AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single...

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AGEC/FNR 406 LECTURE 12
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Transcript of AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single...

Page 1: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

AGEC/FNR 406 LECTURE 12

Page 2: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Static vs. Dynamic Efficiency

Static efficiency is obtained when a single period’s net benefits are maximized.

Dynamic efficiency is obtained when the present values of net benefits are equal for all periods in a multi-period problem.

Dynamic efficiency DOES NOT mean an equal allocation across all periods.

Page 3: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Q

8

4

Example, continued

Q10 10

8

22

4

2. NB = 0.5*(8-4)*10 + 10*(4-2) = 40

1. P = 8 - .4*Q = 4

3. NPV = 40 + 40 /1.05 = 40 + 38 = 78

Page 4: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

8

An alternative approach for a two period model

Step 1: Graph demand in period 1

20 20

8 . 1.05

22

-0.40

Step 2: Modify period 2 demand and graph it BACKWARDS!

-0.40 1.05

Page 5: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

8

Step 3: Overlay the graphs

2020

8 . 1.05

22

-0.40 -0.40 1.05

Page 6: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Efficient allocation

Efficient allocation is where demand curves intersect.

P1 P2

Q1

Q2

10••

=10.12

Page 7: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Important concepts

2020

2 MC = 2 = MEC

Q

P1 P2 MUC = P - MEC

Scarcity rent

Page 8: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Numerical Approach

Step 1: write down NB in each period

NB1 = benefits - costs = (a-(bQ/2))Q - cQ= 8Q1-.2Q1

2 - 2Q1

= 6Q1-.2Q12

NB2 = benefits - costs = (a-(bQ/2))Q - cQ

= 8 Q2 -.2 Q2 2 - 2 Q2

= 6 Q2 -.2 Q2 2

Page 9: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Numerical Approach

Step 2: Get rid of Q2 in NB2

If Q1 + Q2 = Q, then Q2 = Q - Q1 or Q2 = 20 - Q1

so NB2 = 6(20 - Q1)-.2(20 - Q1)(20 - Q1) = 120 - 6 Q1 - 80 + 8 Q1 -.2 Q1 2

= 40 +2 Q1 -.2 Q1 2

Page 10: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Numerical Approach

Step 3: Calculate present value of 2-period benefit

NPV = NB1/(1+r)0 + NB2/(1+r)1

= 6Q1-.2Q12 + (40 +2Q1 -.2Q1

2 )/1.05

= 6Q1-.2Q12 + 38.095 + 1.905*Q1 - 0.1905*Q1

2

= 7.905Q1 - .3905 Q12 + 38.095

Page 11: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Numerical Approach

Step 4: Differentiate to find where NPV reaches max

Max where dNPV/dQ1 = 0

or 7.905 - 0.781Q1 = 0

Q1 = 10.12Q2 = 20 - Q1 = 9.88

P1= 8 - .4*10.12 = 3.95P2 = 8 - .4*9.88 = 4.05

Page 12: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Numerical Approach

NPV = 0.5*(8-P1)*Q1 + (P1 - 2)*Q1

+[ 0.5*(8-P2)*Q2 + (P2 - 2)*Q2 ] /(1+r)

= 0.5*(8- 3.95)*10.12 + (3.95 - 2)*10.12

+[ 0.5*(8-4.05)*9.88 + (4.05-2)*9.88 ] /(1.05)

= 78.10

Page 13: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Key Points

1. Price = MEC + MUC

MUC = 3.95 - 2 = 1.95

2. Under dynamic efficiency Q1 is lower than under static efficiency, and P1 is higher.

3. Under dynamic efficiency P2 is higher than P1 and Q2 is lower than Q1 due to discounting.

Page 14: AGEC/FNR 406 LECTURE 12. Static vs. Dynamic Efficiency Static efficiency is obtained when a single period’s net benefits are maximized. Dynamic efficiency.

Extensions

1. Higher discount rate: allocate more to present.

2. Lower discount rate: allocate more to future

3. With zero discount rate, allocations are equal inboth periods

4. Greater scarcity reduces allocations in both periods.

Without scarcity, MUC = 0