Algebra 2 Honors Semester 1 Instructional...

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Algebra 2 Honors Semester 1 Instructional Materials 2015-2016 Released 8/21/15 Algebra 2 Honors Semester 1 Instructional Materials for the WCSD Math Common Finals The Instructional Materials are for student and teacher use and are aligned to the Math Common Final blueprint for this course. When used as test practice, success on the Instructional Materials does not guarantee success on the district math common final. Students can use these Instructional Materials to become familiar with the format and language used on the district common finals. Familiarity with standards and vocabulary as well as interaction with the types of problems included in the Instructional Materials can result in less anxiety on the part of the students. Teachers can use the Instructional Materials in conjunction with the course guides to ensure that instruction and content is aligned with what will be assessed. The Instructional Materials are not representative of the depth or full range of learning that should occur in the classroom.

Transcript of Algebra 2 Honors Semester 1 Instructional...

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Algebra 2 Honors Semester 1 Instructional Materials 2015-2016

Released 8/21/15

Algebra 2 Honors Semester 1

Instructional Materials for the WCSD Math Common Finals

The Instructional Materials are for student and teacher use and are aligned

to the Math Common Final blueprint for this course. When used as test

practice, success on the Instructional Materials does not guarantee success

on the district math common final.

Students can use these Instructional Materials to become familiar with the

format and language used on the district common finals. Familiarity with

standards and vocabulary as well as interaction with the types of problems

included in the Instructional Materials can result in less anxiety on the part

of the students.

Teachers can use the Instructional Materials in conjunction with the course

guides to ensure that instruction and content is aligned with what will be

assessed. The Instructional Materials are not representative of the depth

or full range of learning that should occur in the classroom.

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Algebra 2 Honors Semester 1 Test Reference Sheet

Sum of Two Cubes π‘Ž3 + 𝑏3 = (π‘Ž + 𝑏)(π‘Ž2 βˆ’ π‘Žπ‘ + 𝑏2)

Difference of Two Cubes π‘Ž3 βˆ’ 𝑏3 = (π‘Ž βˆ’ 𝑏)(π‘Ž2 + π‘Žπ‘ + 𝑏2)

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Multiple Choice: Identify the choice that best completes the statement or answers the question.

1. Write the piecewise function for the graph below:

A. 𝑓(π‘₯) =

{

1

2π‘₯ βˆ’ 5, π‘₯ ≀ 0

βˆ’1

3π‘₯ + 1, 0 < π‘₯ < 3

2π‘₯ + 1, π‘₯ β‰₯ 3

B. 𝑓(π‘₯) =

{

1

2π‘₯ βˆ’ 5, π‘₯ ≀ 0

2π‘₯ + 1, 0 < π‘₯ < 3

βˆ’1

3π‘₯ + 1, π‘₯ β‰₯ 3

C. 𝑓(π‘₯) =

{

βˆ’

1

3π‘₯ + 1, π‘₯ ≀ 0

2π‘₯ + 1, 0 < π‘₯ < 3

1

2π‘₯ βˆ’ 5, π‘₯ β‰₯ 3

D. 𝑓(π‘₯) =

{

1

2π‘₯ βˆ’ 5, π‘₯ ≀ 0

2π‘₯ + 1, 0 ≀ π‘₯ ≀ 3

βˆ’1

3π‘₯ + 1, π‘₯ β‰₯ 3

2. Graph the function 𝑓(π‘₯) = {

βˆ’π‘₯ + 3, π‘₯ ≀ βˆ’3

βˆ’π‘₯2 + 6, π‘₯ > βˆ’3

A.

C.

B.

D.

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3. Three students were chosen to show their solutions for solving the equation

𝑦 = π‘Ž(π‘₯ βˆ’ β„Ž) + π‘˜ for x. Their work is shown below. Determine which students were

correct.

Student #1 Student #2 Student #3

𝑦 = π‘Ž(π‘₯ βˆ’ β„Ž) + π‘˜ 𝑦 = π‘Ž(π‘₯ βˆ’ β„Ž) + π‘˜ 𝑦 = π‘Ž(π‘₯ βˆ’ β„Ž) + π‘˜

𝑦 βˆ’ π‘˜ = π‘Ž(π‘₯ βˆ’ β„Ž) 𝑦

π‘Ž= (π‘₯ βˆ’ β„Ž) + π‘˜

𝑦

π‘Ž= (π‘₯ βˆ’ β„Ž) +

π‘˜

π‘Ž

(𝑦 βˆ’ π‘˜)

