Analisis de la performance de una Bomba Warman

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    Performance analysis and design improvement on a test rig for

    centrifugal slurry pumps at Weir Warman Ltd, Sydney

    Tom Clabbers

    12th December 2006

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    Abstract

    The medium test rig in the test bay of Weir Warman in Artarmon needs refurbishing. Al-though the tests can be conducted fairly quick, the changeovers, from one test to the next,cost too much time. The base frame on which the pump and motor are mounted is basedon a frame that Warman usually supplies with a pump and motor combination. Herein liesthe problem that the current base frame has: it is not specifically designed for a test rig, butrather adapted from a base frame that is installed once, and then kept running for a longtime. The new design that is proposed in this study is in fact designed for this test bay.Pumps and motors are quickly changed in between tests and the piping at both the intakeand discharge side are much easier adapted to a new setup as well.

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    Contents

    1 Introduction 5

    2 Warman slurry pumps 7

    2.1 Weir Warman . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 72.2 Slurry pumps . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7

    3 Pump testing 9

    3.1 Test bay . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 9

    3.2 Tests . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 10

    4 Performance analysis 13

    4.1 Changeovers . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 13

    4.2 Testing . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 14

    4.2.1 Head, power and efficiency versus flow rate . . . . . . . . . . . . . . . 14

    4.2.2 NPSH test with constant flow rate method . . . . . . . . . . . . . . . 144.2.3 Sound level, vibration and bearing temperature rise test . . . . . . . . 15

    4.3 Evaluation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 15

    5 Design of the piping configuration 17

    5.1 Intake side . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 17

    5.2 Discharge side . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 19

    6 Design of the base frame 21

    6.1 Concept . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 216.2 Dimensions and sections . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 23

    6.2.1 Pump plates . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 236.2.2 Columns . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 246.2.3 Floor frame . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 24

    6.2.4 Motor plate . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 24

    6.2.5 Jockey pulley frame . . . . . . . . . . . . . . . . . . . . . . . . . . . . 256.3 Finite element analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 25

    6.3.1 Static analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 26

    6.3.2 Harmonic analysis . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 276.4 Final design . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35

    6.4.1 Floor frame . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 35

    6.4.2 Motor plate . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 36

    6.4.3 E-frame pump pedestal . . . . . . . . . . . . . . . . . . . . . . . . . . 37

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    6.4.4 D-frame pump pedestal . . . . . . . . . . . . . . . . . . . . . . . . . . 386.4.5 Jockey pulley frame . . . . . . . . . . . . . . . . . . . . . . . . . . . . 38

    7 Conclusions 45

    8 Recommendations 47

    A Piping 49

    B Reaction forces 51

    B.1 Pump reaction forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52B.1.1 Gravitational forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . 52B.1.2 Belt tension forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 53B.1.3 Flange loads . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 54

    B.1.4 Flange moments . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 56B.1.5 Total reaction forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . 59

    C Parameter values 61

    C.1 Motor reaction forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 63C.1.1 Gravitational forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . 64C.1.2 Belt tension forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 64C.1.3 Motor torque . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 64C.1.4 Total reaction forces . . . . . . . . . . . . . . . . . . . . . . . . . . . . 65

    D Dimensions and sections in detail 67

    D.1 Pump plates . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 67D.2 Columns . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 69

    D.2.1 Bending . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 70D.2.2 Buckling . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 70

    D.3 Floor frame . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 70D.4 Motor plate . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 71D.5 Jockey pulley frame . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 72

    E Matlab programme instructions 79

    F References 81

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    Chapter 1

    Introduction

    Weir Warman Ltd. is located in Sydney, Australia and designs, manufactures and testscentrifugal slurry pumps. The testing is done on several test rigs. This report describes theperformance analysis and design improvement of one of those test setups: the medium testrig. This test rig is somewhat dated and requires design improvements in order to save timeand money preparing and conducting the tests. The scope of this study is to improve themedium test rig, without changing the actual testing procedures.

    An analysis on the test rig shows what the points of concern are in the current setupand a new design is proposed. In this design the piping configuration is changed. The mainfocus, however, is on the base frame: the frame on which pump and motor are mounted onfor testing. The new design is thoroughly checked for strength properties and a static andharmonic analysis are done using an FEA model. The design is presented by a CAD model

    and the resulting drafts and drawings.

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    Chapter 2

    Warman slurry pumps

    2.1 Weir Warman

    Weir Warman Ltd. is part of the Weir Minerals group, which has been created by bringingtogether the previous global operations of Envirotech and Warman International. Weir Min-erals is the world leader in the design and manufacture of slurry pumps, cyclones, slurry valvesand mill lining systems. Weir Minerals has operations across North America, South America,Africa, Europe, Australia and Asia and employs over two and a half thousand people world-wide. Weir Warman Ltd. forms the Australian and Asian arm of Weir Minerals with sistercompanies located all around the world, including Venlo, The Netherlands. Weir Minerals isa division of The Weir Group PLC, a UK-listed engineering company founded in 1871 andlisted on the London Stock exchange since 1947. Weir Mineral brands include Warman, Ash

    Pump, Galigher, Hazleton, Cavex, GEHO Pumps, Schabaver, Indupaq, Envirotech, Weiresistand IsoGate.

    Headquarters for Weir Warman Ltd. are located in Artarmon, a suburb of Sydney, Aus-tralia, employing around five hundred people. Weir Warman Sydney incorporates a fullyintegrated design, testing, manufacturing and distribution facility for horizontal and vertical-submersible centrifugal slurry pumps, ranging from 1 1

    2inch up to 1 meter intake flange diam-

    eter. Warman pumps are used in various applications. Many industries use Warman slurrypumps to transport, among other things, sand, gravel, coal, phosphate, ash/dust, sugar, andvarious kinds of ore. Warman pumps are used when dealing with abrasive materials like inwet scrubber installations for flue gas desulphurization. Water treatment and public utilityplants make use of a range of Warman slurry pumps. Particular Warman pumps even suit

    the specific demands of various offshore applications. [1]

    2.2 Slurry pumps

    A slurry can be a mixture of virtually any liquid combined with some solid particles. Theflow properties and other characteristics are determined by a great number of variables. Thecombination of the type, size, shape and quantity of the particles together with the nature ofthe transporting liquid make up the slurry behavior. Slurries can be roughly divided in twogroups: non-settling and settling slurries. Non-settling slurries contain only very fine particleswhich can form stable homogeneous mixtures exhibiting increased apparent viscosity and

    density. These slurries usually have low wearing properties but are non-Newtonian. Settling

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    slurries contain coarser particles and tend to form an unstable heterogeneous mixture. Settlingslurries have high wearing properties and form the majority of slurry applications.

    All Warman slurry pumps are centrifugal pumps. The principle of a centrifugal slurrypump is the same as a clear liquid pump. However, because slurries have such differentproperties the pump has to be designed to meet the special requirements. This often resultsin the use of tougher materials. Slurry pumps also have to be able to process large particles.The biggest Warman pump can handle particles up to 53 mm in spherical size. Because ofthis, they need heavier and wider impellers. Generally slurry pumps operate at lower speedsto reduce wear. This means that they have to be larger in size than comparable clear liquidpumps. Because the pumps are only tested using water, the specific design of slurry pumpswill not be elaborated on. [2]

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    Chapter 3

    Pump testing

    Any variation in design or manufacturing, no matter how subtle, will influence the perfor-mance of the pump. Pump testing is necessary to ensure the pump delivers the performanceas specified in the design. However, not all pumps that are tested have new design features.Costumers can opt for an acceptance test to be carried out on their pump before it is de-livered. Whatever the purpose may be, the tests are basically the same. These tests aredescribed in section 4.2.

    3.1 Test bay

    The test facilities at Weir Warman in Sydney are capable of testing the entire range of Warman

    pumps. The facilities consist of four test rigs: the small and medium rig, the dyna rig andthe large test rig. The frame size of the pump to be tested roughly determines which rig isto be used for the test. Every pump is fitted with a standardized frame. Pumps with an A,B or C frame are tested on the small rig. The medium rig handles the D and E frames andF frame pumps use the dyna rig. Anything bigger than an F frame is tested on the large rig.The small and medium rig can be fitted with electric motors ranging from 3.75 to 220 kW,driving the pumps via one or more v-belts. The dyna rig is f itted with a 201 kW motor andthe large rig with a 900 kW motor. The motors on both the dyna rig and the large rig aredirectly coupled via a gearbox to the pump shafts. The four test rigs are all located in thesame test bay. The large rig has its own water basin and pressure tank. The small, mediumand dyna rig share another water tank. We will now focus on the medium test rig, as this is

    the subject of this study.Figure 3.1 shows the side view of the current medium test rig. At the far left is the watertank. When the pump is running, the water leaves the water tank and flows through theintake valve (2), that can automatically (partially) open and close using an electric motor.Behind the intake valve is a flow straightener (4) that is equipped with an air vent (5) used,together with air vent (12), to vent the air from the system when filling. At the bottomof the flow straightener, the lowest point of the system, is a drain valve (3). Pipe (9) is atelescopic pipe. This pipe can slide in- and outward and is necessary to adjust the total pipelength at the intake side for each different pump. The maximum reach of the telescope is550 mm. The pipe segment indicated by (10) can be one or more pipes that connect thetelescopic pipe with the intake flange of the pump. This set of pipes has to have one or more

    reducers, because the telescopic pipe has an internal diameter (ID) that is bigger (312 mm)

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    Figure 3.1: The current medium test rig

    than the intake diameter of the largest pump for the test rig (200 mm). A tapping point (16)is present at two times the ID from the intake f lange of the pump. After the water passes

    the pump, it flows past another tapping point, twice the ID from the discharge flange of thepump. Piping segment (14) should again contain one or more reducers to increase the pipeID to 200 mm. Flange (17) has slots in stead of bolt holes, so the segment from (17) to thepump can be somewhat rotated. Together with two telescopic pipes (11) and (13), it enablespiping segment (14) to be f itted on any pump that is to be tested. Before the water f lowsback into the tank, it flows through pipe (8), which is equipped with an orifice plate and twotapping points (6) and (7) at either side of that plate. At the far left end is the dischargevalve (1), which has the same automatic features as the intake valve.

