Algebra 2 Honors Semester 1 Instructional...
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Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
Released 8/21/15
Algebra 2 Honors Semester 1
Instructional Materials for the WCSD Math Common Finals
The Instructional Materials are for student and teacher use and are aligned
to the Math Common Final blueprint for this course. When used as test
practice, success on the Instructional Materials does not guarantee success
on the district math common final.
Students can use these Instructional Materials to become familiar with the
format and language used on the district common finals. Familiarity with
standards and vocabulary as well as interaction with the types of problems
included in the Instructional Materials can result in less anxiety on the part
of the students.
Teachers can use the Instructional Materials in conjunction with the course
guides to ensure that instruction and content is aligned with what will be
assessed. The Instructional Materials are not representative of the depth
or full range of learning that should occur in the classroom.
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
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Algebra 2 Honors Semester 1 Test Reference Sheet
Sum of Two Cubes π3 + π3 = (π + π)(π2 β ππ + π2)
Difference of Two Cubes π3 β π3 = (π β π)(π2 + ππ + π2)
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
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Multiple Choice: Identify the choice that best completes the statement or answers the question.
1. Write the piecewise function for the graph below:
A. π(π₯) =
{
1
2π₯ β 5, π₯ β€ 0
β1
3π₯ + 1, 0 < π₯ < 3
2π₯ + 1, π₯ β₯ 3
B. π(π₯) =
{
1
2π₯ β 5, π₯ β€ 0
2π₯ + 1, 0 < π₯ < 3
β1
3π₯ + 1, π₯ β₯ 3
C. π(π₯) =
{
β
1
3π₯ + 1, π₯ β€ 0
2π₯ + 1, 0 < π₯ < 3
1
2π₯ β 5, π₯ β₯ 3
D. π(π₯) =
{
1
2π₯ β 5, π₯ β€ 0
2π₯ + 1, 0 β€ π₯ β€ 3
β1
3π₯ + 1, π₯ β₯ 3
2. Graph the function π(π₯) = {
βπ₯ + 3, π₯ β€ β3
βπ₯2 + 6, π₯ > β3
A.
C.
B.
D.
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3. Three students were chosen to show their solutions for solving the equation
π¦ = π(π₯ β β) + π for x. Their work is shown below. Determine which students were
correct.
Student #1 Student #2 Student #3
π¦ = π(π₯ β β) + π π¦ = π(π₯ β β) + π π¦ = π(π₯ β β) + π
π¦ β π = π(π₯ β β) π¦
π= (π₯ β β) + π
π¦
π= (π₯ β β) +
π
π
(π¦ β π)
π= π₯ β β
π¦
πβ π = π₯ β β
π¦
πβπ
π= π₯ β β
(π¦ β π)
π+ β = π₯
π¦
πβ π + β = π₯
π¦
πβπ
π+ β = π₯
A. Student #1 and Student #2 C. Student #1 and Student #3
B. Student #2 and Student #3 D. All students were correct
4. Create a table to represent the graph:
A. Weight (lbs) Shipping Cost ($)
0 < π₯ β€ 1.0 4.00 1.0 < π₯ β€ 2.0 4.50 2.0 < π₯ β€ 3.0 5.00 3.0 < π₯ β€ 4.0 5.50 4.0 < π₯ β€ 5.0 6.00
C. Weight (lbs) Shipping Cost ($)
0 < π₯ β€ 0.9 4.00 1.0 < π₯ β€ 1.9 4.50 2.0 < π₯ β€ 2.9 5.00 3.0 < π₯ β€ 3.9 5.50 4.0 < π₯ β€ 4.9 6.00
B. Weight (lbs) Shipping Cost ($)
0 β€ π₯ β€ 1.0 4.00 1.0 β€ π₯ β€ 2.0 4.50 2.0 β€ π₯ β€ 3.0 5.00 3.0 β€ π₯ β€ 4.0 5.50 4.0 β€ π₯ β€ 5.0 6.00
D. Weight (lbs) Shipping Cost ($)
0 < π₯ < 0.9 4.00 1.0 < π₯ < 1.9 4.50 2.0 < π₯ < 2.9 5.00 3.0 < π₯ < 3.9 5.50 4.0 < π₯ < 4.9 6.00
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
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5. Which of the following graphs shows a function over the domain [β3, β1) βͺ (0, 5]
A.