π‘Ž= π‘₯ βˆ’ β„Ž

𝑦

π‘Žβˆ’ π‘˜ = π‘₯ βˆ’ β„Ž

𝑦

π‘Žβˆ’π‘˜

π‘Ž= π‘₯ βˆ’ β„Ž

(𝑦 βˆ’ π‘˜)

π‘Ž+ β„Ž = π‘₯

𝑦

π‘Žβˆ’ π‘˜ + β„Ž = π‘₯

𝑦

π‘Žβˆ’π‘˜

π‘Ž+ β„Ž = π‘₯

A. Student #1 and Student #2 C. Student #1 and Student #3

B. Student #2 and Student #3 D. All students were correct

4. Create a table to represent the graph:

A. Weight (lbs) Shipping Cost ($)

0 < π‘₯ ≀ 1.0 4.00 1.0 < π‘₯ ≀ 2.0 4.50 2.0 < π‘₯ ≀ 3.0 5.00 3.0 < π‘₯ ≀ 4.0 5.50 4.0 < π‘₯ ≀ 5.0 6.00

C. Weight (lbs) Shipping Cost ($)

0 < π‘₯ ≀ 0.9 4.00 1.0 < π‘₯ ≀ 1.9 4.50 2.0 < π‘₯ ≀ 2.9 5.00 3.0 < π‘₯ ≀ 3.9 5.50 4.0 < π‘₯ ≀ 4.9 6.00

B. Weight (lbs) Shipping Cost ($)

0 ≀ π‘₯ ≀ 1.0 4.00 1.0 ≀ π‘₯ ≀ 2.0 4.50 2.0 ≀ π‘₯ ≀ 3.0 5.00 3.0 ≀ π‘₯ ≀ 4.0 5.50 4.0 ≀ π‘₯ ≀ 5.0 6.00

D. Weight (lbs) Shipping Cost ($)

0 < π‘₯ < 0.9 4.00 1.0 < π‘₯ < 1.9 4.50 2.0 < π‘₯ < 2.9 5.00 3.0 < π‘₯ < 3.9 5.50 4.0 < π‘₯ < 4.9 6.00

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5. Which of the following graphs shows a function over the domain [βˆ’3, βˆ’1) βˆͺ (0, 5]

A.

C.

B.

D.

6. Given 𝑓(π‘₯) = 4 (π‘₯ βˆ’2

7)2

+1

9, identify the domain and range of the function.

A. Domain: (βˆ’βˆž, +∞)

Range: (βˆ’βˆž, βˆ’2

7)

C. Domain: (βˆ’βˆž, +∞) Range: (∞, 4)

B. Domain: [βˆ’βˆž, +∞]

Range: [∞, βˆ’2

7]

D. Domain: (βˆ’βˆž,+∞)

Range: [1

9, ∞)

7. Solve the following system for z:

{

π‘₯ + 2𝑦 βˆ’ 𝑧 = 5βˆ’3π‘₯ βˆ’ 2𝑦 βˆ’ 3𝑧 = 114π‘₯ + 4𝑦 + 5𝑧 = βˆ’18

A. 𝑧 = 0 C. 𝑧 = βˆ’4

B. 𝑧 = βˆ’2 D. 𝑧 = 8

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8. Compare the two functions represented below. Determine which of the following

statements is true.

Function 𝑓(π‘₯) Function 𝑔(π‘₯)

𝑔(π‘₯) = (π‘₯ βˆ’ 6)2 βˆ’ 4

A. The functions have the same vertex.

B. The minimum value of 𝑓(π‘₯) is the same as the minimum value of 𝑔(π‘₯).

C. The functions have the same axis of symmetry.

D. The minimum value of 𝑓(π‘₯) is less than the minimum value of 𝑔(π‘₯).

9. If the function 𝑓(π‘₯) = π‘₯3 is translated left eight units and up ten units, how will the

domain and range of the function change?

A. The domain will become 𝐷: {π‘₯|π‘₯ β‰₯ βˆ’8} and

the range will become 𝑅: {𝑦|𝑦 β‰₯ 10}.

B. The domain will become 𝐷: {π‘₯|π‘₯ β‰₯ 8} and

the range will become 𝑅: {𝑦|𝑦 β‰₯ 10}.

C. The domain will become 𝐷: {π‘₯|π‘₯ β‰₯ βˆ’8} and

the range will remain 𝑅: {𝑦|π‘Žπ‘™π‘™ π‘Ÿπ‘’π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘ }.

D. The domain will remain 𝐷: {π‘₯|π‘Žπ‘™π‘™ π‘Ÿπ‘’π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘ } and

the range will remain 𝑅: {𝑦|π‘Žπ‘™π‘™ π‘Ÿπ‘’π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘ }.

