alg 2 spring2013 review 1

Name: ________________________ Class: ___________________ Date: __________ ID: A

1

alg 2 spring2013 review 1

Multiple ChoiceIdentify the letter of the choice that best completes the statement or answers the question.

Evaluate the expression for the given value of the variable(s).

____ 1. 5a + 5b; a = −6, b = −5a. –55 b. 55 c. 5 d. –5

____ 2. 4(3h − 6)

1 + h; h = −2

a. 32 b. 48 c. −48 d. 30

____ 3. 4b − 4| | + 3 − b 2||

|| + 2b 3; b = 2

a. 19 b. 17 c. –11 d. 21

____ 4. −x2 − 4x − 4; x = –3a. 3 b. –1 c. 11 d. –17

____ 5. The expression −16t2 + 1800 models the height of an object t seconds after it has been dropped from a height of 1800 feet. Find the height of an object after falling for 4.8 seconds.a. 2168.64 ft b. 1431.36 ft c. 1723.2 ft d. 7698.24 ft

Simplify by combining like terms.

____ 6. 4c − 4d + 8c − 3da. 12c + 7d b. 12c − 7d c. −12c − 7d d. −7c + 12d

____ 7. −3(−4y + 3) + 7ya. 19y − 9 b. 10y c. −19y + 3 d. −19y − 9

____ 8. Find the perimeter of the figure. Simplify the answer.

x + y

x

y

x

x

x

2

2

4

a. 9x + 2y b. 10x + y c. 10x + 2y d. 9x + 3y

Name: ________________________ ID: A

2

Solve the equation.

____ 9. 3y + 20 = 3 + 2y

a. −1

17b. 7

2

3c. 23 d. −17

____ 10. 1

4r −

1

16+

1

2r =

1

2+ r

a. 94

b.7

4c. −

9

4d. −

7

4

____ 11. −5y − 9 = −(y − 1)

a. −1

2b. −2

1

2c. −2 d. −

2

5

____ 12. 6(x − 0.8) − 0.2 5x − 4( ) = 6a. –0.5 b. –2 c. 0.5 d. 2

____ 13. 3x + 5| | = 1

a. x = 2 or x = −11

3c. x = 2 or x = −2

b. x = 2 or x = −4 d. x = −11

3 or x = −2

____ 14. 3 3x + 4| | − 7 = 5

a. x = 8

9 or x = −

2

9c. x =

8

9 or x = −2

2

3

b. x = 0 or x = −22

3d. x =

8

9 or x = 0

Solve the equation or formula for the indicated variable.

____ 15. S = 5r2t, for t

a. t = S5

− r b. t = 25rS

c. t = r2 − 5S d. t = S5r2

____ 16. T = 2UE

, for U

a. U = T − E2

b. U = T + E2

c. U = 2T − E d. U = TE2

Name: ________________________ ID: A

3

____ 17. The formula for the time a traffic light remains yellow is t = 18

s + 1, where t is the time in seconds and s is

the speed limit in miles per hour.a. Solve the equation for s.b. What is the speed limit at a traffic light that remains yellow for 4.5 seconds?

a. s = 8t − 8; s = 28 mi/h c. s = 8t − 1; s = 35

b. s = 8t; s = 36 mi/h d. s = 18

t − 1; s = 28 mi/h

Solve for x. State any restrictions on the variables.

____ 18. ax + bx + 9 = 7

a. x = 2a + b

; a ≠ b c. x = 7a + b + 9

; a + b ≠ −9

b. x = 7a + b + 9

; a ≠ 0,b ≠ −9 d. x = −2a + b

; a ≠ −b

____ 19. A rectangle is 3 times as long as it is wide. The perimeter is 60 cm. Find the dimensions of the rectangle. Round to the nearest tenth if necessary.a. 7.5 cm by 22.5 cm c. 20 cm by 60 cmb. 7.5 cm by 52.5 cm d. 15 cm by 22.5 cm

Solve the inequality. Graph the solution set.