    The pump and motor are mounted on a base frame, which is shown in figure 3.2. Thebase frame consists of a floor frame (2), a motor pedestal (A) and a pump pedestal (B). Inorder to adjust the height for the various pumps one or more add-on frames (3) are placed on

    the base plate. An electric motor powers the pump via v-belts. The pre-tensioning of thesebelts is done by adjusting the height of the whole motor. The motor is mounted on the topplate of the motor pedestal. The vertical adjustment of that top plate is done by means offour bolts (1) by which the plate is held up.

    3.2 Tests

    Performance testing at the Artarmon test bay is only carried out using water. This is becauseall the standards with which the pumps have to comply require water testing. Besides, it wouldbe impossible to obtain all the different slurries for the numerous slurry pump applications.

    Standards that are used include:

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    Figure 3.2: The base frame on the current medium test rig

    Australian Standard AS 2417

    International Standards Organization ISO 2548 & 3555

    German Standard DIN 1944

    Hydraulic Institute Standards HIS

    Japanese Standard JIS B8301

    American Petroleum Institute API 610

    Although details differ between standards, they all require the same tests to be carried out.These tests include testing for head and flow rate for different speeds, NPSH testing, soundpressure level, vibration and bearing temperature rise testing.

    The head and f low rate for different speeds define the pump. The pumps characteristic

    curve is obtained from this test. The Net Positive Suction Head or NPSH is tested to establishthe cavitation performance. Cavitation occurs when the fluid pressure is so low in the intakeof a pump that vapor bubbles (or pockets) form and effectively block off the flow into thepump. Cavitation degrades the pump performance and can even destroy pump parts. Thelast three tests straight forward and are performed at the specified duty point of the pump.A detailed description of the tests, including the operating procedures are laid out in section4.2. [3]

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    Chapter 4

    Performance analysis

    Analyzing the performance of the medium test rig involves all quantitative and qualitativeaspects. The test rig should be quick and easy to use, and the test results should be accurateand reliable.

    4.1 Changeovers

    The changeover time is the time it takes to set up the test rig for a test. It also includesclearing the setup as it was used for the preceding test. The operating procedure for achangeover on the current medium test rig is listed below, starting with a clear test rig. Thenumbers between the brackets refer to figure 3.1 and 3.2.

    1. Adjust height of the pump pedestal by clamping one or more add-on blocks (3.2: 3) onbase plate (3.2: 2).

    2. Place and fix pump on pump pedestal (3.2: B).

    3. Place and fix correct motor on motor pedestal (3.2: A).

    4. Determine which pulleys and belts have to be used.

    5. Search for right pulleys and place pulleys on pump and motor shafts.

    6. Place belts on pulleys.

    7. Pre-tension the belts by adjusting motor height.

    8. Search for pipe segments and reducers for intake side (3.1: 10).

    9. Get matching gaskets for flanges on intake side.

    10. Adjust telescopic pipe (3.1: 9).

    11. Attach pipes to telescopic pipe and intake flange.

    12. Search for pipe segments and reducers for discharge side (3.1: 14).

    13. Adjust telescopic pipes (3.1: 11) and (3.1: 13).

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    14. Get matching gaskets for flanges on discharge side.

    15. Turn discharge section using slots in flange (3.1: 17).

    16. Tighten all flange bolts.

    17. Attach manometer tubes to (3.1: 6) and (3.1: 7).

    18. Attach pressure gauge tubes to (3.1: 15) and (3.1: 16).

    19. Place optical tachometer to measure motor speed.

    20. Open intake and discharge valves (3.1: 1) and (3.1: 2).

    21. Open air vents (3.1: 5) and (3.1: 12).

    22. Fill system with water.

    23. Close all air vents once the system is full.

    4.2 Testing

    Before the pump can be tested, one must ensure that the pump and motor are installedcorrectly and the pump is well assembled. First the operator turns on the motor for a briefmoment and lets the pump come to stop. If no irregularities occur, he turns on the motoragain and checks if the pump is running smoothly. The testing can begin, but not before theair is bled from the instrument lines by throttling the manometer and gauge valves.

    4.2.1 Head, power and efficiency versus flow rate

    During this part of the test the intake valve is opened completely and the flow rate is var-ied by partially opening the discharge valve. For a short moment, the discharge valve isclosed entirely. Then, seven other readings are done, the flow rate increasing more or lessevenly spaced including the duty point and the maximum flow. Each time the intake anddischarge pressures, flow rate, pump speed and power are recorded. The pressures are mea-sured with mechanical dial gauges and the flow rate is determined by measuring the pressuredifference over the orifice plate (figure 3.1: 8). The pressure difference is measured with anair-mercury-air manometer connected at both sides of the orifice plate. The power of the

    pump is determined by multiplying the flow rate and pressure difference over the pump. Theefficiency is the power the pump delivers divided by the power of the motor. That motorpower is determined with the measured current the motor draws at a known voltage.

    4.2.2 NPSH test with constant flow rate method

    This test starts by measuring the water temperature and the atmospheric pressure. Whenthe pump is set to the duty speed, the intake valve is fully opened. The discharge valve isthen adjusted to comply with the required flow rate. By entering the data into a spreadsheet,the total discharge head (TDH) and NPSH are calculated and plotted (TDH vs NPSH). Theintake and discharge pressures, pump speed and power are now recorded. Next, the suction

    head is reduced by approximately two meters by closing the intake valve, while maintaining

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    a constant flow rate by opening the discharge valve. If necessary, the drive speed can beadjusted. The operator records the intake and discharge pressures and repeats the last step

    until the the TDH drops below 10% of the stable non-cavitating TDH.

    4.2.3 Sound level, vibration and bearing temperature rise test

    These tests can vary between different standards to which the pump has to comply, butmost standards request the following procedure. When the pump is running at duty speed,the sound pressure level has to be below a maximum allowable value at a certain distancefrom the pump casing. A minimum number of microphone positions may also be required.Background noise readings are taken and the measured values are corrected. The sound levelmeter is calibrated before and after each test using an acoustic calibrator.

    With the pump running at duty speed, vibration measurements are taken at several po-sitions on the pump bearing assembly to cover vibration in three mutually perpendicular

    planes. The measurements are done with a portable vibration meter that is to be held ontothe vibrating part.

    With the pump again running at duty speed, temperature readings are taken on theoutside of the pump bearing housing, at both the drive and pump ends. Readings shouldbe taken over time at thirty minutes intervals, with the pump operating at fixed conditions,until stabilized. The readings are taken with a hand held, digital read-out thermometer, witha thermocouple type probe. Readings of temperatures rise can be high at start up due toexcessive grease churning or bearing run-in. If temperatures rise in excess of 90C, the pumpshould be stopped and allowed to cool before re-starting the test. It may be necessary to stopand start several times before the final bearing temperature rise can be ascertained. [4]

    4.3 Evaluation

    The test rig should make testing as quick and easy as possible. Because changes to the testingprocedures are not within the scope of this study, the changeovers on the test rig are to beimproved.

    The changeover procedure as described in section 4.1 leaves plenty of room for improve-ments. Starting with point 1 and 2. Because there are only two different pump frame sizesfor testing on the medium test rig, there are only two pump pedestal heights necessary, eachwith four bolt holes. That the current medium test rig has several add-on blocks with manyholes and slots in the top plate makes choosing the right set-up needlessly difficult.

    Pretensioning of the of the belts takes up much time currently. The operator places abelt around the two pulleys and then jacks up the whole motor. This is done by adjustingeight nuts on four threads, one at each corner of the motor pedestal. In order to overcome allfriction forces, the operator can only adjust one corner a little bit at a time. Meanwhile hechecks the tension of the belts by pressing against it and checking the deflection. The motorpedestal is also the least stiff part of the base frame. Vibrational problems are therefore mostlikely to occur at that side.

    Finding the right reducers and pipes for the intake and discharge side can take quite sometime. Every pump has its own intake and discharge diameters, bolt hole diameters in theflanges (PCD) and distance from the fixed pipes. Although an experienced operator probablyis rather fast in finding the right combination, time spent on a test should not depend on the

    person conducting the test.

