Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic...

32
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Transcript of Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic...

Page 1: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

©r v2n0v1w3E CKouetOaZ BSio7fVtdwLaxrneC QLiL7CN.k y HAwlWlP 8rsiHgVhvtrsr ir5eWsDeyrSv9emdK.n I bMmaXdDeA cwUixtLhv HIfnEfpi5nki0tcer OAVlsgheZbxr4aW Z2E.5 Worksheet by Kuta Software LLC

Algebra 2ID: 1

Name___________________________________

Period____Date________________©v l2X0v1u30 JKYuptzaf QS1oyfktfw9agrjeE QLKLjCL.U u xAyl2l6 0rKivguhvtNsd 8reensyemr9v1endr.d

Review - 2nd Nine Weeks Exam

Graph each equation.

1)

y =

x + 4 + 4

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

2)

y =

x − 3

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

Simplify.

3)

−7 − 2i

3 − 8i4)

8i

7 + 7i

5)

3i

−10 + i6)

9i

1 + 7i

7)

(

−3 + 6i)(

−5 − 8i) 8)

(

1 − 3i)(

8 + 3i)

9)

(

8 + 6i)(

5 + 6i) 10)

(

−5 − 2i)2

11)

(

2 − i) −

(

4 − 3i) 12)

(

−8 + 4i) +

(

−8 + 4i)

13)

(−3i) −

(

−4 − 5i) + (i) 14)

(

−7 + 2i) −

(

−3 − 4i)

15)

12

416)

15

3 80

17)

20

2 418)

2

9

-1-

Page 2: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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19)

3 5

3 + 320)

4

3 +

3 2

21)

5

−3 + 222)

3

−1 −

3 3

Simplify. Your answer should contain only positive exponents.

23)

3

x−4

y−3

y ⋅

2

y−1

24)

2

x−2

y2 ⋅

3

x3

y2 ⋅

3

x3

y3

25)

m2 ⋅

3

m4

n4

26)

2

x

y−3

3

x3

27)

(

4

u−3)−2

28)

(

2

u4

v−2)−3

29)

(

3

x−3)2

30)

(

2

x4

y2)−3

31)

2

x2

y2

x2

y2

32)

a

b2

4

b3

33)

3

y4

4

y34)

2

a−1

b−1

4

a3

35)

2

m3 ⋅

m−3

n−1

n2 ⋅

n

m−3 36)

(

y4

x−1

y−3

2

x

y2 )

2

37)

(

2

x−1)2

y2

2

x38)

m−1

n0

2

m

n4 ⋅

(

m

n4)2

Factor each completely.

39)

512

x3 − 192

x2 − 320

x + 120 40)

54

p3 − 126

p2 − 9

p + 21

41)

42

a3 + 35

a2 + 30

a + 25 42)

5

k3 + 20

k2 −

k − 4

-2-

Page 3: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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43)

2

x2 + 17

xy + 35

y2 44)

3

n2m2 −

n3m

45)

5

x2 − 58

xy + 80

y2 46)

35

x2 − 160

xy − 300

y2

47)

3

x2y − 19

xy2 − 14

y3 48)

2

a2 − 5

ab

49)

12

x2 + 12

xy + 3

y2 50)

9

x2 − 4

y2

51)

9

x2 +

y2 52)

16

x2 + 9

y2

53)

9

u2 − 25

v2 54)

25

x2 − 30

xy + 9

y2

55)

4

u2 + 20

uv + 25

v2 56)

27

a2 − 12

b2

57)

x3 + 216 58)

24

x3 − 81

59)

1 − 8

u3 60)

216 −

x3

61)

108 + 4

a3 62)

−128

u3 + 250

Perform the indicated operation.

63)

f (

x) =

2

x + 4

g(

x) =

3

x + 4

Find (

f

g)(

x)

64)

h(

x) =

x2 + 5

g(

x) =

2

x + 1

Find (

h +

g)(

x)

65)

h(

x) =

2

x − 5

g(

x) =

x2 + 3

Find (

h ⋅

g)(

x)

66)

f (

x) =

−4

x + 3

g(

x) =

4

x − 4

Find (

f

g )(

x)

67)

g(

x) =

2

x + 1

f (

x) =

x2 + 5

x

Find (

g

f )(

x)

68)

g(

a) =

3

a − 1

h(

a) =

a3 − 4

a

Find (

g −

h)(

a)

-3-

Page 4: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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69)

g(

x) =

2

x + 4

f (

x) =

4

x + 4

Find (

g ⋅

f )(

x)

70)

h(

x) =

x2 + 1

g(

x) =

x + 3

Find (

h

g)(

x)

Identify the vertex, axis of symmetry, and min/max value of each. Then sketch the graph.

71)

y =

(

x + 2)2 + 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

72)

y =

(

x + 3)2 − 5

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

73)

y =

1

3

(

x + 2)2 − 1

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

74)

y =

(

x + 5)2 + 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

-4-

Page 5: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Solve each system by graphing.

75)

y =

5

2

x − 2

y =

−1

2

x + 4

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

76)

y = 3

y =

−2

x − 3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

Sketch the solution to each system of inequalities.