____ 20. 2 + 2k ≤ 8a. k ≥ 3

0 2 4 6 80–2–4–6–8

c. k ≤ 3

0 2 4 6 80–2–4–6–8

b. k ≤ 5

0 2 4 6 80–2–4–6–8

d. k ≥ 5

0 2 4 6 80–2–4–6–8

____ 21. 2r – 9 ≥ –6

a. r ≤ 11

2

0 2 4 6 80–2–4–6–8

c. r ≥ 11

2

0 2 4 6 80–2–4–6–8

b. r ≥ −71

2

0 2 4 6 80–2–4–6–8

d. r ≤ −71

2

0 2 4 6 80–2–4–6–8

Name: ________________________ ID: A

4

____ 22. –4k + 5 ≤ 21a. k ≥ –4

0 2 4 6 80–2–4–6–8

c. k ≤ –4

0 2 4 6 80–2–4–6–8

b. k ≥ −61

2

0 2 4 6 80–2–4–6–8

d. k ≤ −61

2

0 2 4 6 80–2–4–6–8

____ 23. 2(4y – 5) < –10a. y > 0

0 2 4 6 80–2–4–6–8

c. y < 0

0 2 4 6 80–2–4–6–8

b. y < −5

8

0 2 4 6 80–2–4–6–8

d. y > −5

8

0 2 4 6 80–2–4–6–8

____ 24. 2(2m – 5) – 6 > –36

a. m < −61

4

0 2 4 6 80–2–4–6–8

c. m < –5

0 2 4 6 80–2–4–6–8

b. m > –5

0 2 4 6 80–2–4–6–8

d. m > −61

4

0 2 4 6 80–2–4–6–8

____ 25. 4(3b – 5) < –31 + 12b

a. no solutions

0 2 4 6 80–2–4–6–8

c. b > −11

24

0 2 4 6 80–2–4–6–8

b. b < −11

24

0 2 4 6 80–2–4–6–8

d. all real numbers

0 2 4 6 80–2–4–6–8

Name: ________________________ ID: A

5

____ 26. 26 + 6b ≥ 2(3b + 4)

a. all real numbers

0 2 4 6 80–2–4–6–8

c. b ≥ 11

2

0 2 4 6 80–2–4–6–8

b. b ≤ 11

2

0 2 4 6 80–2–4–6–8

d. no solutions

0 2 4 6 80–2–4–6–8

Solve the problem by writing an inequality.

____ 27. If the perimeter of a rectangular picture frame must be less than 200 in., and the width is 36 in., what must the height h of the frame be?a. h < 64 in. b. h > 128 in. c. h > 64 in. d. h < 128 in.

Solve the compound inequality. Graph the solution set.

____ 28. 5x + 10 ≥ 10 and 7x – 7 ≤ 14a. x ≥ 4 or x ≤ 1

0 2 4 6 80–2–4–6–8

c. x ≥ 4 or x ≤ 3

0 2 4 6 80–2–4–6–8

b. x ≥ 0 and x ≤ 1

0 2 4 6 80–2–4–6–8

d. x ≥ 0 and x ≤ 3

0 2 4 6 80–2–4–6–8

____ 29. 4x – 5 < –17 or 5x + 6 > 31

a. x < –3 or x > 5

0 2 4 6 80–2–4–6–8

c. x < –3 or x > 72

5

0 2 4 6 80–2–4–6–8

b. x < −51

2 or x > 7

2

5

0 2 4 6 80–2–4–6–8

d. x < −51

2 or x > 5

0 2 4 6 80–2–4–6–8

____ 30. −2 ≤ 2x − 4 < 4a. 0 ≤ x < − 2

0 2 4 6 80–2–4–6–8

c. 1 ≤ x < 0

0 2 4 6 80–2–4–6–8

b. 1 ≤ x < 4

0 2 4 6 80–2–4–6–8

d. 3 ≤ x < 6

0 2 4 6 80–2–4–6–8

Name: ________________________ ID: A

6

____ 31. The perimeter of a square garden is to be at least 22 feet but not more than 36 feet. Find all possible values for the length of its sides.a. 11 < x < 18 c. 5.5 ≤ x ≤ 9b. 5.5 < x < 9 d. 11 ≤ x ≤ 18

____ 32. Students tested the acidity of the campus pond over a three-day period. On Monday and Tuesday, the pH values were 6.75 and 7.86. Find the range of pH values for Wednesday’s reading that will result in a mean pH greater than 7.1 and less than 7.6.a. 7.01 < x < 7.5 c. 21.3 < x < 22.8b. 16.69 < x < 8.19 d. 10.65 < x < 11.4

Solve the equation. Check for extraneous solutions.

