Acids and Bases
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Acids and Bases
Definitions • Arrhenius– Acid is an H+ donor– Base is an OH- donor
• Bronsted-Lowrey– Acid is an H+ donor– Base is an H+ receptor
• Lewis– Acid is an electron pair acceptor– Base is an electron pair donor
pH
• Measures acidity• = -log [H+]• 7 is neutral• Below 7 is acid, above 7 is base• Close to 7 is weaker, farther away from 7 is
stronger• [H+] = inv log (-pH)• pH + pOH = 14
Common names
• Vinegar Acetic acid• Battery acid Sulfuric acid• Muriatic acid HCl• Stomach acid HCl• Aqua regia HCl + HNO3
• Aspirin Acetylsalicylic acid
Normality
• Equivalents / Liter of solution• Typically, M x subscript of H or OH = N• Need to use normality in titration equation
Acid strength
• Refers to percent dissociation• Measured by Ka
Classification
• Oxy acids– H + an oxygen containing polyatomic anion
• Binary acids– H + a monoatomic anion– OR– H+ a non oxygenated polyatomic anion (ie, CN-)
Oxy acids
• To name:– Name the associated polyatomic anion– Replace –ate with –ic acid– Replace –ite with –ous acid
• To write the formula– Replace the –ic with -ate and write the polyatomic
anion OR– Replace the –ous with –ite and write the polyatomic
anion– Balance your charge out with hydrogen
Examples
• HNO3
• H2SO4
• H2CO3
• HNO2
• H3PO4
• H2CrO4
• H2Cr2O7
Binary acids: no oxygen
• To name:– Prefix is hydro– Name anion with –ic acid ending
• To write the formula:– Write the H– Write the anion formula or symbol– Balance you charge with the subscripts if
necessary
Examples
• HCl• HF• H2S
• HCN• HI
Give names or formulas
• HNO3
• HCl• H2SO4
• Carbonic acid• Nitrous acid• Chromic acid• Hydrocyanic acid
Answers
• HNO3 Nitric acid
• HCl Hydrochloric acid• H2SO4 Sulfuric acid
• Carbonic acid H2CO3
• Nitrous acid HNO2
• Chromic acid H2CrO4
• Hydrocyanic acid HCN
pOH and pH
• pH + pOH always equals 14• This is because the autoionization of water
results in a H+ of 1x10-7 and an OH- of 1x10-7
• Example: if the pH = 7.5, what is the pOH?
Answer
• If the pH = 7.5, what is the pOH?
pH + pOH = 147.5 + pOH = 14pOH = 14-7.5
pOH = 6.5
Neutralization
HCl + NaOH NaCl + HOHYou take the H from the acid and combine it
with the OH from the base. That makes water. What’s left is called a salt.
Titration
• NA X VA = NB X VB
Sample problem
• How many mL of 2.0 N HCl are required to neutralize 30 mL of 3.7 N NaOH?
• NA X VA = NB X VB
• (2.0N)(VA) = (3.7N)(30mL)
• Divide both sides by 2.0N• VA = 55.5mL