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Page 1 Unproctored - Mock CAT 11____ _____ __

__________ _________

_______ __ ____________1 c 2 c 3 d 4 b 5 c 6 b 7 c 8 b 9 b 10 d11 d 12 d 13 c 14 b 15 a 16 a 17 a 18 c 19 b 20 a21 c 22 d 23 b 24 d 25 b 26 d 27 a 28 d 29 d 30 a31 b 32 b 33 a 34 d 35 a 36 c 37 d 38 a 39 d 40 b41 d 42 c 43 a 44 b 45 b 46 b 47 d 48 c 49 d 50 b51 d 52 d 53 d 54 c 55 a 56 a 57 c 58 b 59 d 60 b61 c 62 d 63 c 64 c 65 b

Page 2 Unproctored - Mock CAT 11____ _____ __1. c Let the number of chocolates of varieties A, B and C bought

by Salim be a, b and c not necessarily in that order.Therefore, a2 + (a + 5)2 + c2 = 7(2a + 5 + c)or, 7c + 10 c2 = 2a2 4a.

Also, a2+ (a + 5)2 + c2< 100 ...(i)From (i) we get to know that a can be 1 or 2 or 3 or 4.For a = 1, 2 or 3 we do not get an integer value for c.

If a = 4, then c = 1. In this case b = 9.So, the price of 1 chocolate of varieties A, B and C is 9, 4 and1 respectively.

Short cut method:Since A is the costliest variety of chocolate among the3 varieties and the average price paid by Salim for each

chocolate is Rs. 7, therefore the price of 1 chocolate of varietyA has to be greater than Rs. 7.There is only 1 option which is greater than Rs. 7.

2. c Let X be the external angle of a polygon whose internal angleis the largest. Then other two external angles of other twopolygons are (X + 15) and (X + 27).

So X + (X + 15) + (X + 27) = 177

3X = 135 X = 45.Now external angle360 360= or 45 = or n = 8,

n nwheren is the total number of sides of the polygon with the largest

internal angle.Therefore one polygon has 8 sides and the other polygonshave 6 and 5 sides respectively.

Hence the sum of sides of all the three regular polygons= 8 + 6 + 5 = 19.3. d M = ABC and N = CBA

M N + 396C= (100A + 10B + C) (100C + 10B + A) + 396C

M N + 396 C = 99(A C + 4C)

99(A + 3C) = 990 A + 3C = 10Possible values of A and C that satisfy A + 3C = 10 or1C (10 A) are given by :

3

!A 1 4 7C 3 2 1Now, since the three digit number is greater than 300.

A cannot be equal to 1. B can take any value from0 to 9.Therefore the number of such three digit numbers

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= 10 2 = 20.4. b Let the number of balls with A1, A2, A3, A11 be a 5d, a 4d,

a 3d, a + 5d respectively.Therefore, the number of balls with A1, A3, A5, A7, A9 and A11will be 6a.

6a = 72 or a = 12Number of balls with A1, A6 and A11 = a 5d + a + a + 5d = 3a

= 36.

5. c Let the number of Benos be BSo, the number of Malos will be 139 + B.

Therefore, B + 139 + B = 550092B = 55009 139, B = 27435Therefore the total number of Malos residing in the island =

55009 B = 27574.Hence, option (c) is the correct choice.6. b Let l be the initial quantity of diluted milk in the can and the

initial concentration of milk be m%.

!ml30.

l 35

!mlAlso, 20

l 75

2(l + 75) = 3(l + 35) l = 45 and ml = 2400.If w litres of water is required to be added to the can to makethe concentration of milk in the can 8% then

ml 24008 120 w 300 w 180.l 75 w 8

!!!!7. c Let the age of Sunil, Sunils son and Sunils father be x, y and

z years respectively.z = 5y, x + 6 = z x + y and x + z = 85.Solving the above equations in x, y and z, we get that x = 30,

y = 11 and z = 55.Hence the sum of the ages of Sunils son and Sunil is 41years.

8. b P = (1 30) (2 30) (3 30) (4 30) (29 30) (30 30).P = 3030 30!

P = 256 344 537 74 112 132 17 19 23 29.N = 57 45 38 5 3 3 24 = 25 35 52 192Let the two numbers be 19a and 19b respectively such that

a and b are relatively prime to each other.

(19a) (19b) = N = 25 35 52 192ab = 25 35 52Possible pairs (a, b) are(25 35 52, 1); (25, 35 52); (25 35, 52); (25 52, 35).Therefore, N can be written as the product of two numbers,

such that their HCF is 19, in 4 ways.

Short cut method: Here, the answer has to be a power of2. (Why?)

9. b S !g67g68.... g123S g 67 g 68 g 69 g 70 g 71 ...... g 99g 100 g 101 ...... g 123

!

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S 6 7 8 9 7 8 9 1 2 3 ..... 91 1 1 2 3 ..... 9 1 2 1 2 3

!S !6 24 24 45 45 26S !1281.10. d Case I:When the password contains 2 digits and 3 vowels.Number of possible passwords

= 3C2 5C3 3C1 2C1 3! 2 = 2160.Case II:When the password contains 3 digits and 2 vowels

Number of possible passwords= 3C3 5C2 3C1 2C1 3! 2 = 720.Total number of passwords that Mandeep can create

= 2160 + 720 = 2880.

