Aircraft Structures Plates Reissner-Mindlin Theory · University of Liège Aerospace & Mechanical...

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University of Liège Aerospace & Mechanical Engineering Aircraft Structures Plates Reissner-Mindlin Theory Aircraft Structures - Plates Reissner-Mindlin Theory Ludovic Noels Computational & Multiscale Mechanics of Materials CM3 http://www.ltas-cm3.ulg.ac.be/ Chemin des Chevreuils 1, B4000 Liège [email protected]

Transcript of Aircraft Structures Plates Reissner-Mindlin Theory · University of Liège Aerospace & Mechanical...

Page 1: Aircraft Structures Plates Reissner-Mindlin Theory · University of Liège Aerospace & Mechanical Engineering Aircraft Structures Plates – Reissner-Mindlin Theory Aircraft Structures

University of Liège

Aerospace & Mechanical Engineering

Aircraft Structures

Plates – Reissner-Mindlin Theory

Aircraft Structures - Plates – Reissner-Mindlin Theory

Ludovic Noels

Computational & Multiscale Mechanics of Materials – CM3

http://www.ltas-cm3.ulg.ac.be/

Chemin des Chevreuils 1, B4000 Liège

[email protected]

Page 2: Aircraft Structures Plates Reissner-Mindlin Theory · University of Liège Aerospace & Mechanical Engineering Aircraft Structures Plates – Reissner-Mindlin Theory Aircraft Structures

Elasticity

• Balance of body B – Momenta balance

• Linear

• Angular

– Boundary conditions • Neumann

• Dirichlet

• Small deformations with linear elastic, homogeneous & isotropic material

– (Small) Strain tensor , or

– Hooke’s law , or

with

– Inverse law

with

b

T

n

2m l = K - 2m/3

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• Description

– In the reference frame Ei

• The plate is defined by

with

– Mapping of the plate

• Neutral plane

• Cross section with t0 = E3

• Initial plate S0

– S0 = A x [-h0/2 h0/2], for a plate of initial thickness h0

• Deformed plate S

Plate kinematics

a =1 or 2, I = 1, 2 or 3

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Assumptions

– Small deformations/displacements

• with

– Kirchhoff-Love assumption (no shearing)

• Normal is assumed to remain

– Planar

– Perpendicular to the neutral plane

– Reissner-Mindlin (shearing is allowed)

• Normal is assumed to remain planar

• But not perpendicular to neutral plane

Plate kinematics

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

z

x

g

qy

qy

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• Idea

– Avoiding discretization on the thickness

• u and t constant on the thickness

– Equations are integrated on the thickness

• Linear momentum equation

– Small transformations assumptions ( , , )

• Using

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Linear momentum equation (2)

– Inertial term

• As the main idea in plates is to consider u and t constant on the thickness

– Volume loading term

• With the loading per unit area

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Linear momentum equation (3)

– Stress term

• Gauss theorem

– Where n0 is the normal to the plate

surface (3D volume) in the reference

configuration

– On top/bottom faces n0 = ± E3

– On lateral surface: n0 = na Ea

– Let us define the resultant stresses:

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

∂NA

n

n0 = na Ea E1

E2

E3

A ∂DA

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• Linear momentum equation (4)

– Resultant stresses

• These are two vectors

• Which correspond to the integration of the

surface traction on the thickness

– Symmetric 2x2 matrix +

Out of plane component

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

E1

E2

E3

A

ñ11

ñ22

ñ12

ñ21

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• Linear momentum equation (5)

– From

• Applying Gauss theorem on last term leads to

– Resultant linear momentum equation

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Linear momentum equation (6)

– Defining

• Density per unit area

• Volume loading per unit area

• Resultant loading

– The linear momentum equation

becomes after being integrated on the volume

• Is rewritten in the Cosserat plane A as

• With the resultant stresses

• With the resultant loading

– But we have no equation for bending (yet)

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Angular momentum equation

– Small transformations assumptions ( , , )

• Using

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Angular momentum equation (2)

– Small transformations assumptions (2)

• As second order terms can be neglected

• With

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Angular momentum equation (3)

– Inertial term

• As the main idea in plates is to consider u and t constant on the thickness

– With the density per unit area

– With the mass inertia

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Angular momentum equation (4)

– Loading term

– With the loading per unit area

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Angular momentum equation (5)

– Stress term

• Integration by parts

• Gauss theorem

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

∂NA

n

n0 = na Ea E1

E2

E3

A ∂DA

djl

i

i

i

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as s symmetric

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• Angular momentum equation (6)

– Stress term (2)

– Where n0 is the normal to the plate

surface (3D volume) in the reference

configuration

– On top/bottom faces n0 = ± E3

– On lateral surface: n0 = na Ea

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

∂NA

n

n0 = na Ea E1

E2

E3

A ∂DA

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• Angular momentum equation (7)

– Stress term (3)

• Resultant bending stresses & resultant stresses

– ,

Resultant equilibrium equations

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• Angular momentum equation (8)