77)

x −

y ≥ −1

4

x −

y ≤ 2

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

78)

x + 2

y > −4

x −

y < −1

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

-5-

Page 6: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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79)

4

x −

y < 3

4

x −

y > −3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

80)

x + 3

y < −9

x + 3

y > −3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

Find the discriminant of each quadratic equation then state the number and type of solutions.

81)

−10

n2 − 9

n − 1 = 5 82)

5

x2 − 10

x + 14 = 9

83)

10

a2 − 4

a + 17 = 10 84)

5

k2 + 13 = 10

Solve each equation by completing the square.

85)

x2 − 18

x − 48 = 2 86)

x2 − 10

x − 4 = 7

Solve each equation by factoring.

87)

n2 =

−2

n + 3 88)

k2 + 6

k = −8

Solve each equation with the quadratic formula.

89)

5

p2 + 6

p = 144 90)

4

x2 − 18 = −11

x

Write each expression in radical form.

91)

(4

n)

5

392)

r

1

2

93)

(3

m)

5

494)

(3

x)

5

3

-6-

Page 7: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Write each expression in exponential form.

95)

( 3

n)596)

( 2

v )5

97)

( 5

b)298)

(

x )3

Simplify.

99)

(64

p12)

1

6100)

(27

x6)

5

3

101)

(216

a6)

2

3102)

(64

k6)

1

2

Solve each system by elimination.

103)

9

x − 6

y = 27

3

x − 4

y = 27

104)

3

x + 5

y = −17

x − 10

y = −29

105)

7

x + 3

y = −8

−9

x + 2

y = −19

106)

4

x + 7

y = 11

−9

x + 10

y = 1

Solve each system by substitution.

107)

−2

x + 4

y = −10

x − 2

y = 5

108)

y = 1

8

x + 6

y = 14

109)

x + 2

y = −2

3

x + 6

y = −6

110)

7

x + 5

y = 20

x − 3

y = −12

111) The senior classes at High School A and High School B planned separate trips to the indoor climbing gym.

The senior class at High School A rented and filled 12 vans and 8 buses with 316 students. High School Brented and filled 6 vans and 3 buses with 129 students. Every van had the same number of students in it as

did the buses. How many students can a van carry? How many students can a bus carry?

112) The school that Julio goes to is selling tickets to a choral performance. On the first day of ticket sales theschool sold 2 adult tickets and 13 student tickets for a total of $180. The school took in $120 on the

second day by selling 8 adult tickets and 2 student tickets. What is the price each of one adult ticket and

one student ticket?

-7-

Page 8: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Simplify.

113)

− 5 −

2 3 −

3 114)

−2 6 −

54 −

45

115)

3 27 −

3 3 −

2 8 116)

2 20 +

3 6 +

3 5

Sketch the graph of each function.

117)

y =

4

x − 4

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

118)

y =

1

2

x

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

Simplify.

119)

(

2 − 1)(

−2 2 + 5) 120)

(

3 + 1)(

3 − 1)

121)

4 5(

−2 2 + 5) 122)

5(

5 + 4)

123) 50

xy3 124) 50

x2y4

125) 320

m3n4 126) 320

ab3

Solve each equation. Remember to check for extraneous solutions.

127)

2

n =

3

n − 3 128)

10 −

2

x =

2

x + 2

129) −3 =

−5 + 4

n 130)

13 −

2

x =

x − 2

-8-

Page 9: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Algebra 2ID: 1

Name___________________________________

Period____Date________________©x d2e0w1930 zKcuitnar qSJo9fPtawFairQeT vLKLWCX.d Q GA0lklX QrwiZgJhktKsi mrnefsJeSrDv1e4du.o

Review - 2nd Nine Weeks Exam

Graph each equation.

1)

y =

x + 4 + 4

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

2)

y =

x − 3

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

Simplify.

3)

−7 − 2i

3 − 8i

−5 − 62i

734)

8i

7 + 7i

4i + 4

7

5)

3i

−10 + i

−30i + 3

1016)

9i

1 + 7i

9i + 63

50

7)

(

−3 + 6i)(

−5 − 8i)

63 − 6i

8)

(

1 − 3i)(

8 + 3i)

17 − 21i

9)

(

8 + 6i)(

5 + 6i)

4 + 78i

10)

(

−5 − 2i)2

21 + 20i

11)

(

2 − i) −

(

4 − 3i)

−2 + 2i

12)

(

−8 + 4i) +

(

−8 + 4i)

−16 + 8i

13)

(−3i) −

(

−4 − 5i) + (i)

4 + 3i

14)

(

−7 + 2i) −

(

−3 − 4i)

−4 + 6i

15)

12

4

3

16)

15

3 80

3

12

17)

20

2 4

5

218)

2

9

2

3

-1-

Page 10: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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19)

3 5

3 + 3

15 −

3 5

220)

4

3 +

3 2

−4 3 +

12 2

15

21)

5

−3 + 2

−3 5 −

10

722)

3

−1 −

3 3

3 −

9 3

26

Simplify. Your answer should contain only positive exponents.