____ 33. 4 4 − 3x| | = 4x + 6

a. x =5

8or x =

11

8c. x =

5

8or x =

11

4

b. x =11

8or x =

1

4d. x = −

5

8or x =

11

4

Solve the inequality. Graph the solution.

____ 34. 2x + 3| | ≥ 19a. x ≤ −22 or x ≥ 16

0 10 20 30 400–10–20–30–40

c. x ≤ −11 or x ≥ 8

0 5 10 15 200–5–10–15–20

b. x ≤ −8 or x ≥ 8

0 5 10 15 200–5–10–15–20

d. x ≥ −11 or x ≤ 8

0 5 10 15 200–5–10–15–20

____ 35. 2 x + 14

|||

||| < 9

a. −43

8 < x < 4

3

8

0 2 4 60–2–4–6

c. x < −43

8 or x > 4

3

8

0 2 4 60–2–4–6

b. −43

4 < x < 4

1

4

0 2 4 60–2–4–6

d. x < −43

4 or x > 4

1

4

0 2 4 60–2–4–6

Name: ________________________ ID: A

7

____ 36. Write the ordered pairs for the relation. Find the domain and range.

O 2 4–2–4 x

2

4

–2

–4

y

a. {(–2, 5), (–1, 2), (0, 1), (1, 2), (2, 5)}; domain: {–2, –1, 0, 1, 2}; range: {1, 2, 5}b. {(5, –2), (2, –1), (1, 0), (2, 1), (5, 2)}; domain: {–2, –1, 0, 1, 2}; range: {1, 2, 5}c. {(–2, 5), (–1, 2), (0, 1), (1, 2), (2, 5)}; domain: {1, 2, 5}; range: {–2, –1, 0, 1, 2}d. {(5, –2), (2, –1), (1, 0), (2, 1), (5, 2)}; domain: {1, 2, 5}; range: {–2, –1, 0, 1, 2}

____ 37. . Find the domain and range.

−1,1

2

Ê

Ë

ÁÁÁÁÁÁÁ

ˆ

¯

˜̃˜̃˜̃˜, −

1

2, −1

Ê

Ë

ÁÁÁÁÁÁÁ

ˆ

¯

˜̃˜̃˜̃˜,

3

2, 0

Ê

Ë

ÁÁÁÁÁÁÁ

ˆ

¯

˜̃˜̃˜̃˜, 2,

3

2

Ê

Ë

ÁÁÁÁÁÁÁ

ˆ

¯

˜̃˜̃˜̃˜

Ï

Ì

Ó

ÔÔÔÔÔÔÔÔÔÔÔ

¸

˝

˛

ÔÔÔÔÔÔÔÔÔÔÔ

a.

domain: −1, −1

2,

3

2, 2

Ï

ÌÓ

ÔÔÔÔÔÔÔÔÔÔ

¸

˝˛


range: −1, 0,1

2,

3

2

Ï

ÌÓ


¸

˝˛


c.

domain: −1, −1

2, 2,

3

2

Ï

ÌÓ


¸

˝˛


range: −1, 0,1

2,

3

2

Ï

ÌÓ


¸

˝˛


b.

domain: −1, 0,1

2,

3

2

Ï

ÌÓ


¸

˝˛


range: −1, −1

2, 2,

3

2

Ï

ÌÓ


¸

˝˛


d.

domain: −1, 0,1

2,

3

2

Ï

ÌÓ


¸

˝˛


range: −1, −1

2, 2,

3

2

Ï

ÌÓ


¸

˝˛


Name: ________________________ ID: A

8

____ 38. Find the domain and range of the relation and determine whether it is a function.

O 2 4–2–4 x

2

4

–2

–4

y

a. Domain: all real numbers; range: all real numbers; yes, it is a functionb. Domain: x > 0; range: y > 0; yes, it is a function.c. Domain: positive integers; range: positive integers; no, it is not a function.d. Domain: x ≥ 0; range: y ≤ 0; no, it is not a function.

____ 39. Use the vertical-line test to determine which graph represents a function.

a.

O 2 4–2–4 x

2

4

–2

–4

yc.

