ANALYTICAL GEOMETRY (3D) AND INTEGRAL · PDF fileANALYTICAL GEOMETRY (3D) AND INTEGRAL...

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1 ANALYTICAL GEOMETRY (3D) AND INTEGRAL CALCULUS UNIT I Standard equation of a plane intercept form-normal form-plane passing through given points angle between planes plane through the line of intersection of two planes- Equation of the straight line Shortest distance between two skew lines- Equation of the line of shortest distance UNIT II Sphere Standard equation Length of a tangent from any point-Sphere passing through a given circle intersection of two spheres Tangent plane. UNIT III Integration by parts definite integrals & reduction formula UNIT IV Double integrals changing the order of Integration Triple Integrals. UNIT V Beta & Gamma functions and the relation between them Integration using Beta & Gamma functions TEXT BOOK(S) [1] T.K.Manickavasagam Pillai & others, Analytical Geometry, S.V Publications -1985 Revised Edition. [2] T.K.Manickavasagam Pillai & others, Integral Calculus, SV Publications. UNIT I - Chapter 2 Sections 13 to 21 & Chapter 3 Sections 24 to 31 of [1] UNIT II - Chapter 4 Sections 35 to 42 of [1] UNIT III - Chapter 1 Sections 11 , 12 & 13 of [2] UNIT IV - Chapter 5 Sections 2.1 , 2.2 & Section 4 of [2] UNIT V - Chapter 7 Sections 2.1 to 5 of [2] REFERNECE(S) [1] Duraipandian and Chatterjee, Analytical Geometry [2] Shanti Narayan, Differential & Integral Calculus.

Transcript of ANALYTICAL GEOMETRY (3D) AND INTEGRAL · PDF fileANALYTICAL GEOMETRY (3D) AND INTEGRAL...

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ANALYTICAL GEOMETRY (3D) AND INTEGRAL CALCULUS

UNIT I Standard equation of a plane – intercept form-normal form-plane passing through given

points – angle between planes –plane through the line of intersection of two planes- Equation of the

straight line – Shortest distance between two skew lines- Equation of the line of shortest distance

UNIT II Sphere – Standard equation –Length of a tangent from any point-Sphere passing through a

given circle – intersection of two spheres – Tangent plane.

UNIT III Integration by parts – definite integrals & reduction formula

UNIT IV Double integrals – changing the order of Integration – Triple Integrals.

UNIT V Beta & Gamma functions and the relation between them –Integration using Beta & Gamma

functions

TEXT BOOK(S)

[1] T.K.Manickavasagam Pillai & others, Analytical Geometry, S.V Publications -1985 Revised

Edition.

[2] T.K.Manickavasagam Pillai & others, Integral Calculus, SV Publications.

UNIT – I - Chapter 2 Sections 13 to 21 & Chapter 3 Sections 24 to 31 of [1]

UNIT – II - Chapter 4 Sections 35 to 42 of [1]

UNIT – III - Chapter 1 Sections 11 , 12 & 13 of [2]

UNIT – IV - Chapter 5 Sections 2.1 , 2.2 & Section 4 of [2]

UNIT – V - Chapter 7 Sections 2.1 to 5 of [2]

REFERNECE(S) [1] Duraipandian and Chatterjee, Analytical Geometry

[2] Shanti Narayan, Differential & Integral Calculus.

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PART – A

1. Write down the formula to find the angle between Planes

and

The angle between two planes is

2. Write down the Condition for the line

to be Parallel to the Plane

Condition for the line to be parallel to the plane is

3. Formula for the Length of the tangent from the Point tothe Sphere

The length of the tangent from a point to the sphere is

4. Writethe formula for equation of Tangent plane to Sphere

The equation of tangent plane to sphere is

5. Write down the intercept form of the equation of a plane

The intercept form of the plane is

6. Write down the Condition for two given straight lines to be coplanar.

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The condition for two lines

to be coplanar is

7. Find the centre and radius of the Sphere

The centre is ),,( wvuc

The radius

8. Write down the formula for intersection of two spheres:

The intersection of two sphere is

9. Find the equation of the plane through Pt(2, -4, 5) and parallel to the plane

06724 zyx

Equation of a plane parallel to

Given 1 passes thro

10. Find the point where the line

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meets the plane 5zyx

Let the given line be

11. Find the Centre and Radius of the Sphere

Given

Radius

12. Find the equation of the Sphere thro the circle

5432 zyx and point (1,2,3)

