Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and...

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Acid-Base Acid-Base Equilibria Equilibria Chapter 16 Chapter 16
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Transcript of Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and...

Page 1: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Acid-BaseAcid-BaseEquilibriaEquilibria

Chapter 16Chapter 16

Page 2: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

HA (aq) + H2O (l) H3O+ (aq) + A- (aq)

Weak Acids (HA) and Acid Ionization Constants

HA (aq) H+ (aq) + A- (aq)

Ka =[H+][A-][HA]

Ka ≡ acid dissociation (ionization) constant

Kaweak acidstrength

Page 3: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Calculations with Weak Acids

• Calculate Ka from pH (Use ICE table)

• Calculate pH from Ka and given concentration (ICE table)

• Calculate percent ionization =Concentration ionized

Original concentrationx 100%

Page 4: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

What is the pH of a 0.50 M HF solution (at 25°C)?

HF (aq) H+ (aq) + F- (aq) Ka =[H+][F-][HF]

= 6.8 x 10-4

HF (aq) H+ (aq) + F- (aq)

Initial (M)

Change (M)

Equilibrium (M)

0.50 0.00

-x +x

0.50 - x

0.00

+x

x x

Ka =x2

0.50 - x= 6.8 x 10-4

Ka x2

0.50= 6.8 x 10-4

0.50 – x 0.50If [HF] > 100 Ka

x2 = 3.40 x 10-4 x = 0.018 M

[H+] = [F-] = 0.018 M pH = -log [H+] = 1.72

[HF] = 0.50 – x = 0.48 M

Page 5: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

When can I use the approximation?

Then 0.50 – x 0.50

x = 0.0180.018 M0.50 M

x 100% = 3.6%Less than 5%

Approximation ok.

What is the pH of a 0.05 M HF solution (at 25°C)?

Ka x2

0.05= 6.8 x 10-4 x = 0.006 M

0.006 M0.05 M

x 100% = 12%More than 5%

Approximation not ok.

Must solve for x exactly using quadratic equation...

Let’s determine error introduced:

If [HF] > 100 Ka

Page 6: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

What is the pH of a 0.122 M monoprotic acid whose Ka is 5.7 x 10-3?

HA (aq) H+ (aq) + A- (aq)

Initial (M)

Change (M)

Equilibrium (M)

0.122 0.00

-x +x

0.122 - x

0.00

+x

x x

Ka =x2

0.122 - x= 5.7 x 10-3

NO!!

Approximation not ok.

Is [HF] > 100 Ka ?

Page 7: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Ka =x2

0.122 - x= 5.7 x 10-3 x2 + 5.7 X 10-3 x – 6.95 X 10-4 = 0

ax2 + bx + c =0-b ± b2 – 4ac

2ax =

x = 0.0237 x = - 0.0294

HA (aq) H+ (aq) + A- (aq)

Initial (M)

Change (M)

Equilibrium (M)

0.122 0.00

-x +x

0.122 - x

0.00

+x

x x

[H+] = x = 0.0237 M pH = -log[H+] = 1.625

Page 8: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Percent ionization =

For a monoprotic acid HA:

Percent ionization = [H+]

[HA]0

x 100% [HA]0 = initial concentration

Concentration ionized

Original concentrationx 100%

Fig 16.9The more dilute the acid,the greater the percent

ionization:

Page 9: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Polyprotic AcidsHave more than one ionizable proton

If difference between the Ka1 and subsequent Ka values > 103, the pH generally depends only on the first dissociation.

Page 10: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

NH3 (aq) + H2O (l) NH4+ (aq) + OH- (aq)

Weak Bases and Base Ionization Constants

Kb =[NH4

+][OH-][NH3]

Kb ≡ base ionization constant

Kb

weak basestrength

Solve weak base problems like weak acidexcept solve for [OHˉ] instead of [H+].

Page 11: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

What is the pH of a 0.15 M solution of NH3 whose Kb is 1.8 x 10-5?

In class exercise

Ans. = 11.20

Page 12: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Table 16.4 Some Weak Bases and Aqueous Soln Equilibria

Page 13: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Relationship Between Ka and Kb

HA (aq) H+ (aq) + A- (aq)

A- (aq) + H2O (l) OH- (aq) + HA (aq)

Ka

Kb

H2O (l) H+ (aq) + OH- (aq) Kw

KaKb = Kw

Weak Acid and Its Conjugate Base

Ka = Kw

Kb

Kb = Kw

Ka

Page 14: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Let’s say we need Kb for the acetate ion, CH3COOˉ.

CH3COOˉ + H2O ⇌ CH3COOH + OHˉ

From a Table of Ionization Constants of Some Weak Acids:

Acetic acid CH3COOH Ka = 1.8 X 10ˉ5

Kb = Kw

Ka

105

14

10 X 5.610 X 1.810 X 1.0

Page 15: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Table 16.5 Some Conjugate Acid-Base Pairs

Page 16: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Acid-Base Properties of Salt SolutionsNeutral Solutions:

Salts derived from a strong acid and a strong base

NaCl (s) Na+ (aq) + Cl- (aq)H2O

Basic Solutions:

Salts derived from a strong base and a weak acid.

NaCH3COOH (s) Na+ (aq) + CH3COO- (aq)H2O

CH3COO- (aq) + H2O (l) CH3COOH (aq) + OH- (aq)

Hydrolysis ≡ the reaction of an anion or a cation of a salt

with water

Page 17: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Acid-Base Properties of Salt Solutions

Acid Solutions:

1) Salts derived from a strong acid and a weak base.

NH4Cl (s) NH4+ (aq) + Cl- (aq)

H2O

NH4+ (aq) NH3 (aq) + H+ (aq)

2) Salts with small, highly charged metal cations (e.g. Al3+, Cr3+, and Be2+) and the conjugate base of a strong acid:

Al(H2O)6 (aq) Al(OH)(H2O)5 (aq) + H+ (aq)3+ 2+

Page 18: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Acid Hydrolysis of Al3+

Page 19: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Acid-Base Properties of Salts

Solutions in which both the cation and the anion hydrolyze:

• Kb for the anion > Ka for the cation, solution will be basic

• Kb for the anion < Ka for the cation, solution will be acidic

• Kb for the anion Ka for the cation, solution will be neutral

Page 20: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Factors Affecting Acid Strength

Fig 16.12 Trends in acid-base properties of binary hydrides

Page 21: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Factors Affecting Acid Strength

Page 22: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Arrhenius acid - a substance that produces H+ (H3O+) in water

Brønsted acid - a proton donor

Lewis acid - a substance that can accept a pair of electrons

Lewis base - a substance that can donate a pair of electrons

Definition of An Acid

H+ H O H••••

+ OH-••••••

acid base

N H••

H

H

H+ +

acid base

N H

H

H

H+

Page 23: Acid-Base Equilibria Chapter 16. HA (aq) + H 2 O (l) H 3 O + (aq) + A - (aq) Weak Acids (HA) and Acid Ionization Constants HA (aq) H + (aq) + A - (aq)

Lewis Acids and Bases

N H••

H

H

acid base

F B

F

F

+ F B

F

F

N H

H

H

No protons donated or accepted!

Coordinate covalent bond