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    ANALYSIS OF SHEAR WALL DUE TO LATERAL LOAD

    A Project Report Submitted to the Department of Civil Engineering of

    World University Of Bangladesh in Partial Fulfillment of the

    Requirements for the Degree of Bachelor

    Of

    Science in Civil Engineering

    Submitted By

    MD. ABUL KASHEM

    Reg: WUB 10/08/23/635

    MD. ZAHIRUL HOQUE

    Reg: WUB 10/08/23/636

    MD. MASUD RANA

    Reg: WUB 10/08/23/639

    MD. ABDUL BATEN

    Reg: WUB 10/08/23/623

    RANZU AHMED

    Reg: WUB 10/08/23/637

    Supervisor

    NOVEMBER 2012

    AHMED SHIBLEE NOMAN

    Assistant Professor

    Department of Civil EngineeringWorld University of Bangladesh.

    S M TANVIR FAYSAL ALAM

    CHOWDHOURY

    LecturerDepartment of Civil Engineering

    World University of Bangladesh.

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    LETTER OF TRANSMITTAL

    November 2012

    To

    Ahmed Shiblee Noman

    Assistant Professor

    Department of Civil Engineering

    World University of Bangladesh.

    Subject: Submission of Project Report.

    Sir,

    We are pleased to submit hereby the project report on Analysis of shear wall due to

    lateral load .It was great pleasure to work on such an important topic. This project

    report has been prepared according to the requirement of the World University of

    Bangladesh,

    We are pleased that this report will certainly help you in evaluating our project report on

    Analysis of shear wall due to lateral load. We would be very happy to provide any

    assistance in interpreting any part of the report whenever necessary.

    Thanking You.

    Sincerely yours,

    RANZU AHMED

    Reg: WUB 10/08/23/637

    MD. ZAHIRUL HOQUE

    Reg: WUB 10/08/23/636

    MD. MASUD RANA

    Reg: WUB 10/08/23/639

    MD. ABDUL BATEN

    Reg: WUB 10/08/23/623

    MD. ABUL KASHEM

    Reg: WUB 10/08/23/635

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    DECLARATION

    We hereby, solemnly declare that the work presented in the project report has been

    earned out by us and so far known, none has yet submitted this type of work in any

    University, College and Organization for an academic qualification.

    We hereby guarantee and ensure that the work has been presented by us, does not breach

    any existing copyright.

    We, further, undertake to indemnify the University against any loss or damage arising

    from breach of the for the foregoing obligation,

    RANZU AHMED

    Reg: WUB 10/08/23/637

    MD. ZAHIRUL HOQUE

    Reg: WUB 10/08/23/636

    MD. MASUD RANA

    Reg: WUB 10/08/23/639

    MD. ABDUL BATEN

    Reg: WUB 10/08/23/623

    MD. ABUL KASHEM

    Reg: WUB 10/08/23/635

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    World University of Bangladesh (WUB)

    CERTIFICATION

    This is the certify that the project on ANALYSIS OF SHEAR WALL DUE TO

    LATERAL LOAD, is an authentic and bonafide record of the project work done by

    Md. Abdul Baten, Md. Masud Rana, Ranzu Ahme, Md. Zahirul Haque, and Md. Abul

    Kashem for partial fulfillment of the requirement for the degree of B. Sc in Civil

    Engineering from the World University of Bangladesh (WUB) .

    This project work has been carried out under my guidance and is a record of successful

    work.

    Faculty Guide.

    Ahmed Shiblee NomanAssistant Professor

    Department of Civil Engineering

    World University of Bangladesh.

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    ACKNOWLEDGEMENT

    All parses for the Almighty Allah, the most merciful and beneficent, for giving us

    enormous opportunity endowing us with enough energy and patience to carry on andcomplete this project work.

    We wish to express our profound gratitude and sincere appreciation to our respected

    supervisor Ahmed Shiblee Nomanof the Department of Civil Engineering of the World

    University of Bangladesh, for his continuous guidance, dynamic supervision, invaluable

    suggestion and unfailing enthusiasm throughout the process of completing the project.

    His noble guidance and advice in every segment for the preparation and completion of

    this work carry a most pleasant experience in the lives of the authors, which imbued with

    ever ending remembrance of his great contribution.

    We exceptionally express our deepest gratitude and thanks to professor

    A.F.M Abdur Rauf, Advisor of the Department of Civil Engineering and

    Mr. Skender Ali, Associate Professor of the Department of Civil Engineering,

    Mr. Rabindra Ranjan Saha, Head of the Department of Civil Engineering of the World

    University of Bangladesh, Dhaka, for their grating necessary permission to conduct this

    project work and also for this whole hearted support to give us more enthusiastic in doing

    this project work.

    We are ever grateful to our friends and parents for their inspiration encouragement andblessings.

    RANZU AHMED

    Reg: WUB 10/08/23/637

    MD. ZAHIRUL HOQUE

    Reg: WUB 10/08/23/636

    MD. MASUD RANA

    Reg: WUB 10/08/23/639

    MD. ABDUL BATEN

    Reg: WUB 10/08/23/623

    MD. ABUL KASHEM

    Reg: WUB 10/08/23/635

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    ABSTRACT

    The purpose of this study is to model and analyze the non planar shear wall assemblies

    of shear wall-frame structures. Two nos three dimensional models, for open and

    closed section shear wall assemblies, have been developed.

    These models are based on conventional wide column analogy, in which a planar

    shear wall is replaced by an idealized frame structure consisting of a column and rigid

    beams located at floor levels. The rigid diaphragm floor assumption, which is widely

    used in the analysis of multi storey building structures, is also taken into consideration.

    The connections of the rigid beams are released against torsion in the model proposed

    for open section shear walls. For modeling closed section shear walls, in addition to

    this the torsional stiffness of the wide columns are adjusted by using a series of

    equations.

    Several shear wall systems having different shapes of wall-frame and Flat Plate shear

    wall assemblies have been analyzed by static lateral load, response spectrum where theproposed methods have been used. The results of these analyses are compared with the

    results obtained using common shear wall modeling techniques.

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    TABLE OF CONTENTS

    ACKNOWLEDGMENTS . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ... V

    ABSTRACT. . . . . . . . . . . . . ... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ... . vii

    TABLE OF CONTENTS . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. viii

    LIST OF FIGURES . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ...xiii

    CHAPTER 1

    1. INTRODUCTION. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1

    1.1 Introduction. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ... . . . 1

    1.2 Objectives .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . 3

    1.3 Scope of the Study . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . 4

    1.4 Analysis of Shear Wall . . . . . . . . . . . . . . . . . . . . . . . . . . .... . . . . . 5

    CHAPTER 2

    2. Literature Review. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7

    2.1 Shear Wall Systems. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . 7

    2.2 Equivalent Lateral Force Method . . . . . . . . . . . . . . . . . . . . . . . . .. 8

    2.3 Method of Analysis of Shear Wall Structures . . . . . . . . . . . . . . . . ..10

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    2.3.1 Finite Element Analysis (FEA). . . . . . . . . . . . . . . . .. .. . . . 10