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    Chapter 5

    Design of the piping configuration

    5.1 Intake side

    Figure 5.1: Situation sketch of the intake side

    The piping at the intake side of the pump has to connect the intake flange of the pump tothe flow straightener, (4) in figure 3.1. Because the axial distance varies between pumps, atelescopic pipe is needed to prevent having to use too many different pipes. Another function

    this set of piping has is reducing the diameter of the pipes from the diameter of the flowstraightener to the intake flange. These diameters also vary from pump to pump. Besides thediameter, connecting flanges also have to match the pitch circle diameter, or P.C.D. This isthe diameter of the circle described by the bolt holes in the flange. Having to keep an eye oncosts, as many pipes as possible have to be used that are already in stock. Although there is alist of pipes present at the test bay, modifications made to these pipes are often not recordedand a complete stock taking can be recommended. For this design however, we will assumethe list is accurate.

    For the sake of simplicity, all pumps with the same frame will be bolted down at the sameposition. For that reason only four holes have to be drilled in the top plates and that theshaft ends are virtually in the same spot. In order tot achieve this goal, we have to make sure

    that all these pumps can be connected to the telescopic pipe at the intake side. This telescope

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    can be extended up to 55 cm (maximum distance D in figure 5.1). For some pumps however,this buffer is not entirely free to use. Sometimes when a pump is tested, the impeller has to

    be changed in between tests. This means that a number of pumps has a minimum clearancespecified (distance C in figure 5.1). This clearance is necessary to dismantle the cover plateand change the impellers. In such a case it is most convenient and time efficient to disconnectthe pipe from the intake flange and slide back the telescope, without having to dismantle thewhole setup.

    The fixed parameter is the distance from the flow straightener to the first anchor bolt ofthe current base frame (F in figure 5.1), which is 3.78 meter. There are six bolts anchoredin the concrete floor to fix the current base frame. They will also be used to fix the newframe. The parameter that is of importance for the design of a new base frame is the distancefrom the anchor bolt to a fixed position of the respective D and E frame pumps (parameterE in 5.1). In this case the first bolt hole of the pump frame is chosen for this position.

    Parameters A, B and C as shown in figure 5.1 vary for the different pumps. Parameter E canbe determined using:

    Emin= A + B+ P+ C F

    Emax= A + B+ P+ D F

    with P being the total length of the pipe segments connecting the telescopic pipe to the intakeflange of the pump. Emin and Emax define a range in which the first bolt hole of the pumpframe can be. The pipe segments that make up P for each different pump have to be selectedso that all the ranges overlap. In this overlapping region we can pick a point to position thebolt holes on the pump plates. As a result, not only does the operator have the simple caseof only the one position for any pump, but it is also known which pipes have to be used for

    a specific pump. This saves the time and trouble of solving the puzzle every time. The pipecombinations are listed in tables 5.1 and 5.2. Now that distance E is determined for bothframe sizes the first concept of the base frame can be designed. The values of parameters A,B, C, E and P are listed in appendix A.

    Pump pipe 1 pipe 2 pipe 3 pipe 4

    4/3 D-SH C10 C3 C184/3 D-AHU C10 C3 C184/3 D-AH C10 C6 C8 G64/3 D-AHW C10 C6 C86/4 D-S D16 D18 D14 G6

    6/4 D-SW D16 D18 D146/4 D-SC D22 G66/4 D-SCW D22 G66/4 D-AH D22 G66/4 D-AHW D22 G6150 D-GP E4 E128/6 D-S E4 E128/6 D-SW E4 E12

    Table 5.1: Necessary pipes for D-frame pumps

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    Pump pipe 1 pipe 2 pipe 3

    4/3 E-HH C10 G10

    6/4 E-SH E4 E6 D126/4 E-AH E4 E6 D12150 E-L E4 G108/6 E-SC E4 G108/6 E-SCW E4 G108/6 E-AH E4* G108/6 E-AHW E4* G10

    Table 5.2: Necessary pipes for E-frame pumps. Pipes marked with * have to be slotted at theflange to match PCDs

    5.2 Discharge side

    The position of the discharge flange is different for every pump. The only fixed parameter isthat the discharge flange is always in a horizontal plane. By making use of several rotationflanges in different orientations, all degrees of freedom can be covered. This concept isadopted from the WEIR Netherlands test facilities in Venlo, The Netherlands. Figure 5.2shows the discharge side of the test rig in Venlo, similar to the medium test rig at Warman.The green flanges in the picture are the rotation flanges, which can freely rotate along the axis.Because of the geometry of the pipes, the free pipe end can move in the horizontal plane aswell as up and down. The counterweight at the right balances the pipes. The whole system

    can be easily moved by one operator. The only pipe that has to be changed for differentpumps is the reducer. The reducer is clamped onto the pumps discharge flange rather thanbolted. This has three advantages: it is faster, the PCDs doesnt have to match and is savesone rotation flange on the vertical axis to line up the bolt holes. A full, detailed design of thepiping configuration is not done due to a lack of time.

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    Figure 5.2: Discharge side of a similar test rig in Venlo

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    Chapter 6

    Design of the base frame

    6.1 Concept

    Figure 6.1: Base frame concept

    The current base frame in the test rig is of a similar design to the frames that Warman

    supplies with a pump and motor combination to costumers. The majority of these setups areinstalled once, the motor height adjusted in order to get the right belt tension, and then keptrunning. Occasionally, the motor pedestal can be readjusted to compensate for slacking ofthe belts. The way to tension the belts is robust and durable rather than quick and easy. Inthe test bay however, pump and motor changes are conducted regularly and getting the righttension in the belts takes up much time. For that reason the new design will have a jockeypulley rather than a adjustable motor height. As a result of the new tensioning system, themotor no longer has to be mounted on a high pedestal. By moving the motor shaft fromabove to underneath the pump shaft, the base frame becomes much more compact, which hasa good result on the vibrational properties.

    Figure 6.1 shows the first base frame concept. The whole structure rests on the floor

    frame. It has a U shaped cross section and is attached to the concrete floor with six anchor

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    Figure 6.2: Jockey pulley system: side, top and iso view

    bolts. On the left-hand side is the motor plate. This is the plate that supports the motor.Because the motor plate is placed directly on the floor frame, there is too little space toplace and tighten any nuts underneath. For this reason, a thread will be tapped in all theholes in the motor plate. This will also save time when mounting the motors, for it makesnuts obsolete. To ensure that the motor plate can be easily removed for maintenance andmodification in case of new motors, it will be bolted on the floor frame rather than welded.Underneath the motor plate a stiffener is added. This stiffener is a plate perpendicular to the

    motor plate and parallel to the long side of the floor frame. In order to keep the holes in themotor plate clear, the stiffener is placed on the middle line of the plate. As figure 6.1 shows,there are two pump plates. The lower one is for E frame pumps and is welded onto four squarehollow tubes which will be referred to as the columns. Underneath the columns supports areadded in the floor frame to decrease the bending moment in the floor frame. The upper plateis for the D frame pumps and is welded on four columns of the same sort, though shorter.This plate and columns structure is only used when a D frame pump is tested, and can bebolted on the fixed lower pump plate when necessary. Both pump plates are strengthened bystiffeners: similar to the stiffeners underneath the motor plate, although in this case there aretwo crossed stiffeners per plate. The pulley frame in the back consists of two flange channelswith a beam between them. This beam is attached with two bolts, one through each channel.

    A jockey pulley should be as close to the smallest pulley as possible at the slack side of thebelt. Because any combination of pulleys is possible for use on the test rig, the position of thejockey pulley has to be adjustable in three directions. The beam can be adjusted in heightby choosing another set of holes in the channels. The beam carries a jockey pulley with itsadjusting mechanism. This is not depicted in figure 6.1, but the complete jockey pulley partof the base frame is shown in figure 6.2. The jockey mechanism consist of the main frame,two arms a push rod and an aluminium block on top to connect the rod with the main frame.The main frame is bolted through a slot in the beam between the flange channels. This givesthe jockey pulley the second degree of freedom. Now only the last degree of freedom has tobe taken into account. This is done by means of the previously mentioned pulley mechanism.The side view in figure 6.2 clearly shows four pin joints connecting the arms and the rod both

    to the mainframe and the rod and the pulley both to the arms. Because the aluminium block

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    6.2.2 Columns

    The columns of the pump pedestal are subject to compression, tension and a bending moment.

    They will be checked for buckling and bending, as these will be far more likely to occur thanpure compression or tension failure.

    According to Australian Standards handbook [5], the elastic buckling loadNom of a mem-ber can be calculated as given below. This value should be higher than the maximum forceexerted on the columns.

    Nom= 2EI

    (kel)2 (6.2)

    Where E is the modulus of elasticity andlthe length of the column. keIs the member effectivelength factor that accounts for the way the column is fixed. The loads on the columns arethe reaction forces at the ends of the stiffeners, due to the point loads on the bolt holes, asdetermined in the previous subsection.

    The bending should be calculated as in section 6.2.1. In this case Mx is the maximumlateral force determined in section B multiplied by the length of the column.

    Fll fyZe (6.3)

    The BHP catalogue [7] contains standard square hollow tubes. For each tube size the effectivesection modulusZe is given. This way the right tube can be selected.