10. Which equation is obtained after the graph below is translated 4 units to the left and

5 units up?

A. 𝑓(π‘₯) = βˆ’

1

3(π‘₯ + 7)3 + 3

B. 𝑓(π‘₯) = βˆ’1

3(π‘₯ βˆ’ 1)3 + 3

C. 𝑓(π‘₯) = βˆ’3(π‘₯ + 8)3 βˆ’ 6

D. 𝑓(π‘₯) = βˆ’3(π‘₯ + 2)3 βˆ’ 6

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11. State where the function is increasing and

decreasing.

A. Never Increasing

Decreasing: (βˆ’βˆž,+∞)

B. Increasing: (βˆ’8, 0) βˆͺ (0,+ ∞) Decreasing: (βˆ’βˆž,βˆ’8)

C. Increasing: (βˆ’βˆž,βˆ’8) βˆͺ (0, 8) Decreasing: (βˆ’8, 0)

D. Increasing: (βˆ’8,βˆ’4) βˆͺ (0,+∞) Decreasing: (βˆ’βˆž,βˆ’8) βˆͺ (βˆ’4, 0)

12. The function 𝑓(π‘₯) =1

2π‘₯3 +

1

4π‘₯2 βˆ’

15

4π‘₯ is graphed to

the right. Over which intervals of x is the graph

positive?

A.

B.

C.

D.

13. What are the values of the relative maxima and/or minima of the function graphed?

A. relative maxima: 0

relative minima: βˆ’4, 4

B. relative maxima: 10

relative minima: βˆ’1, 2

C. relative maxima: 3.3, 4.7

relative minima: 0

D. relative maxima: 2, 10

relative minima: βˆ’1

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14. Solve: 5(π‘₯ + 1)2 = 120

A. π‘₯ = ±√23 C. π‘₯ = βˆ’1 Β± 2√6

B. π‘₯ =βˆ’5 Β± 2√30

5 D. π‘₯ = βˆ’3√6 π‘œπ‘Ÿ √6

15. Simplify: 4𝑖(10 + 𝑖) βˆ’ 6(2 βˆ’ 3𝑖)

A. 28 + 22𝑖 C. βˆ’8 + 58𝑖

B. βˆ’16 + 58𝑖 D. 8 + 22𝑖

16. Simplify: (π‘–βˆš5 + 2)2

A. βˆ’1 + 4π‘–βˆš5 C. 3π‘–βˆš5

B. βˆ’1 + π‘–βˆš10 D. βˆ’1

17. Simplify: (π‘–βˆš7 + 8)(π‘–βˆš7 βˆ’ 8)

A. 7𝑖 βˆ’ 64 C. βˆ’57

B. π‘–βˆš7 βˆ’ 64 D. βˆ’71

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18. Simplify:

2𝑖(6βˆ’4𝑖)

3+3𝑖

A. 4𝑖 C. 60 +

2

3𝑖

B. 8

3+ 4𝑖 D.

10

3+2

3𝑖

19. Write

7𝑖(1+2𝑖)+5

3𝑖 as a complex number in standard form.

A.

16𝑖

3 C.

7

3+ 3𝑖

B. βˆ’9 + 7𝑖

3𝑖 D. 7 +

5

3𝑖

20. What are the solutions to the quadratic equation, 3π‘₯2 + 21π‘₯ = 5π‘₯ βˆ’ 60?

A. π‘₯ =βˆ’8 Β± 4π‘–βˆš29

3 C. π‘₯ =

βˆ’8 Β± 2π‘–βˆš61

3

B. π‘₯ =βˆ’8 Β± 2π‘–βˆš29

3 D. π‘₯ =

βˆ’8 Β± π‘–βˆš61

2

21. Given 𝑓(π‘₯) = 2π‘₯2 + 16π‘₯ + 18, find the value of π‘˜ if the function is written in vertex

form, 𝑓(π‘₯) = π‘Ž(π‘₯ βˆ’ β„Ž)2 + π‘˜.

A. π‘˜ = βˆ’9 C. π‘˜ = βˆ’14

B. π‘˜ = 4 D. π‘˜ = 7

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22. Which function is represented by the graph?

A. 𝑓(π‘₯) =

1

3(π‘₯ βˆ’ 3)(π‘₯ βˆ’ 6)

B. 𝑓(π‘₯) = (π‘₯ + 3)(π‘₯ + 6)

C. 𝑓(π‘₯) = (π‘₯ βˆ’ 3)(π‘₯ βˆ’ 6)

D. 𝑓(π‘₯) = 3(π‘₯ βˆ’ 3)(π‘₯ βˆ’ 6)

23. Which of following functions does not represent the parabola with a vertex at (1, 4) and

x-intercepts (βˆ’1, 0) and (3, 0).