C.
B.
D.
6. Given π(π₯) = 4 (π₯ β2
7)2
+1
9, identify the domain and range of the function.
A. Domain: (ββ, +β)
Range: (ββ, β2
7)
C. Domain: (ββ, +β) Range: (β, 4)
B. Domain: [ββ, +β]
Range: [β, β2
7]
D. Domain: (ββ,+β)
Range: [1
9, β)
7. Solve the following system for z:
{
π₯ + 2π¦ β π§ = 5β3π₯ β 2π¦ β 3π§ = 114π₯ + 4π¦ + 5π§ = β18
A. π§ = 0 C. π§ = β4
B. π§ = β2 D. π§ = 8
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8. Compare the two functions represented below. Determine which of the following
statements is true.
Function π(π₯) Function π(π₯)
π(π₯) = (π₯ β 6)2 β 4
A. The functions have the same vertex.
B. The minimum value of π(π₯) is the same as the minimum value of π(π₯).
C. The functions have the same axis of symmetry.
D. The minimum value of π(π₯) is less than the minimum value of π(π₯).
9. If the function π(π₯) = π₯3 is translated left eight units and up ten units, how will the
domain and range of the function change?
A. The domain will become π·: {π₯|π₯ β₯ β8} and
the range will become π : {π¦|π¦ β₯ 10}.
B. The domain will become π·: {π₯|π₯ β₯ 8} and
the range will become π : {π¦|π¦ β₯ 10}.
C. The domain will become π·: {π₯|π₯ β₯ β8} and
the range will remain π : {π¦|πππ ππππ ππ’πππππ }.
D. The domain will remain π·: {π₯|πππ ππππ ππ’πππππ } and
the range will remain π : {π¦|πππ ππππ ππ’πππππ }.
10. Which equation is obtained after the graph below is translated 4 units to the left and
5 units up?
A. π(π₯) = β
1
3(π₯ + 7)3 + 3
B. π(π₯) = β1
3(π₯ β 1)3 + 3
C. π(π₯) = β3(π₯ + 8)3 β 6
D. π(π₯) = β3(π₯ + 2)3 β 6
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
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11. State where the function is increasing and
decreasing.
A. Never Increasing
Decreasing: (ββ,+β)
B. Increasing: (β8, 0) βͺ (0,+ β) Decreasing: (ββ,β8)
C. Increasing: (ββ,β8) βͺ (0, 8) Decreasing: (β8, 0)
D. Increasing: (β8,β4) βͺ (0,+β) Decreasing: (ββ,β8) βͺ (β4, 0)
12. The function π(π₯) =1
2π₯3 +
1
4π₯2 β
15
4π₯ is graphed to
the right. Over which intervals of x is the graph
positive?
A.
B.
C.
D.
13. What are the values of the relative maxima and/or minima of the function graphed?
A. relative maxima: 0
relative minima: β4, 4
B. relative maxima: 10
relative minima: β1, 2
C. relative maxima: 3.3, 4.7
relative minima: 0
D. relative maxima: 2, 10
relative minima: β1
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14. Solve: 5(π₯ + 1)2 = 120
A. π₯ = Β±β23 C. π₯ = β1 Β± 2β6
B. π₯ =β5 Β± 2β30
5 D. π₯ = β3β6 ππ β6
15. Simplify: 4π(10 + π) β 6(2 β 3π)
A. 28 + 22π C. β8 + 58π
B. β16 + 58π D. 8 + 22π
16. Simplify: (πβ5 + 2)2
A. β1 + 4πβ5 C. 3πβ5
B. β1 + πβ10 D. β1
17. Simplify: (πβ7 + 8)(πβ7 β 8)
A. 7π β 64 C. β57
B. πβ7 β 64 D. β71
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18. Simplify:
2π(6β4π)
3+3π
A. 4π C. 60 +
2
3π
B. 8
3+ 4π D.
10
3+2
3π
19. Write
7π(1+2π)+5
3π as a complex number in standard form.
A.
