam for the cyclic load applied at this node from 0 100 Hz.

Time Frequency AMPLITUDE PHASE 1.0000 5.60612 180.000 2.0000 12.6028 180.000 3.0000 2.18990 180.000 4.0000 0.864773 0.00000 5.0000 4.48152 180.000 6.0000 1.23420 180.000 7.0000 0.492995 180.000 8.0000 0.120610 0.00000 9.0000 7.42384 0.00000 10.000 0.999670 180.000 11.000 0.487998 180.000 12.000 0.264899 180.000 13.000 0.859443E-01 180.000 14.000 0.195725 0.00000 15.000 18.0932 0.00000 16.000 0.562964 180.000 17.000 0.301262 180.000 18.000 0.191138 180.000 19.000 0.114949 180.000 20.000 0.408898E-01 180.000 21.000 0.716641E-01 0.00000 22.000 0.559259 0.00000 23.000 0.590390 180.000 24.000 0.248688 180.000 25.000 0.160013 180.000

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26.000 0.111419 180.000 27.000 0.750600E-01 180.000 28.000 0.406758E-01 180.000 29.000 0.185636E-02 0.00000 30.000 0.823647E-01 0.00000 31.000 0.587971 0.00000 32.000 0.352896 180.000 33.000 0.165215 180.000 34.000 0.110859 180.000 35.000 0.811883E-01 180.000 36.000 0.598923E-01 180.000 37.000 0.414967E-01 180.000 38.000 0.226046E-01 180.000 39.000 0.133143E-02 0.00000 40.000 0.429971E-01 0.00000 41.000 0.187482 0.00000 42.000 0.502578 180.000 43.000 0.148045 180.000 44.000 0.933211E-01 180.000 45.000 0.684822E-01 180.000 46.000 0.527021E-01 180.000 47.000 0.405900E-01 180.000 48.000 0.298874E-01 180.000 49.000 0.190946E-01 180.000 50.000 0.643917E-02 180.000 51.000 0.117374E-01 0.00000 52.000 0.480790E-01 0.00000 53.000 0.217821 0.00000 54.000 0.258865 180.000 55.000 0.101841 180.000 56.000 0.673190E-01 180.000 57.000 0.507355E-01 180.000 58.000 0.401021E-01 180.000 59.000 0.320456E-01 180.000 60.000 0.251562E-01 180.000 61.000 0.186102E-01 180.000 62.000 0.116804E-01 180.000 63.000 0.334828E-02 180.000 64.000 0.852847E-02 0.00000 65.000 0.306322E-01 0.00000 66.000 0.104253 0.00000 67.000 0.422084 180.000 68.000 0.948660E-01 180.000 69.000 0.583307E-01 180.000 70.000 0.431823E-01 180.000

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71.000 0.342583E-01 180.000 72.000 0.279384E-01 180.000 73.000 0.228810E-01 180.000 74.000 0.184291E-01 180.000 75.000 0.141595E-01 180.000 76.000 0.969035E-02 180.000 77.000 0.452101E-02 180.000 78.000 0.226126E-02 0.00000 79.000 0.128972E-01 0.00000 80.000 0.354872E-01 0.00000 81.000 0.143716 0.00000 82.000 0.168375 180.000 83.000 0.648751E-01 180.000 84.000 0.428801E-01 180.000 85.000 0.326962E-01 180.000 86.000 0.264466E-01 180.000 87.000 0.219557E-01 180.000 88.000 0.183629E-01 180.000 89.000 0.152384E-01 180.000 90.000 0.123155E-01 180.000 91.000 0.937993E-02 180.000 92.000 0.619860E-02 180.000 93.000 0.243081E-02 180.000 94.000 0.256384E-02 0.00000 95.000 0.103218E-01 0.00000 96.000 0.259931E-01 0.00000 97.000 0.854140E-01 0.00000 98.000 0.207898 180.000 99.000 0.592344E-01 180.000 100.00 0.373391E-01 180.000

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Harmonic Analysis of a Cantilever Beam

1. FEA model

2. Plot Diagram for UY Vs Frequency for Various values

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Result:- Thus the cantilever beam is applied cycling load of frequency 0 100 Hz. Maximum displacement of the beam is obtained by using ANSYS.

Ansys Lab Manual

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Transcript of Ansys Lab Manual