    2.3.2 Continuous Connection Method (CCM) . . . . . . . . . . . . . . 11

    2.3.3 Equivalent Frame Analysis (EFA) . . . . . . . . . . . . . . . . .. . 12

    2.3.4 ETABS non Linear Version 8.5 . . . . . . . . . . . . . . . . . . . ...13

    CHAPTER 3

    3. Research Methodology . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 14

    3.1 Introduction. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ..14

    3.2 Behavior of Symmetric Wall Frame. . . . . . . . . . . . . . . . . . . . . . .. .15

    3.3 Computer Analysis by E-TABS. . . . . . . . . . . . . . . . . . . . . . . . . 15

    3.4 Manual Calculation. . . . . . . . . . . . . . . . . . . . . . . . .20

    3.5 Summery . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ...27

    CHAPTER 4

    4. Modeling of Shear Walls. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .29

    4.1 Two Dimensional (Planar) Shear Wall Models. . . . . . . . . . . . .... . . 30

    4.2 Modeling And Analyzing the Shear Wall Model.. . . . . . . . . . . . . . . 31

    4.3 Equivalent Frame Model (Wide Column Analysis) . . . . .. . . . .. . . 33

    CHAPTER 5

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    FIGURES

    1.1 Typical Floor Plan of a Shear Wall - Frame Building Structure .. . . . . . . . .... 2

    1.2 Typical Shear Wall Sections .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 5

    2.1 Shape of Shear Wall . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . 7

    2.2 Building Structure Subjected to Equivalent Lateral Loads. . . . . . . . . . . . . 9

    4.2 Shear Wall Model . . . . . . . . . . . . . . . . . . . . .. . . . . . . . . . . . . . . . . . . . ..30

    4.2.2 ETABS Shear Wall Model . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 31

    4.2.3 ETABS Model Used for Linear Procedures . . .. . . . . . . . . . . . . . . . . .... . . 32

    4.3.1 Equivalent Frame Model of a Shear Wall . . . . . . . . . . . . . . . . . . . . . ....33

    5.3 U-Shaped Shaped Shear Wall Assembly . . . . .. . . . . . . . . . . . . . . . .... . .39

    5.4 L-Shaped Shaped Shear Wall Assembly . . . . .. . . . . . . . . . . . . . . . . ... . .39

    5.5 W-Shaped Shaped Shear Wall Assembly . . . . . . . . . . . . . . . . . . . . . . . 40

    5.6 H-Shaped Shaped Shear Wall Assembly . . . . .. . . . . . . . . . . . . . . . . . . . ..40

    5.7 T-Shaped Shaped Shear Wall Assembly . . . . .. . . . . . . . . . . . . . . . . . . ...40

    5.8 Plan of a Rectangular Wall Assembly . . . . . . . . . . . . . . . . . . . . . . . . . 41

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    CHAPTER 1

    INTRODUCTION

    1.1 Introduction

    High rise building is a structure vertically cantilevered from the ground level subjected

    to axial loading and lateral forces. It consists of frames, beams, shear walls, core walls,

    and a slab structures which interact through there connected edges to distribute lateral

    and axial load imposed on the building. Lateral forces generated either due to wind

    blowing against the building or due to the inertia forces induced by ground shaking

    which tend to crack the building in shear and push it over in bending. These types of

    forces can be resisted by the use of shear wall system which is one of the mostefficient methods of ensuring the lateral stability of tall buildings.

    For building taller than ten stories, frame action obtained by the interaction of slabs

    and columns is not adequate to give the required lateral stiffness. It also has become

    and uneconomical solution for tall buildings. However it can be improved by statically

    placing shear walls as it is very effective in maintaining the stability of tall buildings

    under severe wind or earthquake loading.

    1. Structural Frame Systems: The structural system consist of frames.

    Floor slabs, beams and columns are the basic elements of the structural

    system. Such frames can carry gravity loads while providing adequate

    stiffness.

    2. Structural Wall Systems: In this type of structures, all the vertical

    members are made of structural walls, generally called shear walls.

    3. Shear WallFrame Systems (Dual Systems): The system consists of

    reinforced concrete frames interacting with reinforced concrete shear

    walls.

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    Most of the high rise reinforced concrete building structures in Bangladesh have shear

    wall-frame systems. A typical floor plan of a shear wall-frame building structure is

    given in Figure 1.1.

    Figure 1.1 Typical Floor Plan of a Shear Wall-Frame Building Structure

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    1.2 OBJECTIVES:

    The main objectives of the research are as follows:

    1. To carry out a frame analysis on shear wall models using ETABS non

    linear version 8.5 software.

    2. To check the reliability of frame analysis method compare to wall

    frame shear wall and flat plate shear wall.

    3. To determine the ultimate lateral load due to wind and earthquake.

    4. To find out and compare the different calculated value of those wall

    frame and flat plate shear wall structures.

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    1.3SCOPE OF THE STUDY

    The main intention of the research work presented in this thesis is to study typical high

    rise building structures with shear wall-frame systems. Proper analysis and design of

    building structures that are subjected to static and dynamic loads is very important.

    Another important factor in the analysis of these systems is obtaining acceptable

    accuracy in the results. The object of this study is to model and analyze shear wall-

    frame structures having non-planar shear walls. In order to reduce the required time

    and capacity for the analysis of the structural systems, frame elements are used instead

    of plane stress elements in modeling the shear walls. Two two-dimensional shear wall

    models, based on the conventional wide column analogy, are developed for modeling

    (a) open and (b) closed section non-planar shear walls. The proposed models can be

    used in both static and dynamic elastic analysis of shear wall-frame structures.

    The accuracy and the efficiency of the proposed models are tested by performing static

    lateral load analysis, response spectrum analysis and time history analysis on single

    shear walls and shear wall-frame systems. In order to check the validity of the

    proposed models, the same analysis are performed on the considered structural

    systems, in which shear walls are modelled by wall elements of ETABS [8.5]. In

    addition, comparisons are made with several methods and experimental results from

    the literature.

    In the first part of the static lateral load analyses, single shear walls having different

    cross- sections are taken into consideration. They are subjected to point loads acting at

    floor levels. Two different loading conditions are applied on the structure:

    (a) Axisymmetric lateral loading

    (b) Pure floor torsions

    Translations and rotations at floor levels are obtained for different shear wall models.

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    1.4 Analysis of shear wall:

    It is a fact that shear walls have high lateral resistance. In a shear wall-frame system,

    this advantage can be used by placing shear walls at convenient locations in the plan

    of the building.

    In general, shear walls are in planar form in the plan of the building. However, some

    combinations of planar walls are also used in the structural systems. Typical non-

    planar shear wall sections used in the building structures are given in Figure 1.2

    Figure 1.2 Typical Shear Wall Sections

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    The analysis of shear wall-frame structures is more complicated than frame systems.

    In order to reflect the actual behavior of the shear walls, several models have been

    developed. Wide column analogy, braced frame analogy and shell element derived by

    using finite element formulation are the most popular models. In the first two models,

    frame elements are used and in the last model, plane stress elements are used.

    Another important point for the lateral load analysis of building structures is modeling

    the structural system. A common method which is widely used in design offices is to

    perform analysis on a two dimensional model obtained from the actual three

    dimensional system by using some simplifying assumptions. The total number of

    degrees of freedom is reduced significantly through this method. Some computer

    programs which model the buildings in series of two dimensional frames in two

    orthogonal directions use the same logic. The displacement compatibility is

    established by infinitely rigid slabs at floor levels.

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    CHAPTER 2

    Literature review

    2.1 Shear walls systems

    Shear walls have been the most common lateral force resisting elements for tall

    building besides frame system. It is an efficient method of ensuring the lateral stability

    of tall buildings and also efficient against torsional effects when combined together

    with frame structure. There stiffness is such that sway movement under wind &

    earthquake load can be minimized.

    Structural forms of shear wall are commonly using buildings of 10 to 30 stories.

    Monolithic shear wall can be classified as short, squat or cantilever as in fig 2.1

    according to there height/depth ratio. The walls may be planer, flanged or core in

    shape.

    Figure : 2.1 Shapes of Shear Wall

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    2.2. Equivalent Lateral Force Method

    The equivalent lateral force method is commonly preferred by design engineers

    because of its simplicity. It is based on the following assumptions:

    1. The effects of yielding on the building structure are approximated

    using elastic spectral acceleration reduced by a modification factor.

    2. A linear lateral force distribution can be used to represent the

    dynamic response of the building structure.

    The following procedure is used for the analysis of building structures using the

    equivalent lateral load method:

    1. Determination of the first natural vibration period.

    2. Determination of the total equivalent seismic load.

    3. Determination of design seismic loads acting at storey levels.

    4. Determination of points of application of design seismic loads.

    5. Analysis of the structural system.

    A building structure subjected to lateral forces obtained by the equivalent lateral forcemethod is shown in Figure 2.2. A triangular distribution of equivalent lateral loads

    with zero loading at the base of the structure is considered in the analysis.

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    Figure 2.2 Building Structure Subjected to Equivalent Lateral Loads

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    2.3 Method of Analysis of Shear wall structures

    Analysis on shear wall structures can be made in elastic, elastic-plastic and ultimate

    condition. Due to its simplicity, elastic analysis is still widely in used today in the

    design offices.

