· Abstract -4rithmetic rings in commutative algebra are Kru11 and Prüfer rings and therefore...
Transcript of · Abstract -4rithmetic rings in commutative algebra are Kru11 and Prüfer rings and therefore...
University of Albert a
Bezout Orders and Kru11 Rings
Enver Osmanagic O
A thesis submitted to the Faculty of Graduate Studies and Research in partial
fulfillrnent of the requirements for the degree of Doctor of Philosophy
Mat hematics.
Department of Mathematical Sciences
Edmonton, Alberta
Fa11 2000
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Abstract
-4rithmetic rings in commutative algebra are Kru11 and Prüfer rings and therefore
include principal ideal rings, Dedekind, valuation and unique factorization rings. The
main tool in the study of arithmetic rings is an appropriate valuation theory. For
commutative domains, it is the theory of valuations on fields initiated by Krull in
1932. The most successful valuation theory for commutative rings with zero divisors is
t he theory introduced by M. E. Manis in 1967. In the non-commutativecase, Schilling
valuations tvere used to determine the Brauer group over local fields and Dubrovin
valuation rings, introduced in 1984, do not only have a rich extension theory, but are
very useful in the investigation of Bezout orders in simple artinian rings. This thesis
concentrates on the s t udy of the ideal structure of non-commutat ive vduation rings
and commutative Krull rings tvith zero divisors.
We first consider the structure of prime ideals of a Dubrovin valuation ring. -4
prime ideal P of a Dubrovin valuation ring R in a simple artinian ring Q is called
Goldie prime if R / P is a prime Goldie ring. We show that in the special case &en
R is a total valuation ring, Goldie prime ideals are exactly completely prime ideals.
Then we proceed to show that any intersection and union of Goldie prime ideals is
again Goldie prime, any idempotent proper ideal is Goldie prime and the intersection
of al1 powers of any proper ideal is Goldie prime. Using these results we show that
in the case of a rank one Dubrovin valuation ring R, the set D(R) of al1 divisorial
ideals of R is a group, order isomorphic to a subgroup of ( E t 7 +).
Next, we show that there exists a complete analogy between the structure of ideals
of a cone in a right-ordered group and the structure of ideals of a Dubrovin valuation
ring. In the r a d one czse, this structure is described completely. Also, show that
for a discrete Dubrovin voluation ring R, the Jacobson radical J ( R ) is principal as
a right R-ideal, D(R) = ( J ( R ) ) and g(R)" = (0).
Finally, we consider an application of the valuation theory in the study of com-
mutative and non-commutative arithmetic rings. If R is a commutative Krull domain
with the quotient field K, R # K, then for any h i t e set {ve,, vyn, - . - , wpn} of es-
sential valuations of the ring R and any set {ml, rn2, . . . , m,) of integers, t here exists
an element x E K such that vlri (x) = m; for all i E {1,2, . . . , n) and v V < x ) 2 O for
all other essential valuations up of R. We prove aa analogous approximation theo-
rem for KrulI rings with zero divisors. This result allows us to characterize divisorial
fractional ideals of an additively regular Krull ring.
To rny parents
To my wife Slavinka and my daughters
Tanja and Maja for their love, patience and understanding
Acknowledgement s
With deep pleasure, 1 want to express my gratitude to my supervisor Professor Ham
Brungs for his very stimulating supervision during my studies a t the University of
Alberta. His experience and broad knowledge of mathematics has aided me a great
deal in accomplishing this task. 1 am indebted to him for the time he h a . spent
introducing me to this subject, for listening and discussing my presentations, and for
his writ ten comments, suggestions and encouragement.
My sincere thanks also go to Professor Sudarshan Sehgal for his constant interest
in my progress, for his support and for the courses in Ring Theory he has taught me.
1 also thank al1 my other professors from the Department, for their effort in providing
an excellent research environment, and al1 members of my examination committee for
their consideration. 1 am also grateful to the External Examiner: Professor Günter
Krause for his comrnents and suggestions on this thesis.
My thanks go to Marion Benedict for her warm welcome, kindness, and willingness
to help.
Finally, 1 would like to express my appreciation and gratitude to my professors,
Veselin Peric and Jusuf Alajbegovic, not only for the time they had spent teaching
me algebra at the University of Sarajevo, but also for their friendship over the years.
Contents
Introduction 1
1 Preliminaries 5
1.1 EIementary properties of orders . . . . . . . . . . . . . . . . . . . . . 5
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.2 Valuation rings 13
. . . . . . . . . . . . . . . . . . . 1.3 Cones in groups and c h a h domains 17
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1.4 Eramples 20
2 Bezout Orders in a Simple Artinian Ring 22
') 3 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.1 Bezout rings -&
. . . . . . . . . . . . 2.2 The basic properties of Dubrovin valuation rings 25
. . . . . . . . . . . . . 2.3 The Ideal Tiieory of Dubrovin valuation rings 30
3 Prime Segments 51
3.1 Prime segments in Dubrovin valuation rings . . . . . . . . . . . . . . 52
3 .1 Rank one and discrete Dubrovin valuation rings . . . . . . . . . . . . 56
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3.3 Examples 61
4 Krull Rings 64
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 4.1 Kru11 rings 64
. . . . . . . . . . . . . . . . . . . . 4.2 Essential valuations of Krull rings 71
4.3 An approximation theorem for Krull rings . . - . . . . . . . . . . . . 73
Bibliography 78
Index 83
Introduction
-4 successful partial proof of the famous Fermat Conjecture (before
AWiles proved the Conjecture), i-e., the impossibility of the equation xP + y p = zP
for p an odd prime number and x , y , r integers # 0, did depend on the uniqueness
of the factorization in the ring Z[Ç] ( Ç # 1 is a p t h root of unity). -4 mistake in his
first attempt to prove the Conjecture led Kummer to his study of the arithmetic of
cyclotomic fields which occupied him for almost 25 years. Using the theory of ideals
and ideal classes in algebraic number fields, Kummer proved the Fermat Conjecture
for every regular odd prime number p , i-e., p -f h, where h is the class number in O(<).
His "ideal prime numbers", that is, "the exponent" with which a factor appears in
the decomposition of a number x E Z [ j ] . is in the modern language the value of a
valvation on the field Q(C) nt x. This development of the theory of algebraic num-
bers between 1830 and 1S60 was one of the two central motivations for the creation of
modern commutative algebra and the study of commutative integral domains, prin-
cipal ideal domains ( P D ) , Prüfer, Krull, Dedekind and unique factorization domains
(UFD). The second source was Algebraic Geometry.
Even t hough a strict definition of the notion of an nrithmetic ring does not exist ,
many arguments suggest that by arithmetic rings in commutative algebra we mean
Kru11 and Prüfer rings which include principal ideal rings (PIR), Dedekind, valuation
and unique factorization rings (UFR).
The main object of study in this thesis are commutative and non-commutative
arit hnlet ic rings. Vire contribute some results concerning the ideal structure of non-
commutative valuation rings and some results about essential valuations of commu-
tative K r d rings with zero divisors.
In Chapter 1, we present background material necessary for the subject. We
discuss the basic results and present the classical theorems from the general theory
of non-commutative rings, the general theory of orders with an emphasis on Bezout
orders in an artinian ring and the theory of commutative and non-commutative valu-
ation rings. For some of these results modified proofs are given. To a certain estent,
this chapter makes the thesis independent of t h e other sources.
Ln 1984, W. Dubrovin introduced a new c l u s of non-commutative valuation rings
in a simple artinian ring, now called Dubrovin valuation rings. In Chapter 2, we
examine the ideal theory of Dubrovin valuation rings. We start with presenting
recent results by J. Grater about Bezout orders in an artinian ring and proceed to
give a modified proof of a characterization theorem for Dubrovin valuation rings
which shows that this class of rings consists exactly of local Bezout orders in simple
artinian rings. In particular, ive consider prime ideals P of a Dubrovin valuation ring
R with the property that R/P is a prime Goldie ring. Such ideals are called Goldie
prime ideals. We first show that in the special case when R is a total valuation ring,
then a prime ideal P of R is a Goldie prime if and only if P is completely prime,
see Proposition 2.3.16. Then we show that Goldie prime ideals have many %ce"
properties.
If Pi, i E A, are Goldie primes in R, then n A and U P, are Goldie prime ideals,
see Proposition 2.3.19 and Corollary 2.3.22. Also, if I2 = I # R is an idempotent
ideal of R1 then 1 is a Goldie prime, Lemma 2.3.20. The essential result for further
esploration of the ideal structure of Dubrovin valuation rings is the result in The-
orem 2-13-24. This theorem shows that the intersection of al1 powers of any proper
ideal of R is a Goldie prime.
The end of Chapter 2 looks at divisorial ideals of a Dubrovin valuation ring R. -4
right R-ideal A is called divisorial if A = -4' = n CS? where c runs over al1 elements
in Q with CS A and S = O,(A). On the set D(R) of al1 divisorial ideals ive define
the partial operation "O" by A O B = (-AB)" if A, B E D ( R ) with O,(A) = O1(B).
With respect to the operation "O", D( R) becomes an algebraic structure known as
Brandt groupoid . We show that in the case when R is a Dubrovin valuation ring of
rank one, (D( R)? O) is a group, order isomorphic to a subgroup of (R, +), the additive
group of real numbers, Theorem 2.3.15 and Lemma 2-3-25.
Chapter 3 explores the ideal structure in a Dubrovin valuation ring. In particular,
our interest lies in pairs Pl > PZ of two distinct Goldie prime ideals Pl and Pz such
that no further Goldie prime ideal exists between Pl and P2. Such a pair is called
a prime segment. We show that in a Dubrovin valuation ring there are exactly
three types of prime segments: archimedean. simple and exceptional. -4pplying this
result to a Dubrovin valuation ring R of rank one, we describe al1 possibilities for
the group D ( R ) and the subgroup H(R) of D(R) of al1 non-zero ideals which are
principal as right R-ideals. Since, in this case: for any non-zero R-ideal -4 in Q
either -4 = -4' E D(R) or A c A' and then A* = CR, A = cJ (R ) for some
c E ' ( Q ) : knowing the groups D( R) and H(R) we are able to describe completely
the structure of al1 ideals in a Dubrovin valuation ring of rank one. This result shows
that rank one Dubrovin valuation rings have an ideal structure compIetely analogous
to that of cones of right ordered groups and, equivalently, of chain domains, which
has been described earlier in papers by H.H. Brungs and G. Torner, [BT76], H.H.
Brungs and N. Dubrovin, [BD], T.V. Dubrovina and N. Dubrovin, [DD96] and H.H.
Brungs and M. Schroder, [BS95]. Also, we show that a rank one Dubrovin valuation
ring R in a simple artinian ring Q with finite dimension over its center has only an
archimedean prime segment. We conclude Chapter 3 by appiying these results to a
discrete Dubrovin valuation ring. We show that every discrete Dubrovin valuation
ring R has an archimedean prime segment J ( R ) > ( O ) , with Z ( R ) # z ( R ) 2 , the
Jacobson radical J ( R ) is principal as a right R-ideal and r) Z(R)" = (0).
The final Chapter 4 is devoted to an application of valuation theory to commuta-
tive and non-commutative arit hmetic rings. In part icular, ive consider commutative
and non-commutative Krull rings. The class of commutative ICrull rings with zero
divisors i17as introduced by R. Kenned- [IienïS] and later esplored by R. Matsuda,
[Mats-] and [MatS5]? and J. Alajbegovic and E. Osmanagic, [A090b] and [A090a].
We prove an approximation theorem for essential valuations of Iirull rings with zero
divisors: Let R be a KruU ring with total quotient ring Kt such that R # K 3 and
{vP 1 E P( R)} is the family of essent ial valuations of R. If {vY,, UV,, . . . ? vp,,}
is a finite set of essential valuations of the ring R and (ni, 7722, . . - , am,) E Zn, then
tliere esists an element r E I ï such that u T t ( z ) = mi for al1 i E {l, 2,. . . . n) and
uV(x) 2 O for al1 other essential valuations v.p of R. This results rnirrors the ana le
gous approximation theorem for essential valuations of I<rull domains. The element x
constructed in the proof of the above result is not necessarily regular. We show that
for the class of addit ively regular rings the element x can be chosen to be regular. In
this case? we give a characterization of divisorial fractional ideals in terms of principal
divisorial ideals. Also. ive hriefly discuss the notions of non-commutative Prüfer rings
and non-commutative Kru11 rings.
Chapter 1
Preliminaries
In this chapter we give the definitions and results from the general theory of as-
sociative rings which are basic for this subject. The main results are taken from
[RM87], [MMU97], [LM7l], [Sch45] and [DubS$]. Throughout this chapter, a ring is
always an associative ring with identity 1 . A subring of a ring R always contains the
identity element of R. For a ring R, we denote by U(R) the set of al1 units of R and
by Cn(0), or sometimes by Reg( R), the set of al1 regular elements of R. -4 right (left)
ideal -A of R is regular if it contains a regular element. The set of al1 zero divisors of
R is denoted by Z( R).
1.1 Elementary properties of orders
-4 ring R is called si,mple if R does not contain nonzero proper two sided ideals. If A4
is any ideal of R, R/M is a simple ring if and only if iLI is a maximal ideal. Clearly,
every division ring is simple. By Wedderburn's Theorem, if R is a simple artinian
ring then R "= Mn(D) for some division ring D.
Let C be a multiplicatively closed subset of a ring R. Then we say that R satisfies
the right Ore condition with respect to C or that C is a e h t Ore set of R if for al1
a E R and c E C, there esist 6 E R and d E C such that ad = cb. If C CR(0), then it
is called a regular right Ore set of R. .A (regular) left Ore set of R is defined similarly.
If C is a (regular) right and left Ore set of R, then it is simply called a (regular) Ore
set of R.
Theorem 1.1.1 ( [Her68]) I fC is a regular right Oir set of R, then there exists
an overring T = RC-' = & of R, called the right quotient ring of R vrith respect to
C such thnt
i) any c E C is a unit o f T ;
ii) for any q E T , there exist a E R and c E C such that q = ac-'.
For arbitraq elements ql, q 2 , . . . , qn f T there exists a common denominator, i.e., a
regular element c E C such that qi = rit-' , i = 1 , 2 , . . . , n for some ri E R.
Let R be a subring of a ring Q. If Q = RCR(0)-', then R is called a right order
in Q . Sometimes, the ring Q is denoted by Q = Q(R). Hence, a subring R of a ring
Q is a right order in Q if and only if R satisfies the right Ore condition with respect
to CR(0). .A lefi order in Q is defined similarly, and a. ring R rvhich is both a right
and a left order in Q is called an order in Q.