23)

3

x−4

y−3

y ⋅

2

y−1

6

x4y324)

2

x−2

y2 ⋅

3

x3

y2 ⋅

3

x3

y3

18

y7x4

25)

m2 ⋅

3

m4

n4

3

m6n4

26)

2

x

y−3

3

x3

6

x4

y3

27)

(

4

u−3)−2

u6

1628)

(

2

u4

v−2)−3

v6

8

u12

29)

(

3

x−3)2

9

x6

30)

(

2

x4

y2)−3

1

8

x12

y6

31)

2

x2

y2

x2

y2

2

32)

a

b2

4

b3

a

4

b

33)

3

y4

4

y

3

y3

434)

2

a−1

b−1

4

a3

1

2

a4b

35)

2

m3 ⋅

m−3

n−1

n2 ⋅

n

m−3

2

m3

n4 36)

(

y4

x−1

y−3

2

x

y2 )

2

y10

4

37)

(

2

x−1)2

y2

2

x

2

y2

x338)

m−1

n0

2

m

n4 ⋅

(

m

n4)2

1

2

m4n12

Factor each completely.

39)

512

x3 − 192

x2 − 320

x + 120

8(

8

x2 − 5)(

8

x − 3)

40)

54

p3 − 126

p2 − 9

p + 21

3(

6

p2 − 1)(

3

p − 7)

41)

42

a3 + 35

a2 + 30

a + 25

(

7

a2 + 5)(

6

a + 5)

42)

5

k3 + 20

k2 −

k − 4

(

5

k2 − 1)(

k + 4)

-2-

Page 11: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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43)

2

x2 + 17

xy + 35

y2

(

2

x + 7

y)(

x + 5

y)

44)

3

n2m2 −

n3m

n2m(

3

m −

n)

45)

5

x2 − 58

xy + 80

y2

(

5

x − 8

y)(

x − 10

y)

46)

35

x2 − 160

xy − 300

y2

5(

7

x + 10

y)(

x − 6

y)

47)

3

x2y − 19

xy2 − 14

y3

y(

3

x + 2

y)(

x − 7

y)

48)

2

a2 − 5

ab

a(

2

a − 5

b)

49)

12

x2 + 12

xy + 3

y2

3

(

2

x +

y)2

50)

9

x2 − 4

y2

(

3

x + 2

y)(

3

x − 2

y)

51)

9

x2 +

y2

Not factorable

52)

16

x2 + 9

y2

Not factorable

53)

9

u2 − 25

v2

(

3

u + 5

v)(

3

u − 5

v)

54)

25

x2 − 30

xy + 9

y2

(

5

x − 3

y)2

55)

4

u2 + 20

uv + 25

v2

(

2

u + 5

v)2

56)

27

a2 − 12

b2

3(

3

a + 2

b)(

3

a − 2

b)

57)

x3 + 216

(

x + 6)(

x2 + 6

x + 36)

58)

24

x3 − 81

3(

2

x − 3)(

4

x2 + 6

x + 9)

59)

1 − 8

u3

(

1 − 2

u)(

1 + 2

u + 4

u2)

60)

216 −

x3

(

6 −

x)(

36 + 6

x +

x2)

61)

108 + 4

a3

4(

3 +

a)(

9 − 3

a +

a2)

62)

−128

u3 + 250

2(

−4

u + 5)(

16

u2 + 20

u + 25)

Perform the indicated operation.

63)

f (

x) =

2

x + 4

g(

x) =

3

x + 4

Find (

f

g)(

x)

6

x + 12

64)

h(

x) =

x2 + 5

g(

x) =

2

x + 1

Find (

h +

g)(

x)

x2 + 2

x + 6

65)

h(

x) =

2

x − 5

g(

x) =

x2 + 3

Find (

h ⋅

g)(

x)

2

x3 − 5

x2 + 6

x − 15

66)

f (

x) =

−4

x + 3

g(

x) =

4

x − 4

Find (

f

g )(

x)

−4

x + 3

4

x − 4

67)

g(

x) =

2

x + 1

f (

x) =

x2 + 5

x

Find (

g

f )(

x)

2

x + 1

x2 + 5

x68)

g(

a) =

3

a − 1

h(

a) =

a3 − 4

a

Find (

g −

h)(

a)

a3 + 7

a − 1

-3-

Page 12: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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69)

g(

x) =

2

x + 4

f (

x) =

4

x + 4

Find (

g ⋅

f )(

x)

8

x2 + 24

x + 16

70)

h(

x) =

x2 + 1

g(

x) =

x + 3

Find (

h

g)(

x)

x2 + 6

x + 10

Identify the vertex, axis of symmetry, and min/max value of each. Then sketch the graph.

71)

y =

(

x + 2)2 + 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (−2, 3)Axis of Sym.:

x = −2

Max value = 3

72)

y =

(

x + 3)2 − 5

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (−3, −5)Axis of Sym.:

x = −3

Min value = −5

73)

y =

1

3

(

x + 2)2 − 1

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (−2, −1)Axis of Sym.:

x = −2

Min value = −1

74)

y =

(

x + 5)2 + 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (−5, 3)Axis of Sym.:

x = −5

Max value = 3

-4-

Page 13: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Solve each system by graphing.

75)

y =

5

2

x − 2

y =

−1

2

x + 4

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

(2, 3)

76)

y = 3

y =

−2

x − 3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

(−3, 3)

Sketch the solution to each system of inequalities.