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Given : 0922 zyxs ; 05432 zyx

1 passes thro (1,2,3)

;

13. Write the equation of the plane making intercepts

Given a=2,b=3,c=4

Equation of plane in intercept form is

14. Find the length of the Tangent from the point to the Sphere

GIVEN :

The Length of The Tangent is

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15. Write down the Equation of the Plane

and Parallel to the line

The Equation of the Plane Containing the Line

16. What are the Intercepts of

17. Find the Length of Perpendicular drawn from (1, 2, 3) on

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Given:

18. Find the Length of the Tangent to the Sphere

Given :

=>

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19. State the Condition for the Straight Line

to lie on the plane

Condition for line to lie on the plane:

The line should be parallel to the plane and

any point on the line should pass through the plane.

20. Find the tangent plane at (-1, 4, -2) on

The equation of the tangent plane is

The equation of tangent plane at (-1, 4,-2) on is

21. Find the normal form of

Given :

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22. Evaluate:

Solution:

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23. Evaluate:

Solution

24. Write down the recurrence formula for Гn

Solution:

Recurrence formula for Гn

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25. . Evaluate:

Solution:

26. Evaluate

Solution:

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27. Find the value of Гn

Solution:

28. Find the value of Г

Solution:

.

29. Evaluate:

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30.

31. Write down the formula for relation between beta and gamma function

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11. Prove thatГ

From 1 and 2

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.

12.

Solution:

By the property of definite integrals

13. Find the value of Г0 ‘n’ is a positive integer.

Г0

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14. State the recurrence formula for gamma function

.

PART – B

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1. Find the shortest distance

Solution:

Let

Any point on line is

Any point on line is

The direction of line joining the point G & H

The direction’s of Line (3,-1,1)

We’ve

Also the direction of line is (-3,2,4)

We’ve

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Solving &

X 7 => 77

X 11=> -77

-270

Sub in

Shortest distance between G & H is

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2. Find the centre and radius of the circle

Solution:

Given the equation of the sphere is

The direction of CQ is (x-0,y-1,z-2)

The direction of

The line CQ is to the given plane and hence parallel to the normal to the plane

The direction of proportional

The point Q is (K, 2K+1,2K+2)

The point is lies on the plane

c

r

a

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The point Q is (1,3,4)

Distance between two points

Radius of the circle

3. Derive the intercept form of a plane

Statement :

find the equation of a plane making intercepts a,b.c on the axis ox, oy, oz respectively

Proof:

let the given plane meet the co-ordinate axis ox, oy, oz, at A, B, C respectively

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Hence the co-ordinates of the points A,B,C are respectively (a,0,0) , (0,b,0), (0,0,c)

Subs the values in

This is known as intercept form of the equation of a plane.

4. Find the equation of the plane through the line

Solution:

Given that

Equation of the plane passing through line is

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Since it is parallel to the line

Solving &

5. Obtain the equation of the sphere through the origin and the circle given by

Solution:

Equation of the sphere passing through the given circle is

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Since it passes through the origin (0,0,0)

6. Show that the plane

Solution:

Given

Centre=(-u, -v, -w)

Centre= (1, 2, -1)

The perpendicular distance from the centre to the plane

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Perpendicular distance =3 units

From &

The

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7. Prove

Solution:

Adding 1 & 2 we get

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To evaluate

Sub 4 in 3 we get

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8. Evaluate

Solution:

9. Evaluate

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10. Evaluate :

Solution:

WKT

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Put

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11.Evaluate:

Solution:

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12. Evaluate:

Solution:

Adding 1 & 2 we get

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13. If

Solution:

Sub n by n-1 in

Multiply ‘a’ on both sides

Subtract 2 from 1

14. If

Solution:

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15. Obtain a reduction formula for

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Solution:

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16. Evaluate:

Solution:

n=3, m=2 in

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Sub 3 in 2 we’ve

17. Show that

Solution:

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18. Show that

Solution:

WKT

Consider LHS

19. Prove .That Г

Solution:

WKT

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WKT

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From 1 & 2

.