For a subset A of a ring R we define rR(A) = {x E R 1 -4x = O} and cal1 it
the right annihilator OF -4. The left annihilator l R ( i l ) is defined similarly. A right
annihilator of R is a right ideal of R and a left annihilator is a left ideal of R.
In an artinian ring al1 one-sided regular elements are units. More precisely the
following result holds:
Lemma 1.1.2 ( [Rob67a]) Let Q be a right artinian ring and c E Q. Then the
following conditions are equivalent:
i i) c is regular;
iii) c is a unit.
Proof. The only impiication we need to prove is (i) + (iii). Assume that rq(c) = O
and consider the chah
of right ideals of Q. Then there e x i t ~ n such that c n Q = cn+'Q. Hence: cn( l - cx) = O
for some x E Q. By (i), 1 = cx. But, cx-1 = O, implies cxc-c = O, Le., c(xc-1) = 0,
and again by (i), xc = 1, Le., c is a unit.
O
The next two results are often used in this work; they describe very useful prop-
erties of orders in an artinian ring.
Lemma 1.1.3 ( [Rob67a]) Let R be a right order in a ,right artinian ring Q
and c E R. Then, the following are equivalent:
i i) rp (c) = 0;
i i i) c 2s regular in R:
i v ) c is regular in Q;
v) c is a unit in Q .
Proof. By
let cq = O
ca = O. By
Lernma 1 .l.2, it is enough to prove (i) + (ii). Assume that rR(c) = O and
for some q E Q. Since q = ab-', where a. b E R and b is regular. then
the assumption, a = O. Hence, q = 0.
Corollary 1.1.4 ( [Rob67a]) Le t R be a right order in a right artinian ring Q
and a , b E R. T h e n ab is regular i f and on ly i f a and b are -regular.
Proof. If ab is regdar, then rR(b) = O. By Lemma 1.1.3, b is unit in Q. Then
a = (a6)b-' is regular in Q, and again by Lemma 1.1.3; a is regular in R.
17
Yote that if a ring R has a right quotient ring Q and Q satisfies ACC for right
or left annihilators, then the property in Corollary 1.1.4 holds. Rings do exits which
do not satisfy this property.
Let R be a ring and kf be a right; R-module. An R-subrnodule L of iV1 is said to
be an essential subnodule if L N # O for any nonzero R-subrnodole iV of M. If L
is an R-submodule of ibi', then there exists an R-submodule L' such that L n L' = O
and L @ L' is an essential submodule in M . If a right ideal 1 of R is an essential
R-submodule of R, then I is cailed an essential right ideal.
A right R-module U is said to be a u n i f o n n module if every nonzero R-submodule
of U is essential. A right R-module !LI is said to have finite Goldie dimension if it
contains no infinite direct sum of nonzero R submodules.
A ring R is called a right Goldie ring if R satisfies the ascending chah condition
(ACC) for right annihilators and R does not contain an infinite direct sum of nonzero
right ideals. A left Goldie ring is defined similarly, and if R is a right and left Goldie
ring, therr R is called Goldie. By Goldie's Theorem, a ring R is a (semiprime) prime
right Goldie ring if and only if R is a right order in a (semisimple) simple artinian
ring Q. Some basic properties of Goldie's rings are summarized in the following two
results:
Theorem 1.1.5 ( [RM87]) Suppose that R i s a semipr ime right Goldie ring
and let 1 be a right ideal of R -Then :
i) I is essential i f and only if I contains a regular element;
ii) i f I is essential, then I is generated b y regular elements.
Theorem 1.1.6 ( [RM87]) If a right R-module M has finite Goldie dimension,
then there ezist uniform R-submodules Ul, Uz, . . . , Un of Ad such that Ul @U2$. . .%Un
is an essential R-submodule of M . In this case n is independent of the choice of the
Ui. W e cal1 n the Goldie dimension of iW and denote it b y dR(!bl) or d ( M ) .
Definition 1.1.7 Let R be an order in a ,ring Q . Then a right R-sub~module I of
Q is called a right R-ideal of Q if
ii) there exists an element c E U ( Q ) such that CI 5 R.
A right R-ideal I of Q is called integral $ 1 C R. A left R-ideal is defined similady.
A right and lefl R-ideal of Q is called an R-ideal.
Let R be a semiprime Goldie ring and Q be the semisimple artinian ring of quo-
tients of R. If i is a right ideal of R, then 1 is a right R-ideal if and only if I is
essential. In particular, any nonzero ttvo sided ideal 1 of a prime Goldie ring R is an
R-ideal since for any nonzero right ideal X of R we have O # S I 2 X n I , i-e., I is
essential and by Theorem 1.1.5, I contains a regular element.
Let R be an order in a ring Q. For any ttvo subsets A and B of Q, tve define:
( A : B ) , = { q ~ Q 1 Bq C -4)
For a right R-ideal 1 of Q we set
Then the following holds:
Lemma 1.1.8 ( [MMUg?]) Let R 6e an order in a ring Q and I 6e a right
R-ideal of Q . Then:
i) O,([) and O r ( [ ) are orders in Q;
ii) i is a lep Or(l)-ideal and a right O,(I)-ideal;
iii) (R : I ) ! is a lep R-ideal and a right 01(1)-ideal.
Definition 1.1.9 -4 ring R is called a right (left) chuin ring i f right (leftl ideals
of R are linearly ordered b y inclusion. A right and left chain ring is called a chain
ring.
We can extend this concept in the following way:
Definition 1.1.10 Let R be a su6ring of a ring Q. Then R is called a right
n-chain ring in Q if for nny elements aa, ai , . . . , a , in Q there exists an element
ai , i E { O , 1,. . . : n ) , such that a; belongs to the right R-submodule generated 6 y the
remaining elements a i , j # i , that is, ai E a j R . A right n-chain ring in itself
is called a right n-chain ring. -4 left n-chah ring is d e h e d sirnilarly. .4 ring which
is both right and lef i n-chain m'ng is called n-chain ring.
Remark 1.1.11 a ) Let S be an o.verring of a ring R in a ring Q . If R is a right
n-chain ring in Q, then R is a right n-chain ,ring in S and S is a right n-chain
ring in Q. Furthermore, $1 C R is an ideal of Q and R is a right n-chain ring
in Q , lhen R / I is a right n-chain ring in Q / I .
b ) The class of 1-chain rings coincides with the class of chain rings.
c) In every cha in h g R, the Jacobson radical,'J(R) is a maximal right and lefi ideal.
By the Remark 1-1-11 c), if R is a semi-simple chain ring, t hen R is a division ring.
The analogous result for n-chain rings is:
Lemma 1-1-12 ( [MMU97]) Let R be a semi-simple ,ring, i.e, J ( R ) = O . Then
R is art inian if and on ly i f R is a right n-chain r ing f o r some n.
Let R be a commutative ring with identity and li its total quotient ring, and S
a multiplicative closed system of R. Then the large quotient ring of R mith respect
to S is defined to be the set RISI = {x E K 1 (3s E S) xs E R}. If -4 is an ideal of R,
then the extension of A is [AIRLq = {x E K 1 (3s E S) xs E A). A ring R is called
r-noetherian if it satisfies the ascending chah condition (ACC) for regular ideals.
Proposition 1.1.13 ( [Gri69]) For a commutat ive ring R the following condi-
t ions are eqvivalent:
ii) Every n o n e m p t y set o f regular ideals of R has a nax i rna l element;
iii) Euery regular ideal of R is finitely generated;
iv) Euety regular pr ime ideal of R is finitely generated.
-4n r-noetherian ring need not be noetherian ( [MatSl]).
Let R be a subring of a ring R' and iet a E R'. If a is a root of a monic polynomial
with coefficients from R, then a is called integral ouer R. If there exists a finitely
generated R-submodule M of R', such that an E for all n, then a is called almost
integral ouer R. The subset Ro of al1 elements in R' which are almost integral over
R is called a complete integral closure of R in R'. If & = R, we Say that R is
completely integrally closed in R'. In the case that R' is total quotient ring of R, Ro
is called a complete integral closure of R and, in the case & = R, we Say that R
is comletely integrally closed . Notions of integrally closed and integral closure are
defmed similady. If a is an integral element over R then a is aImost integral over R.
The converse does not hold. For example, T = Zp) + X Q [ [ X ] ] is a valuation domain
with value group Z x 23, and hence, T is integrally closed but T is not completely
integrally closed.
For the class of r-noet herian rings the notions of completely integrally closed and
int egrally closed coincide.
Proposition 1.1.14 ( [A090a]) [ f a r ing R is r-noetherian and integrally closed,
t h e n R is completely integrally closed.
A ring R bas few zero divisors if Z ( R ) is a finite union of prime ideals; and R is
additiueiy regular if for each r in its total quotient ring Ii, there exists u f R such
t hat r + u E CI,-(O). A ring R is called a Marot r ing or a ring wvit h the proper ty (P) if
every regular ideal is generated by reguIar elements. The relationships between these
classes of rings are summarized in the next theorem:
Theorem 1.1.15 ( [Huc88]) Consider t h e following four cond i t ions o n a corn-
,mutatz'.ve ring R
1) R is a noether ian ring;
2 ) R h a s few zero divisors;
3) R i s a n addit ively regular ring;
4 ) R i s a Maro t r ing .
None of the implications of the Theorem are reversible ( [HucSS], Examples).
1.2 Valuation rings
Valuation Theory is an important and powerful tool in many areas of mathemat-
ics: Number Theory, Theory of Local and Global Fields, Algebraic Geometry and
Model Theory. The first axiomatic definition of a valuation has been stated by Josef
KürschAk in 1913 and the further development, a t the beginning of the 30-th cen-
tury, is associated with works of Kurt Hensel, Alexander Ostrowski and Helmut Hasse.
While this stage of the development of the valuation theory is mainly concerned with
vduations of rank one7 the notion of a general valuation was introduced by Wolfgang
Kru11 in 1933, [Kru32]:
Definition 1.2.1 Let K l e a field and let V be a m a p of I< ont0 a totally ordered
abelian group C, with an added elernent m, such that CG + oa = g + ca = oo, oo > g
for al1 g E G. The map v : K -t G, U{w} is called a (Krull) valuation on Ii and
G, is called the value group of v if the foihwing conditions are satisfied
VI) (Vx E K) v(x) = oo i f and only if x = O
V3) (Vx, y E f i ) su(x + y ) 2 rnin{o(x), v ( ~ ) )
If G, = O then u is called a trivial valuation. If the group G , is the group of
integers, then u is called the discrete valuation of rank one. For exarnple, for every
x E Q = Q \ {O) and a prime number p there exist integers a, r , s such that
x = paS, where r and s are not divisible by p; then the map u, : -+ Z defined
by v,(x) = cr and u,(O) = ca is a discrete valuation of rank one of Q. The ring
& = {I E Ii [ v(x) 2 0) is called the ring of the valuation v and the prime ideal
Pu = {x E li 1 u ( x ) > O) is called the positive ideal of u. The ring R,, satisfies
the following condition: for each x E K , x E R, or x-' E R,. Conversely, if R is a
subring of K such that x E K \ R irnplies x-' E R, then there exists a valuation v of
h'such that R = &. Many authors contributed to this theory, arnong them O.F.G.
Schilling, E. Artin, O. Zariski, P.J. J d a r d , P. Ribenboim, O. Endler and M. Fuliava.
Iinill valuations axe greatly used by Zariski and his school of Algebraic Geometry.
For example: power series rings are used in the study of the algebraic varieties in
projective spaces; abstract Riemann surfaces are developed.
Among competing attempts to develop a theory of valuations for commutative
rings which may have nontrivial zero divisors, the most successful was the definition
of the valuation ring by ME. Manis in [Man67].
Definition 1.2.2 ( [Man67]) .4 map v frorn a commuta t ive ring T onto a totally
ordered abelian group G, mith co adjoined, is called a valuation of T $ the follo.wing
conditions hold:
(i) v(xy) = ~ ( x ) + v(Y);
The ring R, = {x E T 1 u(x) 2 O } is called the ring of the ualration v. The set
P, = { x E T 1 v ( x ) > O ) is a prime ideal of R, and is called the positive ideal of v.
The ring R, and the ideal P, satisfy the following condition:
(iii) For each x E T \ &, there enists y E P, such that xy E R, \ Pu.
Conversely, if R is a subring of a ring T and P is a prime ideal of R such that for each
x E T \ R there enists y E P with xy E R \ P , then there exists a Manis valuation
v on T such that R, = R and P, = P. A pair (R, P) satisfying (iii) is called a
Manis valuation pair of T . For example, the pair ( R : P ) = (Z[X], SZ[X]) is a Manis
valuation pair of the ring T = Z[X, X-'1 . If the group G, is equal to (O) , then v is
called a trivial valuation. If the group Gu is the group of integers, then v is c d e d
the diçcrete caluation of mnk one.
For the theory of Manis valuations refer to [LMiI], [HucSS] and [-4M9-1. In
the last three decades an extension of the theory of commutative integral domains
to commutative rings with zero divisors was developed, see R. Gilmer [Gil72], M.
Larsen, P. McCarthy [LMil], J. Huckaba [HucSS], R. Matsuda [MatS3] and J.
Alajbegovic, J. MoCkoI [AM92].
Io the non-commutative case, a natural question is: Wlich class of rings plays the
same role for the study of non-commutative arithmetic rings as the classes of valuation
domains and Manis valuation rings do for commutative arithmet ic rings'! First,
note that a successful "candidate" should share many properties with commutative
valuation rings, in part icular, the properties of extension of valuations. For esample,
\ire would like to know a non-commutative analogue of the following result due to
Chevalley: If V is a valuation ring of a field F and 1' is an extension of F , then
there exists a valuation ring TV of K with W n F = V. In this case we say that W is
an extension of V in K. Ln order to consider these questions one must decide what
it rneans to have a ualuation o n a division ring. It seemed natural to suggest that
this role is played by Schilling's valuations on a skew field, see (SchlS]:
Definition 1.2.3 A valuation v on a division ring D is a function from D' =
D \ { O ) onto an ordered group G,, such that for al1 a , b E D', v ( a 6 ) = v(a) + v(b)
and u(a + b) 2 min{v(a), ~ ( b ) ) .
For convenience ive extend v to D by v(0) = oo where ca > y and w + y = y+oo = oo
for al1 y E Gu. Such valuations v on D correspond to subrings R of D (called total
invariant valuation rings of D ) with the following two properties:
(T) If x E D' then x E R or x-' E R; we say that R is a total ualuation ring of D.
(1) dRd-' = R, for al1 d f O in D; we say that R is invariant .