77)

x −

y ≥ −1

4

x −

y ≤ 2

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

78)

x + 2

y > −4

x −

y < −1

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

-5-

Page 14: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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79)

4

x −

y < 3

4

x −

y > −3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

80)

x + 3

y < −9

x + 3

y > −3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

Find the discriminant of each quadratic equation then state the number and type of solutions.

81)

−10

n2 − 9

n − 1 = 5

−159; two imaginary solutions

82)

5

x2 − 10

x + 14 = 9

0; one real solution

83)

10

a2 − 4

a + 17 = 10

−264; two imaginary solutions

84)

5

k2 + 13 = 10

−60; two imaginary solutions

Solve each equation by completing the square.

85)

x2 − 18

x − 48 = 2

{

9 + 131 ,

9 −

131}

86)

x2 − 10

x − 4 = 7

{11, −1}

Solve each equation by factoring.

87)

n2 =

−2

n + 3

{1, −3}

88)

k2 + 6

k = −8

{−4, −2}

Solve each equation with the quadratic formula.

89)

5

p2 + 6

p = 144

{

24

5, −6} 90)

4

x2 − 18 = −11

x

{

−11 + 409

8,

−11 −

409

8 }

Write each expression in radical form.

91)

(4

n)

5

3

( 34

n)5

92)

r

1

2

r

93)

(3

m)

5

4

( 43

m )5

94)

(3

x)

5

3

( 33

x )5

-6-

Page 15: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Write each expression in exponential form.

95)

( 3

n)5

n

5

396)

( 2

v )5

(2

v)

5

2

97)

( 5

b)2

b

2

598)

(

x )3

x

3

2

Simplify.

99)

(64

p12)

1

6

2

p2

100)

(27

x6)

5

3

243

x10

101)

(216

a6)

2

3

36

a4

102)

(64

k6)

1

2

8

k3

Solve each system by elimination.

103)

9

x − 6

y = 27

3

x − 4

y = 27

(−3, −9)

104)

3

x + 5

y = −17

x − 10

y = −29

(−9, 2)

105)

7

x + 3

y = −8

−9

x + 2

y = −19

(1, −5)

106)

4

x + 7

y = 11

−9

x + 10

y = 1

(1, 1)

Solve each system by substitution.

107)

−2

x + 4

y = −10

x − 2

y = 5

Infinite number of solutions

108)

y = 1

8

x + 6

y = 14

(1, 1)

109)

x + 2

y = −2

3

x + 6

y = −6

Infinite number of solutions

110)

7

x + 5

y = 20

x − 3

y = −12

(0, 4)

111) The senior classes at High School A and High School B planned separate trips to the indoor climbing gym.

The senior class at High School A rented and filled 12 vans and 8 buses with 316 students. High School Brented and filled 6 vans and 3 buses with 129 students. Every van had the same number of students in it as

did the buses. How many students can a van carry? How many students can a bus carry?

Van: 7, Bus: 29

112) The school that Julio goes to is selling tickets to a choral performance. On the first day of ticket sales theschool sold 2 adult tickets and 13 student tickets for a total of $180. The school took in $120 on the

second day by selling 8 adult tickets and 2 student tickets. What is the price each of one adult ticket and

one student ticket?

adult ticket: $12, student ticket: $12

-7-

Page 16: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

©k Q250S1N3b OKZultQaR gSRoLfttrwfaHraeS iLBLdCE.T j 2A4l8lj Tr2igg1hYtls1 VrceysjeIrFvHeJdf.x Z ZMdaad6e3 lwEiNtoh7 IIsnEfxi8nZirtfe5 dAulVgvecbUr1a1 t2j.c Worksheet by Kuta Software LLC

Simplify.

113)

− 5 −

2 3 −

3

− 5 −

3 3

114)

−2 6 −

54 −

45

−5 6 −

3 5

115)

3 27 −

3 3 −

2 8

6 3 −

4 2

116)

2 20 +

3 6 +

3 5

7 5 +

3 6

Sketch the graph of each function.

117)

y =

4

x − 4

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

118)

y =

1

2

x

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

Simplify.

119)

(

2 − 1)(

−2 2 + 5)

−9 +

7 2

120)

(

3 + 1)(

3 − 1)

2

121)

4 5(

−2 2 + 5)

−8 10 + 20

122)

5(

5 + 4)

5 +

4 5

123) 50

xy3

5

y 2

xy

124) 50

x2y4

5

y2x 2

125) 320

m3n4

8

n2m 5

m

126) 320

ab3

8

b 5

ab

Solve each equation. Remember to check for extraneous solutions.

127)

2

n =

3

n − 3

{3}

128)

10 −

2

x =

2

x + 2

{2}

129) −3 =

−5 + 4

n

{1}

130)

13 −

2

x =

x − 2

{5}

-8-

Page 17: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Algebra 2ID: 2

Name___________________________________

Period____Date________________©U X2x0e1d3E qKouJtHal ISGoafFt7wQaYryey ULELhCc.0 9 VAllBlM Gr1i5gOhMtusc KrxeRsOe4rKvBe2dy.u

Review - 2nd Nine Weeks Exam

Graph each equation.

