Aerosol Can Explosion Test (caution: graphic material) · Aerosol Can Explosion Test (caution:...

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Aerosol Can Explosion Test (caution: graphic material)

Transcript of Aerosol Can Explosion Test (caution: graphic material) · Aerosol Can Explosion Test (caution:...

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Aerosol Can Explosion Test (caution: graphic material)

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Problem: want to eliminate Halon 1301 from use in aircraft cargo bays

1. Halon 1301 (CF3Br) => high ODP, high GWP.

Compound Atmospheric Lifetime (yrs) ODP GWP100

Halon 1301(CF3Br)

65 12 6,900

HFC-125(CF3CF2H)

29 0 3,400

2-BTP(CH2CBrCF3)

0.008 0 N/A

FK-5-1-12(CF3CF2C(O)CF(CF3)2)

0.014 0 1

H

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PressureTransducer

VideoCamera 1

(Top View)

10 m Pressure Vessel

3

Aerosol Can SimulatorThermocouple

Igniter AgentPort

NitrogenPort

Gas Analyzer Probe

Fan

Problem: want to eliminate Halon 1301 from use in aircraft cargo bays

2. But in one FAA-mandated qualification test, the possible replacements make things worse.

FAA Aerosol Can Simulator

PropaneEthanolWater

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2-BTP

FK 5-1-12

HFC-125

No agent

1301

Goals

Understand the overpressure phenomena in the FAA Aerosol Can Test

1. Why is the overpressure occurring with the added suppressants?

2. What can be done about it?

FAA Aerosol Can Simulator

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Understanding Combustion Promotion by Halogenated Fire Suppressants

INTERNATIONAL AIRCRAFT SYSTEMS FIRE PROTECTION WORKING GROUP MEETING

May 11-12, 2011

National Institute of Standards and TechnologyBuilding and Fire Research Laboratory

Innovative Scientific Solutions Incorporated

Greg Linteris, NIST Fire ResearchJeff Manion / Wing Tsang / Don Burgess, NIST Chemical Kinetics

Harsha Chelliah, Univ. of VirginiaVish Katta, Innovative Scientific Solutions, Inc.Fumi Takahashi, Case Western Reserve Univ.

Oliver Meier, The Boeing Company

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Acknowledgements

Wing Tsang, Don Burgess, NIST

John Reinhardt, Dave Blake FAA Technical Center

Med Colket, Ken Smith, UTRC

The work was supported by The Boeing Company.

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Approach

Droplet evaporation, turbulent pre-mixingArcing ignitor

Partially premixed fuel-rich reactants(PREMIX), or distributed reaction region (PSR).

Air and agent mixture

Fuel discharge port (propane/ethanol/water)

High strain (shear), partially premixed diffusion flame region (OFDF).

Partially premixed diffusion flame with ancillary burning of agent (UNICORN)

Ignition induction period (PFR)

Physics in FAA test is too complicated to examine with detailed kinetics, so simplify.

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Progress

Reviewed previous workThermodynamic Equilibrium CalculationsKinetic Mechanism Development

Measurement of 2-BTP DecompositionPerfectly-Stirred Reactor (PSR) CalculationsDiffusion Flame Calculations (Cup Burner)Homogeneous Auto-Ignition (PFR) CalculationsDiffusion Flame Calculations (Counterflow)Premixed Flame Calculations (PREMIX)

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Background:

Researchers Fuel Agents Experiment Phenomena Explanation

Grosshandler and Gmurczyk

Propane, ethylene CF3I, CF3Br, HFCs Detonation -DeflagratoinTube

Higher Ma,flame speed,pressure ratio

None

Shebeko et al. methane, hydrogen C2HF5, C4F10 Deflagration Higer pressure riseand dP/dt

Added heat release from agent

Moriwaki et al. methane, ethane CH3Cl, CH3I, CH3, Br Shock tube Shorter ignition delay None