A. 𝑓(π‘₯) = βˆ’π‘₯2 + π‘₯ + 4 C. 𝑓(π‘₯) = βˆ’π‘₯2 + 2π‘₯ + 3

B. 𝑓(π‘₯) = βˆ’(π‘₯ βˆ’ 1)2 + 4 D. 𝑓(π‘₯) = βˆ’(π‘₯ + 1)(π‘₯ βˆ’ 3)

24.

Which of the following functions represent the parabola opening upwards with a

compression factor of 1

4 and x-intercepts (βˆ’4, 0) and (6, 0).

I. 𝑦 =1

4(π‘₯ + 4)(π‘₯ βˆ’ 6)

II. 𝑦 =1

4π‘₯2 +

5

2π‘₯ βˆ’ 6

III. 𝑦 = 4(π‘₯ βˆ’ 4)2 + 6

IV. 𝑦 =1

4π‘₯2 βˆ’

1

2π‘₯ βˆ’ 6

V. 𝑦 =1

4(π‘₯ βˆ’ 1)2 βˆ’

25

4

A. Options I, IV, and V C. Options I, III, and IV

B. Options I, III, and V D. Options II, IV, and V

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25. Compare the axis of symmetry and the minimum values for the two functions below.

β„Ž(π‘₯) = 2(π‘₯ + 3)(π‘₯ βˆ’ 7)

𝑗(π‘₯) = π‘₯2 βˆ’ 4π‘₯ βˆ’ 21

Determine which of the following statements is correct.

A. The functions β„Ž(π‘₯) and 𝑗(π‘₯) have the same axis of symmetry, but the minimum value

of β„Ž(π‘₯) is less than the minimum value of 𝑗(π‘₯).

B. The functions β„Ž(π‘₯) and 𝑗(π‘₯) have the same axis of symmetry, but the minimum value

of β„Ž(π‘₯) is greater than the minimum value of 𝑗(π‘₯).

C. The functions β„Ž(π‘₯) and 𝑗(π‘₯) do not have the same axis of symmetry, and the minimum

value of β„Ž(π‘₯) is less than the minimum value of 𝑗(π‘₯).

D. The functions β„Ž(π‘₯) and 𝑗(π‘₯) do not have the same axis of symmetry, and the minimum

value of β„Ž(π‘₯) is greater than the minimum value of 𝑗(π‘₯).

26. Given the diagram below, approximate to the nearest foot how many feet of walking

distance a person saves by cutting across the lawn instead of walking on the sidewalk.

A. 60 𝑓𝑒𝑒𝑑 C. 36 𝑓𝑒𝑒𝑑

B. 48 𝑓𝑒𝑒𝑑 D. 24 𝑓𝑒𝑒𝑑

27. Which of the following is the quadratic equation for a parabola with a vertex of (βˆ’8, 2) going through the point (βˆ’13, 12) ?

A. 𝑦 = βˆ’

10

441(π‘₯ + 8)2 + 2 C. 𝑦 =

2

5(π‘₯ + 8)2 + 2

B. 𝑦 = βˆ’2

5(π‘₯ βˆ’ 8)2 + 2 D. 𝑦 =

10

441(π‘₯ βˆ’ 8)2 + 2

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28. A water balloon is launched upward from an initial height (β„Ž0) of 15 feet with an initial

velocity (𝑣0) of 50 feet per second. The height of the water balloon can be modeled by the

equation β„Ž = βˆ’16𝑑2 + 𝑣0𝑑 + β„Ž0 where t is time in seconds and h is the height above the

ground. Find the time it takes the water balloon to hit the ground level. Round your

answers to the nearest hundredth.

A. Time at ground level: 𝑑 = 3.50 𝑠𝑒𝑐 C. Time at ground level: 𝑑 = 3.13 𝑠𝑒𝑐

B. Time at ground level: 𝑑 = 3.40 𝑠𝑒𝑐 D. Time at ground level: 𝑑 = 3.27 𝑠𝑒𝑐

29. Which of the following systems of equations could a student use to write a quadratic

function in standard form for the parabola passing through the points (1, 4), (3, βˆ’2), and

(βˆ’2, 17)?