1)

y =

x + 2

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

2)

y =

x + 3 + 4

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

Simplify.

3)

−6 − 10i

−6 + 8i4)

−3 − 10i

−10 − 7i

5)

8 − 9i

9 + i6)

10 − 9i

5 − 6i

7)

(

−7 + 8i)(

5 − 6i) 8)

(3i)(−5i)(

5 − i)

9)

(

−1 + 7i)2 10)

(

−1 − 7i)(

−8 + 8i)

11)

(

1 + 4i) +

(

−4 + 8i) 12)

(

2 + 7i) +

(

2 − 6i)

13)

(6i) + 7 +

(

−8 + 7i) 14)

(−7i) −

(

−7 − 7i) + (6i)

15)

3 2

816)

5 8

4

-1-

Page 18: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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17)

5 6

3 2718)

5 6

8

19)

4

5 −

220)

2

2 3 + 2

21)

5

−2 +

3 522)

5

5 −

2 2

Simplify. Your answer should contain only positive exponents.

23)

3

y2 ⋅

y3

24)

4

a−1

b4 ⋅

a2

b−1

25)

4

n4 ⋅ 2

n 26)

2

y−4

2

x

y−3

27)

(3

n)2

28)

(

2

x−2

y3)−4

29)

(

3

x

y4)2

30)

(

4

x4

y3)2

31)

u4

2

v

u4

32)

2

x−4

y−4

x4

y4

33)

u−3

v−2

u2

34)

4

y

x4

4

x3

35)

a−2

a2

b−1

(

a

b−2)−3 36)

(

b

a−3)−4

(

a0

b−1)4

a

37)

(

x−2

y−3

2

x2)−4

2

x−3

y3

38)

(

2

x−3

y−2)2

y3

(

x−3)−2

-2-

Page 19: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Factor each completely.

39)

128

x3 + 112

x2 + 112

x + 98 40)

35

v3 + 14

v2 − 25

v − 10

41)

168

b3 − 144

b2 − 63

b + 54 42)

6

n3 + 24

n2 +

n + 4

43)

2

x2 − 15

xy − 27

y2 44)

10

x2 + 86

xy − 140

y2

45)

12

u2 − 42

uv + 36

v2 46)

7

m4 + 37

m3n − 30

n2m2

47)

7

u2 + 41

uv + 30

v2 48)

7

u2 − 10

uv

49)

27

x2 + 18

xy + 3

y2 50)

16

x2 − 9

y2

51)

5

x2 − 5

y2 52)

25

m2 + 10

mn +

n2

53)

a2 − 2

ab +

b2 54)

50

u2 − 18

v2

55)

25

x2 + 30

xy + 9

y2 56)

16

x2 − 24

xy + 9

y2

57)

u3 + 27 58)

−500

x3 − 32

59)

81

x3 + 3 60)

192 + 81

x3

61)

125

x3 − 64 62)

1 − 8

x3

Perform the indicated operation.

63)

g(

x) =

2

x + 3

f (

x) = 2

x

Find (

g

f )(

x)

64)

g(

t) =

−3

t2 + 2

t

h(

t) =

2

t + 2

Find (

g

h )(

t)

-3-

Page 20: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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65)

g(

x) =

−2

x2 −

x

h(

x) =

x − 2

Find (

g

h)(

x)

66)

h(

x) =

2

x + 3

g(

x) =

2

x + 4

Find (

h −

g)(

x)

67)

h(

a) =

4

a + 1

g(

a) =

a2 + 2

Find (

h +

g)(

a)

68)

h(

x) =

x + 1

g(

x) =

−2

x3 + 4

x2 +

x

Find (

h

g)(

x)

69)

f (

n) =

n3 −

n

g(

n) =

4

n + 3

Find (

f +

g)(

n)

70)

h(

x) =

x3 + 5

g(

x) =

4

x − 2

Find (

h −

g)(

x)

Identify the vertex, axis of symmetry, and min/max value of each. Then sketch the graph.

71)

y =

(

x + 5)2 − 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

72)

y =

−1

2

(

x − 4)2

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

73)

y =

−1

2

(

x + 6)2 − 1

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

74)

y =

1

4

(

x − 4)2 + 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

-4-

Page 21: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

©a j2u011s3W qKGugtXak pSAoxfutNwVaXrgef 9LoLaCZ.y 6 VAUlWlH IrsiUgThTtRsq 6r3ejs9etrsvheCdF.W U dMyaHdder mw2iRtmhW YILnbfAi6nvihtaez sAslSgQepbOrAak x2i.q Worksheet by Kuta Software LLC

Solve each system by graphing.

75)

y =

−4

x + 4

y =

x − 2

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

76)

y =

3

4

x − 4

y =

−5

4

x + 4

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

Sketch the solution to each system of inequalities.

77)

2

x +

y ≥ −1

x + 2

y ≥ 4

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

78)

y ≤ −1

4

x +

y > 3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

-5-

Page 22: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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79)

2

x + 3

y ≤ 3

2

x − 3

y > 9

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

80)

5

x + 2

y ≥ −6

x − 2

y ≤ −6

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

Find the discriminant of each quadratic equation then state the number and type of solutions.