Ikeda and Mackie ethane C3HF7 Shock tube Shorter ignition delay None

Mawhinney et al. heptane water mist Heptane pool fi Higher heat release Enhanced fluid-dynamic mixing

Hamins et al hydrocarbons HFCs, water mist, N2, powders Full-scale testsHigher pressure,visual flames

Enhanced fluid-dynamic mixing

Holmstedt et al. propane C3HF7, C2H2F4, CF3Br, Diffusion flame Higher heat release None

Katta et al. methane CF3H Cup burner Higher heat release Agent reaction

Ural none C3HF7, C2H2F4, CHClF2 Flammability tube/chamber

Visual observation Heat loss/gain

Previous findings

~ Of the 65 relevant papers collected and assimilated, these arehighlights (in which enhanced combustion has been discussed):

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Flames go out when:

τchem > τflow

Chemical FlowTime (s) Time (s)

10-1

10-2

10-3

10-4

10-5

10-1

10-2

10-3

10-4

10-5

Background: Flame Extinction

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The flow-field influences the extinction process:

)./exp(/ RTEAccw mO

nFc

−−=≡ ρρτ )./exp(/ RTEAccw mO

nFc

−−=≡ ρρτ

τr = l / vFlow Time:

D ≡ τr /τcChemical Time:

Background: Flame Extinction

-1

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A measure of the overall chemical reaction rate can be obtained with:

Perfectly-Stirred Reactor (PSR) CalculationsDiffusion Flame Calculations (Counterflow)Premixed Flame Calculations

=> Concentrate on R-125

=> Why is it surprising that R-125 did not put out the ACT at 11.3 %

Background: Flame Extinction

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“Suppression of Nonpremixed Flames by Fluorinated Ethanes and Propanes,” E. J. P. Zegers, et al. CNF 121:471-487 (2000)

R-125

fuel

oxidizer

flame

Background: Flame Extinction, Propane-Air with R-125, Counterflow~

jet v

eloc

ity

Cup burner

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R-125

Extinction Strain Rate /s

Age

nt V

olum

e Fr

actio

n

Trees et al. NIST SP-861

Flame Extinction, Heptane-Air with R-125, CounterflowBackground:

~ jet velocity

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To understand why R-125 does not extinguish the FAA ACT, we must understand :

- the fuel reaction chemistry- agent reaction chemistry- mixing- flame characteristics.

Background: Flame Extinction

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Thermodynamic Equilibrium Calculations

What do equilibrium calculations tell us about the general behavior of the system?

To do an equilibrium calculation, one must know the initial reactant mix (fuel, air, agent, water vapor, etc.). We don’t really know them for the ACT, so keep them all as variables, and find the equilibrium conditions for a wide range of initial mixtures.

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HFC-125: Adiabatic Flame Temperature (Taft)

- Taft is high for all η.

- Change in behavior at [X]/[H]=1 (about 7.5 % HFC-125, red curve above).

- With large amounts of agent, a wide range of η gives nearly equivalent Taft.

- As agent is added, more and more chamber volume is necessary to achieve stoichiometric combustion.

- Where flame goes out (Xi=13.5 %), all the chamber volume is involved in combustion (i.e., η=1).

Thermodynamic Equilibrium Calculations

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Taft / KXi

0

Fraction of Chamber Volume Involved in Combustion, η

0.144

0.072

a.)

1000

1500

2000

0 5 10 150.0

0.2

0.4

0.6

0.8

1.0

1.2Taft,max / K

η (T

aft,m

ax )

Inhibitor Volume Fraction in Oxidizer, Xi (%)b.) Inhibitor Volume Fraction in Oxidizer, Xi (%)

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2-BTP: Adiabatic Flame Temperature (Taft)

- Taft is high for all η.

- most of the plot is below [X]/[H]=1 (about 6 % 2-BTP), so can’t see change at [X]/[H]=1 .

- With large amounts of agent, a wide range of η gives equivalent Taft.

- As agent is added, more and more chamber volume is necessary to achieve stoichiometric combustion.