Page 3 Unproctored - Mock CAT 11____ _____ __11. d Let the numbers be K, L, K + L,

KL (K + L) = 12 (K + L)KL = 12.{K, L} = {1, 12}, {2, 6} or {3, 4}

Hence, product P = 156, 96 or 84Required sum = 156 + 96 + 84 = 336.12. d Given, [] = [] = [] =11H2, 1H2 and 1H2 ...(i)As, , and are the roots of the given cubic equation,++ !a and !c. From (i),3 H() 66 a H3 ...(ii)And

1H() 88 c H1 ...(iii)Each of,and is a positive number. Hence for every givenvalue of their sum, equal to a, the maximum possible value oftheir product, equal to c, can be determined. Hence when a

= 3.3, the minimum value of c is 1.331. Hence, when

a !3.31.331Hc H1, and whena !4.8 4.096 Hc H1, and whena !5.76.859 Hc H1 and when

a !4.22.744 Hc H1.Hence, option (d) is incorrect as 2.8 is not a permissiblevalue of c for a !4.2.13. c Perimeter of the base of cuboid = 64 cm.

Length of the base + Width of the base = 32 cm.Length of edge of every cube = 2 cm.Therefore, the sum of the total number of cubes along thelength and the total number of cubes along the width of thecuboid

3216.2

!!Therefore, the number of cubes along the length and the

width of the cuboid can be (1, 15), (2, 14), (3, 13), (4, 12),(5, 11), (6, 10), (7, 9) and (8, 8) not necessarily in that particularorder.

Also, in the cuboid (Number of cubes along the length) (Number of cubes along the breadth) (Number of cubesalong the height) = 78

The only possibility = 3 13 2 = 78.Hence, the number of cubes along the height of the cuboid is2.

14. b Number of ways in which three numbers can be selectedfrom the first 20 natural numbers = 20C3 = 1140.Case 1: Common ratio of the G.P. is 2 = 5 ways

[(1, 2, 4); (2, 4, 8);(3, 6, 12);(4, 8, 16);(5, 10, 20)]Case 2: Common ratio of the G.P is 3 = 2 ways

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[(1, 3, 9); (2, 6, 18)]Case 3: Common ratio of the G.P. is 4 = 1 way

[(1,4, 16)]Case 4: Common ratio of the G.P. is3

2= 2 ways[(4, 6, 9); (8, 12, 18)]

Case 5: Common ratio of the G.P. is43

= 1 way[(9, 12, 16)]Required Probability

11= .1140

15. a Let, the weight of p apples be equal to 1 kg and the weight ofq oranges be equal to 1 kg.Let, the cost price and selling price of 1 apple be C1 and S1

respectively.Let, the cost price and selling price of 1 orange be C2 and S2respectively.

Therefore,10 C2 = p C1 ...(i)

q C2 = 12 C1 ...(ii)15 S2 = p S1 ...(iii)Let, the selling price of 1 kg of oranges be equal to that of xapples.

Therefore, q S2 = x S1 ...(iv)Dividing the equation (i) by (ii), we get that10 pq 12

!p q = 120 ...(v)Dividing the equation (iii) by (iv), we get that15 pq x

!Therefore, x = 8.

16. a

AB

D CQR

P11.27 3.5

In PDC , AQ is parallel to DC, then 73.5 AP11.2 RC AD

!(i)

_PDB !DBC (Alternate angles)andDRP !CRB (Vertically opposite angles), thereforePRD and CRB are similar.84.7 PD

CR CB

!84.7 PA ADCR CB

!PA AD

AD

!AP

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1AD

!84.7 73.5

1RC 11.2 RC

!

11.2 84.7 84.7 RC !RC2 84.7 RCRC2 !948.64Or, RC !30.8 units.

Page 4 Unproctored - Mock CAT 11____ _____ __17. a Given that when f(x) is divided by (x 1), (x 2). and(x 51), it leaves 1, 2, 3, 4. and 51 respectively, as theremainders.

Therefore, f(x) = a (x 1) (x 2)(x 51) + x(f(x) is a polynomial of degree 51, therefore it cannot beanything else).

where a is any constant.Now, putting x = 52 in the above equation we get,f(52) = a 51 50 .. 1 + 52

f(52) = a 51! + 52 (i)Also, f(0) = a (1)51 51! + 0 ...(ii)

Adding equations (i) and (ii), we get that f(52) + f(0) = 52.18. c Let, S be the sum of all the elements of the set P.Therefore, S = (5) + (3) + (1) + 1 + 3 + .......

Or, S = (2 1 7) + (2 2 7) + (2 3 7) + (2 4 7) + .......Let, Tn be the nth element from the left of the set P.Therefore, Tn = (2n 7)1998 1998n 1 n 1

1 1a b (2n 7) (2n)

1998 1998!!

!!!!