16π
3 C.
7
3+ 3π
B. β9 + 7π
3π D. 7 +
5
3π
20. What are the solutions to the quadratic equation, 3π₯2 + 21π₯ = 5π₯ β 60?
A. π₯ =β8 Β± 4πβ29
3 C. π₯ =
β8 Β± 2πβ61
3
B. π₯ =β8 Β± 2πβ29
3 D. π₯ =
β8 Β± πβ61
2
21. Given π(π₯) = 2π₯2 + 16π₯ + 18, find the value of π if the function is written in vertex
form, π(π₯) = π(π₯ β β)2 + π.
A. π = β9 C. π = β14
B. π = 4 D. π = 7
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22. Which function is represented by the graph?
A. π(π₯) =
1
3(π₯ β 3)(π₯ β 6)
B. π(π₯) = (π₯ + 3)(π₯ + 6)
C. π(π₯) = (π₯ β 3)(π₯ β 6)
D. π(π₯) = 3(π₯ β 3)(π₯ β 6)
23. Which of following functions does not represent the parabola with a vertex at (1, 4) and
x-intercepts (β1, 0) and (3, 0).
A. π(π₯) = βπ₯2 + π₯ + 4 C. π(π₯) = βπ₯2 + 2π₯ + 3
B. π(π₯) = β(π₯ β 1)2 + 4 D. π(π₯) = β(π₯ + 1)(π₯ β 3)
24.
Which of the following functions represent the parabola opening upwards with a
compression factor of 1
4 and x-intercepts (β4, 0) and (6, 0).
I. π¦ =1
4(π₯ + 4)(π₯ β 6)
II. π¦ =1
4π₯2 +
5
2π₯ β 6
III. π¦ = 4(π₯ β 4)2 + 6
IV. π¦ =1
4π₯2 β
1
2π₯ β 6
V. π¦ =1
4(π₯ β 1)2 β
25
4
A. Options I, IV, and V C. Options I, III, and IV
B. Options I, III, and V D. Options II, IV, and V
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
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25. Compare the axis of symmetry and the minimum values for the two functions below.
β(π₯) = 2(π₯ + 3)(π₯ β 7)
π(π₯) = π₯2 β 4π₯ β 21
Determine which of the following statements is correct.
A. The functions β(π₯) and π(π₯) have the same axis of symmetry, but the minimum value
of β(π₯) is less than the minimum value of π(π₯).
B. The functions β(π₯) and π(π₯) have the same axis of symmetry, but the minimum value
of β(π₯) is greater than the minimum value of π(π₯).
C. The functions β(π₯) and π(π₯) do not have the same axis of symmetry, and the minimum
value of β(π₯) is less than the minimum value of π(π₯).
D. The functions β(π₯) and π(π₯) do not have the same axis of symmetry, and the minimum
value of β(π₯) is greater than the minimum value of π(π₯).
26. Given the diagram below, approximate to the nearest foot how many feet of walking
distance a person saves by cutting across the lawn instead of walking on the sidewalk.
A. 60 ππππ‘ C. 36 ππππ‘
B. 48 ππππ‘ D. 24 ππππ‘
27. Which of the following is the quadratic equation for a parabola with a vertex of (β8, 2) going through the point (β13, 12) ?
A. π¦ = β
10
441(π₯ + 8)2 + 2 C. π¦ =
2
5(π₯ + 8)2 + 2
B. π¦ = β2
5(π₯ β 8)2 + 2 D. π¦ =
10
441(π₯ β 8)2 + 2
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28. A water balloon is launched upward from an initial height (β0) of 15 feet with an initial
velocity (π£0) of 50 feet per second. The height of the water balloon can be modeled by the
equation β = β16π‘2 + π£0π‘ + β0 where t is time in seconds and h is the height above the
ground. Find the time it takes the water balloon to hit the ground level. Round your
answers to the nearest hundredth.
A. Time at ground level: π‘ = 3.50 π ππ C. Time at ground level: π‘ = 3.13 π ππ
B. Time at ground level: π‘ = 3.40 π ππ D. Time at ground level: π‘ = 3.27 π ππ
29. Which of the following systems of equations could a student use to write a quadratic
function in standard form for the parabola passing through the points (1, 4), (3, β2), and
(β2, 17)?