- Where flame goes out (Xi=6 %), all the chamber volume is involved in combustion (i.e., η=1).

Thermodynamic Equilibrium Calculations

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Taft / K

Xi

η

0.06

0.03

0

c.)

1000

1500

2000

0 1 2 3 4 5 60.0

0.2

0.4

0.6

0.8

1.0

1.2Taft,max / K

η (T

aft,m

ax )

X i (%)d.)Fraction of Vessel Air Involved in Combustion, ηInhibitor Volume Fraction in Oxidizer, Xi (%)

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Xi

0

η

0.044

0.025

0.040

Taft / K BTP simulant

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- Taft is high for all η., but decreases somewhat as agent is added.

- most of the plot is below [X]/[H]=1 (about 11 % CF3Br), so can’t see change at [X]/[H]=1 .

- The amount of chamber volume for peak Taft does not change with Xi.

-Why? => CF3Br + 2H2O = 3HF + HBr + CO2 ,

-i.e., there’s always enough H and O in the system to oxidize the CF3Br without more air!

- The Taft is very sensitive to η.

Halon 1301: Adiabatic Flame Temperature (Taft) Thermodynamic Equilibrium Calculations

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Taft / K Xi

η

0.118

0

e.)1000

1500

2000

0 1 2 3 4 5 60.0

0.1

0.2

0.3

0.4

0.5Taft,max / K

η ( T

aft,m

ax )

X I (%)f.)Fraction of Vessel Air Involved in Combustion, η Inhibitor Volume Fraction in Oxidizer, Xi (%)

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Thermodynamic Equilibrium Calculations

What do they tell us about the maximum pressure rise?

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0

1

2

3

4

5

6

0.0 0.2 0.4 0.6 0.8 1.0η

Xi

0

0.144

0.072

Pressure Rise / bar

a.)

HFC-125: Predicted Pressure Rise

- The higher η, the greater ΔP (more reactants, more heat release, more expansion of hot products—since the oxidizer also includes a “fuel” species).

- The actual fraction of chamber volume (oxidizer) which can react has a large influence on ΔP.

- Equilibrium thermodynamics predicts the final pressure quite well.

- Why does the agent not reduce the extent of reaction?

Thermodynamic Equilibrium Calculations

Fraction of Vessel Air Involved in Combustion, η

0

1

2

3

4

5

6

0 5 10 15

Pressure Rise at η {ypeak} / barTmax

CO2

FAA Experiment

Inhibitor Volume Fraction in Oxidizer, X I (%)

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0

1

2

3

4

5

6

7

0 1 2 3 4 5 6

Pressure Rise at η {ypeak} / bar Tmax

CO2

FAA Experiment

X i (%)

0

1

2

3

4

5

6

7

0.0 0.2 0.4 0.6 0.8 1.0η

Xi

0

0.06

0.03

Pressure Rise / bar

c.)

2-BTP: Predicted Pressure Rise

- Same basic behavior as R-125, but greater ΔP.

- The actual fraction of chamber volume (oxidizer) which can react has a large influence on ΔP.

- Equilibrium thermodynamics predicts the final pressure quite well.

- Why does the agent not reduce the extent of reaction?

Thermodynamic Equilibrium Calculations

Fraction of Vessel Air Involved in Combustion, η Inhibitor Volume Fraction in Oxidizer, Xi (%)

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0

1

2

3

4

5

6

7

0 1 2 3 4 5 6

Pressure Rise at η {ypeak} / bar

Tmax

CO2

FAA Experiment

X i (%)f.)0

1

2

3

4

5

6

7

0.0 0.2 0.4 0.6 0.8 1.0η

Pressure Rise / bar

e.)

Halon 1301: Predicted Pressure Rise

- Higher η has very little effect on ΔP.

- At η of peak Taft, or CO2, the ΔP is constant! => can’t use pressure rise to determine η.