1998n 1

1 7 1998

(7)1998 1998

a b = 7.Alternative Solution:1998a = 5 3 1 + 1 + 3 + 5 + ..... (1998 terms)

= ( 5 3 1) + sum of the first 1995 odd natural numbers.= 9 + (1995)2 = 19952 32 = (1995 + 3)(1995 3)= 1998 1992

or, a = 1992.1998 1999b 2 1999

2 1998

!!a b !7.19. b S = {(2 3 5), (3 5 7), (5 7 11), (7 11 13), (11 13 17), (13 17 19), (17 19 23), (19 23 29) and(23 29 31)}

So, S contains 9 elements.Given that the number of elements in the set N is maximumpossible.

Since, all the elements of the set N are relatively prime to eachother, therefore the maximum possible number of elements in

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the set N could be 3.Also, in the set N, there will be 1 element out of the first 3

elements of the set S, 1 element out of the next 3 elements ofthe set S and 1 element out of the last 3 elements of the set S.This is possible in ten ways:

1.(2 3 5, 7 11 13, 17 19 23)2.(2 3 5, 7 11 13, 19 23 29)3.(2 3 5, 7 11 13, 23 29 31)

4.(2 3 5, 11 13 17, 19 23 29)5.(2 3 5, 11 13 17, 23 29 31)6.(2 3 5, 13 17 19, 23 29 31)

7.(3 5 7, 11 13 17, 19 23 29)8.(3 5 7, 11 13 17, 23 29 31)9.(3 5 7, 13 17 19, 23 29 31)

10.(5 7 11, 13 17 19, 23 29 31)20. aAx

FB Ex + 2

x 2Or

xx + 2 x 2

rD rCLet, Side AC = (2x 2) cm

Side CB = (2x) cmSide BA = (2x + 2) cm, where x is a natural number greaterthan 1.

Let r be the in radius of the ABC .Area ofABC !Area (OBC OAC OAB)

_a1r (2x 2) (2x) 2x 2 3rx.

2

!!Also, semi perimeter(2x 2) (2x) (2x 2)

s 3x

2!!Area ofABC !3x(x 2)(x)(x2) !3rx(x 2)(x)(x 2)r3x

!(x24) !3r2x2 = 3r2 + 4 ... (i)For, x to be a natural number (3r2 + 4) has to be a perfectsquare.

Out of the options given, only for r!3 , the value of x doesnot come out to be an integer.For questions 21 to 23:

Cut-off for QA = 11, VA = 12 and DI = 9.Overall cut-off = 35Marks deducted for the first 6 incorrectly attempted questions = 6 1

4= 1.5.Marks deducted for next 6 incorrectly attempted questions = 6

13= 2.

For each further incorrectly attempted question the negative marks =1

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2.

Cut-off in each section is an integer. So to just clear the cut-offs, thepossible number of questions that can be attempted incorrectly are0, 4, 13, 15, 17, 19, 21, 23, 25, 27........... and so on.

21. c We have to find the minimum number of unattempted questionsin the exam such that student just manages to clear thesectional cut-offs. Let us assume that a student attempted

maximum possible number of questions such that he gets just11,12 and 9 marks in QA, VA and DI respectively.In a section if a student attempts 13 questions incorrectly then

marks deducted from his score1 1 1 3 16 6 2 4.

4 3 2 2 2

!!!So in order to clear the cut-off in QA if a student attempts 13questions incorrectly then he has to attempt 11 + 4 = 15questions correctly.

Page 5 Unproctored - Mock CAT 11____ _____ __On any further incorrectly attempted questions,12

of a markis deducted. So in order to just clear the cut-off student has toget 1 question right and 2 questions wrong in every set of 3

questions.From the above, (15 + 13) = 28 questions have already beenanswered. So 22 questions are remaining out of which 21

(multiple of 3) can be answered. 1 question will be leftunanswered.Similarly in order to clear the cut-off in VA, if a student attempts

13 questions incorrectly then he has to attempt (12 + 4) = 16questions correctly.So (16 + 13) = 29 questions have already been answered.

Out of the remaining 11 questions 9 (a multiple of 3) can beattempted. Two questions will be left unanswered.Similarly in order to clear the cut-off in DI, if a student attempts

13 questions incorrectly then he has to attempt (9 + 4) = 13questions correctly.

So (13 + 13) = 26 questions have already been answered.Out of the remaining 4 questions, 3 can be attempted. 1 questionwill be left unanswered.So the minimum number of questions left unanswered

= 1 + 2 + 1 = 4.22. d To find the minimum number of incorrectly attempted questionswe have to consider number of incorrectly attempted questions

in a particular section as maximum. In that section,12

markswill be deducted after 12 incorrectly attempted questions.Moreover the maximum number of questions is in QA, so we

have to take QA as that particular section, so that the overallnumber of incorrectly attempted questions is minimum.From the solution of the previous question, 28 questions with

13 incorrectly attempted questions just clears the cut-off.Further 21 questions can be answered out of which 7questions can be attempted correctly and the rest incorrectly,

which will not make any difference to the overall score of 11.So the student can attempt 49 questions from QA such that 22are correct and 27 wrong, he will end up having 11 marks,

just enough to clear the cut-off.To just clear the cut-off in VA and DI student has to get at least12 and 9 questions correct. That makes 49 + 12 + 9 = 70

question.Remaining number of questions is 87 70 = 17.Which can be done from any of the sections doing 4 more

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questions right and 13 questions wrong, apart from 12 and 9questions for VA and DI respectively.