81)

−2

x2 + 8

x − 5 = 3 82)

r2 + 2

r − 8 = −8

83)

b2 + 6

b − 5 = 2 84)

n2 − 6

n − 14 = −5

Solve each equation by completing the square.

85)

v2 − 10

v − 102 = −8 86)

a2 − 2

a − 68 = −8

Solve each equation by factoring.

87)

x2 =

−10

x − 21 88)

x2 =

−42 − 13

x

Solve each equation with the quadratic formula.

89)

5

k2 + 11

k = −9 90) 5

a2 =

23 + 3

a

Write each expression in radical form.

91)

p

6

592)

(10

n)

5

6

93)

(2

x)

1

594)

(2

m)

1

4

-6-

Page 23: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Write each expression in exponential form.

95)

( 3

x )5 96) 4

10

r

97)

( 4

b)398)

( 510

n)6

Simplify.

99)

(100

a2)

3

2100)

(

x12)

5

3

101)

(

n3)

5

3102)

(1000

v9)

4

3

Solve each system by elimination.

103)

−5

x − 6

y = 11

−10

x + 2

y = 8

104)

7

x + 6

y = 9

14

x + 12

y = 12

105)

−8

x + 6

y = 7

−28

x + 21

y = 7

106)

4

x − 4

y = 6

−6

x + 6

y = −18

Solve each system by substitution.

107)

−3

x +

y = −9

3

x − 2

y = 15

108)

3

x +

y = −21

4

x − 4

y = 4

109)

y = 1

−5

x + 2

y = 22

110)

3

x − 4

y = 17

−2

x +

y = 2

111) When you reverse the digits in a certain two-digit number you decrease its value by 63. What is the numberif the sum of its digits is 9?

112) Mei and Eugene each improved their yards by planting grass sod and ornamental grass. They bought their

supplies from the same store. Mei spent $168 on 10 ft² of grass sod and 12 bunches of ornamental grass.

Eugene spent $80 on 5 ft² of grass sod and 5 bunches of ornamental grass. Find the cost of one ft² of grass

sod and the cost of one bunch of ornamental grass.

-7-

Page 24: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Simplify.

113)

− 18 −

2 6 −

8 114)

2 5 −

3 +

2 12

115)

2 6 +

2 5 −

3 24 116)

−2 2 −

24 −

2 6

Sketch the graph of each function.

117)

y =

3

x − 5

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

118)

y =

−2 +

2

x

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

Simplify.

119)

(

5 −

2 3)(

−3 + 3) 120)

(

2 + 3)(

4 + 3)

121)

5(

10 +

2 3) 122)

15(

5 +

2 5)

123) 4

64

x4y

4 124) 6

256

x6y

7

125) 3

108

x5y3 126) 32

u4v2

Solve each equation. Remember to check for extraneous solutions.

127)

−15 −

2

n =

−7 −

n 128)

5

n + 3 = 8

129)

2

n =

3

n − 1 130) −7 =

n + 6 − 7

-8-

Page 25: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Algebra 2ID: 2

Name___________________________________

Period____Date________________©j m2u0w1Y37 oKPuxtfaf zSjoAfotNwhaZrMeC hLQLZCk.s Y WA3lQlA qrXiWgThZtys2 KrYeksheLr6vFeAd0.0

Review - 2nd Nine Weeks Exam

Graph each equation.

1)

y =

x + 2

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

2)

y =

x + 3 + 4

x

y

−6 −5 −4 −3 −2 −1 1 2 3 4 5 6

−6

−5

−4

−3

−2

−1

1

2

3

4

5

6

Simplify.

3)

−6 − 10i

−6 + 8i

−11 + 27i

254)

−3 − 10i

−10 − 7i

100 + 79i

149

5)

8 − 9i

9 + i

63 − 89i

826)

10 − 9i

5 − 6i

104 + 15i

61

7)

(

−7 + 8i)(

5 − 6i)

13 + 82i

8)

(3i)(−5i)(

5 − i)

75 − 15i

9)

(

−1 + 7i)2

−48 − 14i

10)

(

−1 − 7i)(

−8 + 8i)

64 + 48i

11)

(

1 + 4i) +

(

−4 + 8i)

−3 + 12i

12)

(

2 + 7i) +

(

2 − 6i)

4 + i

13)

(6i) + 7 +

(

−8 + 7i)

−1 + 13i

14)

(−7i) −

(

−7 − 7i) + (6i)

7 + 6i

15)

3 2

8

3

216)

5 8

4

5 2

-1-

Page 26: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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17)

5 6

3 27

5 2

918)

5 6

8

5 3

2

19)

4

5 −

2

4 5 +

4 2

320)

2

2 3 + 2

3 − 1

2

21)

5

−2 +

3 5

2 5 + 15

4122)

5

5 −

2 2

25 +

10 2

17

Simplify. Your answer should contain only positive exponents.