    The dimensions of the selected tubes for the columns are 75 75 3 mm.

    6.2.3 Floor frame

    The forces that act on the columns also act on the floor frame. The floor frame is made ofa U-profile channel on its side, resulting in a C-profile. Directly underneath the columns,stiffeners are added. A stiffener and a side of the C-profile form a T-section that is subjectto compression, tension and buckling. Checking for buckling is done as in section 6.2.2, withNom being the reaction forces R as determined in section 6.2.1. The maximum compressiona member with cross section area A and ultimate shear strength fy can withstand is

    Fc = fyA. (6.4)

    The thickness of the floor frame is 5 mm.

    6.2.4 Motor plate

    As explained in section 6.1, threads will be tapped in the motor plate to bolt the motordirectly onto the plate. The motor plate has to be thick enough to have an adequate threadfor even the biggest bolts. Because the plate basically substitutes the nuts, it will be as thickas the biggest nut it replaces (20 mm, see Ajax Fasteners, [8]). The plate has one stiffenerunderneath in longitudinal direction, which is placed in the center. Because of symmetry, halfthe structure is considered for the strength calculations. The considered member consists ofhalf the motor plate, half the stiffener and the adjacent part of the floor frame. This part ofthe structure is checked for bending due to the motor reaction forces found in section C.1.

    After that, it will be checked for compression under the maximum compression force and its

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    own weight. Bending is checked in the same manner as before, using equation (6.1). In thisequation, only the effective section modulus Ze is unknown, which depends on the section of

    the structure. The geometry and the thicknesses of the motor plate and the floor frame areknown. Using those numbers, the minimum thickness of the stiffener is calculated. Compres-sion is checked by again using equation (6.4), in whichFc has to be larger than the maximumcompression force acting on the motor plate.

    The thickness of the motor plate is 20 mm and the thickness of the stiffener is 5 mm.

    6.2.5 Jockey pulley frame

    The jockey pulley frame is made up by four parts that will be checked separately to deter-

    mine the sections and dimensions. The main force acting on the whole frame is the force thatthe belts exert on the jockey pulley. First this force has to be calculated using the earlierdetermined belt tension. The force acting on the jockey pulley is then directed through thearms and the push rod onto the main frame and the flange channels. The arms and the pushrod have one specific orientation in which the buckling or bending load has a maximum value.These worst case scenarios are considered when calculating the sections and dimensions ofthese parts. The main frame is subject to bending. This bending moment also depends onthe orientation of the mechanism. The flange channels finally are the last link in the chainand bear the whole load at a certain height, which make up the bending moment they aresubject to.

    The resulting sections and dimensions can be found in appendix D.5.

    6.3 Finite element analysis

    In order to check the design of the base frame, both a static and harmonic analysis areconducted. The finite element analysis (FEA) software Strand7 was used to create a modelof the base frame. Figure 6.3 shows that model. Because the base frame consists mainlyof plates, the model is built up by plate elements, of the quad8 kind. An exception is the

    beam in the jockey pulley system, for which brick elements were chosen. Each element wasassigned the right structural properties and thicknesses. In figure 6.3, sections with the sameproperties have the same color. The baseplate is fixed to the ground at the positions of the sixanchor bolts, which attach the base frame to the floor. To prevent any numerical problems,an area around the bolt holes was fixed, rather than one node. The masses of the pump,motor and pulleys are represented by point masses at the respective centers of mass. Thepoint masses, forces and moments acting on the pump and motor are all directly connected tothe bolt holes on which the motor or pump is fixed using rigid links. Rigid links only transferthe forces and moments from one point to the other, without having any further physicalrepresentation. The forces are visualized in figure 6.3 as light blue arrows, the moments asgreen double pointed arrows. The rigid links have the same color as the forces and the gold

    colored spheres depict the point masses.

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    Figure 6.3: Strand7 FEA model

    6.3.1 Static analysis

    For the calculations done for designing the base frame, many assumptions and approximationswere used. Wrong choices in these assumptions and miscalculations can not be tolerated. Thisanalysis is primarily done to check whether the calculations are indeed well conducted. Thestatic analysis calculates the stresses in the material and the displacement of every node inwhich the base frame is subdivided.

    Figure 6.4 is the output of the stress calculations on the base frame. Von Mises Stresseswere chosen for the output, because that is a combination of the three main stress components.The figure shows that there are very high stress peaks, up to 1421 MPa. Comparing thatto the ultimate shear strength of steel, around 240 MPa, there is obviously a problem. Inthis case however it is a numerical problem. Because the each rigid links is connected to onlyeight nodes at the edge of a bolt hole, the loads are distributed over a very small area. This

    makes the stresses unrealistically high and these FEA results therefore unreliable. Refining

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    Figure 6.4: Stresses on the base frame as calculated with Strand7

    the mesh around these bolt holes and linking the loads to more nodes would reduce this error.This is however time consuming, both to model and to run the simulation. Moreover, theoutcome would remain unreliable, as the magnitude of the error would still be uncertain.

    Rather than that, we look into the displacement of the nodal points of the model. Figure6.5 shows the displacements of the base frame. First of all we see that the displacements haveno large peaks and are evenly distributed. This indicates that there are no singularities likein the stress calculations. The maximum displacements of the plates occur in the Y-direction(see figure for coordinates), with a maximum absolute displacement of about 1.2 mm. Thebricks in the beam of the jockey pulley system have their maximum displacements in the Z-

    direction and are at most 2.8 mm. Both values are perfectly acceptable and we can thereforeconfirm that the structural design of the base frame is satisfactory so far.

    6.3.2 Harmonic analysis

    It is very important to make sure that the base frame has good vibrational properties. Likethe base frame, every structure has several natural frequencies. To prevent violent vibrationsof the base frame during tests, it is preferred that these frequencies are not in the range offrequencies acting on the frame. The problem is that there are many different vibrationsacting on different parts of the base frame. To get an understanding of how the naturalfrequencies of the base frame behave, a harmonic analysis is done on the Strand7 model of

    the base frame as described above. The simulation resulted in the first four natural frequency

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    Figure 6.5: Displacement of the base frame as calculated with Strand7

    modes:

    1. 10.8 Hz, 649 rpm

    2. 13.1 Hz, 785 rpm

    3. 28.0 Hz, 1682 rpm

    4. 55.1 Hz, 3303 rpm

    Figures 6.6 to 6.9 show how the base frame behaves at the natural frequencies. The first mode(figure 6.6) is a rotating motion of the pump pedestal about an axis in the Y-direction, locatedat the center of the concentric lines of displacement. The rest of the modes are translatingmotions. The second mode (figure 6.7) is a motion in Y-direction, with a maximum deflectionat the right hand side columns. Mode three (6.8) is the pump plate vibrating in X-directionand the fourth mode concerns the entire motor plate. As can be seen in figure 6.9, the motorplate vibrates in Y-direction, having a maximum displacement at the right hand side motorbolt holes. The maximum displacements which occur at the natural frequencies are 1 to 2mm, which is most satisfying. Nonetheless, it is not desirable for any of the drive runningspeeds; motor speed, pump speed, impeller tip speed and belt speed, to interfere with anatural frequency of the base frame and set off a response. The fact that so many pump,

    motor, impeller, pulley and belt combinations are possible for use on the test rig makes it

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    Figure 6.6: First mode of natural frequency. Note: depicted displacements are scaled up for

    visual purposes

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    Figure 6.7: Second mode of natural frequency. Note: depicted displacements are scaled up forvisual purposes

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    Figure 6.8: Third mode of natural frequency. Note: depicted displacements are scaled up forvisual purposes

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    Figure 6.9: Fourth mode of natural frequency. Note: depicted displacements are scaled up forvisual purposes

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    Pump Max. speed test speed 10% of test speed

    6/4 S 1800 rpm 1440 rpm 1296 1584 rpm

    4/3 SH 1900 rpm 1520 rpm 1368 1672 rpm8/6 S 1650 rpm 1320 rpm 1188 1452 rpm6/4 SC, 8 vanes 1800 rpm 1440 rpm 1296 1584 rpm6/4 SC, 3 vanes 1800 rpm 1440 rpm 1296 1584 rpm4/3 AH 2750 rpm 2200 rpm 1980 2420 rpm150 GP 1400 rpm 1120 rpm 1008 1232 rpm6/4 AH 1800 rpm 1440 rpm 1296 1584 rpm6/4 SH 1450 rpm 1160 rpm 1044 1276 rpm150 L, 5 vanes 1300 rpm 1040 rpm 936 1144 rpm150 L, 4 vanes 1500 rpm 1200 rpm 1080 1320 rpm4/3 HH, 5 vanes 1400 rpm 1120 rpm 1008 1232 rpm

    4/3 HH, 4 vanes 1400 rpm 1120 rpm 1008 1232 rpm8/6 AH, 4, 560 vanes 1300 rpm 1040 rpm 936 1144 rpm8/6 AH, 6, 545 vanes 1300 rpm 1040 rpm 936 1144 rpm8/6 AH, 4, 510 vanes 940 rpm 752 rpm 677 827 rpm

    Table 6.1: Maximum, test and critical speeds of various pumps

    seemingly impossible to rule out interference with every excitation. Therefore we use andcrystallize the information that we do have at our disposal. First, most of the motors in thetest bay are four pole motors and run at around 1400 rpm. Preferably, there is no natural

    frequency at at least 10% of an excited frequency. This means that the base frame shouldnot have a natural frequency in the range 1260 1540 rpm. Because the first three modes areall vibrations of the pump pedestal, we would like to know at which speeds the pumps arelikely to run when tested. In every Warman pump performance curve, there is a maximumrunning speed specified. Because most of these pumps (and impellers) are relatively small, soto put enough energy into the flow to maintain a decent flow rate (and achieve an acceptablelevel of efficiency) the test speeds are in the higher range of the pump operating speeds.Roughly, the running speeds can be supposed to be at 80% of the maximum running speeds.Table 6.1 shows all the pumps that have a known maximum running speed and could betested on the medium test rig.