    There are several methods available for the analysis of coupled shear wall as been

    introduced in Chapter 1. Three common basic methods that usually been used are

    finite element analysis, continuous connection method and equivalent frame analysis.

    2.3.1 Finite Element Analysis (FEA)

    In finite element method, the main idea is to discrete a complex region defining a

    continuum into simple geometric shapes called finite element. The material properties

    and the governing relationships are considered over these elements and expressed in

    terms of unknown values at element corners. An assembly process, duly considering

    the loading and constrain, results in a set of equations. Solution of this equations gives

    us the approximate behavior continuum.

    The advantage of finite element analysis includes in which the nonlinearities behavior

    of material or structure can be considered in the analysis. The term non linear is use in

    structural analysis to describe a solution where the deformation is not proportional to

    the applied load. This is may be due to geometric nonlinearities, materials

    nonlinearities and the contact of bodies with geometric and materials nonlinearities. It

    also virtually may include various geometrical shapes of structures.

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    Factors that usually considered for nonlinear concrete materials model used in the

    analysis are includes of.

    1) Nonlinear behavior in compression at materials including hardeningand softening

    2) Fracture of concrete in tension based on nonlinear fracture mechanics3) Biaxial strength failure criterion4) Reduction of the shear stiffness after cracking

    Nonlinear finite element analysis (NLFEA) make possible for me to analyze models

    real life conditions on the desktop. The analysis can be made in elastic, elasto-plastic

    and ultimate conditions. Results obtain cold offer very good alternatives to

    excremental results. This method is cheaper but time consuming whereas relatively

    simple force distribution output is required for design but certainly not true for

    research purposes.

    2.3.2 Continuous connection method (CCM):

    Continuous connection method is an analysis where the coupling beams of shear wall

    structure are replaced by continuous connected media along its height. The coupling

    beams are assumed to deform with a point of contra flexure, normally at mid-span.

    The walls are assumed as cantilever system on a rigid foundation and it neglects the

    effect of the beams axial deformation. The openings are replaced by a single

    continuous shear medium.

    The method also allows simple elevation for any load pattern to be included in the

    analysis. A simple analytical solution can be derived, including the accuracy of force

    and deflection by explicit mathematical relationships which are dependent of the no.

    of stories. The analysis can be made in elastic and elasto-plastic conditions. Elasto-

    plastic method of analysis based on CCM is done by dividing the structure into elastic

    and plastic zone.

    Several problems may arise when obtaining the solution to the equation if unusual

    base forms, irregularities of openings, such that new boundary conditions that has to

    be applied to the equation.

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    2.3.3 Equivalent Frame Analysis (EFA)

    Frame analysis may also be called wide frame analogy . It is a simple method and can

    be used in plan frame programs. This method treats the walls and beams as discrete

    frame members .walls and connecting beams are replaced by the line element of

    stiffness equal to those of the units they replaced.

    The method of analysis is based on the assumption that a linear relationship exists

    between the applied action and the resulting displacement .This assumption requires,

    first the material of the frame shall behave in Hookean manner at all points and

    throughout the range of loading considered. Second, it assumes that the changes in the

    geometry of the structure are small enough to be neglected when the internal action

    are calculated .

    Two basic procedures in frame analysis are flexibility method and deflection or

    stiffness method. in the first approach, certain action are temporarily removed, these

    action are the unknowns in the compatibility equations which lead to the

    complementary solution. In the second approach. certain displacements are prevented

    or removed. The equilibrium equations are written in terms of these unknown to be

    sought displacements.

    Stiffness method is the basic method used nonlinear ETABS-8.5 to analyse structures.

    It can be performed in a linear analysis or geometrical non- linear analysis. However,

    this second order elastic analysis has not yet included in the version ETABS 8.5 non

    linear. Since this study was using non linear version ETABS 8.5.

    So the shear wall models where actually analyzed using first-order elastic analysis of

    stiffness method. In this method, the structures assumed to behaves linearly elastic so

    that the principles of superposition applied.

    Occasionally these method give the wrong impression on the behavior of shear wall

    structure under loading (Kwan 1993), however due uncertain and inability to

    understand the post-elastic behavior, time constraint and also its simplicity, the results

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    output are still acceptable by engineers. Thus this study was carried out to view the

    reliability of the method compared to the analytical and NLFEA method.

    2.3.4 ETABS non linear version 8.5

    This manual presents a set of simple building systems that have been analyzed using

    ETABS Version 8.5. The examples demonstrate some of the analytical capabilities of

    the ETABS system. For purposes of verification, key results produced by ETABS are

    compared to independent sources, such as hand calculated results, theoretical or

    published results, or results obtained from other structural/finite element programs that

    are verified not using ETABS. The examples cover each type of element, static and

    dynamic analysis and linear and nonlinear options.

    For each example, this manual contains a short description of the problem; a list of

    significant ETABS options activated; and a comparison of key results with theoretical

    results or results from other computer programs.

    Significant Options of ETABS Activated

    Two-dimensional frame analysis

    Vertical beam span loading

    No rigid joint offsets on beams and column

    Column pinned end connections

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    CHAPTER 3

    RESEARCH METHODOLOGY

    3.1 Introduction:

    The Research Methodology was started with problem identification on reinforced

    concrete shear wall and setting up the objectives & scope of study. Then all the related

    background information were collected an studied for the literature review for

    knowledge updating.

    The major parts of this study are structural modeling and computational analysis using

    frame analysis method in non linear version ETABS. The results obtain then being

    assessed, interpreted and compared with one which was obtained from the calculation.

    3.2: Behavior Of Symmetric Wall-Frame

    Considering the separate horizontal stiffnesss at the top of a typical 10-story elevator

    core and a typical rigid frame of the same height the core might be 10 or more times as

    stiff as the frame. If the same core and frame were extended to a height of 20 stories, the

    core would then be only approximately three times as stiff as the frame. At 50 stories the

    core would have reduced to being collects half as stiff as the frames. This change in therelative top stiffness with the total height occurs because the top flexibility of the core,

    which behaves as a flexural cantilever, is proportional to the cube of the height ,where as

    the flexibility of the frame ,which behaves as a shear lever, is directly proportional to its

    height. Consequently, height is a major factor in determining the influence of the frame

    on the lateral stiffness of the wall-frame.

    A further understanding of frame interaction between the wall and the frame in a wall-

    frame structure is given by the deflected shapes of a shear and a rigid frame subjected

    separately to horizontal loading. The wall deflects in a flexural mode with concavity

    downwind and a maximum slopes at the top, while the frame deflect in a shear mode

    with concavity upwind and a maximum slope at the base. When the wall frame are

    connected together by pin-ended links and subjected to horizontal loading, the deflected

    shape of the composite structure has a flexural profile in the lower part and a shear profile

    in the upper part. Axial forces in the connecting links cause the wall to restrain the frame

    near the base and the frames to restrain the wall at the top. Illustrations of the effect of

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    wall frame inter action are given by the curves for deflection, moments and shear for a

    typical wall-frame structure. The deflection curve and the wall moment curve indicate the

    reversal in curvature with appoint of inflexion ,above which the wall moment is opposite

    in sense to that in a free cantilever. The share as approximately uniform over the height

    of the frame, except near the base where it reduces to a negligible amount. at the top,where the external share is zero, the frame is subjected to a significant positive shear

    ,which is balanced by an equal negative share at the top of the wall, with a corresponding

    concentrated interaction force action between the frame and the wall. Special

    consideration may have to be given in the design to transferring this interaction force

    3.3 Computer Analysis:

    i. GRID ->X-DIC-> 6, Y-DIC-> 5UNITK-FTNO OF story-2

    Typical story height=10

    Bottom story height=6

    Custom Grid spacing -> Edit Grid->

    X Grid Data->

    A=0,B=15,C=20,D=30,E=55,F=60

    Y Grid Data->

    1=0,2=25,3=45,4=50,5=60

    ok-> Grid only-> ok->Get Plan

    ii. Define-> Materials properties->Concrete->Modify/Show Materials-> Materials Name-Concrete->

    iii. Define -> Frame Section-> Delete all Properties->Add/Wide Flange -> Add rectangular->