23)

3

y2 ⋅

y3

3

y5

24)

4

a−1

b4 ⋅

a2

b−1

4

b3a

25)

4

n4 ⋅ 2

n

8

n5

26)

2

y−4

2

x

y−3

4

x

y7

27)

(3

n)2

9

n2

28)

(

2

x−2

y3)−4

x8

16

y12

29)

(

3

x

y4)2

9

x2y8

30)

(

4

x4

y3)2

16

x8y6

31)

u4

2

v

u4

1

2

v32)

2

x−4

y−4

x4

y4

2

x8y8

33)

u−3

v−2

u2

1

u5v234)

4

y

x4

4

x3

yx

35)

a−2

a2

b−1

(

a

b−2)−3

a3

b7 36)

(

b

a−3)−4

(

a0

b−1)4

a

a11

b8

37)

(

x−2

y−3

2

x2)−4

2

x−3

y3

y9x3

3238)

(

2

x−3

y−2)2

y3

(

x−3)−2

4

x12y

-2-

Page 27: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

©n D2T081x3U yKYuRtlaE DSCoRfCtUwVaFrHeI WLnLFCH.c J gAFlLl6 3rqiZgvhBtYsR Jrje3sWewrxvaeQdO.J t aMXaqddeL owkiXtwhT FIWnrf4irnRiotqeS 8AclIgRebbrrba5 q2R.1 Worksheet by Kuta Software LLC

Factor each completely.

39)

128

x3 + 112

x2 + 112

x + 98

2(

8

x2 + 7)(

8

x + 7)

40)

35

v3 + 14

v2 − 25

v − 10

(

7

v2 − 5)(

5

v + 2)

41)

168

b3 − 144

b2 − 63

b + 54

3(

8

b2 − 3)(

7

b − 6)

42)

6

n3 + 24

n2 +

n + 4

(

6

n2 + 1)(

n + 4)

43)

2

x2 − 15

xy − 27

y2

(

2

x + 3

y)(

x − 9

y)

44)

10

x2 + 86

xy − 140

y2

2(

5

x − 7

y)(

x + 10

y)

45)

12

u2 − 42

uv + 36

v2

6(

2

u − 3

v)(

u − 2

v)

46)

7

m4 + 37

m3n − 30

n2m2

m2(

7

m − 5

n)(

m + 6

n)

47)

7

u2 + 41

uv + 30

v2

(

7

u + 6

v)(

u + 5

v)

48)

7

u2 − 10

uv

u(

7

u − 10

v)

49)

27

x2 + 18

xy + 3

y2

3

(

3

x +

y)2

50)

16

x2 − 9

y2

(

4

x + 3

y)(

4

x − 3

y)

51)

5

x2 − 5

y2

5(

x +

y)(

x −

y)

52)

25

m2 + 10

mn +

n2

(

5

m +

n)2

53)

a2 − 2

ab +

b2

(

a −

b)2

54)

50

u2 − 18

v2

2(

5

u + 3

v)(

5

u − 3

v)

55)

25

x2 + 30

xy + 9

y2

(

5

x + 3

y)2

56)

16

x2 − 24

xy + 9

y2

(

4

x − 3

y)2

57)

u3 + 27

(

u + 3)(

u2 − 3

u + 9)

58)

−500

x3 − 32

4(

−5

x − 2)(

25

x2 − 10

x + 4)

59)

81

x3 + 3

3(

3

x + 1)(

9

x2 − 3

x + 1)

60)

192 + 81

x3

3(

4 + 3

x)(

16 − 12

x + 9

x2)

61)

125

x3 − 64

(

5

x − 4)(

25

x2 + 20

x + 16)

62)

1 − 8

x3

(

1 − 2

x)(

1 + 2

x + 4

x2)

Perform the indicated operation.

63)

g(

x) =

2

x + 3

f (

x) = 2

x

Find (

g

f )(

x)

2

x + 3

2

x64)

g(

t) =

−3

t2 + 2

t

h(

t) =

2

t + 2

Find (

g

h )(

t)

−3

t2 + 2

t

2

t + 2

-3-

Page 28: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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65)

g(

x) =

−2

x2 −

x

h(

x) =

x − 2

Find (

g

h)(

x)

−2

x2 + 7

x − 6

66)

h(

x) =

2

x + 3

g(

x) =

2

x + 4

Find (

h −

g)(

x)

−1

67)

h(

a) =

4

a + 1

g(

a) =

a2 + 2

Find (

h +

g)(

a)

a2 + 4

a + 3

68)

h(

x) =

x + 1

g(

x) =

−2

x3 + 4

x2 +

x

Find (

h

g)(

x)

−2

x3 + 4

x2 +

x + 1

69)

f (

n) =

n3 −

n

g(

n) =

4

n + 3

Find (

f +

g)(

n)

n3 + 3

n + 3

70)

h(

x) =

x3 + 5

g(

x) =

4

x − 2

Find (

h −

g)(

x)

x3 − 4

x + 7

Identify the vertex, axis of symmetry, and min/max value of each. Then sketch the graph.

71)

y =

(

x + 5)2 − 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (−5, −3)Axis of Sym.:

x = −5

Max value = −3

72)

y =

−1

2

(

x − 4)2

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (4, 0)Axis of Sym.:

x = 4

Max value = 0

73)

y =

−1

2

(

x + 6)2 − 1

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (−6, −1)Axis of Sym.:

x = −6

Max value = −1

74)

y =

1

4

(

x − 4)2 + 3

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8 Vertex: (4, 3)Axis of Sym.:

x = 4

Min value = 3

-4-

Page 29: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Solve each system by graphing.