So the minimum possible number of incorrectly attemptedquestions by the student = 27 + 13 = 40.23. b The student has to score 35. If he attempts all 120 questions,

no combinations of right and wrong attempts will lead to ascore of exactly 35. So minimum number of unattemptedquestions has to be 1. This can happen in the following

manner:a. QA - 49 attempts, 22 right and 27 wrongb. VA - 40 attempts, 21 right and 19 wrong

c. DI - 30 attempts, 15 right and 15 wrongThis can also be possible in other combinations. But in eachcase at least 1 question is to be left unattempted.

24. d From additional information (4) we know that C is not in groupY and D is not in group Z.Given that C and D are in the same group, which means that

both C and D are in group X.A, C, D, H and I are in group X.Since, we need to find the friend who cannot be in the group

that has exactly three friends; it means that group X will haveonly five friends.From additional information (1) we know that B and J are in

the same group.Also from additional information (2), D, E and F are in different

groups.So, it is clear that in a group which has exactly three friends;B and J will be accompanied by either E or F.So, G will be in the group that has exactly two friends along

with either E or F.25. b Given that F is in group X and G is not in group YSince D, E and F are in different groups and D is not in groupZ, therefore D is in group Y and E is in group Z.Since, C is not in group Y and C, I and H are in the same group,therefore C, I and H are either in group X or group Z.

Also, G is either in group X or Z.Since each group has at least two friends and B and J are inthe same group, therefore in group Y, there are exactly three

friends namely B, J and D.Therefore, out of the pairs mentioned the following four pairsof friends cannot be in the same group; (J, F); (D, G); (B, E)

and (D, I).26. d Let us first form a group that has exactly six friends.Since, in one group there are six friends, therefore in each of

the two other groups there are two friends.Also, we know that D, E and F are in different groups, B andJ are in the same group and so are C, I and H.

This means that in a group which has six friends, the followingfive friends namely B, J, H, I and C must be there.Since, C cannot be in group Y and in group X there is A along

with one out of D, E and F, we can conclude that it is onlygroup Z that can have six friends.The sixth friend in group Z could be either E or F as D cannotbe in group Z.

So, neither A nor G nor D can be in the group that has sixfriends.27. a Since there are exactly five friends in group Z, so it can be

concluded that H, I and C are definitely in group Z.

Since A is in group X, and D, E and F are in different groups,therefore B and J who are in the same group are in group Y.

So, G is also in group Z.The fifth friend in group Z could be either E or F.The third friend in group Y and second friend in group X could

be either D or E or F.Therefore, J is definitely in group Y.28. d The total weight of the cotton at the stalls are listed in the table

given below.Stall Number 1 2 3 4 5 6 7 8 9 10Weight (kgs) 0.6 1 0.7 0.55 0.8 0.6 0.4 2 0.75 1

There are 2 ways to choose 2 kgs of cotton from the stalls in

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which the total weight of the cotton is a fraction of a kg.Let K be the set of stall numbers 3, 4 and 9 and l be the set of

stall numbers 1, 5 and 6.Five kgs of cotton can be chosen in any of the followingcombinations:

(a) (K or l) + stall number 2 + stall number 8 = 2 combinations(b) (K or l) + stall number 8 + stall number 10 = 2 combinations

Page 6 Unproctored - Mock CAT 11____ _____ __(c) K + l + (stall number 2 or stall number 10) = 2 combinations

(d) K + stall number 8 + stall number 7 + (stall number1 or stall number 6) = 2 combinations(e) Stall number 2 + stall number 8 + stall number

10 + stall number 7 + (stall number 1 or stall number6) = 2 combinations(f) K + stall number 7 + stall number 2 + stall number 10 +

(stall number 1 or stall number 6) = 2 combinations.

In total, there are 12 combinations.29. d Minimum possible amount will be paid by Richa, when shechooses to buy cotton from stall numbers1, 2, 7, 8 and 10. The amount will be 24 + 35 + 20 + 56 + 36 =

Rs.171.30. a Since, the price of the cotton (in Rs./kg) at stall number10 becomes Rs.36 Rs.11 = Rs.25, therefore Richa can buy

the cotton by paying Rs.11 lesser than what she had to payearlier (as there is still 1 kg of cotton at stall number 10).So, the minimum amount paid by Richa to buy 5 kgs of cotton

= Rs.171 Rs.11 = Rs.160.Maximum amount will be paid by Richa, when she buys cottonfrom stall numbers 1, 2, 3, 4, 5, 6 and 9, thereby paying a total

of 24 + 35 + 28 + 33 + 36 + 39 + 24 or Rs.219.Therefore, the difference between the maximum and theminimum possible amount Richa can pay to buy 5 kgs of cotton

is Rs.219 Rs.160 = Rs.59.31. b Statement I:If Richa buys cotton from the stall numbers 1, 3 and 9, she will

have to pay the maximum possible amount.It is not necessarily true as there are more than one way inwhich Richa can buy cotton from stall numbers 1, 3 and 9 and

every time she does not necessarily pay the maximum amount.Statement II:

If Richa buys cotton from stall number 3, then she will have tobuy cotton from stall numbers 4 and 9 as well.It is always true as the weight of the cotton at all the threementioned stalls sum up to 2 kgs.