    Section Name-> [For Beam b 10 X 18 Similarly

    Selection C 18 X 21, GB 10 X 18

    Materials->Conc-> Depth 18, Width->10->

    Reinforcement-> Beam-> Concrete Cover to Rebar center->2.5(Top)-

    >2.5(Bottom)-> ok->

    Ok

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    Properties:

    Type of Property to find

    B1=10 X 18

    B2=10 X 21

    B3=10 X 24

    C1=18 X 21

    C2=18 X 24

    C3=21 X 24

    GB=10 X 18->ok->ok->

    Define-> wall/slab/Deck section-> Slab 1->

    Add new Slab->7 ->Concrete->

    Membrane-7

    Bending-7

    Plate->ok->

    Add New Slab->5->concrete->

    Membrane->5

    Bending->5

    Plate->ok->Add New Slab->4->concrete->

    Membrane->4

    Bending->4

    Plate->ok->(Draw lines)->1

    Properties of Object

    Property [say B1 10 X 18(Draw lines at Plan)

    (at story Level -2)[one story]

    [Similarly B1,B3 Beam line draw at plan]

    All stories-> Select -> Properties->C1 18 X 21

    C2 18 X 24, C3 21 X 24 all Column input on plan->

    Select one story new select (plan)-> Base->ok->Esc->

    Select all column->(select)-> Fixed Support(select)->ok->

    Again (Draw lines )(For GB)-> Property-> Select->

    One story->Plan->Story-1->ok->

    GB 10 X 18,(Now Draw GB lines at plan)

    (Esc)->

    Plan-> story-2->ok->

    Select->Property->4->Draw at Plan

    Property->5->(Draw at plan)

    Again property & select ->7-> & Draw at Plan

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    Select-> All Panel (all) and select object fill->Apply all windows ->ok->

    UNIT-KFT->

    Edit-> Edit Story data-> insert story->

    Story height-10

    No of stories->6story

    Select-> (all)->Assign-> Shell area loads-> Uniform->Dead->unit(lb-ft)->

    load 120 lb ft->ok->

    Select (P5 )->Assign-> shell/area loads-> Uniform->

    Live-> Unit(lb ft)->Load-40 lb ft ->ok->

    Define ->static load case->

    Load TYPE Self WT Multiplier Auto Lateral Load

    EQX QUAKE 0 UBC-94->add New

    load->

    EQY QUAKE 0 UBC-94->add Now

    load->WIND X WIND 0 UBC-94->add Now

    load->

    WIND Y WIND 0 UBC-94->add Now

    load->

    Select->EQX,- QUAKE- 0- UBC - 94

    Modify lateral load ->X-Dic->Method a->

    Ct(ft)->0.03->Rw->12

    Seismic Co-Efficient-> Seismic Zone factor, z

    Per Code 0.20->Site Co-Efficient->1.2/1.5Importance factor =I=1.0

    Y-Dic->Method A->

    Ct(ft)->0.03->Rw=12

    Seismic zone Factor,2

    Per Code->0.20->

    Site Co-Efficient, s=1.2

    Importance factor I=1.00->ok->ok->

    Select [all Stories]->

    (All)->Assign->Shall/Area->

    Area object Mesh options->

    [Area object auto Mesh options]

    Auto mesh object into structural elements

    Further Sub divide auto mesh with Maximum elements size of 4->ok-.

    Select auto area mesh ->

    Apply all windows->

    Ok->

    Select (all)->D1 ->ok->

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    Define->Mass source-> From loads->

    Dead-1.2 Add->

    Live-1.6 add->

    EQX-> 1 Add->

    EQY-> 1 Add->

    WINDX=1 Add->ok->

    WINDY=1

    Define->Special Seismic Data->

    Do not include special seismic design data->

    Ok->

    Analyze->select analysis option->

    (OFF) Dynamic analysis->

    Include P-Data->Select P-Data

    Parameters->

    Maximum Iteration10Dead-12 Add->

    Live-1.5 Add->ok

    Analyze->Run Analysis->Save->

    Options->Preferences->Concrete Frame

    Design-> Design Code->ACI 318-99->ok->

    Design-> Concrete Frame Design->

    Start design/Check of Structure Again left site select ->Design->concrete frame

    Design

    Start design/Check of Structure

    Plan->Top of building->ok->Display->Show Deformed shape->

    Dead Static Load ->EQX, EQY, WINDX, WINDY etc 14/16 Loads ->ok->

    Now plan corner select, so we found slab panel any corner deflection value

    () select -> Dcon 14 (similarly we found any type of deflection)

    Display->Show member force/Stress diagram->

    Frame/pier/spandrel force->

    Dead static load moment 3-3

    Similarly share 2-2

    Option ->Moment diagram on tension side ->

    Beam deflection calculation->

    Select any Beam member then right button click we get deflection

    value/moment/share

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    Rebar calculation:

    Design-> Concrete frame design->

    Display design info .->

    Design output->

    Longitudinal Reinforcements->ok->

    Share Reinforcements

    Rebar percentage

    The approximate method of analysis is valuable in providing an understanding of a wall-

    frames behavior and in allowing the initial sizing of members as part of the preliminary

    design process. It does not allow, however, for changes of properties within the height of

    the structure or for the effects of axial deformations of the columns that in a tall slender

    frame could be significant. Therefore, a computer analysis, using one of the widely

    available structural analysis programs, should be used for the final design.

    Modeling the wall frame structure for a computer analysis will follow the principles

    outlined in chapter 4. If the structure is symmetric on plan and subjected to symmetric

    loading. So that it does not twist, a planer model of only one-half of the structure

    subjected to one-half of the loading need be considered. Shear walls and share wall

    core are represented by simple column cantilevers with corresponding moments of

    inertia, while the frames are represented by equivalent assemblies of beam elements.

    In the planar model the cantilever columns and frames are constrained at each floor by

    the analysis programs nodal constraint option, if available, or connected by axially

    rigid links, to cause equal horizontal displacements of the bents, as imposed on the

    structure by the in plane rigidity of the floor slabs. The horizontal loads may be

    applied to the nodes of any convenient column or frame.

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    Analysis of Shear will due to lateral load.

    3.4 : Manual Calculation

    Worked Example:

    15 story Building, 52.5m height, wall frame structure.

    Frame Type Interior Column

    Ixx (m4)

    Exterior Column

    Iyy (m4)

    Girder

    Type-01 0.052 0.030 0.007 (15"24")

    Type-02 0.030 0.013 0.005 (12"24")

    Core Inertia = 597.75 m4

    Elastic modulus. E = 2.0107kn/m

    2

    Wind pressure = 1.5 kn/m2

    Step-01

    Determine parameter- = H

    (a) Add the flexural rigidities EI of all walls and cores to give the total (EI)t. In this

    case there is only a core.

    For the core I = 597.75 m4.

    There fore (EI)t= 2.0107597.75

    = 11.95 109kn-m

    2

    (b) Evaluate the when rigidities (GA) of the rigid frame bents and any wall frame

    bents, using equation 11.26, 11.27 and 11.28 and sum them to give the total (GA)t. In this

    case there are only the former.

    The when rigidities (GA) of the two types of frame (1) and (2) by using the

    expression. For frame type - 01

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    Now, GA =

    CG

    h

    E

    11

    12

    =

    5.3

    052.0303.02

    1

    62.7

    007.04

    15.3

    100.212 7

    = 20.1614.2725.3

    100.212

    = 2.38 105Kn

    FOR FRAME TUPE-02

    GA =

    5.3

    03.03013.02

    1

    62.7

    005.04

    15.3

    100.212 7

    = 17.303815.3

    10212

    7

    = 1.67105Kn

    Total (GA)t= GA = (22.38+21.67) 105

    = 8.10105Kn

    (c) Use the Values obtained in items a and b to evaluate H, using

    t

    t

    EI

    GAHH

    = 52.591095.11

    1010.8

    Therefore 43.0H

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    An analysis for uniformly distributed loading in then made as follows.

