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    Question:  A point object is kept between a plane mirror and a concave mirror facing each other.The

    distance between the mirrors is 22.5cm.Plane mirror is placed perpendicular to the

    principal axis of the concave mirror.The radius of curvature of the concave mirror is

    20cm.hat should be the distance of the object from the concave mirror so that after two

    successive reflections the final image is formed on the object itself.

    Answer:

    !

    ! ! !

     " "!0v x + =

    !

    !0

    !0 "

     x v 

     x 

    =

    #irst image will form at $!

    This!

    will come in negative so adding the negative sign makes the image distance refer

    onl% to magnitude

    !0 " 22.5 22.5 "

    !0 "

     x  x 

     x 

    = +

    !0  x  & ' x  " (5) '!0 "  x )

    0 & " (50 "  x 2 * (5  x 

     x 2 " (5u * (50 & 0

    Solving 

    2(5 (5 " ( (50

    2 x 

    ± ×=

    (5 !5

    2 x 

    ±=

     & +0 cm and !5 cm

    ,orrect answer is !5 cm as +0 cm is be%ond plane mirror.

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