O 2 4–2–4 x

2

4

–2

–4

y

b.

O 2 4–2–4 x

2

4

–2

–4

yd.

O 2 4–2–4 x

2

4

–2

–4

y

Name: ________________________ ID: A

9

____ 40. For f x( ) = 5x + 1, find f −4( ).a. –19 b. 1 c. –21 d. 21

____ 41. Suppose f x( ) = 4x − 2 and g x( ) = −2x + 1.

Find the value of f 5( )

g −3( ).

a. 15

9b. 2

4

7c. −2 d. 2

Graph the absolute value equation.

____ 42. y = x + 4| |a.

O 4 8–4–8 x

4

8

12

16

–4

yc.

O 4 8–4–8 x

4

8

–4

–8

–12

y

b.

O 4 8–4–8 x

4

8

12

16

–4

yd.

O 4 8–4–8 x

4

8

12

16

–4

y

Name: ________________________ ID: A

10

____ 43. y = − 2x + 3| |a.

O 4 8–4–8 x

4

–4

–8

–12

–16

yc.

O 4 8–4–8 x

4

–4

–8

–12

y

b.

O 4 8–4–8 x

4

8

12

–4

–8

yd.

O 4 8–4–8 x

4

–4

–8

–12

–16

y

____ 44. What is the vertex of the function y = − 3x + 2| | − 4?

a. (−2

3, –4) b. (

2

3, –4) c. (

2

3, 4) d. (−

2

3, 4)

Name: ________________________ ID: A

11

____ 45. The graph models a train’s distance from a river as the train travels at a constant speed. Which equation best represents the relation?

RiverHours Before River Hours After River

Mile

s F

rom

Riv

er

2 4–2–4

20

40

60

80

100

a. y = x| | + 60 b. y = x + 60| | c. y = 60x| | d. y =1

60x

||||

||||

____ 46. Write the equation for the translation of y = x| |.

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

a. y = x + 4| | b. y = x| | + 4 c. y = x| | − 4 d. y = x − 4| |

Name: ________________________ ID: A

12

____ 47. Graph the equation of y = |x| translated 4 units up.a.

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

yc.

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

b.

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

yd.

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

____ 48. Compare the graphs of the pair of functions. Describe how the graph of the second function relates to the graph of the first function.y = −2 x| | and y = −2 x| | − 3a. The second function is the graph of y = −2 x| | moved to the right 3 units.b. The second function is the graph of y = −2 x| | moved up 3 units.c. The second function is the graph of y = −2 x| | moved to the left 3 units.d. The second function is the graph of y = −2 x| | moved down 3 units.

Write an equation for the vertical translation.

____ 49. y = −2

9x| | − 7; 2 units down

a. y = −29

x| | − 9 c. y = −29

x| | − 2

b. y = −29

x| | − 2 d. y = −29

x| | + 9

Name: ________________________ ID: A

13

____ 50. Write an equation for the horizontal translation of y = x| |.

O 4 8–4–8 x

4

8

–4

–8

y

a. y = x + 4| | b. y = x − 4| | c. y = − x + 4| | d. y = − x − 4| |

Name: ________________________ ID: A

14

____ 51. The equation y = − x + 5| | describes a function that is translated from a parent function.a. Write the equation of the parent function. b. Find the number of units and the direction of translation.c. Sketch the graphs of the two functions.

a. y = x| |; 5 units right;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

yc. y = x| |; 5 units left;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

b. y = − x| |; 5 units right;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

yd. y = − x| |; 5 units left;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

____ 52. Write the equation that is the translation of y = x| | left 1 unit and up 2 units.a. y = x − 2| | − 1 c. y = x − 1| | + 2b. y = x + 1| | + 2 d. y = x + 2| | − 1

Name: ________________________ ID: A

15

____ 53. Graph the function y = x − 5| | − 4.a.

O 3 6–3–6 x

3

6

–3

–6

yc.

O 3 6–3–6 x

3

6

–3

–6

y

b.

O 3 6–3–6 x

3

6

–3

–6

yd.