    Step-02:

    Determine Horizontal Displacements:

    The displacement at height z from the base is obtained by substituting H and

    Z/H in equation (11.10) or, at ternotively by taking the value of K1corresponding of the

    obtained values of H and Z/H from fig 1.2 and substituting it in the expression.

    30.11/8

    11

    4

    HZHKEI

    wHZY

    t

    For the given structure, the wind loading per unit height.

    W= 1.545.73 = 68.60 Kn/m

    At the top = H = 0.4

    Z/H = 1, K1=0.87 0.43 0.87

    0 1.0

    87.01095.118

    5.5260.689

    4

    HY

    = 0.0047 m.

    STEP-03

    Determine maximum story drift Index:

    The maximum story drift index is obtained by referring to fig 2.2 and scaning

    the appropriate H curve to find the maximum value of K2, which is then substituted in

    max6

    max 2

    3

    kEI

    WH

    dz

    dy

    t

    For the given structure, K2(max) = 0.36

    Therefore, the maximum story drift index approximate height is obtained as,

    Z/H= 0.55m

    36.01095.116

    5.5260.68max

    9

    3

    dz

    dy

    = 0.000050 2 0.2

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    0.43 0.36

    0 0.41

    STEP-04

    Determine bending moments in the wall and frame.

    (a) The total moment carried by the walls in obtained either by substituting H and

    Z/H is equation (11.16) on by taking the appropriate value of K3from fig 3.2 and

    substituting in

    Mb(Z) = 3

    2

    2K

    WH

    For example, at the mid 6th story level Z = 22.75 m, Z/H = 22.75/02.5 = 0.43 of

    the structure considered, K3= 0.283.

    Therefore, the moment in the core is obtained is,

    Mb= 283.02

    5.526.68 2

    = 2.67104Knm H 2 0.05

    0.43 2.28 (K3)

    0 0.35

    For a structure consisting of multiple walls, the moment in any individual wall is

    then obtained by distributing the total wall moment between the walls in proportion to

    their flexural rigidities.

    (b) The total moment in the set of frames of a level Z from the base as expressed inequation (11.17) is equal to the difference between the total external moment and the

    total moment in the walls of that level.

    Ms(Z) =

    )(2

    2

    ZMZHW

    b

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    At the same mid-sixth story level of the given structure as in item 4a. The moment

    carried by the frames is obtained as.

    Ms= 4

    2

    1067.22

    75.225.526.68

    = 3.65103Knm

    The moment in the individual frames is obtained by distributing the total frame

    moment between the frames in proportion to their shearing rigidities.

    Therefore, the moment in frame type-01

    = 35

    5

    1065.31010.8

    1038.2

    = 1.07103 Knm

    and the moment in frame type-2

    = 35

    5

    1065.31010.8

    1067.1

    = 752.53 Kn-m.

    The banding moments of other levels of the structure have been found similarly

    and are potted in fig 11.10 (b)

    STEP-05

    Determine shear forces in wall and frame =

    (a) The total shear in the walls at a level Z from the base may be obtained by

    substituting H and Z/H in equation (11.19) on by taking the value of K4from fig 4.2

    and substituting in equation (11.33)

    Qb(Z) = WHK4

    For example, at the mid-seventh story level (Z=26.25m, Z/H = 0.5 of the structure

    considered, K4= 0.22.

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    Therefore, the their in the core is obtained as,

    Qb= 68.605250.22 H 2 0.02

    = 792.33 Kn 0.43 0.22

    0 0.28

    K4= 0.22

    For a structure consisting of multiple walls, the shear force in the individual, walls

    is then obtained by distributing the total shear between the walls in proportion to their

    flexural rigidities.

    (b) The total shear in the frames of a height Z is the difference between the external

    shear and the total wall shear of that level, as determined above.

    Qs(Z) = W (H-Z) - Qb(Z)

    At the same mid seventh story level of the given structure, as in item 5a, the shear

    carried by the frames is obtained as

    Qs= 68.6 (52.5-26.25) - 792.33

    = 1008.42 Kn.

    The shear in the individual frames is given by distributing the total frame shear

    between the frames in proportion to their shearing rigidities.

    Therefore, the shear in frame type-01

    = Kn30.29642.10081010.81038.2 5

    5

    And the shear in frame type-2

    = 42.10081010.8

    1067.15

    5

    = 208 Kn

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    The values of share at other levels of the structure have been found similarly and

    are potted in fig 11.10.

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    Summary:

    The horizontal interaction between the walls and frames in wall-frame structure causes

    an increased lateral; stiffness of structure, reduced moments in the walls, and, in a

    uniform structure, an approximately uniform shear in the frame. The benefits of

    interaction increase with-frames are economical for buildings of to 15 stories or more.

    The wall-frame horizontal interaction occurs because the different free-deflected

    shapes of the wall and the frame are made to conform to the same configuration by the

    axially stiff connecting girders and slabs.

    An approximate theory is presented for non twisting uniform wall-frames on the basis

    of a continuum model of the structure, with a flexural cantilever representing the

    walls, a shear cantilever representing the frames, and a horizontally stiff continuous

    linking medium repressing the slabs and girders. A characteristics differential equation

    for deflection is retrain in terms of the two structural parameters of the wall frames.

    This has be solved for three tropical types of loading to obtain general formulas for the

    deflections, the story drift, the shears, and moments on the walls and frames. Design

    curves are also develop that allow repeat estimates of the deflections and forces. The

    solution by both formulas and grapes give close estimate of the deflection and forces

    in non twisting uniform wall frames of 15 stories or more, and approximate estimate

    of the forces in non-twisting, non-uniforms wall frames, which may be use as guide

    lines for preliminary design. An accurate estimate of the deflections and forces in non-

    uniform or in twisting wall frame structures requires a computer analysis.

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    CHAPTER 4

    MODELING OF SHEAR WALLS

    According to Earthquake Code a shear wall is defined as a vertical structural member

    having a length of seven or more times greater than its thickness. Being the major

    lateral load resistant units in multi storey building structures, shear walls have been

    studied experimentally and theoretically over the last fifty years.

    In the lateral load analysis of building structures having shear walls, proper methods

    should be used for modeling planar and non-planar shear wall assemblies. Shear wall

    models in the literature can be divided into two:

    1. Models developed for elastic analysis of building structures.

    2. Models developed for nonlinear analysis of building structures.

    The investigation of nonlinear shear wall models is beyond the scope of this study.

    In this chapter, shear wall models developed for the lateral load analysis of multi

    storey structures in elastic region are presented. Since the methods for modeling

    building structures are analyzed separately (two dimensional modeling and three

    dimensional modeling are presented in Chapter 2) shear wall modeling studies can

    also be investigated in according to the two and three dimensional approaches.

    4.1 Two Dimensional (Planar) Shear Wall Models

    The literature mentions several shear wall models that were developed for two

    dimensional elastic analysis of multi storey building structures. In this part, a review

    of these models is given.

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    4.2 Modeling and Analyzing the Shear Wall Model:

    Generally there are several steps in modeling and analyzing the shear walls. First is by

    installing the section properties for every part of the shear wall using section maker in

    ETABS. Followed by building the frame models for every shear walls in ETABS 8.5

    and all the section properties and restraints are assigned to the respective part of the

    structure. Then applying the structure with load and analyzed it too obtain all the

    results.

    Figure 4.2 :Shear Wall Model

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    4.3 Equivalent Frame Model (Wide Column Analogy)

    The equivalent frame model was developed the analysis of plane coupled shear wall

    structures. The model was limited to lateral load analysis of rectangular building

    frames without torsion. It was improved in the 1970s by Mcleod and McLeod and

    Hosny for the analysis of nonplanar shear walls. In the equivalent frame method,

    which is also known as wide column analogy, each shear wall is replaced by an

    idealized frame structure consisting of a column and rigid beams located at floor

    levels. The column is placed at the walls centroidal axis and assigned to have the

    walls inertia and axial area. The rigid beams that join the column to the connecting

    beams are located at each framing level. In this method, the axial area and inertia

    values of rigid arms are assigned very large values compared to other frame elements.