– Resultant bending stress

• These are two vectors

• Which correspond to the integration of the

surface couple on the thickness

– Symmetric 2x2 matrix

Resultant equilibrium equations

E1

E2

E3

A

m11 ~ m21 ~

m22 ~

m12 ~

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• Angular momentum equation (9)

– Stress term (4)

• Applying Gauss theorem

Resultant equilibrium equations

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• Angular momentum equation (10)

– From

• It comes

Resultant equilibrium equations

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• Angular momentum equation (11)

– Resultant form

• But the resultant linear momentum equation reads

• So the angular momentum equation reads

Resultant equilibrium equations

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• Angular momentum equation (12)

– Resultant form (2)

• Defining the applied torque

• Term which is preventing from uncoupling the equations is

Resultant equilibrium equations

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• Angular momentum equation (13)

– Term

• Let us rewrite the Cauchy stress tensor in terms of its components

• As Cauchy stress tensor is symmetrical

• Using

• This new equation can be integrated on the thickness

• Defining the out-of-plane resultant stress

Resultant equilibrium equations

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Angular momentum equation (14)

– Resultant form (3)

• If l is an undefined pressure applied through the thickness, the resultant angular

momentum equation reads

• With

Resultant equilibrium equations

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• Resultant equations summary

– Linear momentum

• Resultant stresses

– Angular momentum

• Resultant bending stresses

– Interpretation

Resultant equilibrium equations

x

sXX

x

sXX

x

sXX

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• What is missing is the link between the deformations and the stresses

– Idea: as the discretization does not involve the thickness, the deformations

should be evaluated at neutral plane too

– Works only in linear elasticity

Material law

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• Deformations

– In small deformations, the tensor reads

• But defining

leads to

• A vector can always be written in terms of its components

Material law

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Deformations (2)

– In small deformations, the tensor reads (2)

• Relations on the normal

– By definition

– In small deformations

– Which implies &

• So relation

• Interpretation

– See next slide

Material law

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Deformations (3)

– In small deformations, the tensor reads (2)

• Interpretation

Material law

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

Motion of the neutral plane

in its plane (2D in-plane

problem): membrane

mode

Motion of the neutral plane

out-of-its-plane: bending

mode

Change of the neutral plane

direction resulting from

1) Bending

2) Out-of-plane shearing

z

x

g1 qy = Dtx

-uz,x

qy = Dtx

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• Deformations (4)

– In small deformations, the tensor reads (3)

• From

• As

and as only the last term depends on x3, the gradient reads

• So the deformations tensor reads

Material law

F = j(x1, x2)+x3 t(x1, x2)

E1

E2

E3

x1

x2 A

x2=cst

t S

x1=cst

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• Deformations (5)

– Deformation modes

• Interpretation: membrane mode

– Location in the deformation tensor

– Corresponds to the in-plane

deformations of the neutral plane

Material law

E1

E2

E3

A

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• Deformations (6)

– Deformation modes (2)

• Interpretation: bending mode

– Location in the deformation tensor

– Corresponds to the final

curvature of the neutral plane

Material law

E1

E2

E3

A 1/k11

t

t

1/Dt,1

Dt Dt

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• Deformations (7)

– Deformation modes (3)

• Interpretation: Through-the-thickness shearing

– Location in the deformation tensor

– Corresponds to the average angle between

the neutral plane normal and the direction

vector t (initially the same)

Material law

z

x

g1 qy = Dt1

-uz,1

qy = Dt1

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• Deformations (8)

– Deformation modes (4)

• Interpretation: Through-the-thickness elongation

– In this model there is no through-the-thickness elongation

– Actually the plate is in plane-s state, meaning there is such a deformation

» To be introduced: x3 t should be substituted by lh(x3) t in the shell

kinematics

» We have to introduce it to get the plane-s effect

» In small deformations this term would lead to second order effects on

other components

Material law

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• Deformations (9)

– Final expression

• We had

– With

• And through-the-thickness elongation lh(x3) t

Material law

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• Hooke’s law

– Small strain tensor

– There are 4 contributions

• Membrane mode

– as frame is orthonormal Hijkl = Hijkl (notation abuse)

with

– As the non-zero components are

Material law

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• Hooke’s law (2)

– There are 4 contributions (2)

• Bending mode

with

– As the non-zero components are

Material law

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• Hooke’s law (3)

– There are 4 contributions (3)

• Shearing mode

with

– As

we can deduce the non-zero components – As we did for beams, we have to account for the non-uniformity of g by a shear section reduction

Material law

x

z

Tz

dx

Tz+ ∂xTz dx

gmax

g

g dx

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• Hooke’s law (4)

– There are 4 contributions (4)

• Through-the thickness elongation

with

– We can deduce the non-zero components

Material law

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• Resultant stresses

– Plane-s state

• Contributions

• Elongation depends on x3

– Part is stretched and

part is compressed

– For pure bending the change

of sign is on the neutral axis

• Average trough the thickness elongation

– Depends on the membrane mode only

Material law

x

z

h L y

z

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• Resultant stresses (2)

