Activity Networks Example 2

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    Activity networks Example 2

    Task Duration (days) Immediate

    predecessors

    A 2 -

    B 3 -

    C 5 -

    D 6 A, B

    E 8 C

    F 2 C

    G 4 D, E

    The table below shows the tasks involved in a project,

    with their durations and immediate predecessors.

    Draw an activity network and use it to find the critical

    activities and the minimum duration of the project.

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    Activity networks Example 2

    Begin with a start node,

    labelled 1.

    Activities A, B and C have no

    preceding activities, so can

    all begin at the start node.

    A(2)

    B(3)1

    C(5)

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    Activity networks Example 2

    Activity D depends on both A

    and B. Since A and B must

    not start and finish at the

    same node, a dummy activity

    is needed to ensure unique

    numbering.

    The dummy activity has

    zero duration. Now

    activity D can be drawn

    in, following on from both

    A and B.

    A(2)

    B(3)1

    D(6)

    2

    3

    C(5)

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    Activities E and F both

    depend on activity C.

    A(2)

    B(3)1

    D(6)

    2

    3

    C(5)

    4

    E(8)

    F(2)

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    E(8)

    Activity networks Example 2

    Since G depends on both D

    and E, these two activities

    must both lead into the

    same node.

    Activity G can now be

    drawn in.

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    5

    C(5)

    4

    E(8)

    F(2)

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    Finally, activities F and G

    must finish at the end node.

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    5 6

    E(8)

    F(2)

    C(5)

    4

    F(2)

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    The next step is to find the

    earliest event times (EETs).

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

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    Event 1 occurs at time zero.

    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    The earliest that event 2 can

    occur is after A has finished, at

    time 2.

    0

    2

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    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    Event 3 cannot occur until

    both A and B have finished,

    so the earliest time at which

    event 3 can occur is 3.

    3

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    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    Event 4 cannot occur until C

    has finished, so the earliest

    time at which event 5 can

    occur is 5.

    5

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    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5The earliest that D can finish

    is at time 9, and the earliest

    that E can finish is at time

    13, so the earliest that event

    5 can occur is time 13.

    13

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    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    The earliest that F can finish

    is at time 7, and the earliest

    that G can finish is at time

    17, so the earliest that event

    5 can occur is time 17.

    17

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    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17

    The next step is to find the

    latest event times (LETs),

    starting from the finish node

    and working backwards.

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    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17

    Event 6 must not occur later

    than time 17, or the project

    will be delayed .

    17

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    The latest G can start is at

    time 13, so the latest time

    for event 5 is 13.

    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

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    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

    The latest that E can start is

    at time 5, and the latest that

    F can start is at time 15, so

    the latest possible time for

    event 4 is 5.

    5

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    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

    5The latest that D can start is

    at time 7, so the latest

    possible time for event 3 is 7.

    7

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    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

    5

    7

    The latest that the dummy

    activity (with zero duration)

    can start is at time 7, so the

    latest possible time for event

    2 is 7.

    7

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    Activity networks Example 2

    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

    5

    7

    7

    The latest that event 1 can

    start is at time 0.

    0

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    A(2)

    B(3)1

    D(6)

    2

    3G(4)

    C(5) E(8)

    4

    5 6

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

    5

    7

    7

    0

    The critical activities are

    activities for which the float is

    zero: i.e. the latest event time

    for activity j the earliest

    event time for activity i is equal

    to the activity duration.

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    Activity networks Example 2

    A(2)

    B(3)

    D(6)

    2

    3G(4)

    C(5) E(8)

    F(2)

    0

    2

    3

    5

    13

    17 17

    13

    5

    7

    7

    0

    The critical activities are

    C, E and G.

    The project can be

    completed in 17 days.

    For analysis of the float in this

    example, see Example 2 in the

    Notes and Examples.

    65

    4

    1

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