    Due to its simplicity, the equivalent frame method is especially popular in design

    offices for the analysis of multistory shear wall-frame structures.

    Figure 4.3.1 Equivalent Frame Model of a Shear Wall

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    CHAPTER 5

    THREE DIMENSIONAL MODELING OF SHEAR WALLS

    IN THE LATERAL LOAD ANALYSIS OF SHEAR

    WALL-FRAME STRUCTURES

    5. Three Dimensional Modeling of Shear Walls in the Lateral Load Analysis of

    Shear Wall-Frame Structures

    As stated in Chapter 1, the main objective of this study is to model nonplanar shear

    wall assemblies in a realistic and feasible way for the analysis of shear wallframe

    structures. The modeling studies are based on rigid diaphragm floor assumption and

    the three dimensional equivalent frame method, in which a planar shear wall is

    modeled using an equivalent column and rigid beams at floor levels. A generalized

    three dimensional finite element program, ETABS 8.5, is used in the studies.

    In the first part of this chapter, the basic assumptions used in the modeling studies are

    presented. These assumptions are divided into three categories:

    1. Material behavior

    2. Element behavior

    3. Structural behavior

    In the second part, the models developed for nonplanar shear walls having open and

    closed sections are presented. The comparison of the proposed models with the other

    shear wall modeling methods (using ETABS wall element and conventionalequivalent frame method) in lateral load analyses are made in the last part of the

    chapter.

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    5.1 Basic Assumptions

    In the analysis of all kinds of structures, a number of assumptions should be made in

    order to reduce the size of the actual problem. As stated above, these assumptions can

    be divided into three categories: material behavior, element behavior and structural

    behavior. In this part, the assumptions used in the modeling studies are presented.

    5.1.1 Material Behavior

    The behavior of the materials in this study is assumed to be linear elastic. Linear

    elasticity is the most common material model for analyzing structural systems and is

    based on the following assumptions:

    1. The material is homogenous and continuous.

    2. The strain increases in a linear portion as stress increases.

    3. As stress decreases, the strain decreases in the same linear portion.

    4. The strain induced at right angles to an applied strain is linearly

    proportional to the applied strain, which is called Poissons ratio

    effect.

    In addition, the effects of cracking, creep, shrinkage and temperature on the material

    are not taken into consideration.

    5.1.2 Element Behavior

    Two different structural elements are used in the analyses. The three dimensional

    frame element, which is presented in Chapter 2 (Figure 2.4), is used for modeling the

    beams and columns of the structural systems. It is assumed to have six degrees of

    freedom at each end. The elements of the equivalent frame model (equivalent wide

    column and rigid beams) are also modelled using three dimensional frame element.

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    The three dimensional shell element, which is used for modeling shear walls in

    verification studies, is assumed to have six degrees of freedom at each node.

    Additional assumptions about the element behavior are as follows:

    1. Shear deformations in the structural elements are ignored.

    2. Frame elements and shell elements have uniform cross-sections

    throughout the length.

    5.1.3 Structural Behavior

    The multistory building systems analyzed in this study are considered to be rigid

    frame structures. In such systems, all structural elements of the system are assumed to

    have infinitely rigid moment resistant connections at both ends. Another assumption

    about the structural system is the linear elastic structural system behavior, in which the

    deformations are proportional to the loads. It is widely used in structural analysis and

    leads to a very important simplification called superposition.

    In superposition, if a linear elastic structure is subjected to a number of simultaneously

    applied loads, the overall response can be determined by summing the responses of the

    structure to the loads applied at one time. Based on this assumption, the behavior of

    the structural system under eccentric lateral loads can be determined by superposing

    the behavior under the considered lateral loads, which are applied axisymmetrically,

    and the behavior under the pure torsion produced by these eccentric lateral loads.

    In the analysis performed in this study, it is assumed that only the structural

    components participate in the overall behavior. The effects of structural components,

    such as non-structural walls, are assumed to be negligible in the lateral load analysis.

    One of the most important assumptions in this study is the rigid diaphragm floor

    assumption, a common assumption which simplifies the problem significantly and

    reduces computing time. The rigid diaphragm floor assumption is based on the rigidity

    of the floors in their own plane. Field measurements on a large number of building

    structures verified that in-plane deformations in the floor systems are small compared

    to the inter-storey horizontal displacements. With the use of rigid floor diaphragms,

    the horizontal lateral loads acting at the floor levels of a building structure are directly

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    transferred to the vertical structural elements (columns and shear walls). This results in

    three displacement degrees of freedom at each floor level (translations in two

    orthogonal directions and rotation about vertical direction), and in-plane

    displacements of the diaphragm can be expressed in terms of these displacements .

    In dynamic analyses, it is assumed that the mass of each floor is lumped at a single

    node on the floor, which is generally the master node. The mass, m, is defined only in

    three degrees of freedom due to the constraining effect of the floor diaphragms. This

    approach is suggested by Chopra .

    5.2 Modeling Nonplanar Shear Walls

    Due to deficiencies in the two dimensional and the pseudo three dimensional lateral

    load analyses that are discussed in Chapter 2, three dimensional analysis should be

    performed for shear wall-frame structures having nonplanar shear wall assemblies. In

    this study, the modeling of nonplanar shear walls is examined in two parts, are as

    follows:

    1. Open sections

    2. Closed sections

    Two different modeling methods are developed for open and closed section shear wall

    assemblies. These methods are based on the behavior of the assemblies in shear wall-

    frame structures subjected to lateral loads for which the rigid diaphragm floor

    assumption is valid. In the modeling studies, the conventional equivalent frame model

    is used with significant modifications. The translational and rotational response of the

    shear wall assemblies are considered separately and the actual behavior of the

    structure subjected to eccentric lateral loads is assumed to be obtained by the

    superposition of the two responses. In the modeling and verification studies, SAP2000

    software is

    used. However, the proposed models can be implemented in any three dimensional

    frame analysis program having constraint option.

    In the following two parts, the proposed models developed for open and closed section

    shear wall assemblies are presented. In the last part, the performance of these models

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    is investigated by comparing the responses of the assemblies in static and dynamic

    loading.

    5.2.1 Modeling of Open Section Shear Walls

    It is a common assumption that due to the high in-plane stiffness of floor slabs, open

    section shear walls can be considered as thin-walled beams of non-deformable contour

    . In modeling open section shear walls, each planar wall in the assembly is replaced

    with a column having the same mechanical properties of the wall as in the equivalent

    frame method. In order to ensure the vertical compatibility of the displacements, the

    rigid beams at floor levels are rigidly connected to each other at the corners. In

    addition, the ends of the rigid beams that are connected to each other are released

    (disconnected) from the connection joint only for torsional moments. In another

    words, the transfer of torsional moments between rigid beams is prevented. In Figure

    the connection details of two orthogonal shear walls are given.

    In three dimensional analysis of open shear wall assemblies modelled by the

    conventional equivalent frame model, serious errors occur especially in the analysis of

    assemblies subjected to torsion. The stiffness of the structural system becomes stiffer

    than with finite element modeling. In the studies, it is observed that releasing the ends

    of the rigid beams from the connection joint decreases the torsional stiffness of the

    shear wall assembly significantly. This difference can be seen in the comparison

    studies of open section shear walls presented in the last part.

    Several modeling studies are performed on the open section shear wall assemblies.

    The plans of the analyzed open section shear walls and the corresponding models

    developed by the proposed method are given in Figure 5.3 to 5.7.

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    Figure 5.3 U-Shaped Shear Wall Assembly

    Figure 5.4 L-Shaped Shear Wall Assembly

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    Figure 5.5 W-Shaped Shear Wall Assembly

    Figure 5.6 H-Shaped Shear Wall Assembly

    Figure 5.7 T-Shaped Shear Wall Assembly

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    5.2.2 Modeling of Closed Section Shear Walls

    The proposed model for closed section shear wall assemblies is similar to the model

    developed for open section shear wall assemblies. The columns are placed at the

    walls centroidal axes and assigned to have the same mechanical properties of the

    walls. Rigid beams are located at the floor levels and make rigid connections with

    each other. Similar to the previous model, the ends of the rigid beams are released at

    the connections only for torsional moments.