- Actual ΔP is always less than predicted. This is due to a chemical kinetic effect, but is it from Br or from reduced temperature (i.e., from mixing-induced dilution)?

=> MUST LOOK AT THE KINETICS TO FIND OUT!

Thermodynamic Equilibrium Calculations

Fraction of Vessel Air Involved in Combustion, η Inhibitor Volume Fraction in Oxidizer, Xi (%)

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- As Xi of agent goes up, ΔP can increase for R-125 and 2-BTP, but not for 1301.

=> MUST LOOK AT THE KINETICS TO FIND OUT WHY!

Halon 1301: Predicted Pressure Rise Thermodynamic Equilibrium Calculations

0

1

2

3

4

5

6

7

0 5 10 15

Pressure Rise at η {ypeak} / bar

X i (%)

Pressure Rise at η {ypeak} / barPressure Rise at η {Taft,peak} / bar

2-BTPR-125

1301

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Kinetic Mechanism Development

CH4-air premixed flame, 0, 4, and 6 % R-125

Currently developing these charts for HFC-125 with propane and ACT.

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Aersol Can Test Mechanism:Species Reactions

C4 hydrocarbon mechanism from Wang 111 784

Ethanol mechanism of Dryer 5 36

HFC mechanism from NIST1,2 51 600

CF3Br mechanism of Babushok (NIST)2 10 122

-------- --------

177 14941 Updated rates from more recent literature, additional rates of fuel radical reaction with R-125.

2 Validation: CH4-air and CH3OH systems (with CHF3 , C2H2F4 , C2HF5, CF3Br, C3HF7):- premixed flame speed, - species profiles in low-pressure premixed flames,- extinction strain rate for counterflow diffusion flames, - cup-burner extinction.

Kinetic Mechanism Development Sub-Mechanisms

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Kinetic Mechanism Development : Measurements of 2-BTP Decomposition

- Can’t do calculations yet for 2-BTP because there’s no mechanism for its initial decomposition.

- Once we have its decomposition to HFC and HBrC fragments, it will feed into the overall NIST HFC mechanism.

- So, we must first estimate/measure/calculate its decomposition => CSTL.

-But! For now, use a 2-BTP simulant:

1 mole CF3Br,

1 mole C2H2,

3 moles N2

(gives the right Taft, and has the right number of molecules).

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ini

ini

hYm

,

,

&

outi

outi

hYm

,

,

&VPTYi

- specified premixed inlet conditions.

- adiabatic (no heat losses), no species reaction at the walls.

- perfectly stirred (outlet conditions are the same as the reactor conditions).

- steady-state operation.

Assumptions:

Perfectly-Stirred Reactor (PSR) Calculations

- Used to estimate the overall chemical reaction rate.

- Performed for R-125, 1301, and 1301 with N2.

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Calculation method

1. We want a measure of τchem2. At the blow-out condition, τchem=τflow3. To find the blow-out condition, calculate Tpsr at decreasing values of the residence

time, τflow, until the time is too short for reaction to occur (Tpsr drops to inlet temperature (blow-out).

From Colket and co-workers, 2010

Perfectly-Stirred Reactor (PSR) Calculations

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- Adding R-125 lowers ωchem for rich mixtures (low η), but raises (then lowers) it for lean mixtures (high η).

−η has a big effect on overall chemical rate at low Xi, less effect at high Xi (follows temperature results).

- i.e., for higher Xi, these curves flatten ( ωchem is insensitive to η for η > 0.4 ).

Perfectly-Stirred Reactor (PSR) Overall Chemical Rate with R-125

1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0

ωpsr / s-1

Fraction of Vessel Air Involved in Combustion, η

Xi

HFC-125

0

0.135

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- Adding 1301 always lowers ωchem (for all η)

- ωchem falls off very steeply with η (for all Xinh; follows temperature results).