A. {

π‘Ž + 4𝑏 + 𝑐 = 𝑦9π‘Ž βˆ’ 2𝑏 + 𝑐 = π‘¦βˆ’4π‘Ž + 17𝑏 + 𝑐 = 𝑦

C. {2π‘Ž + 𝑏 + 𝑐 = 46π‘Ž + 3𝑏 + 𝑐 = βˆ’2βˆ’4π‘Ž βˆ’ 2𝑏 + 𝑐 = 17

B. {π‘Ž + 𝑏 + 𝑐 = 4

9π‘Ž + 3𝑏 + 𝑐 = βˆ’24π‘Ž βˆ’ 2𝑏 + 𝑐 = 17

D. {

π‘₯2 + 4π‘₯ + 𝑐 = 𝑦

3π‘₯2 βˆ’ 2π‘₯ + 𝑐 = 𝑦

βˆ’2π‘₯2 + 17π‘₯ + 𝑐 = 𝑦

30. Determine which expression would make the following statement true:

16π‘₯4𝑦7

? = 4π‘₯3𝑦10

A. 4π‘₯π‘¦βˆ’3 C. 4π‘₯7𝑦17

B. 12π‘₯βˆ’1π‘¦βˆ’3 D. 64π‘₯7𝑦17

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31. In the figure below, the perimeter is 4π‘₯2 + 8π‘₯ βˆ’ 2𝑦 units and the length is 2π‘₯2 + π‘₯ + 𝑦.

What is the width?

A. 𝑀 = 2π‘₯2 βˆ’ 7π‘₯ βˆ’ 3𝑦 C. 𝑀 = 6π‘₯ βˆ’ 4𝑦

B. 𝑀 = 2π‘₯2 + 8π‘₯ βˆ’ 2 D. 𝑀 = 3π‘₯ βˆ’ 2𝑦

32. Multiply: (2π‘₯2 + 4π‘₯ βˆ’ 5)(βˆ’π‘₯2 + 3π‘₯ + 6)

A. βˆ’2π‘₯4 + 2π‘₯3 + 29π‘₯2 + 9π‘₯ βˆ’ 30 C. βˆ’2π‘₯4 + 9π‘₯2 + 21π‘₯ βˆ’ 30

B. 2π‘₯4 + 10π‘₯3 + 19π‘₯2 + 9π‘₯ βˆ’ 30 D. βˆ’2π‘₯4 + 24π‘₯2 βˆ’ 30

33. Factor: 4π‘₯4 βˆ’ 13π‘₯2 + 9

A. (2π‘₯2 βˆ’ 9)(2π‘₯2 βˆ’ 4) C. (4π‘₯2 βˆ’ 9)2(π‘₯2 βˆ’ 1)2

B. (2π‘₯ βˆ’ 3)(2π‘₯ + 3)(π‘₯ + 1)(π‘₯ βˆ’ 1) D. (4π‘₯ βˆ’ 3)(π‘₯ + 3)(π‘₯ + 1)(π‘₯ βˆ’ 1)

34. Factor: 125π‘₯3 βˆ’ 343

A. (5π‘₯ βˆ’ 7)(5π‘₯2 + 35π‘₯ + 9) C. (5π‘₯ βˆ’ 7)(25π‘₯2 + 35π‘₯ + 49)

B. (5π‘₯ βˆ’ 7)(5π‘₯2 + 35π‘₯ βˆ’ 9) D. (5π‘₯ βˆ’ 7)(25π‘₯2 βˆ’ 35π‘₯ βˆ’ 49)

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35. Factor the following using imaginary numbers: 9π‘₯2 + 49

A. (3π‘₯ βˆ’ 7)2 C. (3π‘₯ + 7𝑖)(3π‘₯ βˆ’ 7𝑖)

B. (√3π‘₯ + 7)(√3π‘₯ βˆ’ 7) D. (3π‘₯ + 7𝑖)2

36. Solve: 10𝑦3 βˆ’ 4𝑦2 βˆ’ 2𝑦 = βˆ’5𝑦3 + 3𝑦2

A. 𝑦 = βˆ’3, 𝑦 = 0, 𝑦 = 10 C. 𝑦 = 0, 𝑦 =

1 ± √41

10

B. 𝑦 = βˆ’1

5, 𝑦 = 0, 𝑦 =

2

3 D. 𝑦 = 0

37. Solve: π‘₯4 βˆ’ 64 = 0

A. π‘₯ = ±√8, π‘₯ = Β±8𝑖 C. π‘₯ = Β±8, π‘₯ = Β±8𝑖

B. π‘₯ = Β±2√2, π‘₯ = Β±2π‘–βˆš2 D. π‘₯ = Β±4, π‘₯ = Β±4𝑖

38. What is the remainder in the division (6π‘₯3 βˆ’ π‘₯2 + 4π‘₯ βˆ’ 9) Γ· (2π‘₯ βˆ’ 3)?

A. 15 C. 3

B. βˆ’3 D. βˆ’15

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39. Find the quotient of (3π‘₯3 βˆ’ 44π‘₯ + 8) Γ· (π‘₯ βˆ’ 4)?