Therefore, she cannot buy cotton either from only one or onlytwo of the given stalls.32. b For maximizing the total amount, Richa should buy more

quantity of cotton from the stall that has the highest price ofcotton (in Rs./kg).Therefore, she should buy 600 gms of cotton from stall

numbers 6;550 gms of cotton from stall number 4 and 350gms of cotton from stall number 1.Therefore, the maximum possible amount paid by Richa to buy

1.5 kgs of cotton = 0.6 65 + 0.55 60 + 0.35 40 = Rs.86.For questions 33 to 36:Let the people who wear a blue, red and green shirt be denoted by b,

r and g respectively.Restrictions on the seating arrangement:1. Two bs must not be together.

2. Three rs must be together.3. A b and a g must not be together.4. A g cannot sit on chair numbered 2 or 9.

Case A:A person wearing a red shirt sits on chair numbered 1.Keeping all the restrictions stated above it is not possible to make such

a seating arrangement.Case B:A person wearing a green shirt sits on chair numbered 1.

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It is only possible if another person wearing a green shirt sits on chairnumbered 2, but this violates restriction number 4.

Hence, this is also not possible.Case C:A person wearing a blue shirt sits on chair numbered 1.

The six seating arrangements that are possible are as follows.1 2 3 4 5 6 7 8 9 10Case 1 b r b r g g r r r b

Case 2 b r r r b r g g r bCase 3 b r g g r r r b r bCase 4 b r r r g g r b r b

Case 5 b r g g r b r r r bCase 6 b r b r r r g g r bNow, we see that the cases 4, 5 and 6 are just obtained by reversing

the cases 1, 2 and 3 respectively.It can be concluded that in any possible seating arrangement, thechairs numbered 1 and 10 are always occupied by people wearing

blue shirts. It is given that the number of people wearing a blue shirt is3. Looking at the table given in the question, we observe that in eachof the six arrangements two out of the three different people i.e. A, B

and N always sit on chairs numbered 1 and 10.Hence it can be concluded that the people who wear a blue shirt areA, B and N.

From the given table the person wearing a blue shirt can never sit onchairs numbered 2, 4, 7 and 9.

So, (in arrangement I), A, B and N sitting on chairs numbered 1, 7 and10 is inconsistent.Also, the people wearing red shirts sit on chairs numbered 2 and 9and in all the possible arrangements five different people namely

P, Q, M, Z and R are sitting on chairs numbered either 2 or 9.Therefore, P, Q, M, Z and R are wearing red shirts and K and L arewearing green shirts.

33. a 34. d 35. a36. c Option a: A (Blue), P (Red), R (Red) and L (Green): PermissibleOption b: N (Blue), Q (Red), K (Green) and Z (Red): Permissible.

Option c: K (Green), A (Blue), N (Blue) and Z (Red):Not Permissible.Option d: B (Blue), L (Green), M (Red) and Q (Red): Permissible.

For questions 37 to 40:All the possibilities are listed down in the table shown below.S. No. Name of the Player

PointsEarne dWorld

Rank ing1 Naomi Cavaday 41 52 Stephanie Cornish 37 7

3 Jade Windley 34 8 or 94 Jocelyn Rae 31 105 Naomi Broady 25 11

6 Laura Slater 25 117 Samantha Vickers 23 138 Hannah James 22 or 23 14 or 139 Jade Curtis 22 14 or 15

10 Jassica Jackson 21 16

Page 7 Unproctored - Mock CAT 11____ _____ __

Note: Naomi Broadys World Ranking prior to the tournament couldnot be 10 as other wise Laura Slaters World Ranking must

had been atleast 12.37. d As two players had a World Ranking of 11 prior to thetournament, none of the 10 players had a World Ranking of 12

prior to the tournament.38. a If Hannah James earns maximum possible number of pointsand Naomi Cavaday earns minimum possible number of points,

then the difference between their number of points will be themaximum.So, Hannah James can possibly earn

5 10 + 4 9 = 86 points

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The maximum number of points earned by Hannah James atthe end of the Sunfeast Open can be 86 + 23 = 109 points.

Now, Naomi Cavaday can possibly earn4 2 + 3 + 4 + 5 + 6 + 7 = 33 pointsTotal number of points earned by Naomi Cavaday at the end of

the Sunfeast Open = 41 + 33 = 74.Hence, the required difference = 109 74 = 35 points.39. d Total number of points earned by Jade Curtis

= 9 10 + 22 = 112 points.Out of the given options:Naomi Broady can possibly get a maximum of

25 + 8 10 + 2 = 107 points.Laura Slater can possibly get a maximum of25 + 8 10 + 2 = 107 points.