    Comparing the 10% test speed ranges, one can see that there are two odd ones in the

    list, namely the 4/3 AH pump and the last listed 8/6 AH pump. The rest of the pumpshave a supposed test speed from 1040 to 1520 rpm. Therefore it should be wise to designthe base frame in such a way that there are no natural frequencies between 936 and 1672rpm. Although this condition is already satisfied, we will see wether the design can be furtheroptimized, i.e. wether the safe margin can be enlarged. We define a margin relative to thenatural frequencies of the base frame and we now have the following lower and upper margins(l andu):

    l = 1040 785

    785 100% = 32.5% and u=

    1682 1520

    1682 100% = 9.6%.

    To obtain better margins, we first look at the third natural frequency of the base frame and

    notice that its 1682 rpm is very close to the 1672 rpm we would like to evade. Preferably,

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    the third natural frequency mode must be increased, without raising the second mode toomuch, as we want to stay well clear from the 936 rpm lower limit. Examining the second

    and third mode, we see that the second mode is mainly due to bending of the floor frame,while the third mode involves stretching and twisting of the pump pedestal columns. So bystiffening the pump pedestal and leaving the floor frame as it is, a more satisfying resultshould be achieved. First we increase the thickness of the pump pedestal columns from 3 to5 mm. After adapting the FEA model the simulation is ran again. These are the new firstfour natural frequency modes:

    1. 12.1 Hz, 730 rpm

    2. 13.7 Hz, 819 rpm

    3. 32.0 Hz, 1921 rpm

    4. 55.2 Hz, 3310 rpm

    The third mode has indeed gone up more than the second and the new margins are:

    l = 1040 819

    819 100% = 27.0% and u=

    1921 1520

    1921 100% = 20.9%.

    The lower margin is still well acceptable whereas the upper margin has doubled. Even theearlier discarded running speeds of the 4/3 AH and 8/6 AH pumps fit in better now.

    Adding even more stiffness to the pump pedestal by adding diagonal 5 mm stiffener platesat the sides between the columns does raise the third mode of natural frequency, but raises thesecond one dramatically as well. This one now interferes with the pump and motor speeds,

    as the natural frequencies show:

    1. 13.7 Hz, 822 rpm

    2. 20.5 Hz, 1230 rpm

    3. 54.6 Hz, 3276 rpm

    4. 56.6 Hz, 3396 rpm

    Considering all, base frame will be adapted only by increasing the thickness of the pumppedestal columns from 3 to 5 mm.

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    Figure 6.11: Base frame

    gives assembly 75 mm space to fit his spanner at each side. A similar upright plate is locatedunderneath the right end of the motor plate. This plate is not taken into account for the

    strength calculations in appendix D.4, so if it would cause practical problems, it can be leftout. The holes for the anchor bolts are measured on site and although the four outer holesare in a perfect rectangle, the two inner ones have a 5 mm offset, as shown in firgure 6.12.

    6.4.2 Motor plate

    The motor plate is shown in 6.13. As explained, every motor can be bolted directly ontothe threaded holes. The four outer holes are used to bolt the motor plate to the floor framewith M24 bolts and are not threaded. There are many motors available at Warman fortesting on the medium test rig and the motor plate has to be able to fit all these motors.Like pumps, motors have standardized frames with standard dimensions. A stock taking wasdone and every motor makes use of one of eight different frames. For practical reasons thedimensions of the holes necessary for each motor are not shown in the figure but are listedbelow. Parameters A, B, C and D as depicted in figure 6.13 can be found in the Toshibacatalogue [9]. Note that hole diameter D is the hole diameter in the motor frame. The threadin the plate should be that of the nearest standard metric thread. Parameter C is chosen in

    such a way that the entire motor shaft is aligned directly underneath the pump shaft.

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    Figure 6.12: Floor frame: top and front view

    Frame A B C D

    D280M 419 457 191 24D250M 349 406 169 24D250S 311 406 169 24D200L 305 318 191 19D180L 279 279 112 15D160L 254 254 99 15

    D160M 210 254 99 15D132M 178 216 75 12

    6.4.3 E-frame pump pedestal

    The dimensions of the pump pedestal for E-frame pumps are shown in figure 6.14. Columnsare welded on the floor frame at the position shown in figure 6.12. The 30 mm diameter holesare used for bolting on the E-frame pumps and are positioned in such a way that the set ofpipes listed in table 5.2 can connect the intake flange to the fixed pipes of the test rig. Also,the pump is positioned in such a way that the pump shaft is aligned directly above the motor

    shaft. The 20 mm diameter holes are used to bolt on the pedestal for D-frame pumps.

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    Figure 6.13: Motor plate: top view

    6.4.4 D-frame pump pedestal

    The pedestal for D-frame pumps is only used when a D-frame pump is tested. Figure 6.16shows the top and side view of the D-frame pump pedestal with its dimensions. The pedestalis bolted on the fixed pump pedestal with four bolts. The parts that are used for this con-nection are shown in figure 6.16. The reason that there are two different fasteners is simple:the stiffeners leave little room for the operator to fit the bolts.

    6.4.5 Jockey pulley frame

    As mentioned before, it is most recommended that the pulley and belt supplier is consultedabout the use and design of the jockey pulley and its frame. There has been some contact, inwhich the supplier indicated that it should be possible to use such a belt tensioning system,but no more information was present at that time. The actual pulley is not modeled, but it isrepresented by a simple cilinder. Obviously, the design can change depending on the jockey

    pulley and any additional information from the supplier. When altering the frame, one should

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    Figure 6.14: E-frame pump pedestal: top and front view

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    Figure 6.15: D-pedestal fasteners

    always recalculate the structural properties as done in section 6.2.5 and appendix D.5. The

    dimensions of the jockey pulley frame are given in figures 6.17 and 6.18. There should be twodifferent mechanisms. Each one consists of the mechanism shown in 6.18 without the slottedbeam and supports either an SPB or an SPC size pulley. Depending on the belt that is used,the right mechanism is simply bolted on the slotted beam. This beam could be quite heavyand less manageable when made of steel, so making it of aluminium is more practical. Thesame applies to the member through which the push rod can slide and is connected to themain frame.

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    Figure 6.16: D-frame pump pedestal: top and side view

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    Figure 6.17: Complete jockey pulley frame: top, side and front view

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    Figure 6.18: Jockey pulley mechanism: side, front and top view

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    Chapter 7

    Conclusions

    The medium test rig in its current state leaves much room for improvement. The operatorconducting a test faces the same challenges every time a new pump is set up for testing. Thebase frame is not standardized for the standard pump and motor frames. To get the righttension in the v-belts the operator has to lift the whole motor by adjusting eight nuts onfour threads, small steps at a time to overcome friction. To find the piping that is necessaryto connect the fixed piping to the intake flange of the pump requires experience because thepipes in stock are not properly documented. To fit the discharge pipes the operator has touse a scissor lift to adjust several telescopic pipes, which takes time and some safety risks.

    Solutions to all these problems are presented. A new design for a base frame proposedthat makes use of a jockey pulley to pre-tension the v-belts quick and easy, adjusting onlyone thread. It also also makes use of the standardized frames of the motors and pumps.

    Thanks to this standardization, every combination of pipes at the intake side of the pumpis known. These combinations are documented and enable any Warman employee to quicklyfind the right pipes. A whole new drag n drop piping configuration at the discharge side isproposed using rotation flanges. Fitting these flanges in the correct orientation and adding acounterweight makes it very easy to fit the piping to the discharge flange of the pump.

    The base frame is thoroughly checked for its structural and vibrational properties. Theapproximations for finding the reaction forces on a pumps bolt holes presented in appendixB are described in great detail and can be used for similar problems.

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    Chapter 8

    Recommendations

    In this chapter there will be some comments on the study presented in the report. First ofall, although much effort has gone in to this research, it is no guarantee that everything iswithout errors. Moreover, there is no substitute for experience, so please make sure the reportgets read carefully by an experienced Warman engineer.

    For a smoothly operating test bay, it is recommended that all pipes and reducers are labeledand stored orderly. A well arranged stock combined with tables 5.1 and 5.2 make changingthe piping at the intake side of the setup light work. An idea for the piping at the dischargeside is proposed in chapter 5.2. Although it is not completely designed in this report, it isworthwhile to look into. It is recommended that the supplier is contacted about the rotationflanges. If desired, Weir Netherlands in Venlo, where this system is already implemented, can

    also be contacted.