A. {
π + 4π + π = π¦9π β 2π + π = π¦β4π + 17π + π = π¦
C. {2π + π + π = 46π + 3π + π = β2β4π β 2π + π = 17
B. {π + π + π = 4
9π + 3π + π = β24π β 2π + π = 17
D. {
π₯2 + 4π₯ + π = π¦
3π₯2 β 2π₯ + π = π¦
β2π₯2 + 17π₯ + π = π¦
30. Determine which expression would make the following statement true:
16π₯4π¦7
? = 4π₯3π¦10
A. 4π₯π¦β3 C. 4π₯7π¦17
B. 12π₯β1π¦β3 D. 64π₯7π¦17
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31. In the figure below, the perimeter is 4π₯2 + 8π₯ β 2π¦ units and the length is 2π₯2 + π₯ + π¦.
What is the width?
A. π€ = 2π₯2 β 7π₯ β 3π¦ C. π€ = 6π₯ β 4π¦
B. π€ = 2π₯2 + 8π₯ β 2 D. π€ = 3π₯ β 2π¦
32. Multiply: (2π₯2 + 4π₯ β 5)(βπ₯2 + 3π₯ + 6)
A. β2π₯4 + 2π₯3 + 29π₯2 + 9π₯ β 30 C. β2π₯4 + 9π₯2 + 21π₯ β 30
B. 2π₯4 + 10π₯3 + 19π₯2 + 9π₯ β 30 D. β2π₯4 + 24π₯2 β 30
33. Factor: 4π₯4 β 13π₯2 + 9
A. (2π₯2 β 9)(2π₯2 β 4) C. (4π₯2 β 9)2(π₯2 β 1)2
B. (2π₯ β 3)(2π₯ + 3)(π₯ + 1)(π₯ β 1) D. (4π₯ β 3)(π₯ + 3)(π₯ + 1)(π₯ β 1)
34. Factor: 125π₯3 β 343
A. (5π₯ β 7)(5π₯2 + 35π₯ + 9) C. (5π₯ β 7)(25π₯2 + 35π₯ + 49)
B. (5π₯ β 7)(5π₯2 + 35π₯ β 9) D. (5π₯ β 7)(25π₯2 β 35π₯ β 49)
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35. Factor the following using imaginary numbers: 9π₯2 + 49
A. (3π₯ β 7)2 C. (3π₯ + 7π)(3π₯ β 7π)
B. (β3π₯ + 7)(β3π₯ β 7) D. (3π₯ + 7π)2
36. Solve: 10π¦3 β 4π¦2 β 2π¦ = β5π¦3 + 3π¦2
A. π¦ = β3, π¦ = 0, π¦ = 10 C. π¦ = 0, π¦ =
1 Β± β41
10
B. π¦ = β1
5, π¦ = 0, π¦ =
2
3 D. π¦ = 0
37. Solve: π₯4 β 64 = 0
A. π₯ = Β±β8, π₯ = Β±8π C. π₯ = Β±8, π₯ = Β±8π
B. π₯ = Β±2β2, π₯ = Β±2πβ2 D. π₯ = Β±4, π₯ = Β±4π
38. What is the remainder in the division (6π₯3 β π₯2 + 4π₯ β 9) Γ· (2π₯ β 3)?
A. 15 C. 3
B. β3 D. β15
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39. Find the quotient of (3π₯3 β 44π₯ + 8) Γ· (π₯ β 4)?
A. 3π₯2 β 12π₯ + 4 C. 3π₯2 β 32 +
β120
π₯ β 4
B. 3π₯2 β 12π₯ + 4 +β8
π₯ β 4 D. 3π₯2 + 12π₯ + 4 +
24
π₯ β 4
40. What is the end behavior for the function, π(π₯) = (π₯4 β 5π₯ β 3)(β9π₯5 + 6π₯3)?
A. as π₯ β ββ, π(π₯) β ββ and as π₯ β +β, π(π₯) β +β
B. as π₯ β ββ, π(π₯) β +β and as π₯ β +β, π(π₯) β +β
C. as π₯ β ββ, π(π₯) β ββ and as π₯ β +β, π(π₯) β ββ
D. as π₯ β ββ, π(π₯) β +β and as π₯ β +β, π(π₯) β ββ
41. The equation π₯3 β 3π₯2 + 4π₯ β 12 = 0 is graphed below. Use the graph to help solve
the equation and find all the roots of the function.
A. π₯ = 3,β2, 2
B. π₯ = β12, 1, 3
C. π₯ = 3,β2π, 2π
D. π₯ = 12,3 β πβ7
2,3 + πβ7
2
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42. Which polynomial is graphed below?