Samantha Vickers can possibly get a maximum of23 + 8 10 + 2 = 105 points.None of the three players can possibly get the World Ranking

2 at the end of the Sunfeast Open as their points are wellbelow 112.40. b The maximum value of X can be 8 as each of these three

players will get 10 points from each of the matches playedagainst the remaining seven players. Among themselves, eachone of these three would play 2 matches, of which she will

get the maximum (10 points) from one match and the minimum(2 points) from the other.

Hence, if the value of X has to be maximum possible, LauraSlater at the end of the Sunfeast Open must have got 10points in 8 matches each and 2 points in 1 match (as explainedabove).

Total number of points earned by Laura Slater in this case atthe end of the Sunfeast Open is 25 + (8 10) + 2 = 107.Note: This is the only possible value of number of pointsearned by Laura Slater if the value of X has to be maximumpossible.41. d All the sentences are grammatically correct.

42. c Refer to the lines in Para 1 and Para 2. It was, he added, notstodgy. Stodginess, certainly, is something that the appeal toclouds might well be hoped to ward off. ..Moreover, not

only does the cloud seem opposed to all material loading,equally it appears to resist being weighted down. Gehryasserts that the cloud is not stodgy and wants to push its

cloudy, light and dynamic character. Options (a) and (b) indicatewhat Gehry would like his recent architecture to be seen as.Here stodgy refers to being earthy or heavy a characteristic

quite opposed to that of clouds.43. a Option (a) is true as Charles Jencks has viewed the dynamitingof the Pruitt- Igoe as the death rattle or the end of modernism.

Option (b) is incorrect as famously promoted refers to thedeath rattle of modernism and not being an iconic exampleof matter after form. Definitely, the demolition is seen as an

iconic example but being famously promoted refers to thedeath rattle of modernism. Option (c) is incorrect as,according to the passage, matter after form and not matteraspiring to form is the characteristic thing that accompanies

destruction and demolition. Option (d) is incorrect as in thepassage, it is mentioned that the cloud has been of interest tothose who want to transgress architectures disciplinary

nature but nothing of this sort has been mentioned about the

Pruitt-Igoe housing.44. b Refer to the lines in Para 2 Stodginess, certainly, is something

that the appeal to clouds might well be hoped to ward off. Ofall the flow-motifs available to oppose the heaviness ofcongealed and earth-bound stodge, the slow and complex

three-dimensional circulation, drift and dispersion of the nebularseems the most promising. It is clear that there is an attemptto make the cloud appear non-stodgy even though there is a

component of stodge in the cloud. Thus, (a) can be inferredfrom the passage. Option (c) can be inferred from the 4thparagraph which states the cloud is an area of interest for

practices on assault upon it. It clearly implies that people

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who want to widen the scope of architecture beyond therigid framework within which it operates are interested in

Gehrys cloud. Option (d) can be inferred from the lines in thelast para, Curiously it was two buildings by the same architect,Minoru Yamasaki, that supplied the material for these two

most iconic examples of the destructuring of form into cloud.Option (b) is partly correct as seen in the 3rd paragraph, butit cannot be inferred that postmodern architecture regards

modern architecture as its rival.45. b All the pairs except the one in option (b), exhibit a relationshipof synonyms. Colossal means huge: of a bulk, extent, power,

or effect approaching or suggesting the stupendous orincredible. Whereas, the adjective diminutive meansexceptionally or notably small. Sluggish is a synonym of

Lethargic. Dilapidated means decayed, deteriorated or falleninto partial ruin especially through neglect or misuse.Tumbledown means dilapidated or ramshackle. Fervent and

zealous are synonyms of each other. Fervent meansexhibiting or marked by great intensity of feeling. Zealousmeans filled with or characterized by zeal marked by fervent

partisanship for a person, a cause or an ideal.46. b In the question, filling the first blank would help us to eliminatetwo options (c) and (d). The 2nd adjective describing the 'gods

of wood and stone' must be negative as it has to complementthe first adjective - 'battered'. Between options (a) and (b),

the second blank would be the deciding factor. 'Totemic' whichmeans suggestive of totemism (belief in kinship with or mysticalrelationship between a graph or an individual and a token - anobject serving as the emblem of a family or clan and often as

a reminder of its ancestry) fits the second blank. Moreover,'toted' in (a) would not fit the second blank as it is an inflectedform of the transitive verb 'tote' which means to lug.

Page 8 Unproctored - Mock CAT 11____ _____ __47. d Rahuls opinion is that Rohit was denied promotion for reasonsother than his age. For strengthening his point, Rahul presentsinstances where some people who are older than Rohit, are

promoted. In order to weaken Rahuls argument, we need tohighlight that Rohit was denied promotion due to his age.Option (a) is incorrect as it makes the candidature of Rohit

strong for promotion but it does not weaken Rahuls argument.