    The spreadsheet that is currently used for calculating the reaction forces on Warman basefram contains some crude calculations and approximations. This is the reason why appendixB proposes a new calculation of these forces. Because some of the problems are staticallyindeterminate, approximations had to be used, resulting in errors as well. These errors, how-ever, are minimized. The calculations are documented very detailed and can easily be fedinto a spreadsheet.

    As mentioned before, the jockey pulley frame and especially the adjusting mechanism isdesigned around the actual jockey pulley. The supplier of belts and pulleys will know more

    concerning the materials that are best to be used. The frame can than be carefully adjustedto the pulley, respecting the strength calculations in section 6.2.5 and appendix D.5.

    In designing the base frame, standard material dimensions were not always reckoned with.The flange channels of the jockey pulley frame and the square hollow sections used for thecolumns are in fact found in supplier catalogues, but the rest of the plate material was not.If it turns out to be more practical or economical to change some dimensions of the baseframe, please make sure the essential dimensions, e.g. the pump height, remain unchanged.Obviously, the altered parts should be checked again for there structural properties.

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    Appendix A

    Piping

    Listed below are the values of parameters A, B, C, E and P as shown in figure 5.1 for eachpump suitable for the medium test rig. All values are in mm.

    Pump A B C Emin Emax E P

    4/3 D-SH 280 165 -725 -175 550 35104/3 D-AHU 279 192 180 -751 -381 370 35104/3 D-AH 280 187 149 -837 -436 401 36004/3 D-AHW 408 187 230 -520 -200 320 31556/4 D-S 248 152 180 -870 -500 370 37006/4 D-SW 375 152 -552 -2 550 32556/4 D-SC 281 186 -657 -107 550 3420

    6/4 D-SCW 409 186 -785 -235 550 34206/4 D-AH 317 220 254 -727 -431 296 34206/4 D-AHW 446 219 -855 -305 550 3420150 D-GP 330 185 -600 -50 550 33158/6 D-S 265 184 -534 16 550 33158/6 D-SW 393 184 -662 -112 550 3315

    Pump A B C Emin Emax E P

    4/3 E-HH 381 248 279 -574 -303 271 31756/4 E-SH 356 216 -687 -137 550 33456/4 E-AH 351 219 250 -685 -385 300 3345

    150 E-L 376 237 275 -473 -198 275 30908/6 E-SC 376 233 -469 81 550 30908/6 E-SCW 531 233 -624 -74 550 30908/6 E-AH 402 292 350 -554 -354 200 30908/6 E-AHW 554 292 -706 -156 550 3090

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    p q

    Fy

    Fz

    Py Qy

    Pz Qz

    l1 l2

    l3

    Figure B.1: 2D force model

    A quick check shows that all forces add up to zero: Py+ Qy+ Fy = 0. Now we consider ahorizontal force, Fz. This time the horizontal reaction forces are not equal to zero. Again,this problem is indeterminate, because both points p and q are fixed in horizontal direction.To avoid elaborate calculations of minimal value, we assume that the horizontal force Fz isequally distributed over points p and q:

    Pz =Qz = 1

    2Fz . (B.5)

    The vertical reaction forces Py and Qy can also be determined by using the moments aboutp and q.

    Mp= 0 : l3Fz+ l1Qy = 0

    Mq = 0 : l3Fz l1Py = 0

    This gives:

    Py = l3

    l1Fz and (B.6)

    Qy = l3l1

    Fz. (B.7)

    B.1 Pump reaction forces

    Figure B.2 shows the 8/6 AH slurry pump. This is the biggest and heaviest pump that can betested on the medium test rig and which has a known mass. The most important dimensionsas well as the assigned numbers to the four bolt holes are depicted. As mentioned before thedimensions that are used will be parametrical for the time being.

    B.1.1 Gravitational forces

    The pump mass is represented by a single point load acting at the center of mass. When apump is designed at Weir Warman, the center of mass is not entirely determined. Only thehorizontal distance from the intake flange is calculated, but it is reasonable to assume that

    the center of mass is on the centerline of the pump. We can now use the model presented in

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    Figure B.2: pump dimensions

    figure B.1 and plug in the right parameters for the problem. In this case, l1= C, l2= D andFy = mpg, wheremp is the mass of the pump andg is the gravitational acceleration. Point prepresents the line through points 1 and 4, and q the line through 2 and 3. Due to symmetryPy and Qy are equally distributed over the points on lines p and q. This results in:

    F1y,1= F4y,1 = LdD

    2Cmpg and (B.8)

    F2y,1= F3y,1 = LdC+ D

    2C mpg. (B.9)

    WithF1y toF4y the reaction forces in vertical direction at points 1 to 4. Ld is a safety factoraccording to Australian standards [12]. The standard specifies safety factors for two types ofloads: dead loads (Ld) and live loads (Ll). Live loads are loads that are applied externallyand/or involve moving parts, the dead load is none of that and thus basically the gravitationalforce. The mass of the pulley also has to be taken into account. This is represented by a pointload at the end of the pump shaft. Similar to the method used above, now l1 = C, l2 = KandFy =mplg, wherempl is the mass of the pulley. Parameter p represents the line throughpoints 2 and 3, and q the line through 1 and 4. Py andQy are again equally distributed overthe points on lines p and q. We find:

    F1y,2= F4y,2 = Ld C+ K2C mplg and (B.10)

    F2y,2= F3y,2 = LdK

    2Cmplg. (B.11)

    B.1.2 Belt tension forces

    Warman protocol states that the belt tension is to be calculated according to the Fenner beltdrive manual. To calculate the static tension, TS, we need to estimate the force, P, requiredto depress a belt 16 mm per meter of span. An indication ofP and the formulae (B.12) to(B.14) can be found in the catalogue. With nb being the number of belts used:

    TS= 32P nb (B.12)

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    To determine the approximate total, dynamic tension,TD, imposed by a drive when running,the centrifugal tension per side, TC, must be subtracted from the static tension.

    TD = 2(16P TC)nb (B.13)

    The centrifugal tension developed in a belt is a function of its weight and the square of itsvelocity.

    TC=M S2, with S=

    dn

    60 (B.14)

    In (B.14), Mis the mass per meter length of the belt, d the diameter of one pulley and n therotational speed of that pulley in revs/min. As well as P, M can be found in Fenner [10].Similar to the gravitational force of the pulley, the belt tension force acts at the end of thepump shaft.

    F1y,3= F4y,3 = LlC+ K

    C

    16PM

    dn60

    2nb and (B.15)

    F2y,3= F3y,3 = LlK

    C

    16P M

    dn60

    2nb. (B.16)

    Again, safety factors are applied.

    B.1.3 Flange loads

    For every Warman pump there is a list of maximum allowable flange loads and moments [11].Because these are the maximum loads the pump can bare before breaking, these loads include

    nearly every external load on the pump. This is the reason why the shaft torque from thebelt drive and the impuls due to the fluid flow are not separately considered. A base framefor a pump has to be designed to withstand the reaction forces of those loads. In those loadsa safety factor is already included. The maximum allowable f lange loads and moments areshown in figure (B.3). The forces and moments are specified as listed below.

    Intake flange:

    Fz = Axial load along the z axis, into or out of the pump through A

    Fxy = Force in the xy plane in any direction through A

    Mz = Torsional moment about the z axis through A

    Mxy = Torsional moment about any axis in the xy plane through A

    Discharge flange:

    Fy = Axial load along the y axis, into or out of the pump through B

    Fxz = Force in the xz plane in any direction through B

    My = Torsional moment about the y axis through B

    Mxz = Torsional moment about any axis in the xz plane through B

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    Fz

    Fxz

    Fxy

    Fyx

    y

    z

    A

    B

    Mz

    Mxy

    My

    Mxz B

    A

    Figure B.3: maximum allowable f lange loads and moments

    Point A is located at the center of the outside face of the intake flange and point B atthe center of the outside face of the discharge f lange. Although axial and radial forces areactually acting at the bolt pitch circle diameter (PCD), they are assumed to act as pointloads at points A and B. The directions in which the forces and moments act are based on aworst case scenario adding as much as possible to the already calculated reaction forces. Thedirections are depicted in figure B.3.

    First, we determine the reaction forces due to the loads acting at the intake flange. Onceagain, the model in figure B.1 and the symmetry is used. This time, l1 = C, l2 = F andl3 = G. Point p represents the line through 1 and 4, q the line through 2 and 3. Filling inthese values in equations (B.3) and (B.4) gives the reaction forces due to Fxy.

    F1y,4= F4y,4 = F

    2CFxy (B.17)

    F2y,4= F3y,4 = C+ F

    2C Fxy. (B.18)

    The reaction forces due toFz are determined by using equations (B.5) to (B.7). Again usingthe symmetry to find the correct formulae.