Note that valuations on the finite dimensional centrai simple division algebras are
used to show that the Brauer groups & ( F ) over a local field F are isomorphic to
Q/Z. Using valuations. the central simple algebras over global fields: i-e., algebraic
number fields or algebraic function fields, are classified. This work is associated with
the famous names of H. Hasse, R. Brauer, E. Noether and A. Albert, see [PieS-].
However, the valuation of the center F of a division ring D such that [D : FI < oo, in
general, cannot be extended to the whole algebra. For example, for p an odd prime
number, the valuation ring Z(,) in the center Q = Z(W(Q)) of the Cdimensional
algebra of quaternions over the rationals cannot be extended by a total invariant
valuation ring in E(Q), see Example 1.42. This difficulty has been overcorne by the
introduction of Dubrovin valuation rings in a simple artinian ring, see [DubS1]. A
very well developed ideal theory and extension theory in the finite dimensional case
justify the name valuation rings.
Definition 1.2.4 Let R be a svbring in a simple artinian ring Q and asswme that
M is an idenl of R such thn t R / M is a simple artinian ring, and /'or each q E Q \ R
there are ele,ments r ,rr E R with qr,rrq E R \ M . Then R is called a Dubrovin
valuation ,ring of Q.
Exarnples of Dubrovin valuation rings are given in Section 1.4.
Note: that in the case Q = K is a commutative field the classes of Schilling val-
uation rings. i.e, total invariant rings in Q, total valuation rings in Q and Dubrovin
valuation rings of Q al1 agree and are in fact equal to the class of the classical corn-
mutative valuation domains in Q = K. More precisely:
Theorem 1.2.5 Let R be a Berout order in a simple artinian ring Q. Then:
1. R is a Dubrovin valuation ring o f Q i f and only if R / J ( R ) is a simple artinian
ring.
2. R is a total valuation r ing of Q i f and only i f R / J ( R ) and Q are skew fields.
3. R is a Krull valuation r ing in Q i f and only i f R / Z ( R ) and Q are fields.
For the general theory of Dubrovin valuation rings see [DubM], [DubSS], [Dubgla],
[GraSzb] and [MMU9'7].
We mention here the foilowing extension t heorem for Dubrovin valuation rings.
Theorem 1.2.6 ( [Dub85] and [BG90]) F o r euery valuation ring V in the
center F of a jînite dZ.mensional central simple algebra D, there exists a Dubrouin
valuation ring R of D such that R n F = V .
A very rich extension theory using Dubrovin valuation rings has been developed
in the last decade, see for example papers by PI'. Dubrovin [DubSj], H.H. Brungs, J.
Grater [BGSO], J. Grater [Gra92a], P. Morandi [MorSS], P. Morandi, A. Wadsworth
[MW891 and A. Wadsn-orth [WadSS]. This suggests that among three competing
concepts of noncommutative valuation rings, Le., Schilling's total invariant valuation
rings, total valuation rings in a skeew field (equivalently, chain domains) and Dubrovin
valuation rings in a simple art inian ring, the last one is the most effective for the study
1.3 Cones in groups and chain domains
Let G be a group. A cone of a group G is a subset P of G such that PP C P and
P U P-' = G. It follows that the identity element e of G belongs to P. If in addition
P n P-' = {el, then P is called a basic cone of G. In this case, we Say that (G, P)
is a right ordered group with a 5, b if and only if ba-l E P for a, b E G. The right
order <, will also be a left order if and only if aPadl = P for all a E G. The group
(G, P) is then a linearly ordered group.
Let P be a cone of G. -4 non-empty subset 1 of G is called a right P-ideal if
I P C 1 and 1 Ç aP for some a E G. Left P-ideals and P-ideals are defined similarly
If 1 Ç P then we omit the prefix "P-" and cal1 I a right (left) ideal of P. Moreover,
if 1 # P, then we Say that (right or left) ideal 1 is proper. A proper ideal 1 of the
cone P is said to be pr ime (completely p r i m e ) if for a , b E P we have a E 1 or 6 f 1
whenever a Pb C I (respectively, ab E I).
The proofs of the following resuIts are similar to those of the corresponding as-
sertions about chain rings:
C l ) The set of right (left) P-ideals is totally ordered with respect to inclusion.
C2) The set of elements invertible in the cone P is the intersection P n P-' and it
is a subgroup of G.
C 3 ) The subset J ( P ) of elements non-invertible in P is a maximal right (left)
ideal. This ideal is a completely prime ideal and P = J ( P ) U U ( P ) and
U ( P ) r) J ( P ) = 0, where U ( P ) is the set of a11 units of P.
We note that a s ~ b n n g R of a skew field D is a total ualuation ring $ and only if (Ra, - ) is a cone in ( D a , -). -4ny total valuation s u b n n g R of a skew field D is a
Bezout order in D with R / J ( R ) a skew field.
Let G be a group with a cone P. We Say that a total valuation ring R of a skem
field D is associated with P if the following conditions hold:
b) Every element d E D' can be written as d = glu1 = u2g2 with gl, g~ E G and
ul, 112 E LJ(R) and PgI P = Pg2 P ;
The existence of total valuation rings wit h prescribed associated cones has been
studied recently, see papers by H.H. Brungs and G. Torner, [BTSS], T.V. Dubrovina
and N.I. Dubrovin, [DD96], and H.H. Brungs and N.I. Dubrovin, [BD]. Many
examples are constructed by the authors mentioned above.
The following result describes the correspondence between the c h i n of right P-
ideafs in a group G with a cone P and the chain of right R-ideals in the total valuation
ring R of a skew field D associated with a cone P.
Theorem 1.3.1 Let a total valuation ring R o f a skew field D be associated with a
cone P of a group G. T h e n ~ ( 1 ) = IR, for a right P-ideal 1, defines a n iso~morphisrn
between the chain o f right P-ideals in G and the chain of right R-ideals in D. T h e
inverse mapping .ri, assigns t o each right R-ideal A the right P- ideal +(.il) = A n G.
This correspondence preserues the properties of being a n ideal, a completely prime
ideal and a prime ideal, and R-ideals correspond to P-ideals.
Since the cone R' of D' is associated with the total valuation ring R in the skew
field D, an immediate consequence of Theorem 1.3.1 is the following result:
Corollary 1.3.2 Let R be a total ualuntion subring of a skew field D wiih right
(lefi) R-ideal A. T h e n A \ { O } is a right (lefi) R'-ideal i n D'. Conuersely, if 1
is a right ( l e m R'-ideai i n D*! then I U { O ) is a right ( l e p ) R-ideal i n LI. T h i s
correspondence preserues the properties of being an ideal, a pr ime ideal, a co,mpletely
prime ideal and o f being proper.
We conclude this section with the result by N-Dubrovin, which will allow the
construction of total valuation rings wit h prescribed associated cones.
Theorem 1.3.3 ( [Dub93]) Let P Se a cone i n a group G' and F a skeu; field
such that the following condit ions hold:
a) P does n o t con ta in a m i n i m a l ideal;
b) For every right P-ideal 1, the group ring F U ( O r ( I ) ) is an Ore domain.
Then there exists a skew field D and a total ualuation ,ring S of D associated .with P.
1.4 Examples
Wë have seen in Theorem 1-2.5 that if R is a Dubrovin valuation ring in a simple
artinian ring Q with R / J ( R ) a skew field, then Q is a skew field and R is a chain
domain. Hence, chain domains are special Dubrovin valuation rings. Also, rnatrix
rings over chain domains are Dubrovin valuation rings.
A particular esample of a Dubrovin valuation ring is the following:
Example 1.4.1
The r ing R = hl(Z(,)) of quaternions over the valuation ring Z(,), cuhere p is an
odd prime number, is a Dubrovin valuation ring in the ring Q = H(Q) of quaternions
ouer the rationals.
Proof. M = pR is a two sided ideal of R, R / M = Q @ FPi @ IFp j @ Fpk, where Fp
is a field of p elements. Since R/M contains nontrivial zero divisors, we have R / M 2
MZ(Fp). TO check the second condition of Definition 1.2.4 we take an arbitrary
element q = q~ + qli + qz j + q3k E Q \ R. Shen at least one of qi does not belong
to Z(,). Among these, we choose one, Say q,, ivith smallest pad ic valuation. Then
qs = A p"st, where a, > O and p f r,, p { t,. Let r = p a S t , E R. Then qr E R \ M.
The nest esample was announced in Section 1.2.
Example 1.4.2 A ualuation domain V of the center F of a central simple diuision
algebra D with [D : F ] < co, cannot be extended to a total ualuation ring in D.
Proof. Let p be an odd prime number, D = H(Q) be the Pdimensional algebra of
quaternions over the rationals, F = Q is the center of D and V = Z(,) the valuation
ring of the padic valuation on F = Q. Assume thât t k e exkts a total vduation ring
R in D which extends V' i-e., R 0 Q = V. Since R is a chain domain, the Jacobson
radical ikf = J ( R ) is a maximal right (left) ideal of R. Hence, R/M is a division ring.
Also [R/M : Z~,)/pZ(,J 5 [D : Q] = 1 < 00. Therefore, R/M is a finite division ring .. .
and b - Wedderburn Theorem, R/M is commutative. So = ,i.e., 2ji E M. But:
i,j are units in D. Hence, 2 E M , a contradiction which shows that V = Z(,) cannot
be extended to a total valuation ring in D.
O
Exarnple 1.4.3
The valuation Rng V = Zp) of Q has a total invan'ant extension in D = H(Q).
Proof. For an element a = a0 + a l i + a z j + a& E D , where a; E 0, we define
a' = a0 - al i - a 2 j - a3k and N ( a ) = aa* = a: + a: + a$ +a$. It can be shown that:
1. ( a + a)= = al + O-. (a0)- = 9%-, for al1 a , j3 E 0;
2. N(c@) = N(a)N(,O), for ail a: ,O E D;
3. N(a - l ) = N ( a ) - ' , for al1 a E D;
4. B = {a E D 1 N ( a ) E Z(2)) is a subring of LI;
Now. for a E D \ B, N ( a ) E Q\ Z(2). Hence, N ( a - l ) = N(a)-' E Z(2). So, a-' E B,
Le., B is a total valuation ring in D. Also, crB = Ba for al1 a E D, Le., B is invariant.
Hence, B is a total invariant extension of V in D.
El
Chapter 2
Bezout Orders in a Simple
Artinian Ring
A ring R is said to be local if R = R / J ( R ) is a simple artinian ring. In this chapter
we consider Bezout rings, and, in particular, local Bezout orders in a simple artinian
ring. These orders are exactly Dubrovin valuation rings (see Theorem 2 2 s ) . In
Section 2.3 ., the prime spect rum of a Dubrovin valuation ring is investigated.
2.1 Bezout rings
A commutative integral domain is called a Bezout domain if each finitely generated
ideal of R is principal. Hence, every principal ideal domain (P ID) is a Bezout domain
and every noetherian Bezout domain is a PID.
ExampIe 2.1.1 There ezists a Bezout do.main which is not a PID.
Proof. Let (G, P ) be a commutative ordered group with the positive cone P, i.e.,
P P Ç P, P U P-' = C: and P n P-' = { e ) . Let F be any field and consider
the group ring FG and the subring T = FP = { C a , p 1 a, E F, p E P}. Then
S = {C a,p 1 a. # O) c T is a multiplicatively closed system in T. Since F is a field
and G' is a commutative ordered group, FG does not have nontrivial zero divisors
and it is a commutative dornain. Consider the localization V = TS-' of T a t S in
the quotient field K = Q ( F G ) of the domain FG.
The set of al1 nonzero principal ideals of V is exactly the set { g V 1 g E P ) and
glV = g2V if and only if gl = 92.
For, let O # t = a,g~ + a,,gi + - + a,,g, E T = FP where gi E P, a , E F\ { O h be any element and assume that e < go < 91 < 9 2 < - . < gn. Then t = gos1, where
S I = ~,+a, ,g; '~~+- -+a,,g~'g, E S. Since V = TS-', each element O # v E V has
the form v = ts-' for some t E T and s E S-Hence, vV = gosls-'V = gQV.Assume
g lV = g2V but gl < 9 2 . Then V = g ; 1 g 2 ~ = p V for some p E P.This implies
1 = pts-', i.e.: s = pt E S, a contradiction.
Hence, the lattice of principal ideals of V is a chain, and if I = (vl : us,. - .un)V
is a finitely generated ideal of V, then I is principal, Le., V is a Bezout domain.
Note that V is a valuation domain and the valuation associated to V on I< has G as
the value group. Choosing the group G to be (IR, +), the valuation domain V is not
discrete and hence, V' is not a PID.
O
Every Bezout domain is a Prüfer domain, i.e., every finitely generated ideal of R
is invertible. Therefore, for each commutative Bezout dornain R and a prime ideal
P of R, the localization Rp is a valuation ring and R = n Rp, where P runs over al1
maximal ideals of R.
Noncommutative Bezout rings have been studied by many authors, see P. Cohn
[Coh63], [CohS5], J. Robson [Robgïb], H.H. Brungs [BruS6], R. Beauregard [Bea'iS].
Following [RobG'ib], a ring R is called a right Bezout ring if the following conditions
are satisfied:
i) a b is regular in R if and only if a and b are regular;
ii) a R n bR contains a regular element for every pair of regular elements a, b of R;
iii) For every pair of regular elements a, 6 E R the right ideals a R n bR and aR + b R
are principal.
A left Bezout ring is defined similarly and a Bezout ring is a ring which is right and
left Bezout. A right Bezout ring is not necessarily a left Bezout ring but if a ring R
has a left and right quotient ring Q which is ar t idan, then R is right Bezout if and
only if R is left Bezout. Also, $ R is sernipnrne Goldie, then R is a Bemut ring if and only if e v e q finitely generated right ideal of R is principal, see [RobG'ib], Th.2.4.
and Th.3.5.
Example 2.1.2 There exists a ring R that is a right Bezout ring but it is not a
left Bezout ring.
Proof. Consider the field Ii = Q(t) and define the map a : K +- K with ~ ( q ) = q,
for al1 q E Q and g ( t ) = t2. Then o is a monornorphisrn from K into Ii. Define
R := {CE0 xiai 1 ai E ri) where ax = zo(a) , for al1 a E K. Then R is a ring.
An element O # r = a0 + tal + x2az + - - E R is a unit if and only if a0 # O. Let
f = xna, + ~"+'a,+~ + . . E R where n 2 1 and a, # O. Then f R = xnuR, where
u = a, + xa,+l + - E U ( R ) , i-e., fR = xnR. Hence, al1 principal right ideals of R
are of the form xnR, n = 1, 2, - . . , Le., R is a right Bezout ring.
