Advanced Algebra with Trigonometry 4.1 Inverse Functions.
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Transcript of Advanced Algebra with Trigonometry 4.1 Inverse Functions.
Advanced Algebra with Trigonometry
4.1 Inverse Functions
Inverse Concepts
Stand Up Sit Down
Go To Sleep Wake Up
2 Steps Forward, then turn Right
Turn Left, then 2 Steps Backward
Square, Mulitply, then Add
Subtract, Divide, then Square Root
4.1 Inverse Functions
Inverse relation: a mapping of output values back to their original input values
In plain English: switch the x and y!! (x, y) becomes (y, x)!!
Write the inverse relation: {(2, 3), (5, 6), (9, 3)}
Was the original relation a function? What about the inverse?
If both the original relation and the inverse relation are functions, we call the
two functions inverse functions. NOTE: f −1 is read as f inverse.
Two functions f and f −1 are inverses of each other provided that
f (f −1(x)) = x and f −1(f (x)) = x.
ff−1 f−1fx → → f(x) → → x x → → f−1(x) → → x
Example] Let f(x) = x + 2. f -1(x) = x – 2 Let x = 5.
5 → 5 + 2 → 7 7 → 7 – 2 → 5 5 → 5 – 2 → 3 3 → 3 + 2 → 5
{(3, 2), (6, 5), (3, 9)
Yes No . . . 3 repeats
Steps to find inverse: 1. Switch x and y 2. Solve for y
Think of the inverse as “undoing” the original function.
f(x) = 3x + 1 (linear) Think: multiply by 3; then add 1
Write as y =; then switch x and y.y = 3x + 1
x = 3y + 1 Now, solve for y.
3y + 1 = x This step just makes it easier on the eye.
3y = x – 1
31x
y
Think: subtract 1; then divide by 3.
1 1( )
3
xf x
Rename y as f –1(x)
Check both function compositions to insure we found the correct inverse!!
f(f –1(x)) = f = 3 + 1
31x
31x
= x – 1 + 1
= x
(f –1(f(x)) = f –1(3x + 1) =3
11x3
= 3x3
= x
f(x) = 3x + 11 1( )
3
xf x
f(x) = x2 + 2, x ≥ 0 (Note the domain restriction: we are only interested in the right side of the parabola.)
f−1(x) =
y = x2 + 2
x = y2 + 2Switch x and y.
y2 + 2 = x Easier on the eye.
y2 = x − 2
Solve for y.
y = 2x
2x Because the original domain was restricted to non-zero reals, you are only interested in the positive portion of the solution.
Check both function compositions to insure we found the correct inverse!!
f(f –1(x)) = f = 2x 22x2
= x – 2 + 2
= x
(f –1(f(x)) = f –1(x2 + 2) = 22x2
= 2x
= x
f(x) = x2 + 2, x ≥ 0 2x f−1(x) =
Try this example: f(x) 3x2
1
y 3x2
1
x 3y21
x3y21
3xy21
)3x(2y
Quick check:
Let x = 8 f(x) = 7
f –1(7) = 8
1( ) 2( 3)f x x
Try this example: f(x) = x3 + 5
y = x3 + 5
x = y3 + 5
y3 = x – 5
3 5xy
y3 + 5 = x
Quick check:
f(2) = 13
f –1 (13) = 2
31 5 xf
Is the graph a function??? Use the Vertical Line Test!!!
Is the graph’s inverse a function??? Use the Horizontal Line Test!!!
OOPS!!
The graph’s inverse is NOT a function.
Remember: The graphs of inverses are reflections of each other in the line y = x.
f(x)= x2
f -1(x)
Some people can just visualize what an inverse graph looks like using the definition. Others of us need a little assistance.
My secret: On the original graph, pick two or three easily identified points.Write them down.Switch the x and y coordinates!!!Plot the new points to give you a start on drawing the inverse.Graph the line y = x.The inverse graph will be symmetric about the line y = x.
Consider the function shown in the graph:
Then I would plot (−1, −2), (0, 0), and (3, 2).Now it is easier to sketch the inverse!!
I would write down the coordinates of the three points indicated:(−2, −1), (0, 0), and (2, 3).
f(x)
f -1(x)
Review: To find the inverse of a relation or function:
To test if two relations are functions:
Don’t forget about any domain restrictions!
Switch x and y.Solve for y.
Use Composition to verify that f(g(x)) equals x and g(f(x)) equals x