    F1z,1 = F2z,1= F3z,1= F4z,1 = 1

    4Fz (B.19)

    F1y,5= F4y,5 = G

    2CFz (B.20)

    F2y,5= F3y,5 = G

    2CFz (B.21)

    Determining the reaction forces due to the loads on the discharge flange is not as straight for-

    ward as the previous cases. Because the discharge flange is not on the center plane (involving

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    the centerline and the y axis), we can no longer appeal to symmetry and simply divide theforces found from the side view by 2. To overcome this problem, we use the views from both

    the side and the front and average the reaction forces found in these views for each point.This will give a good estimate for the actual answer to the indeterminate problem. Beginningwith the side view, we find that l1 = C, l2 = E and l3 = H. Point p represents the linethrough 1 and 4, q the line through 2 and 3. For the front view, l1= A, l2= B and l3= H.Point p represents the line through 3 and 4, q the line through 1 and 2. With superscriptsfor the side view reactions and f for the front view we find the reactions due to Fy:

    Fs1y = Fs4y =

    E

    2CFy

    Fs2y = Fs3y =

    C+ E

    2C Fy

    Ff

    1y = Ff

    2y =

    A + B

    2A Fy

    Ff3y = Ff4y =

    B

    2AFy.

    Averaging the forces found for both views gives the approximation of the reaction forces dueto Fy.

    F1y,6 = 1

    2

    A + B2A

    E

    2C

    Fy (B.22)

    F2y,6 = 1

    2

    A + B2A

    +C+ E

    2C

    Fy (B.23)

    F3y,6 =

    1

    2 B

    2A C+ E

    2C

    Fy (B.24)

    F4y,6 = 1

    2

    B2A

    + E

    2C

    Fy (B.25)

    The reaction forces due to the horizontal force on the discharge flange,Fxz , are approximatedin the same manner as the reactions due to Fy. Using equations B.5 to B.7 we find:

    F1z,2= F2z,2= F3z,2= F4z,2 = 1

    4Fxz (B.26)

    F1y,7 = 1

    2

    H2A

    H

    2C

    Fxz (B.27)

    F2y,7 = 1

    2H

    2A+ H

    2C

    Fxz (B.28)

    F3y,7 = 1

    2

    H2A

    H

    2C

    Fxz (B.29)

    F4y,7 = 1

    2

    H2A

    + H

    2C

    Fxz . (B.30)

    B.1.4 Flange moments

    In order to calculate the reaction forces as a result of the maximum allowable flange momentsin the xz plane, the model in figure B.1 is slightly modified, as presented in figure B.4.Starting with the left model, where there is a moment Macting at two offsets, the balance of

    forces in the horizontal direction shows thatPz = Qz. This means that there is no resulting

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    p q

    Py Qy

    Pz Qz

    M

    r

    l1 l2

    l3

    p q

    Py Qy

    Pz Qz

    M

    r

    l1

    l3

    Figure B.4: 2D moments model

    force acting on the holding bolts or the base frame. We now consider the sum of forces in thevertical direction and the sum of moments about point r to find reaction forces Py and Qy.

    Mr = 0 : (l1+ l2)Py+ l2Qy M= 0

    Fy = 0 : Py+ Qy = 0

    This results in the reaction forces:

    Py = M

    l1and (B.31)

    Qy = M

    l1. (B.32)

    We find that the reaction forces are independent ofl2and l3, so calculating the reaction forcesfor the situation on the right hand side of figure B.4 should give the same results.

    Mr = 0 : 1

    2IPy

    1

    2IQy M= 0

    Fy = 0 : Py+ Qy = 0

    As expected, the resulting reaction forces are the same as found in equations (B.31) and(B.32):

    Py = M

    l1and (B.33)

    Qy = M

    l1. (B.34)

    The reaction forces as a result of Mxz, Mz and Mxy are now easily found, considering thereactions Py andQy are equally distributed over the two point on lines p and q, because themoments act on an axis rather than at a point.

    F1y,8= F2y,8 = Mxz2A

    (B.35)

    F3y,8= F4y,8 =

    Mxz

    2A (B.36)

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    F1y,9= F2y,9 = Mz2A

    (B.37)

    F3y,9= F4y,9 =

    Mz2A (B.38)

    F1y,10= F4y,10 = Mxy2A

    (B.39)

    F2y,10= F3y,10 = Mxy

    2A (B.40)

    The last moment we have to find the reaction forces for is My, a torque acting on the discharge

    1 2

    34

    My

    A

    B

    C E

    Fz

    Fx FM

    Figure B.5: model forMy approximation

    flange. Once again, this is an indeterminate problem. It is clear that the moment doesntinflict any vertical forces. However, there are reaction forces in the horizontal plane, thathave to be approximated. For this approximation, we replace the moment at the dischargeflange with a force, FM, acting at the center of the rectangle made up by points 1, 2, 3 and

    4, producing momentMy. A sketch is shown in figure B.5. FMis made up by its componentsin x and z direction: Fx and Fz:

    Fx = MyB+ 1

    2A

    (B+ 12

    A)2 + (E+ 12

    C)2

    Fz = MyE+ 1

    2C

    (B+ 12

    A)2 + (E+ 12

    C)2

    These forces have reaction forces at points 1, 2, 3 and 4. BecauseFx and Fz act at the center,the reaction forces are evenly distributed over the four points:

    F1x= F2x = F3x= F4x = My

    4

    B+ 12

    A

    (B+ 1

    2A)2

    + (E+ 1

    2C)2

    (B.41)

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    F1z,3 = F2z,3= F3z,3= F4z,3 = My

    4

    E+ 12

    C

    (B+ 12

    A)2 + (E+ 12

    C)2 (B.42)

    B.1.5 Total reaction forces

    The total reaction forces on the pump frame are the sum of all the forces acting at one pointin one direction. In the x direction there are only the reaction forces due to moment My.

    F1x= My

    4

    B+ 12

    A

    (B+ 12

    A)2 + (E+ 12

    C)2 (B.43)

    F2x= My

    4

    B+ 12

    A

    (B+ 12

    A)2 + (E+ 12

    C)2 (B.44)

    F3x=

    My

    4

    B+ 12

    A

    (B+ 12A)2 + (E+ 12C)

    2 (B.45)

    F4x= My

    4

    B+ 12

    A

    (B+ 12

    A)2 + (E+ 12

    C)2 (B.46)

    The total reaction force in the y direction for each point is the sum of the 10 separatecalculated reaction forces.

    F1y =10i=1

    F1y,i = LdD2C

    mpg LdC+K2C

    mplg LlC+KC

    16P M

    dn60

    2nb+

    F2C

    Fxy+ . . .

    G2C

    Fz 1

    2

    A+B2A E

    2C

    Fy

    1

    2

    H2A H

    2C

    Fxz

    Mxz2A Mz

    2A

    Mxy2A

    (B.47)

    F2y =10i=1

    F2y,i = LdC+D2C

    mpg+ LdK2C

    mplg + LlKC

    16PM

    dn60

    2nb

    C+F2C

    Fxy . . .

    G2C

    Fz 1

    2

    A+B2A

    + C+E2C

    Fy

    1

    2

    H2A

    + H2C

    Fxz

    Mxz2A Mz

    2A + Mxy

    2A

    (B.48)

    F3y =10i=1

    F3y,i = LdC+D2C

    mpg+ LdK2C

    mplg+ LlKC

    16PM

    dn60

    2nb

    C+F2C

    Fxy . . .

    G2C

    Fz+ 1

    2

    B2A C+E

    2C

    Fy+

    1

    2

    H2A H

    2C

    Fxz+

    Mxz2A

    + Mz2A

    + Mxy2A

    (B.49)

    F4y =10i=1

    F4y,i = LdD2C

    mpg LdC+K2C

    mplg LlC+KC

    16P M

    dn60

    2nb+

    F2C

    Fxy+ . . .

    G2C

    Fz+ 1

    2

    B2A

    + E2C

    Fy+

    1

    2

    H2A

    + H2C

    Fxz+

    Mxz2A

    + Mz2A

    Mxy2A

    (B.50)The total reaction forces in the z direction are:

    F1z =3

    i=1

    F1z,i = 1

    4Fz

    1

    4Fxz

    My4

    E+ 12

    C

    (B+ 12

    A)2 + (E+ 12

    C)2; (B.51)

    F2z =3

    i=1

    F2z,i = 1

    4

    Fz 1

    4

    Fxz My

    4

    E+ 12

    C

    (B+ 1

    2A)2

    + (E+ 1

    2C)2

    ; (B.52)

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    F3z =3

    i=1

    F3z,i = 1

    4Fz

    1

    4Fxz

    My4

    E+ 12

    C

    (B+ 12

    A)2 + (E+ 12

    C)2; (B.53)

    F4z =3

    i=1

    F4z,i = 1

    4Fz

    1

    4Fxz

    My4

    E+ 12C

    (B+ 12

    A)2 + (E+ 12

    C)2. (B.54)

    The parameter values are listed in appendix C. Filling these values in the equations above,we find the values of the pump reaction forces.