On t.he otlier hand, for the left ideals Rx and R x t , the intersection Rx n Rxt = 0 ,
i.e., R is not a left Bezout ring.
0
In [Bea73] it is shown that any ring T between a Bezout domain R and its
quotient field Ii is a quotient ring of R and T is also a Bezout domain. The following
theorem generalizes this result .
Theorem 2.1.3 ( [Gra92b]) Let R be a fiight) Berout ring having a right and
left quotient ring Q which is right artinian and let T be an ovem-ng of R in Q.
Furthemore, let S = U ( T ) n R. Then the following hold:
i) S is a left Ore set of R;
i i ) T
iii) T is a Bezout ring
2.2 The basic properties of Dubrovin valuation rings
Throughout this section, Q is a simple artinian ring, R is a Dubrovin valuation ring of
Q and k.1 is the ideal satisfying conditions of Definition 1.2.4. The following results
are the main steps to pro= that !LI is the Jacobson radical of R and that it is a
unique maximal ideal of R. The results are important by themselves and very often
used in this work.
Lemma 2.2.1 ( [Dub84]) For any right (lefi) R-subrnodule I of Q the following
holds:
Proof. Let I be a right R-submodule of Q so that I n R C M. Let x E 1. If
x E Q \ R, then there exists an element r E R such that xr E R \ Ad. But, xr f Il
i.e.,zr E I r ) R C M , acontradiction. So, I E R, i.e., 1 Ç R. Hence, I = I n R 2 M .
Lemma 2.2.2 ( [Dub84]) M does not contain nonrero right (lep) ideals of the
ring Q.
Proof. Let a E Q, a # O and aQ M . I f I + aQ C U ( Q ) , then aQ C J ( Q ) = O ,
Le., a = O. So: 1 + aQ U ( Q ) . Therefore, there exists an element q E Q such that
1 + aq 6 CI(Q). But, Q is an artinian ring and by Lemma 1.1.2, every one sided
regular element of Q is invertible. So, L := Iq( 1 + aq) # O. Also, L 0 R C M. Hence,
by Lernma 2.2.1, L Ç M. Since Laq # O, LaQ is a nonzero 2-sided ideal of the ring
Q. Hence, LaQ = Q. Then 1 E LaQ C bf, a contradiction.
cl
Lemrna 2.2.3 ( [Dub84]) 1 + M 2 u ( R )
Proof. Let m E LW and L := Zq(l + m). Then L n R E M. By Lemma 2.2.1 and
Lemma 2.2.2, L = O. Since Q is an artinian ring, 1 + rn E U ( Q ) . So, for any rn E M ,
( 1 + m)-' exists. If ( 1 + m)-' E Q \ R, then (1 + m)-' - 1 6 R and there exists an
element s E R such that r := [(l + m)-' - 11s E R \ M. Then ( 1 + m)r = -ms, so
that r = -m(r + s ) E M , a contradiction.
Theorem 2.2.4 ( [Dub84]) Let R be a Dubrouin valuation ring of Q . Then LW
is the Jacobson radical of R. In particular: hl is the unique maximal ideal of R.
Proof. Since R / M is a simple artinian ring , f(R) E M. By Lemma 2.2.3, 1M
Corollary 2.2.5 Let S be an ouerrzhg of R in Q and le t 1 be a proper ideal of
S. Then 1 C Z ( R ) . In particdar, J ( S ) Ç y ( R )
Proof. Let 1 # S be any two-sided ideal of S. Then I n R # R, i x . , I r ) R is a
proper ideal of R. Hence, by Theorem 2.2.4, I n R c g ( R ) and by Lemma 2.2.1;
1 c J ( R ) .
To characterize Dubrovin valuation rings in terms of Bezout orders and n-chah
rings, we need the next two results.
Lemma 2.2.6 ( [Dub84]) Let R be a Dubrovin uahation ring of Q and I be a
right R-submodule of Q. Then
Proof. First note that I / I J ( R ) is a right R-module. Let n = dR(R) be the Goldie di-
mension of the R-module R a n d assume that the opposite holds, Le., d E ( I / I f ( R ) ) >
n. Then, since R is a simple artinian ring there exist a , b E 1, b I g ( R ) such that
and
since ( a R + I J ( R ) ) / I g ( R ) 9 a R / a R n I Y ( R ) and a J ( R ) C a R n I g ( R ) , it follows
from aR/aR n I T ( R ) R / g ( R ) that a R n I g ( R ) = a r ( R ) and hence, aR/aJ (R) E
R / Y ( R ) - So, r ~ ( a ) C J ( R ) . On the other hand, rR(a) = rQ(a) n R. Hence, by
Lemma 2.2.1, rQ(a) C Z ( R ) . Then, by Lemma 2 - 2 2 and Lemma 1.1.2: a is a unit
in Q. So, we can rewrite aR n I J ( R ) = a z ( R ) in the form R n a- ' IJ(R) = J ( R ) .
Again, by Lemma 2.2.1? a- ' IJ (R) Ç z(R), i-e., I J ( R ) = a J ( R ) . Now,
Hence. a R n bR C a J ( R ) , i.e.? R n a-'bR g ( R ) . By Lemma 2.2.1: a-'bR C J ( R ) .
This implies b E I g ( R) , a contradiction.
O
Lemma 2.2.7 ( [Dub84]) Let R be a Dubrovin valuation ring of Q. Then any
finitely generated right (left) R-subrnodule of Q is principal.
Proof. Let I be a right finitely generated R-submodule of Q. By Lemma 2.2.6,
dR(l/IJ(R)) 5 dR(R), where R = R / Z ( R ) is a simple artinian ring. Hence, R =
I / IJ(R) @ N for some right R-submodule N of R. Since R is a cyclic R-module,
I/IJ(R) is a cyclic R-module and hence 1 / 1 3 ( R ) is a cyclic R-module, i-e., aR + IJ(R) = I , for some a E 1. But, 1 is a finitely generated R-module. By Nakayama7s
lemma, this implies that I = aR, i.e., 1 is a cyclic R-module. SimiIarly for left
R-submodules .
O
The next result is the main characterization theorem for Dubrovin valuation rings.
Theorem 2.2.8 ( [DubS4] and [MMU97]) Let R be a subring of a simple
artinian ring Q. Then the following conditions are equiualent:
(1) R is a Dubrovin ualuation ring O/ Q.
(2) R is a local Bezout order in Q.
(3) R is a local n-chain ring in Q for some n with d(R) 3 n, vrhere R = R/J(R).
Proof.
If Ive assume that (1) holds, then by Lemma 2.2.7, R is a local Bezout ring.
Let q E Q be any element. Consider the finitely generated right R-submodule
R + qR of Q. Then R + qR is principal, i.e., R + qR = SR for some s E Q. Hence,
1 = sr for r E R. This implies that the right annihilator rp(r) of r in Q is equal to
0, rq( r ) = O. Hence, by Lemma 1.1.2, r is a unit in Q. On the other hand, q = sx
for some x E R. So, q = r-lx.
We are left to prove that every regular element in R is invertible in Q. Let c E R
be a regular element and consider q E ro(c). Then, cq = O. If q E Q \ R, then by (l),
there exists an element r E R so that qr E R \ 3 ( R ) . Then cqr = O and qr E R irnply
that qr = O, since c is regular in R. Hence, qr f J ( R ) , a contradiction which proves
that q E R, and hence, q = O. So, r Q ( c ) = O, and by Lemma 1.1.2, c is a unit in Q.
This proves that R is a left order in Q. Similarly, R is a right order in Q.
Assume that (2) holds and let n = d(@. Let qo, q,, - - , qn E Q. Then goR + Q I R + - - - + qn R is a finitely generated right R-submodule of Q. By (2 ) : we can write
-1 qi = si ri7 where ri, si E R with si regular elements. For elernents s ~ ' E Q, there
-1- exist a common denominator, Le., a regular element t E R such that s ~ ' = t r,,
f o r s o m e r ; ~ R. T h e n q o R + q 1 R + - - + q , R = t - L ( i ; o r o R + ~ r l R + . - - + ~ r n R ) .
Since R is a Bezout order in a simple artinian ring Q, the finitely generated right
ideal %roll + Krl R + . . + Kr, R of R is principal. So, there exists an element s E Q
so that qoR + ql R + - + q,R = SR. Since d ( s R / s g ( R ) ) 5 n = d ( R ) , there exists
i, Say i = O, such that qlR + --• + qnR + s J ( R ) = SR. By Nakayama's lemma,
ql R + - - - + qnR = SR. So, qo E SR = q, R + . - . + qn R, Le., R is a right n-chah ring
in Q. Similarly, R is a left n-chah ring in Q.
Suppose that (3) holds and let rn = d ( R ) , i.e., rn is the length of "the longest" direct
sum of uniform right (left) ideds of R which is essential. We only need to prove that
for al1 q c Q \ R there exist r , r' E R such that qr, r'q E R \ z ( R ) .
Let q E Q \ R. Since R is a simple artinian ring, right ideals of R are generated - by idempotents. Hence, there exist a set {q7 G, - - - , e,) of primitive orthogonal
- idempotents of R. Let el, e2, , e, be the inverse images of c, si - - , e, under
the map R t R = R / J ( R ) respectively. By Remark 1-1-11 a), R is an n-chain - ring. Since m 2 n, R is an rn-chain ring. Consider the elements q, c7 G, . . - , e,.
There are two possibilities, qR + J ( R ) E CE, e;R + g(R) or there exists i such that
eiR C qR + x e j R + J ( R ) . The first case is impossible, since then q E R. Hence, i f i
e; = qr+ Cejr j+x, where x E z ( R ) and rj , r E R. Then qr E R\Z(R). Otherwise, jf i -
ei - Cejrj E y( R): i-e., = Cej+io7 i.e., the idempotents {q, c, - - - , e,) are not i# j j#i
primitive.
Similarly, there exists r' E R such that r'q f R \ g(R).
Note that every condition in Theorem '2.2.5 is equivalent to the condition that R
is a local semi-hereditary order in Q. Since the notion of semi-hereditary order is not
essential for this work we omit the details of this characterization- For details see
2.3 The Ideal Theory of Dubrovin valuation rings
Throughout this section, R is a Dubrovin valuation ring i n a simple artinian ring Q.
In this section we study the properties of R-ideals, divisorial ideals and overrings of
R. In particular, ive consider prime ideals of R. The foliowing result is crucial for
the study of the ideal theory of Dubrovin valuation rings- The detailed proof can be
found in [DubS$] and [MMU97].
Lemma 2.3.1 ( [Dub84] and [MMU97]) Let R be Du6rovin valuation ring
of Q and let T2 C Tl be right R-subrnodules of Q such that
(1) Tl ZS regular and
( 2 ) there ezists a sulring S of 01(T2) such that for an y regular elements t l , t z E Tl
there is a regular element t E Tl with Stl + St2 C - St.
Then either Tl = T2 or there is a regular element to E Tl such that Tz C t o J (R ) .
The next result shows that Dubrovin valuation rings share a very important prop-
erty with other types of valuation rings.
Proposition 2.3.2 ( [Dub84]) Let R be a Dubrouin valuetion ring of Q and
let S' be a Beaout order in Q. Then the set of regular S - R-sub-bimodules of Q is
linearly ordered by inclusion. In particular, the set of al1 R-ideals of Q and hence,
the set of ail two-sided ideals of RI are linearly ordered b y inclusion.
Proof. Let Tl , T2 be regular S - R-sub-bimodules of Q. Set To = Tl n 37% If To = Tl ,
then Tl Ç T;?. Let TO C Tl. Then, by Lemma 2.3.1 there exists a regular element to E
Ti such that TO C t d ( R ) c toR C T I . Hence, Tz r) toR C T2 n Tl = To 2 t o 3 ( R ) ,
that is? 1;'- n R Ç J ( R ) . B y Lemma 2.2.1, tr1T2 C J ( R ) , Le- Tî C t O J ( R ) C Tl-
17
Let P be a prime ideal of a ring R. If CR(P) := { r E R ( r + P is regular in R / P )
is a regular Ore set of R, then the quotient ring RCR(P)-' = CR(P)-l R of R with
respect to CR(P) is denoted by Rp =PR and is called the localization of R. The
overrings T of a Dubrovin valuation ring R in Q are again Dubrovin valuation rings
of Q that are in one-to-one correspondence with the prime ideals P of R for which
R / P is prime Goldie. More generally, the following results hold:
Theorem 2.3.3 ( [Dub84], [Gr592b]) Let R 6e a Bezout order in a simple
artinian ring QI let B be a Dubrouin uahation ring of Q contaitzing R and let P =
J ( B ) R. Then P is a prime ideal of R such that R/P is Goldie, CR(P) = {r E
R 1 r + P is regular in R /P ) is a regular left and right Ore set and B = Rp =PR.
Conversely, $ R is a Bezout order in a s imp le ar t inian r ing Q and P is a prime
ideal o f R such tha t RI P is Goldie, t hen CR(P) is a regular lef i and n g h t Ore set and
Rp is a Dubrouin ualuation ring o f Q s u c h that J ( R p ) n R = P.
Theorem 2.3.4 ( [Dub84]) Let R be a Dubrouin ualuation ring of a simple
ar t inian ring Q and let S be a n ouerring of R in Q . T h e n R = R / J ( S ) is a Dubrovin
v a h a t i o n ring of 3 = S / g ( S ) , S i s a Dubrovin ualuation r ing of Q and S = Ry(s).
Proof. By Corollary 2.2.5, J ( S ) C R and by Theorem 2.2.S, R is an n-chain ring
in Q with d ( R ) = d ( R / J ( R ) ) 2 n. Hence, by Remark 1-1-11, S is an n-chain ring
in Q and S is an n-chain ring in S. Since S is a semi-simple ring, by Lemma 1.1.12, - S is an artinian ring. If I C S is any ideal of S, then by Corollary 2.2.5; 1 C r ( R )
and hence, 1 + I C 1 + 3 ( R ) 2 U(R) C U ( S ) , i.e., 1 Z ( S ) . So, = S / Z ( S ) is
a simple artinian ring . By Theorem 2.1.3, S is a Bezout order in Q. Hence, S is
a Dubrovin valuation ring of Q. Since R / r ( E ) P R / J ( R ) is a simple artinian ring
and d ( Z / ~ ( ? i ) ) > n, by Theorern 2.2.8, R is a Dubrovin vduâtion ring in S. Hence,
R / J ( S ) is a prime Goldie ring and by Theorem 2.3.3, S = Rs(s).
0
It follows, that prime ideals P of a Dubrovin valuation ring R such that RI P is a
prime Goldie ring, are very important. Therefore, the following definition is natural:
Definition 2.3.5 T h e pr ime ideal P of a Dubrovin ualuation r ing R is called a
Goldie p n m e ideal if RI P is a prime Goldie ring.