Option (b) is not the correct choice as it does not go againstRahuls argument. Option (c) is incorrect as it highlights age

as one of the factors on account of which Rohit was deniedpromotion. Option (d) is the correct answer as it weakens theargument of Rahul by questioning the validity of evidence

furnished by him. It clearly states that people who are olderthan Rohit were promoted, as there was no one to challengetheir candidature on the basis of age. In other words, age

was not the limiting factor in their case.48. c In the first paragraph, the author clearly mentions that thereproach of abstraction derives mainly from Humean

empiricism. He further elaborates the reproach in the lines,Psychological conception of abstract ideas as the productof customary conjunctions of particular ideas, based on

resemblances, annexed to general names. This refers togeneralizing tendencies. So, option (a) can be inferred from

the passage. Option (b) can be inferred from the 2ndparagraph. Refer to the lines, These two critical tendencies

epistemological and practical-political often converge withinMarxism, as in Derek Sayerss The Violence of Abstraction .But their combination is by no means restricted to the Marxist

tradition. Option (c) cannot be inferred from the passage.Even the practical political version is associated with a nonmodernor non-contemporary text like the Lukcsian trajectory

of Western Marxism.49. d Refer to the lines in Para 2 ..which holds that, not merelydespite but precisely because of the necessity of abstraction

to thought ,(the character of the necessity, that is), there is

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something both cognitively and politically inadequate aboutknowledge itself: not only existing knowledge, but all possible

knowledges. It can be inferred that the necessity ofabstraction to thought reveals the inadequacy of existingknowledge. But it is not explicitly clear whether the inadequacy

of knowledge leads to the necessity of abstraction to thought.So A is distorted. In the second paragraph, the author mentionsFor Feyerband, for example, the history of Western thought

could be told as A Tale of Abstraction versus the Richness ofBeing, but this in no way, shows that Western thought haspreferred the path of abstraction over tapping into the realms

of being. Thus, B also cannot be inferred. C cannot be inferredfrom the passage; the passage , in the 2nd paragraph,mentions, Increasingly, it seems, from a variety of different

stand points, abstraction understood here as conceptualabstraction - is accompanied by both a certain melancholy(loss of the real object) and a certain shame (complicity in the

domination of the concept and hence repression of other,more vibrant, more creative aspects of existence), this in nomanner suggests that abstraction is accompanied by shame

primarily because of submission to some kind of dominationwhich has lead to repression.50. b The passage starts off with the two versions of reproach or

opposition to abstraction. Then it talks about the domination byabstraction and its effects on individuals and behavioural

patterns of groups. Thus, the predominant content or themeof the passage is an opposition to abstraction and itsdomination. Hence option (b) is best suited as the title to thepassage. Option (a) is the initial part of the passage and is

encompassed in option (b). Option (c) is the second half ofthe passage and also encompassed in option (b). Option (d)is an incorrect title as the passage is not talking about theeffects of the reproach to abstraction.51. d The modifying phrase precisely aligned with the stars isincorrectly placed in sentence 4. The correct sentence should

read Precisely aligned with the stars, the Angkor templeswere instruments for assisting... or the sentence can bewritten as The Angkor temples, precisely aligned with the

stars, were instruments for .52. d C is an apt opener as it introduces the issue - "we will oftentry to persuade people of what we find beautiful, even though

we do not believe.." B gives a reason for such persuasion;thus CB constitute a mandatory pair. D adds to B by stating"Moreover, we are often aware of the contingency of our

own judgements' foundation" A adds further to thediscussion (Nevertheless, we do think that certain aesthetic) by providing a concession to D. E further adds to D. Thus,

the correct sequence is CBDAE.53. d Refer to the line, By imposing a Pigovian Tax a governmentcan artifically create a cost for such activity - ideally a cost

equal to what the price would be had a market for suchactivity existed. Also One of the uses of taxes is todiscourage activity that has negative externalities, or we believeis otherwise economically/socially harmful.. Here the author

refers to an activity that has a negative externality. A and Ctalk about activities which have a negative externality. But Btalks of imposing a Tax for disasters which are not a regular

negative externality. The negative externalities referred to in

the passage are those which definitely occur in a regularmanner from an activity. But a disaster may or may not occur.

Hence, the tax mentioned in B does not qualify as a PigovianTax.54. c Refer to the second last para of the passage. The author

admits that he has been rather hard on the supporters of theFairTax- which shows that he has opposed the Fair Taxers tosome extent. Option (a) is substantiated by the line The

FairTaxers take it too far - the amount of revenue needed tofinance all the government programs we value cannot begenerated by simply a consumption tax alone. Option (b) is

also correct. The author starts the discussion on the Fair

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Taxers with Since taxes deter the activity that is being taxed,then why in the world would we ever tax income? and ends

with the basic idea is sound. This shows that the authorsupports the philosophy of the Fair Taxers as taxes are meantto be a deterrent. Option (c) cannot be said to be true as the

author does not comment on any long term scenario. He isdiscussing about current things.55. a If the tax on Marijuana has to deter people from purchasing it

then the tax must be transferred to the customer who paysfor Marijuana. Hence option (a) is an assumption on which theidea of legalizing Marijuana and then taxing it is based. Option

(b) is beyond the scope of the passage as the passage doesnot talk of crimes. Option (c) is again not the concern of thepeople as the tax is meant to be more of a deterrent. Option

(d) is not the correct choice as the purpose of heavy taxationis to deter people from using Marijuana. It is too far-fetched toassume that this will stop people from procuring Marijuana

illegally.

