alg 2 sec. 5.1 and 5.2 outline...

5
alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012 Tonight's Homework: Pages 6 9 #19, 23, 27, 33, 37, 44 46, 55, 57 Pages 15 – 17 #9, 11, 17, 27, 29, 37, 39, 51, 53 Sec. 1.1 Graph Quadratic Functions in Standard Form *Graph *Finding the min or max value *Multistep problem Sec. 1.2 Graph Quadratic Functions in Vertex or Intercept Form *Graph *Using a model *Changing the form of the equation Standard Form: f(x) = ax 2 + bx + c Direction: a > 0 _______________ a < 0 _____________ The Axis of Symmetry is The vertex is The yintercept is c. So, the point is (0, c) is on the parabola. Compared to the graph of f(x) = x 2 , a graph is narrower if |a| > 1 and wider i y=x 2 Parent Function: y=2x 2 y= 1 x 2 2 y=x 2 |a| < 1wide |a| > 1narrow |a| = 1same widths: Compare the graphs. (wider, narrower, same) 1) f(x) = Graph, label the vertex, and axis of symmetry.

Transcript of alg 2 sec. 5.1 and 5.2 outline...

Page 1: alg 2 sec. 5.1 and 5.2 outline notes.notebookamhs.ccsdschools.com/UserFiles/Servers/Server_2856713/File/Staff... · alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

 Tonight's Homework:Pages 6 ­9  #19, 23, 27, 33, 37, 44 ­ 46, 55, 57

Pages 15 – 17  #9, 11, 17, 27, 29, 37, 39, 51, 53Sec. 1.1 Graph Quadratic Functions in Standard Form*Graph*Finding the min or max value*Multi­step problem

Sec. 1.2 Graph Quadratic Functions in Vertex or Intercept Form*Graph*Using a model*Changing the form of the equation

Standard Form: f(x) = ax2 + bx + c

Direction: a > 0 _______________ a < 0 ______________

The Axis of Symmetry is  

The vertex is 

The y­intercept is c. So, the point is (0, c) is on the parabola.

Compared to the graph of f(x) = x2 , a graph is narrower if |a| > 1 and wider if |a| < 1

y=x2Parent Function:

y=2x2

y= 1 x2

2

y=­x2

|a| < 1­­­­wide|a| > 1­­­­narrow|a| = 1­­­­same

widths:

Compare the graphs.(wider, narrower, same)

1) f(x) = 

Graph, label the vertex, and axis of symmetry.

Page 2: alg 2 sec. 5.1 and 5.2 outline notes.notebookamhs.ccsdschools.com/UserFiles/Servers/Server_2856713/File/Staff... · alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

2)  6 ­

Vertex Form: f(x) = a(x ­ h)2 + k

The vertex is (h, k).

The axis of symmetry is x = h.

The graph opens up if a > 0 and down if a < 0.

Page 3: alg 2 sec. 5.1 and 5.2 outline notes.notebookamhs.ccsdschools.com/UserFiles/Servers/Server_2856713/File/Staff... · alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

Page 4: alg 2 sec. 5.1 and 5.2 outline notes.notebookamhs.ccsdschools.com/UserFiles/Servers/Server_2856713/File/Staff... · alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

Intercept Form: f(x) = a(x ­ p)(x ­ q)

The x­intercepts are p and q

The axis of symmetry is x = p + q                 2

The graph opens up if a> 0 and opens down if a < 0.

Page 5: alg 2 sec. 5.1 and 5.2 outline notes.notebookamhs.ccsdschools.com/UserFiles/Servers/Server_2856713/File/Staff... · alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

alg 2 sec. 5.1 and 5.2 outline notes.notebook September 25, 2012

The woodland jumping mouse can hop surprisingly long distances given its small size. A relatively long hop can be modeled by

y = ­2 x (x­6) 9

where x and y are measured in feet.

1) How far can a woodland jumping mouse hop?

2) How high can it hop?