Xote that J ( R ) and (0) are Goldie primes of a Dubrovin valuation ring R.
Remark 2.3.6 I n the special cases, when R is a total valuation ring in a skew
field Q, i.e.! R is a Bezout order in Q with R / J ( R ) being a skew field. o r when R is
a Bezout order in a central sinmple algebra Q , the bcect ion given in Theorem 2.3.3,
is described by the following results:
a) If R is a Bezout order i n a skew field Q such that R / J ( R ) is a skew field, Le.,
R is a total valuation n'ng in Q , then there exists a one-to-one correspondence
between overrings B of R i n Q and the set of completely prime ideals of R given
b y B + J ( B ) n R a n d P + R S d L = Rp, w h e r e S = R\P.
b) ( [Gra92b]) If R i s a Bezout order in a central simple algebra Q , B is the set of
all Dubrouin vahat ion rings of Q containing R, and P is the set of al1 prime
ideals of R , then the n a p f : B + P given by B ct J ( B ) n R is a uel l defined
anti-order isomorphism iuhere f - l ( P ) = Rp- hfooreouer, R = n Rp where the
intersection .mns over al1 maximal ideals of R, i.e., R is a n intersection of
Dubrocin valuation rings.
Remark 2.3.7 From the result in Remark 2 3 . 6 b), it follows that if R is a
Dubro.uin valuation n'ng in a simple art inian ring Q with finite dimension over i ts
center Ii', then euery prime ideal P of R is Goldie prime and there is a bijection
between specR and the set of al1 ouerrings of R i n Q given by P Rp ( R p i s the
localization with respect to the set CR(P) of elements r E R regular modulo P l . Th i s
result was obtained b y Dubrouin, [DubS5], Theorem 1.
In the following part of this section we discus a theory of divisors of a Dubrovin
valuation ring. The following results are needed.
Lemma 2.3.8 ( [MMU97]) Let R 6e a Dubrovin valuation ring of Q. Then
O , ( J ( R ) ) = Or(Z (R) ) = R.
Proof. Assume R C O,(J( R)). Then by Lemma 2.3.1, there exists a regular element
to E O,(g(R) ) such that R 2 t J ( R ) and hence, ta1 E J ( R ) . But then, 1 E J ( R ) ,
a contradiction. Thus, R = O,(Z(R)). Similarly, R = Oi(Z(R)).
Lemma 2.3.9 Let R be a Dubrovin ualuation r ing o f Q a n d P be a p r i m e ideal of
R. Then O,(P) = Or(P).
Proof. Since the set of al1 overrings of R in Q is linearly ordered by inclusion, we may
assume Of( P) C Or(P)-Then, JyOr(P)) C 3(Ol(P)) . Hence, J (Or (P) ) (Or ( P ) P ) =
(J (O,(P))O,(P))P C 3 ( O r ( P ) ) P E J ( O i ( P ) ) P C O I ( P ) P C P. But 3 ( O r ( P ) )
and O,(P)P are 2-sided ideals of R. Thus, since P is a prime ideal of R, we have
Z(O,(P)) E P or O,(P)P C P, Le, P = J (O , (P ) ) or O,(P) = Or(P) . Thus,
Oi(P) = Oi(z(O,(P)) = O,(J(O,(P)) = Or(P) by Lemma 2.3.S, or O,(P) = Ol(P).
So, in both cases Or( P) = Or(P).
Lemma 2.3.10 ( [MMU97]) Let R be a Dsbrovin ualuation ring of Q , -4 be a n
R-ideal of Q and le t S = O,(A) . T h e n the following are equiualent:
(1) -4 is principal as a right S-ideal.
Proof.
(1) (2 ) : Let A = aS for some a E A. Then A-' = Sa-' and (2) follows.
( 2 ) (3): Let A-'-4 = S. If A = A z ( S ) , then -4-'A = A-'A J(S), i.e., S = J(S),
a contradiction.
(3 ) + (1): Let A > rlZ(S). Then by Lemma 2.3.1, there exists a regular element
t E -4 such that -4,7(S) C tZ(S) C A z ( S ) , that is, tJ(S) = AJ(S). Hence,
t-'AJ(S) = J ( S ) . Therefore, t-'A C 0 i ( 3 ( S ) ) = S. Thus, A E tS , that is,
A = ts. O
On the set of right (left) R-ideals we introduce the following operation:
Definition 2.3.11 Let 1 be a right R-ideal and S = O,(I). LVe de jne 1' = n CS, where c runs over all elements in Q with CS > i. Similady, for any left R-ideal L
with T = O I ( L ) we define *L = nTc , where c r u n s over all elernents in Q with
T c L.
That 1' =*I for an R-ideal I follows from Proposition 3-3-13. In the next result,
the basic properties of the "*"- operation are given. Note that in Chapter 4, we
briefly discuss an analogous operation for commutative rings.
Proposition 2.3.12 ( [MMU97]) Let R be a Dubrouin valuation ring of Q and
let 1 be a e h t R-ideal o f Q . Then:
(3) (ci)' = ci', for any c E U(Q)
(4) (CI)-' = I-'c-~, jOr any c E U ( Q )
Proof. (1) : This is trivial.
(2) : By (l), I' C (1')'. Assume 1' c (1')'. Then, there exists an element
x E (IR)' such that x $- 1'. Therefore, there exists an element bo E Q with boS > 1 but x $ boS. Also, x E CS, for al1 c E Q with CS 2 IV. But, boS > 1 implies 1- Ç boS
and thus, x E b05, a contradiction.
(3) : Let c E U ( Q ) and x E 1' be an arbitrary element. Consider any b E Q such
that b S > cl. Then I C c-'bS and since x E IX, by the Definition 2.3.11, x E c-'bS
so that cx E bS. Thus, c c E (ci)". Since x was an arbitrary element, cl" C (cf)'.
Conversely, let x E (CI)". Let b E Q be any element with bS > 1. Then CI C cbS.
Hence, (cl)' Ç cbS, that is, x E cbS. But, b was an arbitrary element. Therefore,
x E n cbS, with bS > 1, that is, x E c (n bS) = ci' and (CI)' C cl' follows.
(4) : Let c E U ( Q ) and x E I-'. Then cIxc-'ci = cIxI C c l implies xc-' E
( C I ) Thus, 1-'c-' E (CI)-'. Conversely, x E (CI)-', implies c l x c i C cl. Hence,
i x c l C 1, that is, xc E Id' . Thus, x E I-L~-L and (ci)-' 1-'c-l follows.
cl The proof of the following result can be found in [MMUSC].
Proposition 2.3.13 Let R be a Dubrovin vaiuation ring of Q and let A be an
R-ideal of Q. Set S = O,(A) and T = Or( i l ) . Then:
(2) A" = A* and (.il-')' = A-'
( 3 ) I/ -4 is not principal a s a right S-ideal then -4-'A = J ( S ) and J ( S ) is not a
principal right S-idenl.
(4) If -4 c A*, then A' = CS and A = cJ(S) for some regular element c E A*. In
particular, A = A'J(S).
An R-ideal -4 of Q is called divisorid if A = A'. With D ( R ) we denote the set
of al1 divisorial R-ideals of Q. On the set D(R) we define the partial operation "O"
by A O B = (AB)' if A, B E D ( R ) with O,(A) = O1(B) . The next result shows that
( D ( R ) , O) is an algebraic structure known as Brandt groupoid without connectivity
property.
Theorem 2.3.14 ( [Dub84]) Let R be a Dubrovin va[uation ring of Q. Then
( D ( R ) , O) has the following properties:
(1) For every A E D(R), there exist unique elernents &(A) and E f ( A ) in D(R) such
that
( 2 ) For A, B E D ( R ) , the product A O B is defined i f a n d only if Er(A) = Ei(B) .
(3) Iffor A, B, C E D(R) the products Ao B and B o C are defined, then (-4 O B ) O C
and -4 O ( B O C ) are dejîned and they are equal.
( 4 ) For every element -4 E D ( R ) t h e m ezists a unique e lement A E D(R) such tha t
Proof. (1) : Let A E D(R) and set & ( A ) := O,(A), E l ( A ) := Or(A) . Then:
&(A) E D(R) : First, we prove that S := O,(Er(-4)) = O,(-4). For q E S, we
have q E O,(A)q C O,(A). Conversely, q E Or ( A ) implies Or(A)q C Or( A), i.e.,
q E S. Hence,
that is, Er(A) = &(A)' E D(R).
0 A O E,(A) is defined since O,(-4) = Oi(O,(-4)) = Oi(E,(A)).
simiiarly, E I ( A ) E D(R), Ei(A) O A is defined and E l ( A ) o A = -4. The uniqueness
of the right and the left units follows by a familiar argument.
(2) : This follotvs immediately from the defini tion.
(3) : Let A, B, C E D(R) and let Ao B and BoC are defined, Le., 0,(.4) = Oi(B)
and Or(B) = Ol(C). It is enough to prove that
((-4B)'C)' = (ABC)' = (.4(BC)')'
If .4B = (AB)' , then the first equality holds. Let AB c (AB)' and let S = O,(AB).
Then S > O,(B) and since Oi(B) = O,(A) > A-'A, we have A-'AB C B. If
A-'AB = B, then O,(B) > Or(-4B) = S , i.e., S = Or(B) . If A-'AB c B, then
-4-'-4 C Ol(B) = O,(-4). By Lemma 2.3.10, this implies that A is not principal
as a right O@)-ideal. Hence, by Proposition 2.3.13 ( 3 ) , A-'A = J(O,(A)) =
J(Or(l3))- Hence, B > J ( O I ( B ) ) B and by the left version of Lemma 2.3.10, B is
principd as a left Oi(B)-ideai. So, B = Oi(B)b ; for some b E B. Therefore, S =
O,(AB) = O,(AOl(B)b) = O,(AO,(A)b) = Or(Ab) = b-'O,(A)b = b-10i(B)b =
O,(Oi( B ) b) = O,(B). Hence, S = Or(AB) = Or(B). Now, since AB is not divisorial,
by Proposition 23-13 (3) and (4), (AB)' = CS and AB = c J ( S ) , for some c E U(Q),
and g ( S ) is not principal right S-ideal. Then g ( S ) - ' J ( S ) C O , ( z ( S ) ) = S by
Lemma 23-10. Hence, S C Z(S)- ' implies J ( S ) = S J ( S ) 2 g ( S ) - ' J ( S ) 2 J ( S ) ,
i.e., J ( S ) - ' J ( S ) = J ( S ) . This irnplies J(S)- ' C O r ( g ( S ) ) = S , i.e.. J(S)- ' = S.
Finally, by Propositions 2.3.12 and 2.3.13, since Or(C) = O,(B) = S and J ( S ) =
J(Oi(C)) = C we have (ABC)' = (cZ(S)Cjx = c(Z(S)C)^ = c(C)' = (CC)' =
(cOi(C)C)* = (CSC)' = ((AB)'C)'. Similady, (ABC)' = (A(l3C)')'.
(4) : Let A E D(R) and denote S = O,(A), T = Of(A-'). Then S = T. To
prove this, first note that R and S are overrings of R. Since by Theorem 2.3.3 and
Proposition 2.3.2, overrings of R are linearly ordered by inclusion, we can assume
that R S C T.
If A-'A = S, then by Lemma 2.3.10, A = a s for some regular element a E -4 and
also A-' = Sa-'. Hence, q E T implies qSa-' C Sa-', i-e., q E S. So, T C S.
If A-' A c S , then K L A C J ( S ) . Hence, 1 + A-% C 1 + 3 ( S ) C U ( S ) c U ( T ) ,
i-e., A-'A 2 J ( T ) . Assume that S c T. Then A c AT, since otherwise -4 = AT
and T C O,(A) = S. By Lemma 2.3.1, there exists a regular element c E A T such
that A C c J ( S ) C CS C -4TS C .4TT = AT. Multiplying by T on the right, we have
AT = cT. Furthermore, A 5 CS implies c-' E .a-'. Thus, T = c-'-4T A-'AT C
J(T)T = J ( T ) , a contradiction that shows that S = T, i-e., O,(A) = 01(.4-').
Similarly, O, (A-' ) = Ol (A) .
This impiies that the products A-'oA and Ao A-' are defined and by the definition (1) A-' O A = (A-'A)' Ç S* = O,(A)' = O,(A) = S. Hence, A-' o A E. O,(A).
Let c E U ( Q ) be any element such that A%4 C CS. Then c- 'X 'A C S, Le.,
c-'A-' 2 A-'. Hence, C-l E OL(;2-') = O,(A), i.e., 1 E CS. This implies S C
n CS = ( A-' A)' = A-' o A, i.e., A-' O -4 = O,(A) . Similarly, -4 o A-' = OI(A). cS2.44 A
O
Now, we consider a Dubrovin valuation ring R of rank one, that is, J ( R ) and (0)
are the only Goldie prime ideals. Ln this case, the only proper overring of R is Q, and
the opetation "O" is defined on the whole of D ( R ) . The following result shows that for
a rank one Dubrovin valuation ring R, the structure ( D ( R ) , O ) from Theorem 23-14
becomes a group.
Theorem 2.3.15 Let R be a Dubrouin ualuation ring of Q of rank one. Then
( D ( R ) , o ) is a group.
Proof. By Theorem 2.3.3 t here are no proper overrings of R in Q. Hence, for every
A E D(R), O,(A) = Ol(A) = R. Thus, for any two elements A? B E D(R),
O,(A) = Oi(B) = R, that is, A O B is defined. So, "O" is defined on the whole of
D(R)-
Furthemore, there exists a unique element E = R E D ( R ) such that for every
A E D(R) , A O E = E O A = A, that is, there is an identity element in D ( R ) .
Finally, for every A E D(R) , there is a unique element A-' E D( R) (see the proof
of Theorem 23-14) such that -4 O -4-L = Or(A) = O,(-4) = A-' O -4 = R = E. Since
"0" is associative, ( D ( R ) , O ) is a group.
O
Now, we consider Goldie prime ideals of a Dubrovin valuation ring. We first show
that in the special case of the total valuation ring, the classes of Goldie prime ideals
and completely prime ideds coincide.
Proposition 2.3.16 Let R be a total ualuation r ing in a skew field Q , and let
P be a prime ideal of R. Then, P is a Goidie prime if and only if P is completely
prime.