Perfectly-Stirred Reactor (PSR) Overall Chemical Rate with 1301

1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0

Fraction of Vessel Air Involved in Combustion, η

Xi

1301ωpsr / s-1

0

0.045

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- Adding 2-BTP simulant lowers or raises ωchem (depending upon η)

- variation of ωchem with η is mild at high Xinh, but strong without agent.

Perfectly-Stirred Reactor (PSR) Overall Chemical Rate with 2-BTP simulant

1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0

Xi (%)

0

Fraction of Chamber Volume Involved in Combustion, η

4

2.5

ωpsr / s-1

4.4

BTP simulant

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1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0

Fraction of Vessel Air Involved in Combustion

XR-125 = 7.5 %

13.5 %

11.2 %

Inhibitor Volume Fraction in Air %

ωpsr / s-1

- Top two curves do not put the flame out; bottom one does.

Perfectly-Stirred Reactor (PSR) Calculations R-125 vs. 1301

Overall Chemical Rate / s-1

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1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0

Fraction of Vessel Air Involved in Combustion

X1301 = 2.2 %

XR-125 = 7.5 %

X1301 = 3.9 %13.5 %

ωpsr / s-1

- For R-125, we can use pressure rise data with equilibrium calculations to estimate η.

- For 1301, can’t use pressure rise, so we don’t really know η.

Perfectly-Stirred Reactor (PSR) Calculations R-125 vs. 1301

Overall Chemical Rate / s-1

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- For R-125, we can use pressure rise data with equilibrium calculations to estimate η (solid dots).

- For 1301, can’t use pressure rise, so we don’t really know η. =>BUT for 1301 ωchem is very sensitive to η.

Perfectly-Stirred Reactor (PSR) Calculations R-125, 2-BTPsim, and 1301

1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0Fraction of Vessel Air Involved in Combustion, η

X1301 = 2.2 %

X1301 = 3.9 %XR-125 = 13.5 %

ωpsr / s-1

Xinh = 0 %

XR-125 = 7.5 %

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- For R-125, or 2-BTP simulant, we can use pressure rise data with equilibrium calculations to estimate η(solid dots).

- For 1301, can’t use pressure rise, so we don’t really know η. =>BUT for 1301 ωchem is very sensitive to η.

Perfectly-Stirred Reactor (PSR) Calculations R-125, 2-BTPsim, and 1301

1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0Fraction of Vessel Air Involved in Combustion

X1301 = 2.2 %

X1301 = 3.9 %XR-125 = 13.5 %

ωpsr / s-1

Xi = 0 %

XR-125 = 7.5 %

XBTPsim = 2.5 %

XBTPsim = 4.8 %

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1. More agent generally reduces wpsr , for all assumed values of η.

2. For the case η=0.47, there is little change in wpsr for the curve for HFC-125 up to 30 %.

3. For HFC-125 (blue curves), the reduction in wpsr with addition of agent is similar regardless of the value of h; i.e., for η=0.33, η=0.47, or η(Taft|peak).

4. The effectiveness of the agent CF3Br is very sensitive to the value of η.

5. For CF3Br to be more effective than HFC-125, η must be greater than about 0.4.

Perfectly-Stirred Reactor (PSR) Calculations R-125 vs. 1301

10

100

1000

10000

0 10

1 0

1 0 0

1 0 0 0

1 0 0 0 0

PSR

Ove

rall

Che

mic

al R

ate

/ s

-1

Inhibitor Volume Fraction / Inhibitor Volume Fraction at Suppression (%)

HFC-125, η= 0.47

1301, η = 0.47

1301, η = 0.33

HFC-125, η(Taft,max)

10050

HFC-125, η= 0.33

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1. More agent generally reduces wpsr , for all assumed values of η.

2. For the case η=0.47, there is little change in wpsr for the curve for HFC-125 up to 30 %, and for the curve for 2-BTP simulant up to 50 %.

3. For HFC-125 (blue curves), the reduction in wpsr with addition of agent is similar regardless of the value of h; i.e., for η=0.33, η=0.47, or η(Taft|peak).