O 3 6–3–6 x

3

6

–3

–6

y

Name: ________________________ ID: A

16

____ 54. Describe the relationship between the graph of y = x + 3| | − 4 and the graph of y = x| | in terms of a vertical and a horizontal translation. Then graph y = x + 3| | − 4.a. 3 units left and 4 units down;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

yc. 3 units up and 4 units right;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

b. 3 units right and 4 units down;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

yd. 3 units down and 4 units left;

O 2 4 6–2–4–6 x

2

4

6

–2

–4

–6

y

Name: ________________________ ID: A

17

Graph the absolute value inequality.

____ 55. y < |x + 2| – 2a.

O 3 6–3–6 x

3

6

–3

–6

yc.

O 3 6–3–6 x

3

6

–3

–6

y

b.

O 3 6–3–6 x

3

6

–3

–6

yd.

O 3 6–3–6 x

3

6

–3

–6

y

Name: ________________________ ID: A

18

____ 56. y ≥ |x + 3| – 2a.

O 3 6–3–6 x

3

6

–3

–6

yc.

O 3 6–3–6 x

3

6

–3

–6

y

b.

O 3 6–3–6 x

3

6

–3

–6

yd.

O 3 6–3–6 x

3

6

–3

–6

y

Name: ________________________ ID: A

19

____ 57. –|x – 1| > y – 5a.

O 3 6–3–6 x

3

6

–3

–6

yc.

O 3 6–3–6 x

3

6

–3

–6

y

b.

O 3 6–3–6 x

3

6

–3

–6

yd.

O 3 6–3–6 x

3

6

–3

–6

y

Name: ________________________ ID: A

20

Write an inequality for the graph.

____ 58.

O 3 6–3–6 x

3

6

–3

–6

y

a. y ≤ |x + 3| – 1 c. y ≤ |x – 3| – 1b. y ≤ |x – 3| + 1 d. y ≥ |x – 3| – 1

Other

59. What is the maximum number of 3.5-to-5-min songs that can fill a 120-min CD? What is the minimum number? Write your answer as a compound inequality. Explain your reasoning.

ID: A

1

alg 2 spring2013 review 1Answer Section

MULTIPLE CHOICE

1. ANS: A DIF: L1 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.1 Evaluating Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 1 KEY: algebraic expression,order of operationsMSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

2. ANS: B DIF: L2 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.1 Evaluating Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 1 KEY: algebraic expression,order of operationsMSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

3. ANS: D DIF: L3 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.1 Evaluating Algebraic Expressions STO: NC 1.03KEY: absolute value MSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

4. ANS: B DIF: L1 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.1 Evaluating Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 2 KEY: algebraic expression MSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

5. ANS: B DIF: L1 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.1 Evaluating Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 3 KEY: algebraic expression,word problem,problem solvingMSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

6. ANS: B DIF: L1 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.2 Simplifying Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 4 KEY: like terms,combine like terms,algebraic expressionMSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

7. ANS: A DIF: L2 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.2 Simplifying Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 4 KEY: like terms,combine like terms,algebraic expressionMSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

ID: A

2

8. ANS: C DIF: L1 REF: 1-2 Algebraic ExpressionsOBJ: 1-2.2 Simplifying Algebraic Expressions STO: NC 1.03TOP: 1-2 Example 5 KEY: perimeter,like terms,algebraic expressionMSC: NAEP A3b, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.11, TV.LV21/22.12, TV.LV21/22.52, TV.LVALG.53

9. ANS: D DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 1KEY: solve an equation MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

10. ANS: C DIF: L2 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 1KEY: solve an equation MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

11. ANS: B DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 2KEY: solve an equation,Distributive Property MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

12. ANS: D DIF: L2 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 2KEY: solve an equation,Distributive Property MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

13. ANS: D DIF: L1 REF: 1-5 Absolute Value Equations and InequalitiesOBJ: 1-5.1 Absolute Value Equations STO: NC 2.08 TOP: 1-5 Example 1KEY: absolute value MSC: NAEP N1g, NAEP A4c, CAT5.LV21/22.50, CAT5.LV21/22.55, IT.LV17/18.AM, IT.LV17/18.CP, S9.TSK3.GM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

14. ANS: B DIF: L1 REF: 1-5 Absolute Value Equations and InequalitiesOBJ: 1-5.1 Absolute Value Equations STO: NC 2.08 TOP: 1-5 Example 2KEY: absolute value MSC: NAEP N1g, NAEP A4c, CAT5.LV21/22.50, CAT5.LV21/22.55, IT.LV17/18.AM, IT.LV17/18.CP, S9.TSK3.GM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