20. Evaluate:

y

Solution:

x=0

x

y=0

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Put

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21. Evaluate taken over the positive of the circle

solution:

But given positive quadrant

.

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PART – C

1. Show that the lines and 3x – 2y + z +5 = 0 and

2x + 3y + 4z – 4 = 0 lies on a plane, also. Find the point of intersection and the equation

of the plane.

Solution:

To find the symmetric form of 3x – 2y + z +5 = 0 & 2x + 3y + 4z – 4=0

The equation of the plane are

Solving 1 & 2

in

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Any point on the given line is

Step :2

To find direction ratio’s

(using the condition of perpendicular )

Solving &

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)13,10,11(),,( cba

Condition for co-planer

=0

=0

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=> 0 = 0

The line are Co-planar

Let

Any point on the line is

Any point on the line is

Step: 3

To find the point of intersection

Comparing x terms

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Comparing y terms

Comparing z terms

Solving &

X 3

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Sub in

Sub in

The lines are intersecting

The point of intersecting is (2, 4, -3)

Equation of the plane = 0

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= 0

2. Find the condition that the plane lx + my + nz = 8 may touch the sphere

Solution:

A plane will touch a sphere if the length of from the centre of the sphere to the plane is

equal to the radius of the sphere.

The centre of the given sphere is and the radius is

Now the length of the perpendicular from to

the plane

Length of the perpendicular = radius of the sphere

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=

Squaring on both sides

=

=

3. Find the equation of the tangent plane to the sphere

at p(x, y, z) on it.

Also S.T radius to the radius through the point.

Solution:

The given sphere is

W.K.T the line joining the centre of a sphere to any point on point it is to the

tangent plane at the point.

The centre of the given sphere is the direction ration of the line joining

the point

The equation of the plane passing through and having cp as its normal is,

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But is a point on the sphere And therefore satisfies

(ie)

(ie)

Substituting the value of in we get

Which is required equations of the tangent plane.

4. Find theS D between z axis and straight line given by

Solution :

The equation of the plane passing through the line

is

The plane given by equation 1 is parallel to z axis The direction cosines of z axis (0, 0, 1)

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The normal to the plane is to z axis by the condition of

Thus the equation of the plane is

The equation of the plane is

Any point on z axis is to the plane since (0, 0, 0) lie on z axis

The shortest distance = length of the from (0, 0, 0) to the plane

5. Obtain the length the tangent from to the sphere

Solution: Let p be the point & C be the centre of the sphere

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To prove :

A tangent from p to the sphere the co-ordinates of the sphere is equal to

T

P(x1, y1, z1) CCCCC ),,( WVUC

6. Evaluate

Solution:

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From &

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7. If show that

deduce the value f(n,n)

Solution

W.K.T

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2, becomes

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8. Evaluate

Solution:

+ ,

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9.Evaluate

Solution

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Hence

10. Evaluate

Solution:

To cover the whole positive octant of the sphere

Hence the required integral is

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11. Evaluate

Solution :

multiply by abc

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2520

223 cba

12. Expression

Solution

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Here

To find

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12.

Proof:

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Similarly Гn

Multiply &

To evaluate the double integral in . we can use the polar coordinates put

the area of the element dx. dy becomes to cover this

region in polar co-ordinates we have to take from ‘0’ to

=>

From

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&

13. Evaluate:

Solution:

-a a

-b

o

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But given that x,y in positive quadrant

14.

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x = 0 y = x

y = 0

The region of integration is bounded by lines y=x, x=0 ( y axis ) and an infinite

boundary

Take – Strips to x- axis to change the order of integration

The extremities of the strip lie on x =0 , y = x.

.

15.

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y

Q(0,2a)

x' o x

P(a,a)

y’ x+y=2a

x varies from 0 to a. hence the region of integration is OPQ .

by changing the order of integration, we first integrate x keeping y as constant.

Thus the strip is parallel to x axis and x varies .

in covering the same region the end of these strips extend to the line y = 2a-x to

the curve hence we divide the integration into two parts by the line

y=a which passes through p

in the first region y varies from 0 to a and in the next region from 0 to 2a.

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