Page 9 Unproctored - Mock CAT 11____ _____ __56. a The first blank needs an expression which should be aptenough to be related with the catastrophic situation evident in

the given text. Option (b) is negated as 'fore-and-aft' meansparallel with the length of a structure, running lengthwise.

Option (c) is out of context. An 'argy-bargy' referes to a livelydiscussion; an argument or a dispute. Option (d) is also out ofcontext as 'hustle and bustle means busy and noisy activity.This expression is simply too inappropriate to relate with the

magnitude of the disastrous situation. Option (a) is the bestchoice. 'Fire and brimstone' is God's means of destroyingsinners; it is the torments suffered by sinners in hell. In the

second blank, 'carry about' which means to carry someoneor something with one; to carry someone or something fromplace to place, is the appropriate one to be used here.

57. c In all the options except (c), the second word mentions thecharacteristic of the person (mentioned as the first word). Asciolist indulges in a superficial show of learning. A

hoodwinker intends to decieve by false appearance. Amountebank is a boastful unscrupulous pretender. Anamputee is one that has had a limb amputated. Ablation is a

process and not a characteristic. It refers to a surgical removal;

loss of part by melting or vapourisation.58. b Option (a) is not looked at very favourably by the author.

Refer to the lines in the third paragraph, Despite importantqualifications and refinements, and, I think, a certain amountof denegation (its not enough to put some words in scare

quotes), Ryles argument tends to privilege an abstractednotion of `the literary text, to be apprehended, he says, `atonce in itself, so that he ends up with a conservative

legitimation of the aesthetic in textual studies of just the kindhe - and others beside him - have hoped to avoid. Option (c)is clearly criticized by the author in the last para. Option (d) is

also looked at unfavourably by the author. Refer to the lines inthe third paragraph, and that his position is seriously damagedby the degree of its adherence to an older paradigm of `the

text, a view which has insufficiently taken on board the recentshift to a more radical notion of the text as always in a relation

to its reader, implying a text/reader dialectic. Option (b) is notreflective of an opposition from the author toward Ryle. The

author criticizes Ryle for excessively identifying cultural studieswith their historical conjuncture and not just connecting culturalstudies with their historical conjuncture.

59. d The quote indicates that a lot of formalism brings one back toHistory. Option(a) is not suggested by the quote. Option (b)conveys an incorrect meaning of the quote. Option (c) gives

a distorted sense of the quote. In the passage, formalism isunfavourably looked upon as taking one back to History andnot positively as encouraging history.

60. b Although, the author gives examples and quotations from

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Ryles book on several occasions, he uses them merely todevelop his argument and analysis. Therefore (b) would take

precedence over options (a) and (c). The authors tone in thepassage is balanced and not reflective of vehement criticism,this rules out option (d).

61. c Only statement 3 is grammatically correct. In sentence 1, thephrase musnt eat should be replaced with dont have toeat; musnt is used to indicate that something is not allowed

whereas dont have to is used to indicate that something isnot necessary. In sentence 2, got suspicious should bereplaced with became suspicious. In sentence 4, will should

be replaced with would.62. d An accent cannot be summated or temporised hence, options(a) and (c) are negated. The technique used here should

create a lively setting that brings out the stark differenceaptly. Hence routine is ruled out, putting option (b) out ofcontext. This leaves us with option (d). To 'encapsulate' is to

enclose; to express or show the most important facts aboutsomething. 'Vivid' descriptions, settings, etc. produce veryclear, powerful and detailed images in the mind, and hence

the word would serve the purpose.63. c A opens the paragraph as it introduces the topic. E logicallyfollows A as it describes how the author had met the 'mystic';

C follows E as it describes the consequence (author'sacceptance of the offer and his visit to the psychic reader.) D

forms a mandatory pair with C as it describes the interior ofthe psychic reader's home in Nottingham. B describes theevent of psychic reading at the reader's house and continuesthe discussion further.

64. c The reasoning followed by Nagendra in the question statementis that one should not do A because of B. Option (a) is incorrectas it goes against the reasoning given in the question statement.There is no place for circumstances in the reasoning. Option(b) is beyond the scope of information given in the questionstatement. One cannot decide about more or less from the

information given. Option (c) is the correct answer as itprovides the justification for the reasoning of the questionstatement. Option (d) is incorrect, as it has reversed the

parameters (not to do A because of B does not mean not to doB because of A).65. b The author concludes that Krishnan is a Hindustani Classical

singer. The basis of this conclusion is Krishnans ability torecognize the works of Kumar Gandharva. The author furtherstates that a vast majority of people who are not Hindustani

Classical singers cannot recognize the work of KumarGandharva. But, a vast majority does not mean that no one,who is not a Classical Hindustani singer cannot recognize the

work of Kumar Gandharva. This implies that Krishnan can beone who is not a Classical Hindustani singer but can recognizethe work of Kumar Gandharva. This conclusion leads us to

option (b). Option (a) is incorrect as the argument in no waysuggests that people have to know Pandit Kumar Gandharvain order to be able to recognize his works. Option (c) is not thecorrect choice, as it does not highlight the flaw in the argument.