15. ANS: D DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 3KEY: solve an equation,transforming a formula MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

ID: A

3

16. ANS: D DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 3KEY: solve an equation,transforming a formula MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

17. ANS: A DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 KEY: solve an equation,transforming a formula,multi-part question,word problemMSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

18. ANS: D DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.1 Solving Equations STO: NC 1.03 TOP: 1-3 Example 4KEY: solve an equation,restrictions on a variable MSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

19. ANS: A DIF: L1 REF: 1-3 Solving EquationsOBJ: 1-3.2 Writing Equations to Solve Problems STO: NC 1.03TOP: 1-3 Example 5 KEY: word problem,problem solving,perimeter,rectangleMSC: NAEP A3a, NAEP A4a, CAT5.LV21/22.50, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, IT.LV17/18.PS, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.17, TV.LV21/22.52, TV.LVALG.54

20. ANS: C DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.1 Solving and Graphing Inequalities STO: NC 1.03TOP: 1-4 Example 1 KEY: inequality,graphing MSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54


22. ANS: A DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.1 Solving and Graphing Inequalities STO: NC 1.03TOP: 1-4 Example 1 KEY: inequality,graphing MSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54


ID: A

4

24. ANS: B DIF: L2 REF: 1-4 Solving InequalitiesOBJ: 1-4.1 Solving and Graphing Inequalities STO: NC 1.03TOP: 1-4 Example 1 KEY: inequality,graphing MSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

25. ANS: A DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.1 Solving and Graphing Inequalities STO: NC 1.03TOP: 1-4 Example 2 KEY: inequality,graphing,no solutionsMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

26. ANS: A DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.1 Solving and Graphing Inequalities STO: NC 1.03TOP: 1-4 Example 2 KEY: inequality,graphing MSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

27. ANS: A DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.1 Solving and Graphing Inequalities STO: NC 1.03TOP: 1-4 Example 3 KEY: word problem,problem solving,inequalityMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

28. ANS: D DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.2 Compound Inequalities STO: NC 1.03 TOP: 1-4 Example 4KEY: compound inequality containing AND,graphing,compound inequalityMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

29. ANS: A DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.2 Compound Inequalities STO: NC 1.03 TOP: 1-4 Example 5KEY: compound inequality containing OR,graphing,compound inequalityMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

30. ANS: B DIF: L2 REF: 1-4 Solving InequalitiesOBJ: 1-4.2 Compound Inequalities STO: NC 1.03 TOP: 1-4 Example 4KEY: compound inequality containing AND,compound inequality,graphingMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

31. ANS: C DIF: L1 REF: 1-4 Solving InequalitiesOBJ: 1-4.2 Compound Inequalities STO: NC 1.03 TOP: 1-4 Example 6KEY: compound inequality,word problem,problem solving,perimeter,squareMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

ID: A

5

32. ANS: B DIF: L2 REF: 1-4 Solving InequalitiesOBJ: 1-4.2 Compound Inequalities STO: NC 1.03 TOP: 1-4 Example 6KEY: compound inequality,word problem,problem solving,average,rangeMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

33. ANS: C DIF: L2 REF: 1-5 Absolute Value Equations and InequalitiesOBJ: 1-5.1 Absolute Value Equations STO: NC 2.08 TOP: 1-5 Example 3KEY: absolute value,extraneous solutions MSC: NAEP N1g, NAEP A4c, CAT5.LV21/22.50, CAT5.LV21/22.55, IT.LV17/18.AM, IT.LV17/18.CP, S9.TSK3.GM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

34. ANS: C DIF: L1 REF: 1-5 Absolute Value Equations and InequalitiesOBJ: 1-5.2 Absolute Value Inequalities STO: NC 2.08 TOP: 1-5 Example 4KEY: absolute value,graphing,compound inequality containing OR MSC: NAEP N1g, NAEP A4c, CAT5.LV21/22.50, CAT5.LV21/22.55, IT.LV17/18.AM, IT.LV17/18.CP, S9.TSK3.GM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