4. The 2-BTP simulant (green curves) is much less effective than HFC-125.

5. The effectiveness of the agents CF3Br and 2-BTP simulant (which differ primarily in the addition of C2H2 to CF3Br in the 2-BTP simulant) are both very sensitive to the value of h, but the influence is in the opposite direction: increasing h reduces the effectiveness of 2-BTP simulant, but increases the effectiveness of CF3Br.

6. For CF3Br to be more effective than HFC-125, η must be greater than about 0.4.

Perfectly-Stirred Reactor (PSR) Calculations R-125 vs. 1301

10

100

1000

10000

0 10

1 0

1 0 0

1 0 0 0

1 0 0 0 0

PS

R C

hem

ical

Rat

e /

s-1

Inhibitor Volume Fraction / Inhibitor Volume Fraction at Suppression

HFC-125, η= 0.47

1301, η = 0.47

1301, η = 0.33

HFC-125, η(Taft,max)

BTPsim η=0.33

BTPsim η=0.47

10050

BTPsim η(Taft,max)

HFC-125, η= 0.33

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Current Understanding

Equilibrium and PSR Calculations Indicate:1. In the FAA ACT with R-125 or 2-BTP, to achieve the observed pressure rise, a large fraction of the chamber volume (with the agent) must be involved in the combustion.

2. Thus, the agents are not inert, but rather, act like poorly-burning fuels.

3. Unlike in other flames, very little kinetic inhibition is occurring with R-125 and 2-BTP; whereas, CF3Br does inhibit the flame, as expected.

4. The amount of chamber volume involved in the combustion, η, appears to be a key parameter controlling the kinetic behavior (i.e., the kinetic inhibition by CF3Br is very sensitive to η, but R-125 is not).

5. Simulations with 2-BTPsimulant imply that the fuel portion of the 2-BTP molecule causes it to be much less effective than CF3Br.

Perfectly-Stirred Reactor (PSR) Calculations

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=> With R-125 or 2-BTP:

- the peak Taft does not drop much with added agent.

- more agent requires higher η.

- at high Xi, Taft is nearly the same regardless of the equivalence ratio.

=> With CF3Br,

- Taft drops off away from stoichiometric.

- η is not changed with added agent.

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Taft / KXi

0

Fraction of Chamber Volume Involved in Combustion, η

0.144

0.072

a.)

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Taft / K

Xi

η

0.06

0.03

0

c.)

1000

1500

2000

0.0 0.2 0.4 0.6 0.8 1.0

Taft / K Xi

η

0.118

0

e.)

R-125 2-BTP CF3Br

Equilibrium Calculations Indicate:

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0

1

2

3

4

5

6

7

0 5 10 15

Pressure Rise at η {ypeak} / bar

X i (%)

Pressure Rise at η {ypeak} / barPressure Rise at η {Taft,peak} / bar

2-BTPR-125

1301

=> With R-125 or 2-BTP, complete reaction of the agent at the equivalence ratio giving peak Taft can predict the pressure rise (except at the extinction point).

=> With CF3Br, adding agent will never increase the pressure rise, even without kinetic inhibition.

Equilibrium Calculations Indicate (pressure rise):

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Perfectly-Stirred Reactor (PSR) Calculations Indicate:

=> With R-125 or 2-BTP simulant, at high Xi, the overall reaction rate is relatively unchanged as equivalence ratio changes.

=> With CF3Br, the overall reaction rate is very sensitive to the equivalence ratio.

1

10

100

1000

10000

0.0 0.2 0.4 0.6 0.8 1.0Fraction of Vessel Air Involved in Combustion

X1301 = 2.2 %

X1301 = 3.9 %XR-125 = 13.5 %

ωpsr / s-1

Xi = 0 %

XR-125 = 7.5 %

XBTPsim = 2.5 %

XBTPsim = 4.8 %

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Key Questions Still to Answer

0. Are the results for 2-BTP itself the same as for 2-BTP simulant?

• Is the amount of involved oxidizer the key feature?