    In the case of pure torsion, due to the rigid floor assumption, it is observed that rigid

    beams behave independently from the wide columns and make closed loops at floor

    levels. For this reason, the torsional stiffness of the model becomes much smaller than

    the torsional stiffness of the actual closed section assembly, as it is a summation of the

    torsional stiffnesses of disconnected wide columns in the model. This problem is also

    stated by Smith and Girgis . They reported that the closed section shear walls

    modelled by the equivalent frame method become less stiff than with the finite

    element method.

    The proposed model solves this problem by modifying the torsional constants of the

    wide columns by using the torsional constant of the shear wall section considered. The

    procedure has three steps:

    1. Calculation of the torsional constant of the closed section (Jc)

    2. Calculation of the torsional constants of the wide columns (Ji)

    Figure 5.8 Rectangular Shear Wall Assembly

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    5.2.3 Comparison of the Proposed Models With Other Models

    The performance of the proposed models are compared with the following shear wall

    modeling methods:

    1. Modeling with ETABS wall elements

    2. Conventional equivalent frame method

    In the comparisons, the following single shear wall assemblies are taken into

    consideration:

    1. U-shaped shear wall (SWS1) shown in Figure 5.3

    2. L-shaped shear wall (SWS2) shown in Figure 5.4

    3. W-shaped shear wall (SWS3) shown in Figure 5.5

    4. H-shaped shear wall (SWS4) shown in Figure 5.6

    5. T-shaped shear wall (SWS5) shown in Figure 5.7

    6. Rectangular shear wall (SWS7) shown in Figure 5.8

    All assemblies have four stories with rigid diaphragms at the floor levels. The height

    of all stories is 3.0 m and the thickness of the shear walls is 0.25 m. Other dimensions

    of the shear wall assemblies are given in the related figures.

    Two different types of analyses are performed in comparison studies of single shear

    wall assemblies:

    1. Static lateral load analysis.

    2. Dynamic analysis to obtain natural vibration periods of the assemblies.

    In the static lateral load analyses, two different loading conditions are used as shown.

    In loading condition 1, the shear wall assemblies are subjected to axisymmetric lateral

    loads acting at floor levels. Each of the four loads is 100 t. In load condition 2,

    assemblies are subjected to pure torsions (out of plane moments) at the floor levels.

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    CHAPTER 6

    Analysis and Result Interpretation:

    This Chapter consists of the results from frame analysis. The analysis was carried out

    to study the structural behavior of reinforced concrete shear wall structures under

    lateral loading at the ultimate condition. The study is focused on the determination of

    the ultimate lateral load due to wind and earthquake.

    6.1 : Calculation:

    SHEAR WALL -1(at point 4, 39, 50)

    A. Base Moment: WIND-X

    1. Plate Element : MY = 6028 (kip-in)2. Column Element : MY = 6018 (kip-in)

    B. Base Moment: WIND-Y

    1. Plate Element : MX = 5441 (kip-in)2. Column Element : MX = 5612 (kip-in)

    C. Base Moment: EQ-X

    1. Plate Element : MY = 20908 (kip-in)2. Column Element : MY = 21753 (kip-in)

    D. Base Moment: EQ-Y

    1. Plate Element : MX = 36509 (kip-in)2. Column Element : MX = 36502 (kip-in)

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    SHEAR WALL -2(at point 4, 5, 55)

    A. Base Moment: WIND-X

    1. Plate Element : MY = 1417 (kip-in)2. Column Element : MY = 1450 (kip-in)

    B. Base Moment: WIND-Y

    1. Plate Element : MX = 705 (kip-in)2. Column Element : MX = 703 (kip-in)

    C. Base Moment: EQ-X

    1. Plate Element : MY = 4179 (kip-in)2. Column Element : MY = 4169 (kip-in)

    D. Base Moment: EQ-Y

    1. Plate Element : MX = 29289 (kip-in)2. Column Element : MX = 29284 (kip-in)

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    SHEAR WALL -3(at point 25, 39, 52)

    A. Base Moment: WIND-X

    1. Plate Element : MY = 1808 (kip-in)2. Column Element : MY = 1804 (kip-in)

    B. Base Moment: WIND-Y

    1. Plate Element : MX = 1223 (kip-in)2. Column Element : MX = 1234 (kip-in)

    C. Base Moment: EQ-X

    1. Plate Element : MY = 7143 (kip-in)2. Column Element : MY = 7148 (kip-in)

    D. Base Moment: EQ-Y

    1. Plate Element : MX = 19743 (kip-in)2. Column Element : MX = 19737 (kip-in)

    Note:

    WIND-X = Wind Load at X-Axis

    WIND-Y = Wind Load at Y-Axis

    EQ-X = Earth Quake Load at X-Axis

    EQ-Y = Earth Quake Load at Y-Axis

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 WIND-X -0.29 0 6 0 0 0

    BASE 39 WIND-X -0.03 -0.01 2.39 0 0 0

    BASE 50 WIND-X 0.29 -0.73 5.98 0 0 0

    Summation Base WIND-X -0.03 -0.74 14.36 5641 -6028 -288

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 WIND-X -0.26 0 5.93 0 0 0

    BASE 39 WIND-X -0.03 -0.01 2.1 0 0 0

    BASE 50 WIND-X 0.31 -0.71 6.76 0 0 0

    Summation Base WIND-X 0.02 -0.72 14.79 5612 -6018 -288

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-Y 0.05 -0.2 36.8 0 0 0

    BASE 39 EQ-Y 0 -0.09 -13.61 0 0 0

    BASE 50 EQ-Y -0.07 79.24 67.78 0 0 0

    Summation Base EQ-Y -0.03 78.95 90.97 36509 -38179 33130

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-Y 0.04 -0.14 31.64 0 0 0

    BASE 39 EQ-Y 0 -0.1 -10.58 0 0 0

    BASE 50 EQ-Y -0.05 79.33 71.37 0 0 0

    Summation Base EQ-Y -0.02 79.09 92.43 36502 -38160 33170

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-X -0.87 0 18.14 0 0 0

    BASE 39 EQ-X -0.08 -0.02 8.17 0 0 0

    BASE 50 EQ-X 1.09 -1.02 23.5 0 0 0

    Summation Base EQ-X 0.14 -1.04 49.81 18693 -20908 -1218

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-X -0.78 0.00 18.19 0 0 0

    BASE 39 EQ-X -0.08 -0.02 7.15 0 0 0

    BASE 50 EQ-X 0.99 -0.98 26.48 0 0 0

    Summation Base EQ-X 0.12 -1.00 51.82 18501 -21753 -1118

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 WIND-Y -0.29 0 6 0 0 0

    BASE 5 WIND-Y -0.29 0 -7.63 0 0 0

    BASE 55 WIND-Y 0 0 0 0 0 0

    Summation Base WIND-Y -0.58 0 -1.63 -705 1417 252

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 WIND-Y -0.26 0 5.23 0 0 0

    BASE 5 WIND-Y -0.26 0 -6.95 0 0 0

    BASE 55 WIND-Y 0 0 0 0 0 0

    Summation Base WIND-Y -0.52 0 -1.72 -703 1450 256

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 WIND-X -0.29 0 6 0 0 0

    BASE 5 WIND-X -0.29 0 -7.63 0 0 0

    BASE 55 WIND-X 0 0 0 0 0 0

    Summation Base WIND-X -0.58 0 -1.63 -705 1417 252

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 WIND-X -0.26 0 5.23 0 0 0

    BASE 5 WIND-X -0.29 0 -6.86 0 0 0

    BASE 55 WIND-X 0 0 0 0 0 0

    Summation Base WIND-X -0.55 0 -1.63 -703 1450 256

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    PLATE

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-X -0.87 0 18.14 0 0 0

    BASE 5 EQ-X -0.85 0 -20.25 0 0 0

    BASE 55 EQ-X -2.21 0 0 0 0 0

    Summation Base EQ-X -3.93 0 -2.11 -2208 4179 1696

    COLUMN

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-X -0.78 0 18.19 0 0 0

    BASE 5 EQ-X -0.76 0 -20.76 0 0 0

    BASE 55 EQ-X -2.21 0 0 0 0 0

    Summation Base EQ-X -3.75 0 -2.57 -2163 4069 1619

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-Y 0.05 -0.2 36.8 0 0 0

    BASE 5 EQ-Y -0.03 -0.2 31.7 0 0 0

    BASE 55 EQ-Y 0 -2.46 0 0 0 0

    Summation Base EQ-Y 0.02 -2.86 68.49 29289 -31810 -1347

    COLUME ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 4 EQ-Y 0.04 -0.14 37.64 0 0 0