35. ANS: B DIF: L2 REF: 1-5 Absolute Value Equations and InequalitiesOBJ: 1-5.2 Absolute Value Inequalities STO: NC 2.08 TOP: 1-5 Example 5KEY: absolute value,compound inequality containing AND MSC: NAEP N1g, NAEP A4c, CAT5.LV21/22.50, CAT5.LV21/22.55, IT.LV17/18.AM, IT.LV17/18.CP, S9.TSK3.GM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

36. ANS: A DIF: L1 REF: 2-1 Relations and FunctionsOBJ: 2-1.1 Graphing Relations STO: NC 2.03a TOP: 2-1 Example 2KEY: ordered pair,domain,range,relation MSC: NAEP A2b, NAEP A2e, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.PRA, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56

37. ANS: A DIF: L2 REF: 2-1 Relations and FunctionsOBJ: 2-1.1 Graphing Relations STO: NC 2.03a TOP: 2-1 Example 2KEY: domain,range,graphing,relation,ordered pair MSC: NAEP A2b, NAEP A2e, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.PRA, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56

38. ANS: B DIF: L2 REF: 2-1 Relations and FunctionsOBJ: 2-1.2 Identifying Functions STO: NC 2.03a TOP: 2-1 Example 5KEY: domain,range,relation MSC: NAEP A2b, NAEP A2e, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.PRA, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56

39. ANS: C DIF: L1 REF: 2-1 Relations and FunctionsOBJ: 2-1.2 Identifying Functions STO: NC 2.03a TOP: 2-1 Example 5KEY: graphing,vertical-line test MSC: NAEP A2b, NAEP A2e, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.PRA, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56

ID: A

6

40. ANS: A DIF: L1 REF: 2-1 Relations and FunctionsOBJ: 2-1.2 Identifying Functions STO: NC 2.03a TOP: 2-1 Example 6KEY: function notation MSC: NAEP A2b, NAEP A2e, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.PRA, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56

41. ANS: B DIF: L2 REF: 2-1 Relations and FunctionsOBJ: 2-1.2 Identifying Functions STO: NC 2.03a TOP: 2-1 Example 6KEY: function notation MSC: NAEP A2b, NAEP A2e, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.PRA, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56

42. ANS: B DIF: L1 REF: 2-5 Absolute Value Functions and GraphsOBJ: 2-5.1 Graphing Absolute Value Functions STO: NC 2.08aTOP: 2-5 Example 1 KEY: absolute value MSC: NAEP A2d, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.52, TV.LVALG.56

43. ANS: D DIF: L1 REF: 2-5 Absolute Value Functions and GraphsOBJ: 2-5.1 Graphing Absolute Value Functions STO: NC 2.08aTOP: 2-5 Example 1 KEY: absolute value MSC: NAEP A2d, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.52, TV.LVALG.56

44. ANS: B DIF: L2 REF: 2-5 Absolute Value Functions and GraphsOBJ: 2-5.1 Graphing Absolute Value Functions STO: NC 2.08aTOP: 2-5 Example 1 KEY: absolute value,vertex MSC: NAEP A2d, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.52, TV.LVALG.56

45. ANS: C DIF: L2 REF: 2-5 Absolute Value Functions and GraphsOBJ: 2-5.1 Graphing Absolute Value Functions STO: NC 2.08aTOP: 2-5 Example 4 KEY: constant speed,relation,absolute valueMSC: NAEP A2d, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.16, TV.LV21/22.52, TV.LVALG.56

46. ANS: B DIF: L1 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.1 Translating Graphs Vertically STO: NC 2.08bTOP: 2-6 Example 3 KEY: horizontal translation,vertical translationMSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

47. ANS: A DIF: L2 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.1 Translating Graphs Vertically STO: NC 2.08bTOP: 2-6 Example 2 KEY: vertical translation MSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

48. ANS: D DIF: L1 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.1 Translating Graphs Vertically STO: NC 2.08bTOP: 2-6 Example 1 KEY: compare,absolute value,vertical translationMSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

ID: A

7

49. ANS: A DIF: L2 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.1 Translating Graphs Vertically STO: NC 2.08bTOP: 2-6 Example 3 KEY: vertical translation MSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

50. ANS: B DIF: L1 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.2 Translating Graphs Horizontally STO: NC 2.08bTOP: 2-6 Example 5 KEY: horizontal translation MSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