A. 3π‘₯2 βˆ’ 12π‘₯ + 4 C. 3π‘₯2 βˆ’ 32 +

βˆ’120

π‘₯ βˆ’ 4

B. 3π‘₯2 βˆ’ 12π‘₯ + 4 +βˆ’8

π‘₯ βˆ’ 4 D. 3π‘₯2 + 12π‘₯ + 4 +

24

π‘₯ βˆ’ 4

40. What is the end behavior for the function, 𝑓(π‘₯) = (π‘₯4 βˆ’ 5π‘₯ βˆ’ 3)(βˆ’9π‘₯5 + 6π‘₯3)?

A. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ βˆ’βˆž and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ +∞

B. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ +∞ and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ +∞

C. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ βˆ’βˆž and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ βˆ’βˆž

D. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ +∞ and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ βˆ’βˆž

41. The equation π‘₯3 βˆ’ 3π‘₯2 + 4π‘₯ βˆ’ 12 = 0 is graphed below. Use the graph to help solve

the equation and find all the roots of the function.

A. π‘₯ = 3,βˆ’2, 2

B. π‘₯ = βˆ’12, 1, 3

C. π‘₯ = 3,βˆ’2𝑖, 2𝑖

D. π‘₯ = 12,3 βˆ’ π‘–βˆš7

2,3 + π‘–βˆš7

2

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42. Which polynomial is graphed below?

A. 𝑓(π‘₯) = (π‘₯ + 1)(π‘₯ βˆ’ 3)

B. 𝑓(π‘₯) = (π‘₯ βˆ’ 1)(π‘₯ + 1)(π‘₯ + 3)

C. 𝑓(π‘₯) = π‘₯(π‘₯ βˆ’ 3)(π‘₯ + 1)

D. 𝑓(π‘₯) = π‘₯(π‘₯ + 3)(π‘₯ βˆ’ 1)

43. Find all of the zeros of 𝑓(π‘₯) = π‘₯3 βˆ’ 3π‘₯2 + 4π‘₯ βˆ’ 2.

A. π‘₯ = 1 + 𝑖, 1 βˆ’ 𝑖, 1 C. π‘₯ = βˆ’2 , βˆ’1, 1, 2

B. π‘₯ = 1 D. π‘₯ = βˆ’1,βˆ’2𝑖, 2𝑖

44. Write a polynomial function of least degree that has rational coefficients, a leading

coefficient of 1, and the zeros 3𝑖, √2 , βˆ’4.

A. 𝑓(π‘₯) = π‘₯5 βˆ’ 4π‘₯4 + 7π‘₯3 + 28π‘₯2 βˆ’ 18π‘₯ βˆ’ 76

B. 𝑓(π‘₯) = π‘₯5 βˆ’ 4π‘₯4 βˆ’ 13π‘₯3 βˆ’ 52π‘₯2 + 36π‘₯ + 144

C. 𝑓(π‘₯) = π‘₯5 + 4π‘₯4 + 7π‘₯3 + 28π‘₯2 βˆ’ 18π‘₯ βˆ’ 72

D. 𝑓(π‘₯) = π‘₯6 βˆ’ 9π‘₯4 βˆ’ 130π‘₯2 + 288

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45. A manufacturer is going to package their product in an open rectangular box made from a

single flat piece of cardboard. The box will be created by cutting a square out from each

corner of the rectangle and folding the flaps up to create a box. The original rectangular

piece of cardboard is 20 π‘–π‘›π‘β„Žπ‘’π‘  long and 15 π‘–π‘›π‘β„Žπ‘’π‘  wide. Write a function that

represents the volume of the box.