• Does the agent reaction rate affect the strain conditions in the FAA ACT?

• Why are the kinetics with R-125 not slower (i.e., slow enough for

extinguishment)?

• Does Br help slow the kinetics with 2-BTP?

• Is the overpressure due to a pressure enhancement of the agent

flammability?

• Is the inerting concentration required for suppression?

• Is there any way around the undesired results?

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Other Ongoing Work

1. Cup burner flame simulations.

2. Premixed flame simulations.

3. Counterflow diffusion flame simulations.

4. Homogeneous ignition simulations.

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Future Plans

1. - Perform further analysis of simulations in progress to understand reasons for lack of kinetic inhibition with R-125. - Perform 2-D, axi-symmetric, unsteady simulations for a turbulent fuel jet to understand the effects of mixing on the extinction. - Repeat existing calculations at higher pressure.

2. Perform large-scale tests in cooperation with the FAA Technical Center to test our understanding.

3. 2-BTP: - measure and estimate decomposition rate - develop kinetic mechanism- perform calculations- analyze results to understand lack of kinetic effect with 2-BTP

4. Develop a new laboratory-scale experiment to:- validate our understanding (e.g., η, pressure effects), and the mechanisms.- explore range of conditions for which inhibition/enhancement occurs- rapidly screen new agents.

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New Constant-Volume Combustion Device*

*Photo Courtesy of Prof. Li, Purdue

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Questions ?

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Extra Material

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0 00

0 000000 0

00 0 0 0

0 00

000 00

0 00

00 00 0 00

0 00 0

00

0

0 0

1 1

1

11

1 1

1

3

3

3

3

88

8

8 8

12

1212

12

12

18181818

1818

18

1818

18

25

25

25

25

y = 0.0615x2 - 1.6472x + 11.057

0

0.5

1

1.5

2

2.5

3

3.5

4

4.5

5

10 12 14 16 18 20

O2 Mole Fraction in Air / %

CF 3

Br M

ole

Frac

tion

in A

ir / %

Flammable

non-Flammable

Perfectly-Stirred Reactor (PSR) Calculations 1301 with N2

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Kinetic Mechanism Development : Measurements of 2-BTP Decomposition

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Single Pulse Shock Tube

Dump Tank

Sample Tanks

GC Column> C4

GC ColumnC1 - C4

Driver Section

Diaphragm

Driven Gas (Sample)

FID 1 FID 2 MSDData

SamplePort

Splitter

Driver Gas

Valve & Loop Sampling System

Characteristics:

System heated to 100 °C

τ = (500 ± 50) μs (monitored with pressure transducers)Typical shock conditions: 2‐6 bar, 900 – 1250 K 

Advantages of Shock Tube for Gas Kinetic Studies:

Essentially a pulse heater, τ = (500 ± 50) μsNo surface induced chemistry (diffusion slow compared with τ)Use of dilute conditions, radical chain inhibitors, sensitive GC/MS analysis 

isolation of initial processes, observation of multiple channels

Kinetic Mechanism Development : Measurements of 2-BTP Decomposition

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Studies of 2-BTP Decomposition

Bimolecular decomposition induced by reactive radicals (e.g. H atoms):

Initial studies show products indicating displacement and abstraction of Br  as major channels.

But ‐ product spectrum more complex than expected with some as yet unidentified species.

Work in progress to determine mechanism and kinetics.

Unimolecular (initial studies):

HBr elimination from 2‐BTP ca. 100x slower than unfluorinated analog

Initial kinetic studies show some interference from radical induced decomposition (work in progress)

Slow rate suggests importance of radical processes in practical systems 

-1.5-1

-0.50

0.51

1.52

2.53

3.5

8 8.5 9 9.5

log

k(H

Br e

limin

atio

n) s

-1

10000/T K

Kinetics of HBr Elimination

2‐bromopropene

2‐BTP(333‐trifluoro‐2‐bromopropene)

H + 2‐BTP              Products