51. ANS: D DIF: L1 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.2 Translating Graphs Horizontally STO: NC 2.08bTOP: 2-6 Example 4 KEY: horizontal translation,multi-part questionMSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

52. ANS: B DIF: L1 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.2 Translating Graphs Horizontally STO: NC 2.08bTOP: 2-6 Example 6 KEY: horizontal translation MSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

53. ANS: C DIF: L1 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.2 Translating Graphs Horizontally STO: NC 2.08bTOP: 2-6 Example 7 KEY: horizontal translation MSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

54. ANS: A DIF: L3 REF: 2-6 Vertical and Horizontal TranslationsOBJ: 2-6.2 Translating Graphs Horizontally STO: NC 2.08bTOP: 2-6 Example 8 KEY: translation,horizontal lineMSC: NAEP A2d, CAT5.LV21/22.54, CAT5.LV21/22.56, IT.LV17/18.AM, S9.TSK3.GM, S9.TSK3.PRA, S10.TSK3.GM, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.56, TV.LVALG.58

55. ANS: A DIF: L1 REF: 2-7 Two-Variable InequalitiesOBJ: 2-7.2 Graphing Two-Variable Absolute Value Inequalities STO: NC 2.08a TOP: 2-7 Example 3 KEY: absolute valueMSC: NAEP A4c, NAEP A4d, CAT5.LV21/22.50, CAT5.LV21/22.53, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DI, S9.TSK3.DSP, S9.TSK3.PRA, S10.TSK3.DSP, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.54, TV.LVALG.56

56. ANS: D DIF: L1 REF: 2-7 Two-Variable InequalitiesOBJ: 2-7.2 Graphing Two-Variable Absolute Value Inequalities STO: NC 2.08a TOP: 2-7 Example 3 KEY: absolute valueMSC: NAEP A4c, NAEP A4d, CAT5.LV21/22.50, CAT5.LV21/22.53, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DI, S9.TSK3.DSP, S9.TSK3.PRA, S10.TSK3.DSP, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.54, TV.LVALG.56

ID: A

8

57. ANS: D DIF: L2 REF: 2-7 Two-Variable InequalitiesOBJ: 2-7.2 Graphing Two-Variable Absolute Value Inequalities STO: NC 2.08a TOP: 2-7 Example 3 KEY: absolute valueMSC: NAEP A4c, NAEP A4d, CAT5.LV21/22.50, CAT5.LV21/22.53, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DI, S9.TSK3.DSP, S9.TSK3.PRA, S10.TSK3.DSP, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.54, TV.LVALG.56

58. ANS: C DIF: L1 REF: 2-7 Two-Variable InequalitiesOBJ: 2-7.2 Graphing Two-Variable Absolute Value Inequalities STO: NC 2.08a TOP: 2-7 Example 4 KEY: absolute valueMSC: NAEP A4c, NAEP A4d, CAT5.LV21/22.50, CAT5.LV21/22.53, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DI, S9.TSK3.DSP, S9.TSK3.PRA, S10.TSK3.DSP, S10.TSK3.PRA, TV.LV21/22.12, TV.LV21/22.14, TV.LV21/22.16, TV.LVALG.54, TV.LVALG.56

OTHER

59. ANS: 24 ≤ x ≤ 34; if all of the songs on the CD are the maximum length, 5 minutes long, then the minimum number of songs will fit on the CD. 120 divided by 5 is 24, so the CD can contain a minimum of 24 songs. The shortest possible song is 3.5 minutes. Since 120 divided by 3.5 is approximately 34.29, the CD can contain at most 34 complete songs.

DIF: L2 REF: 1-4 Solving Inequalities OBJ: 1-4.2 Compound InequalitiesSTO: NC 1.03 KEY: compound inequality,reasoning,writing in mathMSC: NAEP A4a, CAT5.LV21/22.45, CAT5.LV21/22.50, CAT5.LV21/22.54, IT.LV17/18.AM, IT.LV17/18.DP, S9.TSK3.NS, S9.TSK3.PRA, S10.TSK3.NS, S10.TSK3.PRA, TV.LV21/22.10, TV.LV21/22.12, TV.LV21/22.16, TV.LVALG.54

alg 2 spring2013 review 1

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