A. π(π₯) = (π₯ + 1)(π₯ β 3)
B. π(π₯) = (π₯ β 1)(π₯ + 1)(π₯ + 3)
C. π(π₯) = π₯(π₯ β 3)(π₯ + 1)
D. π(π₯) = π₯(π₯ + 3)(π₯ β 1)
43. Find all of the zeros of π(π₯) = π₯3 β 3π₯2 + 4π₯ β 2.
A. π₯ = 1 + π, 1 β π, 1 C. π₯ = β2 , β1, 1, 2
B. π₯ = 1 D. π₯ = β1,β2π, 2π
44. Write a polynomial function of least degree that has rational coefficients, a leading
coefficient of 1, and the zeros 3π, β2 , β4.
A. π(π₯) = π₯5 β 4π₯4 + 7π₯3 + 28π₯2 β 18π₯ β 76
B. π(π₯) = π₯5 β 4π₯4 β 13π₯3 β 52π₯2 + 36π₯ + 144
C. π(π₯) = π₯5 + 4π₯4 + 7π₯3 + 28π₯2 β 18π₯ β 72
D. π(π₯) = π₯6 β 9π₯4 β 130π₯2 + 288
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45. A manufacturer is going to package their product in an open rectangular box made from a
single flat piece of cardboard. The box will be created by cutting a square out from each
corner of the rectangle and folding the flaps up to create a box. The original rectangular
piece of cardboard is 20 πππβππ long and 15 πππβππ wide. Write a function that
represents the volume of the box.
A. π(π₯) = π₯3 β 35π₯2 + 300π₯ C. π(π₯) = π₯2 β 35π₯ + 300
B. π(π₯) = 4π₯3 β 70π₯2 + 300π₯ D. π(π₯) = 4π₯2 β 70π₯ + 300
46. Identify any holes, asymptotes, and intercepts of π(π₯) =π₯2βπ₯β6
π₯2+7π₯+10
A. Horizontal Asymptote: π¦ = β2, 3
Vertical Asymptote: π₯ = β5,β2
Hole: ππππ
x-intercept: (10, 0) y-intercept: (0, β6)
C. Horizontal Asymptote: π¦ = 1
Vertical Asymptote: π₯ = β5
Hole at π₯ = β2
x-intercept: (3, 0)
y-intercept: (0,β3
5)
B. Horizontal Asymptote: ππππ
Vertical Asymptote: π₯ = β5
Hole at π₯ = β2
x-intercept: (3, 0) y-intercept: (0, β5)
D. Horizontal Asymptote: π¦ = β5
Vertical Asymptote: π₯ = 1
Hole: ππππ
x-intercept: (β2, 0), (β5, 0) y-intercept: (0, β2), (0, 3)
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47. State the Domain and Range of the function: π¦ = π₯+7
3π₯β15
A. π·πππππ: {π₯|π₯ β β5} π ππππ: {π¦|π¦ β β7}
C. π·πππππ: {π₯|π₯ β 5}
π ππππ: {π¦|π¦ β 13}
B. π·πππππ: {π₯|π₯ β β5}
π ππππ: {π¦|π¦ β β715}
D. π·πππππ: {π₯|π₯ β 5}
π ππππ: {π¦|π¦ β β73}
49. Which statement describes the end behavior of the function π(π₯) = β5π₯+4
2π₯β3 ?
A. as π₯ β ββ, π(π₯) β +3
2 and as π₯ β +β, π(π₯) β β
5
2
B. as π₯ β ββ, π(π₯) β ββ and as π₯ β +β, π(π₯) β +3
2
C. as π₯ β ββ, π(π₯) β β5
2 and as π₯ β +β, π(π₯) β β
5
2
D. as π₯ β ββ, π(π₯) β ββ and as π₯ β +β, π(π₯) β β5
2
48. Which of the following is the graphing form of π(π₯) = 4π₯β14
π₯β6 ?
A. π(π₯) =6
π₯ β 3+ 10 C. π(π₯) =
4
π₯ β 6+ 4
B. π(π₯) =4
π₯ β 3+ 10 D. π(π₯) =
10
π₯ β 6+ 4
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50. Which is a graph of π(π₯) = 4π₯+4
π₯+2 with any asymptotes indicated by dashed lines?