A. 𝑉(π‘₯) = π‘₯3 βˆ’ 35π‘₯2 + 300π‘₯ C. 𝑉(π‘₯) = π‘₯2 βˆ’ 35π‘₯ + 300

B. 𝑉(π‘₯) = 4π‘₯3 βˆ’ 70π‘₯2 + 300π‘₯ D. 𝑉(π‘₯) = 4π‘₯2 βˆ’ 70π‘₯ + 300

46. Identify any holes, asymptotes, and intercepts of 𝑓(π‘₯) =π‘₯2βˆ’π‘₯βˆ’6

π‘₯2+7π‘₯+10

A. Horizontal Asymptote: 𝑦 = βˆ’2, 3

Vertical Asymptote: π‘₯ = βˆ’5,βˆ’2

Hole: π‘›π‘œπ‘›π‘’

x-intercept: (10, 0) y-intercept: (0, βˆ’6)

C. Horizontal Asymptote: 𝑦 = 1

Vertical Asymptote: π‘₯ = βˆ’5

Hole at π‘₯ = βˆ’2

x-intercept: (3, 0)

y-intercept: (0,βˆ’3

5)

B. Horizontal Asymptote: π‘›π‘œπ‘›π‘’

Vertical Asymptote: π‘₯ = βˆ’5

Hole at π‘₯ = βˆ’2

x-intercept: (3, 0) y-intercept: (0, βˆ’5)

D. Horizontal Asymptote: 𝑦 = βˆ’5

Vertical Asymptote: π‘₯ = 1

Hole: π‘›π‘œπ‘›π‘’

x-intercept: (βˆ’2, 0), (βˆ’5, 0) y-intercept: (0, βˆ’2), (0, 3)

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47. State the Domain and Range of the function: 𝑦 = π‘₯+7

3π‘₯βˆ’15

A. π·π‘œπ‘šπ‘Žπ‘–π‘›: {π‘₯|π‘₯ β‰  βˆ’5} π‘…π‘Žπ‘›π‘”π‘’: {𝑦|𝑦 β‰  βˆ’7}

C. π·π‘œπ‘šπ‘Žπ‘–π‘›: {π‘₯|π‘₯ β‰  5}

π‘…π‘Žπ‘›π‘”π‘’: {𝑦|𝑦 β‰ 13}

B. π·π‘œπ‘šπ‘Žπ‘–π‘›: {π‘₯|π‘₯ β‰  βˆ’5}

π‘…π‘Žπ‘›π‘”π‘’: {𝑦|𝑦 β‰  βˆ’715}

D. π·π‘œπ‘šπ‘Žπ‘–π‘›: {π‘₯|π‘₯ β‰  5}

π‘…π‘Žπ‘›π‘”π‘’: {𝑦|𝑦 β‰  βˆ’73}

49. Which statement describes the end behavior of the function 𝑓(π‘₯) = βˆ’5π‘₯+4

2π‘₯βˆ’3 ?

A. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ +3

2 and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ βˆ’

5

2

B. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ βˆ’βˆž and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ +3

2

C. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ βˆ’5

2 and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ βˆ’

5

2

D. as π‘₯ β†’ βˆ’βˆž, 𝑓(π‘₯) β†’ βˆ’βˆž and as π‘₯ β†’ +∞, 𝑓(π‘₯) β†’ βˆ’5

2

48. Which of the following is the graphing form of 𝑓(π‘₯) = 4π‘₯βˆ’14

π‘₯βˆ’6 ?

A. 𝑓(π‘₯) =6

π‘₯ βˆ’ 3+ 10 C. 𝑓(π‘₯) =

4

π‘₯ βˆ’ 6+ 4

B. 𝑓(π‘₯) =4

π‘₯ βˆ’ 3+ 10 D. 𝑓(π‘₯) =

10

π‘₯ βˆ’ 6+ 4

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50. Which is a graph of 𝑓(π‘₯) = 4π‘₯+4

π‘₯+2 with any asymptotes indicated by dashed lines?

A.

C.

B.

D.

51. Translate the graph of 𝑓(π‘₯) = 6π‘₯+7

π‘₯+1 one unit down and four units left. Which of the

following is the function after the translations?

A. 𝑔(π‘₯) =1

π‘₯ βˆ’ 4βˆ’ 1 C. 𝑔(π‘₯) =

1

π‘₯ βˆ’ 3+ 5

B. 𝑔(π‘₯) =6

π‘₯ βˆ’ 4βˆ’ 1 D. 𝑔(π‘₯) =

1

π‘₯ + 5+ 5

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52. Which of the following functions is modeled by the graph below?

A. 𝑓(π‘₯) = βˆ’

2

π‘₯ + 3+ 4

B. 𝑓(π‘₯) =2

π‘₯ + 3+ 4

C. 𝑓(π‘₯) =

2

π‘₯ βˆ’ 3+ 4

D. 𝑓(π‘₯) = βˆ’2

π‘₯ βˆ’ 3+ 4

53. Simplify: π‘₯2βˆ’9π‘₯+14

π‘₯2βˆ’6π‘₯+5

π‘₯2βˆ’8π‘₯+7

π‘₯2βˆ’7π‘₯+10

A. (π‘₯ βˆ’ 7)2

(π‘₯ βˆ’ 5)2 C.