Proof. Assume that P is a Goldie prime. Then, by Theorem 2.3.3, S = Rp zp R
is a Dubrovin valuation ring of Q and J(S) n R = P. But, by Corollary 2.2.5,
J ( S ) 2 J ( R ) c R, so that P = J(S). On the other hand- S as an overring of
R in Q, is a total valuation ring in Q. Hence, Ç = S/J(S) is a skew field. Thus,
R = R / P = R / J ( S ) is a subring of a skem field S, that is, R / P is an integral
domain. So, P is a completely prime ideal.
Conversely, if P is completely prime ideal, then R/ P is an integral domain. Also,
R is a Dubrovin valuation ring in Q with R = R/J(R) is a skew field. Hence, d(R) =
d ( R / J ( R ) ) = 1. By Theorem 22.8, R is a l-chain domain; so by Remark 1.1.11,
E = R/ P is also 1-chah dornain such that R / z ( E ) = RI P / T ( R ) / P "- R / z ( R ) is
a skew field. Again, by Theorem 22.8, R / P is a Dubrovin valuation ring in R, Le.,
R / P is a prime Goldie ring. Thus, P is a Goldie prime.
T h e natural question is: Does there exist a Dubrovin valuation ring with a prime
ideal that is not Goldie prime? This question was raised by H.H.Brungs and G.Torner
in [BT76]. in the form: Does there exist a prime c h a h ring with zero divisors, Le., a
chain ring with a prime ideal that is not completely prime? N-Dubrovin, [Dub93],
gave the positive answer t o this question.
Example 2.3.17 ( [Dub93]) There exists a Dubrovin ualuation ring with a
p r i m e ideal that is not Goldie prime.
Proof. Consider the group SL(2 , R ) of 2 x 3 matrices with real entries and determi-
nant 1. Then
are subgroups of SL(2 , R ) and every element s E S L ( 2 , IR) can be written in a unique
way a s s = r ( p ) u for r ( y ) f S, O 5 y < 27r , u f U.
Consider now first the universal covering group l? of S where l? = {xt 1 t f R } with
xt1xt2 = xtl+t2 as operation, and xt' 5 xfz if and only if t 5 t 2 . AS a linearly ordered
group, I' is isomorphic to (B, +, 5). The covering map r from R t o S with r(xt) = r ( t )
is a homomorphisrn with Ker T = (x2"), the cyclic subgroup of B generated by x2'.
Next we define the covering group G of SL(2 , B) as the set G = { x t u 1 xt E r, u E
LJ} with the operation given by:
where 9 E [O, 2rrj and u l r ( y ) = r(+)u; for $ E [O, 2 ~ ) . The mapping T above is
extended to a map from G to SL(2 , R) by defining r (x t i r ) = r ( t )u .
Finally, we consider the subsemigroup P = {xru 1 O 5 r E R, u E U) of the group
G. Then P U P-' = G and P n P-' = U. The element x" is contained in P and is
central in P. So, Q = x"P is an ideal of P, properly contained in the maximal ideal
J ( P ) and, in addition, n Qm = n xTmP = 0. Since x"/2xr/2 E Q but x " / ~ Q, Q is
a prime ideal in P that is not completely prime. It can be shown that P satisfies the
conditions of Theorem 1.3.3. hence, there exists a skew field D and a total valuation
ring S in D associated to the cone P. By Theorem 1.3.1, the corresponding ideal
y(Q) = QS = xTPS is a prime ideal of the ring S that is not completely prime. Now,
applying Theorem 1.3.5 and Proposition 2-3-16, S is a Dubrovin valuation ring with
a prime ideal y(Q) that is not Goldie prime.
17
The following results show that Goldie prime ideals of a Dubrovin valuation ring
R in Q have nice properties. These resuIts are important steps for describing the
structure of ideals in Dubrovin valuation rings. But first, we prove the following
basic fact which we will use frequently.
Lemma 2.3.18 L e t R be a Dubrouin uafuation ring of a simple artinian ring Q
and let S be an ouerring of R in Q. If 1 # R is a non-zero ideal of R sach that
I 3 g ( S ) , then iS = S.
- Proof. The ideal I/J(S) is a nonzero ideal in R = R / g ( S ) which is a Dubrovin
valuation ring in 3 = S / g ( S ) by Theorern 2.3.4. Since R is a prime Goldie ring, the
ideal I / J ( S ) is essential and by Theorem 1.1.5, it is a regular ideaI. So, there exists - an element r E 1 so that r + J(S) is a regular element in R = R / J ( S ) . Hence,
r + J ( S ) is a unit in 3 = S / g ( S ) , that is, r E U(S). Thus IS = S.
Proposition 2.3.19 Let Pi be Goldie primes in R, i E A. Then P = n Pi is a
Goldie prime.
Proof. Since Pi is Goldie, the localkation Rp, eXists for every i and we set S = U Rp,.
The overrings Rpi of R in Q are totally ordered by inclusion. Hence, S is a ring in Q
containing R. By Theorem 2.3.4, S is a Dubrovin valuation ring of Q and z ( S ) C Pi
since Rpi C S. It follows that z ( S ) is a Goldie prime contained in P (Theorem 2.3.3).
Assume that P > z ( S ) . Then by Lemma 2.3.18 we have PS = S. Hence,
1 = C pisi for elements pi in P and si in S = U Rpi. But, the rings Rp, are totally
ordered by inclusion. SO, there exists an index jo E A with si E Rp,, for al1 i and
pi E P C Pjo-
Therefore, 1 = C p i s ; E Pj0Rp,. = Pjo, a contradiction that shows P = J(S),
which is a Goldie prime.
O
Lemma 2.3.20 Let I # R be a non-zero ideal in R with I = 12. Shen I is
neither a principal right O,(I)-ideal nor a principal left O[([)-ideal.
Proof. Both S = O,(I) and T = Oi(I) are overrings of R and hence either T C S
or S C T? since the overrings of R are linearly ordered by inclusion. It is enough
to consider the case T C S. We show first that I 2 J ( S ) . Otherwise, I > J ( S )
and by Lemma 2-3.18, it follows that S = IS = I, a contradiction that proves
I J ( S ) . Assume that I is principal as a right S-ideal, i-e., I = as. Then, by
Corollary 1.1.4, a is regular element. Then, a S = I = IZ = aSaS implies S = Sas
and 1 = Cy='=, siat;, si, t ; E S, follows. Since S = Rs(s) = J(s$3, t here exist elements
c. d in CR(J(S)) with CS; E R, t id E R for al1 i. Hence cd = C cs;at;d E I Ç, g ( S ) ,
a contradiction which proves that I is not a principal right S-ideal. Since T 2 S
implies I 5 J(S) 5 J ( T ) , a similar argument shows that I is not a principal left
T-ideal.
O
The next result shows that idempotent ideals # R are Goldie primes.
43
Proposition 2.3.21 Let I2 = I # R be an idempotent ideal. T h e n the following
hold:
b) 1 = J ( S ) is a Goldie prime with S = R3(sp
Proof. Let S = O,(I) and T = Or([). It is enough to consider the case S C T. From
Lemma 2-3-20, it follows that I is neither a principal right S-ideal nor a principal left
T-ideal. Hence, I-'1 = J ( S ) and II-' = J ( T ) by Proposition 2.3.13(3). Further,
Id' = {x E Q 1 X I C S } = ( S : I ) [ _> T. Conversely, if x E (S : I ) ( , then X I C: S
and XI = x12 C S I C I , and x E T follows; we have proved that 1-' = T. However,
IIdi = J ( T ) C g ( S ) J ( R ) c R implies 1-' C (R : I),. Further, if q E ( R : I),,
then Iq & R C O,(I), i.e., Iq = I I q C I . Hence, q E O , ( I ) = S , i.e., ( R : I ) , C S.
Thus T = 1-' C S and T = S follows which proves a).
Now, 37s) = 1-'1 = T I = I which proves that I is Goldie prime, since J ( S ) is
a Goldie prime. In addition, S = R3(s) follows and both parts of b) are proven.
O
The nest result shows that the union of Goldie primes is again a Goldie prime.
Corollary 2.3.22 Let R be a Dubrovin ualuation ring and let R > Pi, i E h, be
Goldie primes in R. Then:
a) P = (J Pi is Goldie prime;
Proof. If there exists a Pj with Pj > Pi for al1 i, then P = Pj is a Goldie prime,
Rp = Rp, = n Rps, and P = z( R p ) implies Q ( P ) = O, ( P ) = R p , by Lemrna 2.3.8.
We can therefore assume that for every Pi there exists a Pj with Pj > Pi::. Hence,
P > Pi for al1 i, and P > P2 > Pi for all i, since otherwise Pz Pi, which would
irnply P C Pi, since Pi is prime. It foliows from Proposition 2.321 that P = P2
is a Goldie prime with Rp = O I ( P ) = Or(P)- It remains to prove that S = O!(P)
where S := n Rp, . Let x E O l ( P ) , hence x P C P. Since P > Pi is an ideal in R
and R/P, is Goldie, P contains an element in CR(Pi) and PRF. = Rpi. Therefore,
xRe = x P R R c PRp, = Rpi ; so x E Rpi for al1 i; hence x E S follows. Conversely, if
x E S and a E P, then there exists Pi with a E Pj, and xa E SPj C RpJPj = P, c P
proves x E O[( P ) ; so S = Or ( P ) follows.
O
Now, let I # R be an ideal of R that is not Goldie prime. Then, the families:
R = {P 1 P is a Goldie prime, I c P}
S = { P 1 P is a Goldie prime, P c I }
are not empty since J ( R ) E R and (0) E S. By Proposition 3-3-19 and Corol-
lary 23-22, Pl = n { P 1 P E R) and P2 = U { P 1 P E S ) are Goldie primes,
Pl > 1 > PZ and and no further Goldie prime ideal exists between Pl and R2.
Definition 2-3.23 Let R be a Dubrouin ualuation ring of Q . A p r i m e segment
of R (and of Q ) is a pair of two distinct Goldie primes Pl > P2 > ( O ) in R so that
no further Goldie prime exists between Pl and Pz.
The next result is the most important for the study of prime segments of a
Dubrovin valuation ring.
Theorern 2.3.24 Let I # R be an ideal in the Dubrovin valuation ring R. Then
r) In = P is Goldie prime.
Proof. The result follows if 0 In = f m for a certain m, since then ( I m ) 2 = Im is
idempotent and we can apply Proposition 23.21. We c m therefore assume that
and show that the assuming P not to be Goldie prime leads to a contradiction.
First, let A and B be ideals of R such that P C *4 and P c B. Then there exists
an 72 such that In C A and 1" B. Otherwise, for al1 n, A 2 In c 1 or B C In C 1,
Le., -4 C n In = P or B C In = P, a contradiction. Thus, .AB > I n l n = 12" > P;
so, P is a prime ideal.
If 1 itself is not Goldie prime, then by the remark above, there exists a prime
segment PL 2 P2 in R with Pl > I I ) P2.
If I itself is a Goldie prime that does not have a lower neighbor among Goldie
primes, then I = (J Pi for Goldie primes I > Pi. In this case, I > I2 > Pi for al1
i and hence I = 12. So, P = n In = I is a Goldie prime, which is a contradiction,
since P is assumed not to be Goldie prime.
Therefore, we can assume that there exists a prime segment Pl > P2 in R with
Pl > I 2 P2 - We define N : = Pi 1 Pl C 1. Then I3 = I l i E Pl I Pl = iV and t herefore
n In = n N n = P follows; in addition, N and P are Rpl-ideals. After localizing at
Pi we obtain Rpl > Pl > N > n Nn = P > PZ and P is not Goldie prime in Rpl.
We therefore can consider Rp, / P2 and can assume from now on that R has rank one
with R 3 J ( R ) = P, 2 1V II n N n = P 3 (0).
We consider the following set W of ideals in R :
W = { L 1 Pl > L > P, L an ideal of R);
note that W contains Nn for n 2 2. Two cases may happen.
Case 1- : IV contains a n ideal L which i s not divisorial
Then L c Lœ where L' = n C R with CR > L (by Definition 2.3.11 and the fact
that R is of rank one and hence O,(L) = R).
It follows from Proposition 2.3.13 (1) and (4), that L' = (15-')-', L' = a R and
L = aJ(R) = aPL for some unit a in Q. Note that a is regular but not a unit in R
sinceotherwise L = a J ( R ) = a R g ( R ) = R J ( R ) = J ( R ) = Pl. Aiso, L* = a R C Pl.
Since O I ( L = ) = aRa-l = R we have Lm = a R = Ra and (L-)" = anR = Ran for
n 2 1.
It follows that the set C = {an 1 n = 1,2,. . . ) is an Ore system in R, and since
a-' 6 R, we have R c RC-' C Q ; Le., RC-l is a proper overring of R. Hence,
RC-l = Q. Since P is a non-zero ideal in R, it contains a regular element c and
C-l = ra-" for some r in R and some n 2 1. Hence, an = cr E P: which implies
(L')" = anR 5 P ; so Lw 2 P c L c Lm7 which is a contradiction.
Case 2. : L = L u f o r aLZ L E t V
Let L E W and consider the R-ideal L-l ; it is divisorial since (L-')= = ((L-l)-l)-l =
(L=)-l = L-l. We cclairn that L-' > B. Otherwise, L-' = R and (L-IL) ' = L* = L.
On the other hand, by Theorem 2.3.15, (L-' L)' = L-' O L = Or(L) = R, a contra-
diction.
We consider ilo = (J L-l? L E W, and want to prove that A. is an overring of R,
hence equai to Q. Let x, y be elements in A. and x E L;', y E LyL for LI , L2 f W
follows. Either Ll C L2 or Lz C L L and we can assume LI C L S -
Since
for any non-zero ideal L of R, it follows that L;' C L;' and s & y E L;'.
Further, L;' LY 'L~L* 2 L;'RLl C L;' L~ C R shows that LF'L;' C
(R : L2L1)i = (&Li)-', and xy E (L2Ll)-l. In order to see that xy E Ao, note
that Pl > Li > P and Pl > Lz > P imply Pl > Lz Ll > P since P = n Nn and
Nn+l C Nn for al1 n.
To reach the final contradiction we choose a r e g d u element c in P # (O). Since
Q = AO = U Lw', L E W, there exists L in W with c-' E L-'. Therefore, C-'L C
L-'L R and L E CR C P7 but P c L. It follows that P = n In is Goldie prime.
Lemma 2.3.25 Let R be a rank one Dubrouin valvation r ing . Then the group
( D ( R ) , o ) is order isomorphic tu a subgroup of (R, +), the additive group of real
nurnbers.