75)

y =

−4

x + 4

y =

x − 2

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

(2, −4)

76)

y =

3

4

x − 4

y =

−5

4

x + 4

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

(4, −1)

Sketch the solution to each system of inequalities.

77)

2

x +

y ≥ −1

x + 2

y ≥ 4

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

78)

y ≤ −1

4

x +

y > 3

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

-5-

Page 30: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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79)

2

x + 3

y ≤ 3

2

x − 3

y > 9

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

80)

5

x + 2

y ≥ −6

x − 2

y ≤ −6

x

y

−5 −4 −3 −2 −1 1 2 3 4 5

−5

−4

−3

−2

−1

1

2

3

4

5

Find the discriminant of each quadratic equation then state the number and type of solutions.

81)

−2

x2 + 8

x − 5 = 3

0; one real solution

82)

r2 + 2

r − 8 = −8

4; two real solutions

83)

b2 + 6

b − 5 = 2

64; two real solutions

84)

n2 − 6

n − 14 = −5

0; one real solution

Solve each equation by completing the square.

85)

v2 − 10

v − 102 = −8

{

5 + 119 ,

5 −

119}

86)

a2 − 2

a − 68 = −8

{

1 + 61,

1 −

61}

Solve each equation by factoring.

87)

x2 =

−10

x − 21

{−3, −7}

88)

x2 =

−42 − 13

x

{−7, −6}

Solve each equation with the quadratic formula.

89)

5

k2 + 11

k = −9

{

−11 +

i 59

10,

−11 −

i 59

10 } 90) 5

a2 =

23 + 3

a

{

3 + 469

10,

3 −

469

10 }

Write each expression in radical form.

91)

p

6

5

( 5

p)6

92)

(10

n)

5

6

( 610

n)5

93)

(2

x)

1

5

52

x

94)

(2

m)

1

4

42

m

-6-

Page 31: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Write each expression in exponential form.

95)

( 3

x )5

x

5

3 96) 4

10

r

(10

r)

1

4

97)

( 4

b)3

b

3

498)

( 510

n)6

(10

n)

6

5

Simplify.

99)

(100

a2)

3

2

1000

a3

100)

(

x12)

5

3

x20

101)

(

n3)

5

3

n5

102)

(1000

v9)

4

3

10000

v12

Solve each system by elimination.

103)

−5

x − 6

y = 11

−10

x + 2

y = 8

(−1, −1)

104)

7

x + 6

y = 9

14

x + 12

y = 12

No solution

105)

−8

x + 6

y = 7

−28

x + 21

y = 7

No solution

106)

4

x − 4

y = 6

−6

x + 6

y = −18

No solution

Solve each system by substitution.

107)

−3

x +

y = −9

3

x − 2

y = 15

(1, −6)

108)

3

x +

y = −21

4

x − 4

y = 4

(−5, −6)

109)

y = 1

−5

x + 2

y = 22

(−4, 1)

110)

3

x − 4

y = 17

−2

x +

y = 2

(−5, −8)

111) When you reverse the digits in a certain two-digit number you decrease its value by 63. What is the numberif the sum of its digits is 9?

81

112) Mei and Eugene each improved their yards by planting grass sod and ornamental grass. They bought their

supplies from the same store. Mei spent $168 on 10 ft² of grass sod and 12 bunches of ornamental grass.

Eugene spent $80 on 5 ft² of grass sod and 5 bunches of ornamental grass. Find the cost of one ft² of grass

sod and the cost of one bunch of ornamental grass.

ft² of grass sod: $12, bunch of ornamental grass: $4

-7-

Page 32: Algebra 2 - Review - 2nd Nine Weeks Exam.ks-ia2€¦ · Find the discriminant of each quadratic equation then state the number and type of solutions. 81) −10 n2 − 9n − 1 = 5

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Simplify.

113)

− 18 −

2 6 −

8

−5 2 −

2 6

114)

2 5 −

3 +

2 12

2 5 +

3 3

115)

2 6 +

2 5 −

3 24

−4 6 +

2 5

116)

−2 2 −

24 −

2 6

−2 2 −

4 6

Sketch the graph of each function.

117)

y =

3

x − 5

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

118)

y =

−2 +

2

x

x

y

−8 −6 −4 −2 2 4 6 8

−8

−6

−4

−2

2

4

6

8

Simplify.

119)

(

5 −

2 3)(

−3 + 3)

−21 +

11 3

120)

(

2 + 3)(

4 + 3)

2 2 + 6 +

2 3 + 3

121)

5(

10 +

2 3)

5 2 +

2 15

122)

15(

5 +

2 5)

5 15 +

10 3

123) 4

64

x4y

4

2

xy4

4

124) 6

256

x6y

7

2

xy6

4

y

125) 3

108

x5y3

3

xy3

4

x2

126) 32

u4v2

4

u2v 2

Solve each equation. Remember to check for extraneous solutions.

127)

−15 −

2

n =

−7 −

n

{−8}

128)

5

n + 3 = 8

{5}

129)

2

n =

3

n − 1

{1}

130) −7 =

n + 6 − 7

{−6}

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