    BASE 5 EQ-Y -0.02 -0.13 29.66 0 0 0

    BASE 55 EQ-Y 0 -2.46 0 0 0 0

    Summation Base EQ-Y 0.02 -2.72 67.3 29284 -31844 -1357

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 WIND-Y -0.02 0.01 -1.37 0 0 0

    BASE 39 WIND-Y -0.03 -0.01 2.39 0 0 0

    BASE 52 WIND-Y 8.95 -0.01 3.24 0 0 0

    Summation Base WIND-Y 8.9 -0.01 4.25 1223 -1808 -2519

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 WIND-Y -0.02 0.01 -1.83 0 0 0

    BASE 39 WIND-Y -0.03 -0.01 4.1 0 0 0

    BASE 52 WIND-Y 8.13 0 2.02 0 0 0

    Summation Base WIND-Y 8.08 0 4.29 1234 -1804 -2514

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 WIND-X -0.02 0.01 -1.37 0 0 0

    BASE 39 WIND-X -0.03 -0.01 2.39 0 0 0

    BASE 52 WIND-X 8.95 -0.01 3.24 0 0 0

    Summation Base WIND-X 8.9 -0.01 4.25 1223 -1808 -2519

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 WIND-X -0.02 0.01 -1.83 0 0 0

    BASE 39 WIND-X -0.03 -0.01 4.1 0 0 0

    BASE 52 WIND-X 8.13 0 2.02 0 0 0

    Summation Base WIND-X 8.08 0 4.29 1234 -1804 -2514

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 EQ-Y 0.02 -0.06 1.43 0 0 0

    BASE 39 EQ-Y 0 -0.09 -13.61 0 0 0

    BASE 52 EQ-Y -1.68 0.9 -56.39 0 0 0

    Summation Base EQ-Y -1.66 0.75 -68.57 -19743 31358 830

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 EQ-Y 0.12 -0.07 1.72 0 0 0

    BASE 39 EQ-Y 0 -0.1 -15.58 0 0 0

    BASE 52 EQ-Y -1.78 0.87 -52.32 0 0 0

    Summation Base EQ-Y -1.66 0.70 -66.18 -19737 31332 834

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 EQ-X -0.07 0.02 -4.18 0 0 0

    BASE 39 EQ-X -0.08 -0.02 8.17 0 0 0

    BASE 52 EQ-X 30.21 -0.03 11.75 0 0 0

    Summation Base EQ-X 30.06 -0.03 15.74 4884 -7143 -8637

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 EQ-X -0.07 0.02 -3.89 0 0 0

    BASE 39 EQ-X -0.08 -0.04 9.67 0 0 0

    BASE 52 EQ-X 30.21 0 9.89 0 0 0

    Summation Base EQ-X 30.06 -0.02 15.67 4864 -7148 -8632

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    PLATE ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 EQ-X -0.07 0.02 -4.18 0 0 0

    BASE 39 EQ-X -0.08 -0.02 8.17 0 0 0

    BASE 52 EQ-X 30.21 -0.03 11.97 0 0 0

    Summation Base EQ-X 30.06 -0.03 15.96 4884 -7143 -8667

    COLUMN ELEMENTS

    Story Point Load FX (Kip) FY (Kip) FZ (Kip) MX (Kip-in) MY (Kip-in) MZ (Kip-in)

    BASE 25 EQ-X -0.07 0.02 -4.23 0 0 0

    BASE 39 EQ-X -0.08 -0.04 9.15 0 0 0

    BASE 52 EQ-X 30.47 0 9.11 0 0 0

    Summation Base EQ-X 30.32 -0.02 14.03 3464 -7082 -8732

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    lxix

    Figure - 1

    Figure - 2

    Fig: Comparative values of Base Moment due to Lateral Load (Shear Wall-1)

    0

    5000

    10000

    15000

    20000

    25000

    30000

    35000

    40000

    EQ-X EQ-Y

    Plate

    Column

    5100

    5200

    5300

    5400

    5500

    5600

    5700

    5800

    5900

    6000

    6100

    WIND-X WIND-Y

    Plate

    Column

    Load

    Ki-in

    Axis (X, Y)

    Axis (X, Y)

    Load

    Ki-in

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    lxx

    Figure - 1

    Figure - 2

    Fig: Comparative values of Base Moment due to Lateral Load (Shear Wall-2)

    0

    5000

    10000

    15000

    20000

    25000

    30000

    EQ-X EQ-Y

    Plate

    Column

    0

    200

    400

    600

    800

    1000

    1200

    1400

    1600

    WIND-X WIND-Y

    Plate

    Column

    Load

    Ki-in

    Axis (X, Y)

    Axis (X, Y)

    Load

    Ki-in

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    lxxi

    Figure - 1

    Figure - 2

    Fig: Comparative values of Base Moment due to Lateral Load (Shear Wall-3)

    0

    5000

    10000

    15000

    20000

    EQ-X EQ-Y

    Plate

    Column

    0

    500

    1000

    1500

    2000

    WIND-X WIND-Y

    Plate

    Column

    Axis (X, Y)

    Load

    Ki-in

    Load

    Ki-in

    Axis (X, Y)

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    lxxiii

    Findings of the study are as follows:

    1. Values are closed :analyzing of Plate shear wall and column shear wall

    structures we have found base moment values are very closed.

    2. Frame Methods are more accurate: according to analysis of two

    methods that we have got more accurate results in frame method as a

    alternate for plate element method.

    3. Economical And Memory Efficient: the frame element method is

    more economical and memory efficient.

    4. Frame analysis method is very simple rather than plate element method.

    Recommendation:

    The study is used for building structure, similar study may be done for

    Bridge structure.

    We have done this method by static analysis. Dynamic analysis should

    be used to analysis the structures to have a comparative result .

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    REFERENCES

    [1] Stafford Smith, B., and Coull A., Tall Building Structures: Analysis and

    Design, John Wiley and Sons, 1991.

    [2] Taranath, B. S., Structural Analysis and Design of Tall Buildings, McGraw-

    Hill Company, 1988.

    [3] Wilson, E. L., Dovey, H. H. and Habibullah, A., ETABS, Three

    Dimensional Analysis of Building Systems, Computers and Structures Inc.,

    Berkeley, California, USA.

    [4] MacLeod, I. A., Analytical Modeling of Structural Systems, Ellis Horwood

    Limited, 1990.

    [5] Response of Buildings to Lateral Forces, ACI Committee Report, SP- 97,

    American Concrete Institute,

    [6] Rutenberg, A. and Eisenberger, M., Simple Planar Modeling of

    Asymmetric Shear Buildings for Lateral Forces, Computers and Structures,

    Vol.24, No.6, 1986: 885-891.

    [7] Smith, B. S. and Cruvellier, M., A Planar Model for the Static and

    Dynamic Analysis of Asymmetric Building Structures, Computers and

    Structures, Vol.48, No.5, 1993: 951-956.

    [8] Wilson, E. L. and Dovey, H. H. Three Dimensional Analysis of Building

    Systems - TABS, Report No. EERC 728, College of Engineering,

    University of California, Berkeley, California, December 1972.

    [9] Hoenderkamp, J. C. D., Simplified Analysis of Asymmetric High Rise

    Structures with Cores, The Structural Design of Tall Buildings, Vol.11,

    2002: 93-107.

    [10] Wilson, E. L., Dovey, H. H. and Habibullah, A., TABS90, Three

    Dimensional Analysis of Building Systems, Computers and Structures Inc.,

    Berkeley, California, USA, 1994.