    F x y z

    1 -0.145 kN -45.5 kN -9.79 kN2 -0.145 kN 63.3 kN -9.79 kN3 -0.145 kN 81.1 kN -9.79 kN4 -0.145 kN -38.6 kN -9.79 kN

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    Appendix C

    Parameter values

    D-frame pumpsParameter Symbol Value Unit Source

    pump dimension A 0.432 m 6/4D-AH drawingspump dimension B 0.013 m 6/4D-AH drawingspump dimension C 0.213 m 6/4D-AH drawingspump dimension D 0.249 m 6/4D-AH drawingspulley diameter d 0.400 m Fenner belt drives design manual [10]pump dimension E 0.317 m 6/4D-AH drawingspump dimension F 0.537 m 6/4D-AH drawingsflange load Fxy 9550 N Warman data sheet [11]flange load F

    xz 2050 N Warman data sheet [11]

    flange load Fy 4100 N Warman data sheet [11]flange load Fz 19100 N Warman data sheet [11]pump dimension G 0.330 m 6/4D-AH drawingsgravitational acceleration g 9.81 m/s2 -pump dimension H 0.668 m 6/4D-AH drawingspump dimension K 0.271 m 6/4D-AH drawingssafety factor Ld 1.25 - Australian Standard 1170-1 1989 [12]safety factor Ll 1.5 - Australian Standard 1170-1 1989 [12]belt mass M 0.315 kg/m Fenner belt drives design manual [10]motor mass mm 800 kg Toshiba motor catalogue [9]

    pump mass mp 615 kg Warman data sheet [11]pulley mass mpl 44.0 kg Fenner belt drives design manual [10]flange load Mxy 2800 Nm Warman data sheet [11]flange load Mxz 485 Nm Warman data sheet [11]flange load My 243 Nm Warman data sheet [11]flange load Mz 1400 Nm Warman data sheet [11]motor running speed n 1480 rpm Toshiba motor catalogue [9]number of belts nb 5 - Fenner belt drives design manual [10]pre-tension force P 150 N Fenner belt drives design manual [10]motor power Pm 220 kW Toshiba motor catalogue [9]motor dimension U 0.419 m Toshiba motor catalogue [10]

    motor dimension V 0.360 m Toshiba motor catalogue [10]motor dimension W 0.457 m Toshiba motor catalogue [10]

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    E-frame pumps

    Parameter Symbol Value Unit Sourcepump dimension A 0.546 m 8/6E-AH drawingspump dimension B 0.045 m 8/6E-AH drawingspump dimension C 0.257 m 8/6E-AH drawingspump dimension D 0.290 m 8/6E-AH drawingspulley diameter d 0.400 m Fenner belt drives design manual [10]pump dimension E 0.402 m 8/6E-AH drawingspump dimension F 0.694 m 8/6E-AH drawingsflange load Fxy 16900 N Warman data sheet [11]flange load Fxz 4400 N Warman data sheet [11]flange load Fy 8800 N Warman data sheet [11]

    flange load Fz 33800 N Warman data sheet [11]pump dimension G 0.457 m 8/6E-AH drawingsgravitational acceleration g 9.81 m/s2 -pump dimension H 0.917 m 8/6E-AH drawingspump dimension K 0.351 m 8/6E-AH drawingssafety factor Ld 1.25 - Australian Standard 1170-1 1989 [12]safety factor Ll 1.5 - Australian Standard 1170-1 1989 [12]belt mass M 0.315 kg/m Fenner belt drives design manual [10]motor mass mm 800 kg Toshiba motor catalogue [9]pump mass mp 1464 kg Warman data sheet [11]pulley mass mpl 44.0 kg Fenner belt drives design manual [10]

    flange load Mxy 6000 Nm Warman data sheet [11]flange load Mxz 1400 Nm Warman data sheet [11]flange load My 700 Nm Warman data sheet [11]flange load Mz 3000 Nm Warman data sheet [11]motor running speed n 1480 rpm Toshiba motor catalogue [9]number of belts nb 5 - Fenner belt drives design manual [10]pre-tension force P 150 N Fenner belt drives design manual [10]motor power Pm 220 kW Toshiba motor catalogue [9]motor dimension U 0.419 m Toshiba motor catalogue [9]motor dimension V 0.360 m Toshiba motor catalogue [9]motor dimension W 0.457 m Toshiba motor catalogue [9]

    C.1 Motor reaction forces

    Remembering equation (B.2), the reaction forces on the motor frame consist of the reactionsdue to the gravitational forces, the belt tension forces and reactions due to the motor torque.Figure C.1 shows an electric motor and it dimensions. The bolt holes have the same numberingas the bolt holes in the pump frame. The side view in figure C.1 shows points 1 and 4 at theleft and 2 and 3 at the right side. In the front view its 3 and 4 at the left side and 1 and 2

    at the right.

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    Figure C.1: motor dimensions

    C.1.1 Gravitational forces

    Similar to the calculations in section B.1, both the gravitational forces of the motor and thepulley inflict reaction forces at the holding bolts. The center of mass of the motor is unknown,but it is reasonable to assume that it is on the shaft centerline of the motor in the middle ofthe bolt holes in the motor frame. This means that the reaction forces due to the weight ofthe motor are equal on every point.

    F1y,1= F4y,1= F2y,1= F3y,1= Ld1

    4mmg, (C.1)

    with mm the mass of the motor. Modifying equations (B.10) and (B.11) for the motordimensions gives the reaction forces on the motor frame as a result of the weight of thepulley.

    F1y,2 = F4y,2 = LdV

    2Umplg (C.2)

    F2y,2 = F3y,2 = LdU+ V

    2U mplg (C.3)

    C.1.2 Belt tension forces

    The tension in the belts is also calculated in section B.1. Using the motor dimensions andequations (B.15) and (B.16) while keeping in mind that the tension forces now act in theopposite direction we find:

    F1y,3= F4y,3 = LlU+ V

    U

    16P M

    dn60

    2nb and (C.4)

    F2y,3= F3y,3 = LlV

    U

    16P M

    dn60

    2nb. (C.5)

    C.1.3 Motor torque

    The motor torque Tmacts on the motor as a moment on the shaft line. The 2D moment model,

    figure B.4, is used again. Parameter Irepresents the width of the motor base, dimension W

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    in figure C.1. Converting formulas (B.33) and (B.34), we find for the reaction forces:

    F1y,4 = F2y,4 = LlTm2W (C.6)

    F3y,4 = F4y,4 = LlTm2W

    (C.7)

    A live load factor is applied. The motor torque is not directly measured, but calculated usingthe powerPm and running speedn of the motor.

    Tm =Pm

    , with =

    2

    60n (C.8)

    The motor torque reaction forces are now available:

    F1y,4= F2y,4 = Ll15PmnW (C.9)

    F3y,4= F4y,4 = Ll15PmnW

    . (C.10)

    C.1.4 Total reaction forces

    The total reaction forces on the holding bolts are the sum of the reactions calculated in thissection.

    F1y =4

    i=1

    F1y,i = Ld1

    4

    mmg +LdV

    2U

    mplgLlU+ V

    U

    16PM

    dn

    60

    2nb+Ll

    15Pm

    nW

    (C.11)

    F2y =4

    i=1

    F2y,i = Ld1

    4mmgLd

    U+ V

    2U mplg + Ll

    V

    U

    16PM

    dn60

    2nb + Ll

    15PmnW

    (C.12)

    F3y =4

    i=1

    F3y,i = Ld1

    4mmgLd

    U+ V

    2U mplg + Ll

    V

    U

    16PM

    dn60

    2nbLl

    15PmnW

    (C.13)

    F4y =4

    i=1

    F4y,i = Ld1

    4mmg +Ld

    V

    2UmplgLl

    U+ V

    U

    16PM

    dn60

    2nbLl

    15PmnW

    (C.14)

    Again using the values parameter values from C we find the motor reaction forces.

    Fy

    1 29.4 kN2 -14.1 kN3 -18.8 kN4 24.7 kN

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    Appendix D

    Dimensions and sections in detail

    D.1 Pump plates

    d1

    d2

    d

    1 2

    34

    Figure D.1: Pump plate model with parameters

    Although the two pump plates differ slightly, they can be checked in the same manner. FigureD.1 shows a pump plate. It consists of the plate, two stiffeners underneath and four bolt holeson which the assumed point forces act. Due to the load, the structure will bend. The stiffenerswill contribute the most to the stiffness of the structure and because they are placed in such away that they are very close to the holes, the assumption is made that the forces act directly

    on those members. For the sake of simplicity, the stiffeners will be checked separately. Toaccount for the plate stiffness somehow, the members will be considered as T sections. d1, dAnd d2, as depicted in figure D.1 and D.2 are respectively the distance from the end of themember to the first hole, the distance between both holes and the distance from the secondhole to the other end of the member. In order to calculate the maximum bending moment ofa member the reaction forces at both ends of the beam (R1 andR2 in figure D.2) have to bedetermined. This is done using basic structural mechanics: the sum of all moments shouldbe equal to zero. For the sake of convenience we take the moments aboutR1 and R2, withl= d1+ d + d2.

    MR2 = 0 : R1l+ F1(d + d2) + F2d2= 0 (D.1)

    MR1 = 0 : F1d1+ F2(d + d1) + R2l= 0 (D.2)

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    F1

    F2

    R1

    R2d1

    d2

    d

    wptp

    hs

    ts

    yc

    Figure D.2: T-beam model

    Knowing the reaction forces at the ends of the beam, the maximum moment acting on thebeam can be determined. This maximum moment is the largest absolute value of the momentsacting at the bolt holesM1 and M2.

    R1 =

    F1(d + d2) F2d2

    l and R2=