(π‘₯ βˆ’ 5)(π‘₯ βˆ’ 7)

2(π‘₯ βˆ’ 1)

B. (π‘₯ βˆ’ 2)2

(π‘₯ βˆ’ 1)2 D.

(π‘₯ βˆ’ 7)

2(π‘₯ βˆ’ 1)

54. Perform the indicated operation: π‘₯+2

π‘₯+5βˆ™ π‘₯2

π‘₯+2

π‘₯+1

π‘₯+5

A. π‘₯2(π‘₯ + 1)

(π‘₯ + 5)2 C.

(π‘₯ + 5)2

π‘₯2(π‘₯ + 1)

B. (π‘₯ + 2)2

π‘₯2(π‘₯ + 1) D.

π‘₯2

π‘₯ + 1

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55. Perform the indicated operation: π‘₯+4

π‘₯+8+π‘₯βˆ’1

π‘₯βˆ’3βˆ’

5π‘₯βˆ’6

π‘₯2+5π‘₯βˆ’24

A. 2π‘₯2 + 3π‘₯ + 41

(π‘₯ + 8)2(π‘₯ βˆ’ 3)2 C.

2π‘₯2 + 3π‘₯ βˆ’ 14

(π‘₯ + 8)(π‘₯ βˆ’ 3)

B. 10π‘₯2 βˆ’ 2π‘₯ βˆ’ 12

(π‘₯ + 8)(π‘₯ βˆ’ 3) D.

βˆ’3π‘₯ + 9

(π‘₯ + 8)(π‘₯ βˆ’ 3)

56. Simplify: 1

1βˆ’π‘₯+

π‘₯

π‘₯βˆ’1

A. 1 C. π‘₯ + 1

1 βˆ’ π‘₯

B. π‘₯ + 1

π‘₯ βˆ’ 1 D.

π‘₯ + 1

(π‘₯ βˆ’ 1)2

57. If each of the following expressions is defined, which is equivalent to π‘₯ βˆ’ 1 ?

A. (π‘₯ + 1)(π‘₯ βˆ’ 1)

(π‘₯ βˆ’ 1) C.

(π‘₯ + 1)(π‘₯ + 2)

π‘₯ βˆ’ 2Γ·π‘₯ + 2

π‘₯ βˆ’ 2

B. (π‘₯ βˆ’ 1)(π‘₯ + 2)

π‘₯ + 1βˆ™π‘₯ + 1

π‘₯ + 2 D.

π‘₯ + 1

π‘₯ + 2+π‘₯ βˆ’ 1

π‘₯ + 2

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58. Perform the indicated operation:

π‘₯βˆ’3

2βˆ’4

π‘₯+1+π‘₯

3

A. 3π‘₯ + 3

2(π‘₯ + 4) C.

3π‘₯2 βˆ’ 6π‘₯ βˆ’ 9

βˆ’8π‘₯

B. π‘₯3 βˆ’ π‘₯2 βˆ’ 15π‘₯ + 36

6(π‘₯ + 1) D.

3π‘₯2 βˆ’ 6π‘₯ βˆ’ 9

2(βˆ’4 + π‘₯)

59. Solve: 2

π‘₯2βˆ’4=

1

2π‘₯βˆ’4

A. π‘₯ = βˆ’2 C. π‘₯ = 2

B. π‘₯ = 0 D. π‘›π‘œ π‘ π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘›

60. Solve: π‘₯βˆ’1

π‘₯+1+π‘₯+7

π‘₯βˆ’1=

4

π‘₯2βˆ’1

A. π‘₯ = βˆ’1,βˆ’ 2 C. π‘₯ = βˆ’2

B. π‘₯ = βˆ’1, 1 D. π‘›π‘œ π‘ π‘œπ‘™π‘’π‘‘π‘–π‘œπ‘›

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Answers

1. B 13. B 25. A 37. B 49. C

2. A 14. C 26. D 38. A 50. B

3. C 15. B 27. C 39. D 51. D

4. A 16. A 28. B 40. D 52. A

5. D 17. D 29. B 41. C 53. B

6. D 18. D 30. A 42. C 54. D

7. C 19. C 31. D 43. A 55. C

8. B 20. B 32. A 44. C 56. A

9. D 21. C 33. B 45. B 57. B

10. A 22. D 34. C 46. C 58. A

11. D 23. A 35. C 47. C 59. D

12. A 24. A 36. B 48. D 60. C