A.
C.
B.
D.
51. Translate the graph of π(π₯) = 6π₯+7
π₯+1 one unit down and four units left. Which of the
following is the function after the translations?
A. π(π₯) =1
π₯ β 4β 1 C. π(π₯) =
1
π₯ β 3+ 5
B. π(π₯) =6
π₯ β 4β 1 D. π(π₯) =
1
π₯ + 5+ 5
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52. Which of the following functions is modeled by the graph below?
A. π(π₯) = β
2
π₯ + 3+ 4
B. π(π₯) =2
π₯ + 3+ 4
C. π(π₯) =
2
π₯ β 3+ 4
D. π(π₯) = β2
π₯ β 3+ 4
53. Simplify: π₯2β9π₯+14
π₯2β6π₯+5
π₯2β8π₯+7
π₯2β7π₯+10
A. (π₯ β 7)2
(π₯ β 5)2 C.
(π₯ β 5)(π₯ β 7)
2(π₯ β 1)
B. (π₯ β 2)2
(π₯ β 1)2 D.
(π₯ β 7)
2(π₯ β 1)
54. Perform the indicated operation: π₯+2
π₯+5β π₯2
π₯+2
π₯+1
π₯+5
A. π₯2(π₯ + 1)
(π₯ + 5)2 C.
(π₯ + 5)2
π₯2(π₯ + 1)
B. (π₯ + 2)2
π₯2(π₯ + 1) D.
π₯2
π₯ + 1
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55. Perform the indicated operation: π₯+4
π₯+8+π₯β1
π₯β3β
5π₯β6
π₯2+5π₯β24
A. 2π₯2 + 3π₯ + 41
(π₯ + 8)2(π₯ β 3)2 C.
2π₯2 + 3π₯ β 14
(π₯ + 8)(π₯ β 3)
B. 10π₯2 β 2π₯ β 12
(π₯ + 8)(π₯ β 3) D.
β3π₯ + 9
(π₯ + 8)(π₯ β 3)
56. Simplify: 1
1βπ₯+
π₯
π₯β1
A. 1 C. π₯ + 1
1 β π₯
B. π₯ + 1
π₯ β 1 D.
π₯ + 1
(π₯ β 1)2
57. If each of the following expressions is defined, which is equivalent to π₯ β 1 ?
A. (π₯ + 1)(π₯ β 1)
(π₯ β 1) C.
(π₯ + 1)(π₯ + 2)
π₯ β 2Γ·π₯ + 2
π₯ β 2
B. (π₯ β 1)(π₯ + 2)
π₯ + 1βπ₯ + 1
π₯ + 2 D.
π₯ + 1
π₯ + 2+π₯ β 1
π₯ + 2
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
Released 8/21/15
58. Perform the indicated operation:
π₯β3
2β4
π₯+1+π₯
3
A. 3π₯ + 3
2(π₯ + 4) C.
3π₯2 β 6π₯ β 9
β8π₯
B. π₯3 β π₯2 β 15π₯ + 36
6(π₯ + 1) D.
3π₯2 β 6π₯ β 9
2(β4 + π₯)
59. Solve: 2
π₯2β4=
1
2π₯β4
A. π₯ = β2 C. π₯ = 2
B. π₯ = 0 D. ππ π πππ’π‘πππ
60. Solve: π₯β1
π₯+1+π₯+7
π₯β1=
4
π₯2β1
A. π₯ = β1,β 2 C. π₯ = β2
B. π₯ = β1, 1 D. ππ π πππ’π‘πππ
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
Released 8/21/15
Algebra 2 Honors Semester 1 Instructional Materials 2015-2016
Answers
1. B 13. B 25. A 37. B 49. C
2. A 14. C 26. D 38. A 50. B
3. C 15. B 27. C 39. D 51. D
4. A 16. A 28. B 40. D 52. A
5. D 17. D 29. B 41. C 53. B
6. D 18. D 30. A 42. C 54. D
7. C 19. C 31. D 43. A 55. C
8. B 20. B 32. A 44. C 56. A
9. D 21. C 33. B 45. B 57. B
10. A 22. D 34. C 46. C 58. A
11. D 23. A 35. C 47. C 59. D
12. A 24. A 36. B 48. D 60. C