Proof. CVe define a binary relation " 2 " on D( R) by A 2 B if and only if -4 C B,
for all A, B E D(R). Clearly, the relation " 2 " is reflexive, antisymmetric and
transitive, Le., it is a partial order on D(R). Since the elements in D(R) are totally
ordered by incIusion, the relation " 2 " is a total order. Furthermore, -4 C B
implies AC BC and CA C C B for al1 A, B, C E D ( R ) . Hence, A C B implies
-4 O C = (-AC)' C (BC)' = B O C and C O A = (CA)' (CB)' = C O B for al1
A, B, C E D(R). Therefore. " 2 " is compatible with " O " and (D(R), O , 2) is a
totally ordered group.
Vie prove that D(R) is an archimedean group, i-e., for a11 1, B E D(R) with
1 C R, there exists an integer n such that ( In)* c B.
Clearly, it is enough to prove that for every I E D( R), I C R , the intersection
ri = n ( r n ) - = (01. Let 1 E D(R), I c R. Then I C J = J ( R ) . If I c J, then by Theorem 2-3-24,
n in = ( O ) , since J > (O) is a prime segment. If I = J > J2, then by the same
argument, again In = (O) . We are left with the case I = J = J2. In this case, by
Lemma 2.3.10, J is not principal as a right R-ideal, since O,(J) = R. This implies
that J' = R. In fact, if J C CR for some c E U(Q), then c-'J C R and, hence,
Rc-'RJ 2 R. If Rc-'RJ = R, then ( R : J)iJ = R, i.e. J-' = (R : J) i . This implies
J-'J = R = O,(J) and by Lemma 2.3.10, J is principal as a right R-ideal, a con-
tradiction. So, Rc-'RJ C R, i-e. Rc-= R J 2 J which implies Rc-'R C Oi(J) = R,
Le. R C CR. This means that I* = J* = R > J = 1 , that is, 1 is not divisorial, a
contradiction. Therefore, the case I = J = J2 cannot arise; so n In = ( O ) holds for
any I f D(R), 1 C R.
Now, assume that K = n(In) ' # (O). First note that I< is divisorial, since
Ic 2 ( In)= for al1 n implies h" C ((In)')' = (In)' for al1 n, i-e., Ii' C n(In)* = Iï
and K = K* follows. Hence, there exists an integer k, such that K > ik. Otherwise,
1; c n Ik C n ( l q x = A', i-e. (O) = 1;. NOW, K' = K > (1")' 3 ( IN1)= , since if
( r k ) = = (Ik+')=, then I = R, because ( D ( R ) , o ) is a group. Hence, K > (Ikf')- > n ( ï k ) - = I<, a contradiction which shows that I< = n ( I n ) ' = (O) , i.e. (D(R), O) is
an archimedean group. By Holders Theorem, (see for example, [Sch50]- Theorem 1,
Chapter l), D(R) is order isomorphic to a subgroup of (W. +).
In the case of a Dubrovin valuation ring R of rank one, the group (D(R), O, 2)
contains a subgroup we denote by H(R) := {I E D(R) 1 I = aR, O # a E Q), i-e.
the set of al1 those non-zero ideals I which are principal as right R-ideals. For,
if 1 = aR E H ( R ) , then a is a regular element, i.e. a is a unit in Q. Hence,
Oi(a R) = a Ra-' and since R is of rank one, aRa-' = R, i.e. a R = Ra. Therefore,
for aR, bR E H(R) we have aR O bR = (aRDR)' = (abR)' = abR E H(R) and
I-' = Ra-' = a-'R E H(R).
Let I be any non-zero R-ideal in Q. Then 1 is either divisorial and then I = I' E
D(R) or I c 1' and then by Proposition 2.3.13 (4), 1' = a R = Ra E D(R) and
I = aJ(R)(R) for some a E U ( Q ) . Therefore, the lattice of al1 ideals of rank one
Dubrovin valuation ring R is known completely if D(R) and H ( R ) are known.
The next result describes two possibilities for an arbitrary p i m e ideal in a Dubrovin
valuation ring R.
Proposition 2.3.26 Let R be a Dubrouin valvation ring of Q , [et P be a prime
ideal of R, and S = O,(P) = Ol(P) . Then P is either a Goldie prime and P =
J ( S ) , o r P is not Goldie p r i m e and J ( S ) is the minimal Goldie pr ime containing
P. iWoreover, i n the second case, there is no ideal of R properly between P and z ( S ) .
Proof. Since 1 + P C U ( R ) C U ( S ) , clearly P C J ( S ) .
If P = J ( S ) ? then P is a Goldie prime, by Theorem 2.3.3.
If P c J ( S ) , then P is not a Goldie prime, since otherwise R p P = P , i.e.,
Rp C O 1 ( P ) = S , which contradicts S c Rp.
Let I be an ideal of R such that P c I C z ( S ) . Then by Theorem 2.3.24,
Pt := n In is a Goldie prime. Also, P c Pl, since P c In, for al1 n. Otherwise,
there exists an n such that I" C P and then I C P, a contradiction. Furthermore,
POr(P1) P' = POl ( P l ) P' C P P' 2 P. Since P O r ( P f ) C P' c R, clearly PO, ( P t ) is
a two sided ideal of R. Hence, PO,(Pf) C P since P is a prime ideal and P' P.
so, O r ( P f ) C O,(P) =S.
Hence, by Lemma 2.3.8,
Corollary 2.3.27 If P is a prime ideal of a Dubrovin valuation ring R that is
not Goldie prime and S = O,(£') = Oi(P) , then J ( S ) > P > n Pn is the "highest"
prime segment i n ring S .
Chapter 3
Prime Segments
The existence of a Dubrovin valuation ring R in a simple artinian ring Q wi th a prime
ideal I that is not Goldie prime irnplies the existence of a prime segment Pl > I > Pz,
consisting of a pair of two distinct Goldie primes Pl and Pz in R such that no further
Goldie prime esists between Pl and Pz (see Example 2.3.17 and the remark after
Corollary 2-3-22).
In the last decade, prime segments were defined and studied in different situations.
In [BD], H.H. Brungs and N.I. Dubrovin considered prime segments in total valuation
rings . They classified prime segments and in the rank one case described the structure
of al1 ideals. Also, examples for al1 cases were constructed. In [BS95], H.H. Brungs
and M. Schroder defined prime segments in valued skew fields and gave methods for
constructing valued skew fields with prescribed types of prime segments. In [DD96],
the structure of ideals and prime ideals in a cone P of a right ordered group G is
studied. The rank one case is described completely and corresponding examples are
constructed. In [BTgS], H.H. Brungs and G. Torner defined right cones and classified
t heir prime segments.
Note that prime segments correspond to jumps in ordered and right ordered
groups. Let (G, P ) be a right ordered group with the positive cone P, Le., PP C P ,
P n P-' = { e } and P U P-l = G. A subset H C G is called convex if x, y E H
g E G, x <_ g 5 y implies g E H. The set Z of al1 convex subgroups of G is a
chain containing ( e ) and G. If CA (A E h ) is in S, then n C.1 and U C.1 are again
in E. Hence, every element g # e in G defines two subgroups Dl C E C so tha t
C > Dl g E C \ D, and C contains no convex subgroups strictly between C and D.
Such a pair C > D is called a jump in C (see [Iiop98] and [Fuc63]). In this situation
there exists a 1 - 1 correspondence between Z and the set of al1 completely prime
ideals of the cone P. More preciselÿ:
Theorem 3.0.28 Let (G, P ) be a right ordered group.
If A E Co A # G, is a conuex subgroup of G then I = P\ ( P il) is a completely
prime ideal of the cone P.
Conuersely, if 1 # P is a comp[etely prime ideal of the cone P , then A = ( P \ 1) U ( P \ 1)-l is a conuex subgroup of G.
By this correspondence, jurnps in C correspond to the prime segments in the cone
P.
In this chapter, prime segments in a Dubrovin valuation ring R are classified and
the structure of the lattice of al1 ideals in the rank one case is completely described.
The results obtained show that there exists a complete analogy between the ideal
structure of a cone in a right-ordered group and the structure of ideals of a Dubrovin
valuation ring in a simple artinian ring.
3.1 Prime segments in Dubrovin valuation rings
In this section, R denotes a Dubrovin valuation ring in a simple art inian ring Q.
Definition 3.1.1 Let Pl ZI P2 be a pr ime segment of R.
52
The prime segment Pl > P2 is called archimedean if for al1 a E Pl \ P2 there exists
an deal I E Pl such that a E I and n In = Pz.
The prime segment Pl > Pz is- called simpIe i f there are no ideals between Pl and
p2
The is called exceptional i f there exists a prime ideal I in R that is not Goldie
prime such that Pl 2 i 3 Pz-
Lemma 3.1.2 Let Pl > P2 be a prime segment in R.
i) If PL > P2 W exceptional and i is a prime ideal that is not Goldie prime such
that Pi > 1 3 Pz, then there are no ideais between Pl and I , Pl = P: and
nrn = pz,-
ii) If Pl > P: or Pl = U 1, I c Pl, Le., Pl is the union ofideals 1 properly contained
in Pl, then the prime seg.ment PL > Pz is archfmedean.
Proof. i) Let L be an ideal of R such that PI > L 2 1. Then by Theorem 23.24,
P = Ln is a Goldie prime ideal of R and Pl > L > P 3 1 > P2, a contradiction.
Furthermore, P: > I since otherwise P: Ç 1, which implies Pl C 1. Hence, Pl = P:.
A ~ S O , n rn = pz.
ii) First, assume that Pl > P: and let a E Pl \ Pz. Set 1 := Pl. Then a E I and
n In = n PT C PL c Pl Hence, n In = P2 since n In is a Goldie prime.
Next, assume that Pl = (J 1, the union of al1 ideals I properly contained in Pl
and let a E Pl \ Pz. Then there exists an ideal 1 c Pl such that a E I. Then
Pl > I > n In 2 Pz, i-e n in = PZ, by the same argument as in the first case.
O
The next result shows that there are exactly three types of prime segments in a
Dubrovin valuation ring R.
Theorem 3.1.3 For a prime segment Pl > f i of a Dubrouin uahation ring R
exactly one of the follo-wing possibilities occurs:
a ) Pl > Pz is archimedean;
b ) Pl > P2 is simple;
c ) Pl 3 P2 is exceptional.
Proof. Let L := (J 1 be the union of al1 ideals 1 of R properly contained in Pl. If
L = P2, t hen there are no ideals between Pl and Pz, Le., the prime segment Pl 3 P2
is simple.
Next, we prove that the prime segment Pl 3 P2 is exceptional if and only if
Pl > L > P2 and Pi = P:.
Let these conditions be satisfied. Then L is a prime ideal of R. For, if B and C
are ideals of R such that B > L and C > L then B 2 Pl and C _> PL since otherivise
B C Pl or C C Pl, Le., B C L or C C L. Hence, BC > P: = Pl 3 L. So, L is a
prime ideal that is not Goldie, i-e., the prime segment PL > Pz is exceptional. The
converse was proved in Lemma 3.1.2.
We are left ivith the case that Pl > P: or Pl = U 1 for ideals I of R with
Pl > 1 > P2. In both of t hese cases the prime segment Pl 3 P2 is archimedean, as
we have shown in Lemma 3 - 1 2
cl
Consider the set K ( P 1 ) := {a E Pi ( PlaPl c Pl) . Theo, for any r E R and
a E I i ( P l ) , PlruPl Ç PlaPl c Pl and PlarPl C PinPl C Pt, i.e., ra, ar E I i ' (9 ) .
.-lso, for a , b E IiW(Pl) we have PlaP1 E PlbPl or PlbPl C PlaPl. In the first case,
Pl ( a + b) Pl C Pl bPl c Pl. Hence, a + b E Ir'(Pl). Similarly, in the second case,
a f b E Iip(Pl). Therefore, Ii(Pl) is an ideal of R. Using the ideal K( Pl ), we can
prove the following result :
Corollary 3.1.4 The prime segment Pi 3 Pz of R is archimedean if and only i f
IC(Pl) = Pl, it is simple i f and onZy i f I i (P l ) = P2 and it is exceptional if and only
if PL > K ( P l ) 3 P2. In the fast case, K ( P 1 ) is n prime ideal that is not Goldie.
Proof. First, let Pl > P2 be archimedean. For any a E Pz, PlaPl C - Pz c PL, i.e.,
a E K(Pl ) . If a E Pl \ P2 then there exists an ideal 1 c Pl, such that a E 1. Hence,
P1aPL C I c Pl, Le., a E I i (P l ) . So, Pl C K ( P l ) C Pi, Le., l i ( P l ) = PL.
Conversely, let K ( P l ) = Pl and assume that Pl > Pz is not archimedean. If
Pl > P2 is simple and a E Pl \ P2 then f i > P& > &, a contradiction. If PL > P2
is exceptional, then for a prime ideal I that is not Goldie such that PL > I > P2 and
a E Pi \ I , we have Pla PL = Pl Ra RPl C 1 c PL, since there are no ideals between
Pl and 1 by Lemma 3.1.2 i). But 1 is a prime ideal of R. Bence, PL C 1 or Ra R C 1,
a contradiction which shows that Pi 3 Pz is archimedean.
Next, let PL > 6 be simple and assume that there exists an element a E I i ( P l ) \ P2. Then PL > PluPl 2 P2, since PLaPl = Pl RaRPl 2 P2 implies Pl 2 P2 or a E P2-
But this is impossible. So, l i ( P l ) = fi.
Conversely, let K ( P l ) = P2 and assume that Pl 2 P2 is not simple. If Pl > Pz
is archimedean, then for a E Pl \ Pz there exists an ideal 1 c PL with a E 1. Then
PlaPl 2 I c Pl, Le., a E I i (P l ) = P2, a contradiction. If Pl > P2 is exceptional
than for a prime ideal I of R that is not Goldie with PL > 1 3 P2 and a E I \ P2, we
have fiaPl C I c Pl, i.e-, a E L'(Pl) = P2: a contradiction.
Finally, let PL 2 P2 be exceptional and let I be a prime ideal of R that is not
Goldie such that PL > I > Pz. If a E IC( Pl) \ I then Pla Pl C 1 C Pl . Hence, Pl C I
or a E 1, a contradiction which shows that I = K ( P l ) .
Conversely, let Pl > K(Pl ) > Pz. First, there are no ideals of R between PL and
h'(Pl). For, if 1 was an ideal of R such that Pi > I > I i (P l ) , then for a E I\ K ( P l )
ive would have PLa Pl E 1 c PL, Le., a E &.'.(Pl). Secondly, K ( P 1 ) is a prime ideal of
R. For, if B and C are ideals of R such that B > K ( P l ) and C > IC(Pl), then, as
noted first, B > Pl and C > f i . But Pl = P:, since P: c Pl implies P; c Pl, Le.,
Pl C I i (Pl) , a contradiction. Hence, BC > P: = Pl > K(P1). So, Ii(P1) is a prime
ideal of R that is not Goldie, and the prime segment Pl > P2 is exceptional.