– Plane s-stated (2)

• Values ab can now be deduced

with

• Can be rewritten as a through-the-thickness constant term and a linear term

– With

• Out-of-plane shearing remains the same

Material law

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• Resultant stresses (3)

– From stress fields

– Membrane resultant stresses

Material law

In plane membrane stress Out-of plane shear stress

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• Resultant stresses (4)

– Membrane resultant stresses (2)

• In plane component: membrane stress

– As is cst with x3

– Defining the membrane Hooke tensor

»

» As

– 2D plane-s problem

Material law

E1

E2

E3

A

ñ11

ñ22

ñ12

ñ21

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• Resultant stresses (5)

– Membrane resultant stresses (3)

• Out-of-plane component: shear stress

– As is cst with x3

– Defining the shearing Hooke tensor

»

» As

– Corresponds to the average

shearing of a beam

Material law

z

x

g1 qy = Dt1

-uz,1

qy = Dt1

q3

q3

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• Resultant stresses (6)

– Out-of-plane resultant stresses

• We defined

– Owing to previous definitions

»

» With

– Corresponds to the shearing

symmetrical to the out-of-plane

shearing

Material law

y

z

A*

x

t

t

b(z)

z

x

g1 qy = Dtx

-uz,x

qy = Dtx

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• Resultant stresses (7)

– From stress fields (2)

– Bending resultant stresses

Material law

Bending stress

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• Resultant stresses (8)

– Bending resultant stresses (2)

– As

– Defining the bending Hooke tensor

»

» As

– 2D bending problem

Material law

E1

E2

E3

A

1/k11

t

t

Dt Dt

m11 ~ m21 ~

m22 ~

m12 ~

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• Deformations (small transformations)

– In plane membrane

– Curvature

– Out-of-plane sliding

Reissner-Mindlin equations summary

E1

E2

E3

A

E1

E2

E3

A 1/k11

t

t

1/Dt,1

Dt Dt

z

x

g1 qy = Dt1

-uz,1

qy = Dt1

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• Resultant stresses in linear elasticity

– Membrane stress

– Bending stress

– Out-of-plane shear stress

Reissner-Mindlin equations summary

E1

E2

E3

A

ñ11

ñ22

ñ12

ñ21

E1

E2

E3

A

1/k11

t

t

Dt Dt

m11 ~ m21 ~

m22 ~

m12 ~

z

x

g1 qy = Dt1

-uz,1

qy = Dt1

q3

q3

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• Resultant equations

– Membrane mode

– with

– with

• Clearly, the solution can be directly computed in plane Oxy (constant Hn)

– Boundary conditions

» Dirichlet

» Neumann

• Remaining equation along E3:

Reissner-Mindlin equations summary

∂NA

n

n0 = na Ea E1

E2

E3

A ∂DA

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• Resultant equations (2)

– Bending mode

• &

– with

– with

• Solution is obtained by projecting into the plane Oxy (constant Hq, Hm)

– 2 equations (a=1, 2) with 3 unknowns (Dt1, Dt2, u3)

– Use remaining equation

Reissner-Mindlin equations summary

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• Resultant equations (3)

– Bending mode (2)

• 3 equations with 3 unknowns

• To be completed by BCs

– Low order constrains

» Displacement or

» Shearing

– High order

» Rotation or

» Bending

Reissner-Mindlin equations summary

∂NA

T

n0 = na Ea E1

E2

E3

A ∂DA

p

∂MA

M

n0 = na Ea E1

E2

E3

A ∂TA

p

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• Membrane problem

– Similar to 2D elasticity

• Bending problem

– 3 degree of freedom by nodes

– Shear locking

• For reduced thickness (h/L→0) the structure is too stiff

• This results from the fact that for thin thickness u3,a → Dta physically

– Bernoulli assumption for beams

• Then we have extra constrains but no new degree of freedom

• The solution found is then zero deformation

– In order to avoid shear locking

• Different techniques

• High order elements

• Shear strains g evaluated at particular points (assumed strain method)

– These values can be formulated in terms of the displacements/rotations

degrees of freedom

• Internal degrees of freedom (enhanced assumed strain method)

• ….

Finite-element implementation

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References

• Lecture notes

– Aircraft Structures for engineering students, T. H. G. Megson, Butterworth-

Heinemann, An imprint of Elsevier Science, 2003, ISBN 0 340 70588 4

• Other references

– Papers

• Simo JC, Fox DD. On a stress resultant geometrically exact shell model. Part I:

formulation and optimal parametrization. Computer Methods in Applied Mechanics

and Engineering 1989; 72:267–304.

• Simo JC, Fox DD, Rifai MS. On a stress resultant geometrically exact shell model.

Part II: the linear theory, computational aspects. Computer Methods in Applied

Mechanics and Engineering 1989; 73:53–92.

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