It follows from this result that the type of the prime segment Pl > Pz is the same
for any Dubrovin valuation ring R of Q that contains this prime segment.
3.2 Rank one and discrete Dubrovin valuation rings
Let R be a rank one Dubrovin valuation ring of Q. Then Q is the only proper overring
of R and we have shown, see Theorem 2-3-15 and Lemma 2.3.25, that (D(R), O, 2) is
a group, order isomorphic to a subgroup of (R, +). Also D ( R ) contains the subgroup
H ( R ) of al1 nonzero ideals which are principal as right ideals. Using these facts and
Theorem 3.1.3, we now proceed to give a complete description of the lattice of two
sided ideals for rank one Dubrovin valuation rings.
Theorern 3.2.1 Le t R be a rank one Dubrouin valuation r ing o f the simple ar-
t in ian ,ring Q with m a x i m a l ideal J = J(R).
Then exactly one o f t he following possibilities occurs:
a ) The segment J > ( O ) is archimedean and either
i ) J > J 2 and t h e n D ( R ) ( J ) H(R) is an in f in i te cyclic group; o r
ii) J = J 2 and t h e n D(R) i (R, +) and H ( R ) is a dense subgroup of D(R).
b) T h e segment J > ( O ) is s imple and then D(R) = H(R) = {R) is the trivial group.
c ) T h e segment J > ( O ) is exceptional. In th i s case i f 1 is a n o n Goldie pr ime of
R with J > I > (O) , then D(R) = (1) is the inJinite cyclic group generuted b y
I = 1' and a n integer k 2 O ez is ts with H ( R ) = ((Ik)') ( the segment is said t o
be exceptional o f type b).
Proof. We saw in Lemrna 2.3.25 that D ( R ) is an archimedean group.
C L A I M : A s s u m e that R contains a max imal divisorial ideal 1 C R, and let C C R
be a n y divison-al ideai. T h e n there exists a n integer n 2 1 such tha t C = (In) ' .
Since ( D ( R ) , O ) is archimedean with the identity element R, there exists a minimal
n with n 3 1 and C > In. Hence In-' > C > (In)' and (In-')' > C. Therefore,
since " O '' is compatible with "2" we have
and, by the maximality of 1, since C O (I-("-'))= = (C(I-(n-l))-)* is divisorial, we
have I = C 0 (I-("-'))'. Therefore, C = (In)' and the clairn is proved.
a) Let J > (O) be archimedean. Two cases occur, J > J2 and J = J 2 .
By Lemma 23-10, we have J > J2 if and only if J is principal as a right R-ideal,
since S = O,( J ) = R, Le., J = a R. Then, as noted after the proof of Lemma 2-3-25?
O i ( J ) = aRa-' = R. Hence, J = a R = Ra C R is a maxima1 divisorial ideal of R.
By the claim, J is a genrrator of the group D(R); so this proves the case a) i).
Next we consider the case a) ii) where J = J 2 and J > (O) is an archimedean
segment. For every non-zero element a in J there exists therefore an ideal Il 2 J
such that a E 11 and n 1; = O. Then RaR C Il c J, since Ii = J would imply
J = n Jn = n 1; = O, which is a contradiction. We want to show that the ideal
I = RaR is a principal right R-ideal for any O # a in J and hence that I E H ( R ) .
If 1 is not right principal, then IJ = I (Lemma 3-3-10) and a = CQ, riasi with
ri E R, S i E J , for al1 i. Since R is a left Bezout order there exists s in R with
Rsl + - - - + Rs, = Rs; hence O # s E J, T2 = RsR c J and 1 = IT2 follows.
Since Tl = J and O,(T*) = R is right Bezout, we can apply the left-right sym-
metric version of Lemma 2.3.1 to obtain a regular element to in TL = J such that
T' = RsR C Jto. Hence, I = TT2 2 IJto C I J = I and I = I J t o = Tto foliows. Since
to is regular, f o l exists in Q. Now, Itol = 1; so tôl E O,([) = R, a contradiction
since to f J.
This proves that 1 = RaR is in H(R) for any O # a E J. Finally, for every
RaR c J there exist b E J\ RaR and RaR c RbR c J follows; H(R) and D(R) are
therefore isomorphic to dense subgroups of (R, +). Since the intersection Ii = n Ii of
divisorial ideals of R is divisorial if I< # (O), D(R) is also complete and D(R) - (Et, +)
follows.
The assertion in case b) is trivial.
It remains to consider the case c) where J > I > ( O ) is an exceptional prime
segment. In this case, J = J2 is not principal as a right R-ideal, and as in the
proof of Lemma 2.325, Js = R, i.e J is not divisorial. But I' = I , since otherwise
I 3 1, J > 1, yet 1 = I*J by Proposition 23 -13 (4), which is a contradiction for
the prime ideal 1. Hence, 1 is a maximal divisorial ideal (there are no ideals of R
between J and 1). Therefore, D(R) = (1) by the claim and H ( R ) is then equal to
((1")-) for some li 2 0.
O
The exceptional case is the most interesting. It splits into countably many sub-
cases, depending on the integer li 2 O. We give chains of d l ideals in every case.
If R = O, then H ( R ) = {R), i.e., there are no principal right ideals. If L is any
ideal of R, then either L = L' E D(R) = (1) or L c L* and then L' is a principal
right ideal of R, i.e.: Lx E H ( R ) . Hence, L' = R and L = J. Therefore, the proper
ideals of R are J, (0) and powers of 1, i.e,
is the chain of al1 ideals of R.
If k = 1, then H ( R ) = (1) = D(R) . Hence, 1* = 1 = aR = Ra is principal,
(In)*=aRoaRo---oaR=(aRaR-.-aR)'=anR= Ran and
is the chain of al1 ideals of R.
Ifk > 1, then H ( R ) = ( ( I V * ) ) . Hence, (Ik)* = aR = R a and I" a J. This follows,
since Ik c ((I).. Otherwise, I~ = (1"). = aR and then I'J = a R J = aJ C U R = 1'.
Hence, I J c 1. B y Lemma 2.3.10, 1 is a principal right R-ideal ând the contradiction
k = 1 follows- In the case k > 1, the chain of al1 ideds of R is therefore:
To analyze the prime segment of a rank one Dubrovin valuation ring R in a simple
artinian ring Q with finite dimension over its center K , the following result is needed:
Lemma 3.2.2 ( [MMUW], Lemma 7.9 Chapter II) Let R be a Dubrouin
ualuation r ing in a simple artinian r ing Q with Jînite d imens ion ouer its center K .
I f Z ( R ) is f initely generated as a n ideal, then g ( R ) # J(R)* .
The next result shows that in the finite dimensional case the prime segment of a
ranli one Dubrovin valuation ring R is archimedean.
Lemma 3.2.3 If R is a rank o n e Dubrouin ualuation ring i n a simple artinian
ring Q with finite dimension ouer its center I ' , then the prime segment J ( R ) > ( 0 )
m u s t be archimedean.
Proof. By Remark 2.3.7, every prime ideal of R is Goldie. Hence: J ( R) > ( O ) is not
excep tional.
Assume that the prime segment z ( R ) > ( O ) is simple.
Case 1. : J ( R ) i s f ini tely generated as a n ideal
Then, by Lemma 3.2.2, J ( R ) > J ( R ) 2 > ( O ) . But, by Lemma 2.3.10, J ( R ) =
U R = Ra, since Oi(aR) = aRa-' = R. Hence, if g(R)* = ( O ) , then a2R = ( O ) , i-e.,
R = ( O ) . This shows that g ( R ) > ,7(R)2 > ( O ) , a contradiction.
Case 2. : J ( R ) is not f ini tely generated as a n ideal
Let O # x E g(R). Then, RxR # (0) and z ( R ) > RxR > ( O ) , since otherwise
Rx R = J ( R ) is finitely generated as an ideal.
O
To conclude this section we briefiy discuss discrete Dubrovin vaiuation rings.
Definition 3.2.4 A Dubrovin valuation ring R in a simple artinian ring Q is
called discrete i f R is of rank one and J # J 2 .
Let R be a discrete Dubrovin valuation ring of Q. By Theorem 3.2.1, the prime
segment J > ( O ) is archimedean with J # J 2 , D ( R ) - ( J ) % H ( R ) , and n Jn = ( 0 ) .
For, by Lemma 2.3.10, J is a principal as a right R-ideai, Le., J = a R = Ra
for some regular element a E J. The prime segment J > (O) is not simple, since
otherwise J2 = a 2 R = (O), i.e., R = (O). Aiso, J > ( O ) is not exceptional; for
otherwise J = JZ by Lemma 3-12 .
Hence, when Q is a commutative field, then Definition 3.2.4 coincides with the def-
inition of discrete valuation domains in a field, see for example, [Bou'i?], Chapter VI.
Note that a discrete Dubrovin valuation ring R is a non-artinian ring, since otherwise,
by Lemma 1.1.2, every regular element r E R is a unit in R, Le., R = Q. and the
contradiction J = J 2 = ( 0 ) follows.
3.3 Examples
In this section, we discus some examples which show that al1 cases in Theorem 3.1.1
can be realized.
Example 3.3.1 There exists a Dubrouin ualuatéon ring of rank one with an
archimedean prime segment J > ( O ) of the type described i n Theorem 3.21, case
a ) i).
Proof. It follows from the remark after Definition 3.2.4, that any discrete Dubrovin
valuation ring R provides an example to illustrate the case a ) i). In particular, the
ring R = M2 (Z (,)), where p is a prime, is an example of a discrete Dubrovin valuation
ring in the simple artinian ring Q = I&(Q). Also, any discrete rank one commutative
valuation domain R, like Z(,, or the poiver series ring I C [ [ X ] ] over a field K , is an
example for the case a ) i).
O
Example 3.3.2 ( [BS95]) There exists a valuation domain V of r a d one with
quotient field F whose associated valuation has the value group H , a dense subgroup
in (t, +), illustrating the case a) ii) in Theorem 3.2.1.
Proof. Krull's construction from 1932 of a commutative valuation domain with given
commutative ordered group as the value group of the associated valuation, can be
used to illustrate the case a) ii). We take (H, H+) to be any dense subgroup of
(R, +), where H C , is the positive cone of H and as in Example 2.1.1, we construct
a commutative valuation domain V as the localization of the subring I<Hf of the
group ring I i H over a field K at the multiplicatively closed set S = {x ahh E ICH' 1 a0 # O). Le., V = (I<Hf)S-'. The set of al1 principal ideals of V is exactly t h e set
{hl/ 1 h E H ç ) , and hl V = hzV if and only if hl = hz. Then V is a valuation domain
of r a d one in the quotient field F = Q ( K H ) , and the associated valuation on F has
H as its value group. Since H is dense in IR, V is an example that illustrates the case
a) ii) in Theorem 3.2.1.
Example 3.3.3 ( [BS95])
with a s imple prime segment.
There exists a Dubrouin valuation ring R of rank one
Proof. In order to construct a total valuation ring R of rank one with a simple prime
segment? we consider the dense subgroup H = Q of (B, +) and the commutative
valuation domain V = (FH+)ShL constructed in Example 3-32? where F is a field.
We denote by K = Q ( F H ) the field of quotients of the group ring F H . Then
a : + K, defined by a(h) = 2h for h E H, is an automorphism of K compatible
with the valued field ( I i , V). Hence, o induces an automorphism 0 : V -t V with
a(h) = 2h, h E H.
Now; consider the skew-polynomial rings T := V[x, o] c K[x7 a]. Then, K [ x , O] is
a domain with a left and right division algorithm. This implies that K[x, O] is a left
and right PID and hence a noetherian domain. Therefore, K [ x , o] is a left and right
Ore domain. Ço, there exist the classical ring of quotients D := Q(Ii[x, a]).
Coosider the set S = (C l i a i 1 ai E V7 at least one ai is a unit in V). Then, S
is multiplicatively closed and S satisfies the Ore conditions. Therefore, R = TS-' =
{ts-' 1 t E T, s E S} is a subring of D = Q(K[x, O ] ) . Furthermore, R = V [ x , OIS-'
is a rank one total valuation ring in a division ring D. Its nonzero principal right ideals
have the form hl?; h E H+ = O+. Hoivever, xh = xa(k) = $2, i.e., xhR = $ R > hR.
This shows that J ( R ) > (O) is a simple prime segment.
O
Example 3.3.4 ( [Dub93], [BD]) For w e r y nonnegatiüe integer k there en'ts
a rank one total valuation ring whose pr ime segment is exceptional of t ype k.
Proof. The skew field of quotients of the group ring F G of the covering group G over
a skew field F of the group SL(2,R) contains total valuation rings with exceptional
prime segments of type k, for each integer k 2 0. For k = 1, the construction is
described, with more details, in Example 2-3-17. In fact, for al1 k = 0,1,2, ..., the
group G contains certain subgroups Hk with the exceptional positive cone Pk of type
corresponding to k. The cone Pk satisfies the conditions in Theorem 1.3.3 and hence,
there exists a total valuation ring Sk associated with Pk. Now, applying Theorem 1.3.1
to the ring Sk, it follows that Sk is a rank one total valuation ring with the exceptional
prime segment of type k. Note, that for this construction, Dubrovin7s results from
[DubSJ] are needed. No easy construction is known.
0
Sorne results of Chapters 2 and 3 will appear in [BMO].
Chapter 4
Krull Rings
For a commutative Krd l ring, the role that the group of divisorial ideals of a r a d
one Dubrovin valuation ring plays in the previous chapters, is played by the group
of divisors of regular fractional ideals. In this chapter, we discuss commutative and
non-commutative Krull rings. We use the group of divisors of a commutative Krull
ring R with the total quotient ring ri, R # K , to prove an approximation theorem.
A version of this chapter has been published, [Osm99].
4.1 Krullrings
Commutative Prüfer domains play a central role in the study of classical commuta-
tive integral domains. A commutative dornain R is called Pnifer domain if every
non-zero finitely generated ideal of R is invertible. Clearly, commutative PIDs and
commutative Bezout domâins are Prüfer domains. The classical ideal theory of com-
mutative domains has been extended to commutative rings with zero divisors. M.
Griffin [Gri69] introduced the notion of commutative Prüfer rings with zero divisors
and gave many characterizations of that class of rings.
Definition 4.1.1 A commutative ring R is called Prü fer ring i f euery regular
finitely generated ideal of R is inuertible.
Theorem 4.1.2 ( [Gri69], [LM71]) Let R be a commvta t ive ring, and let Ii
be the total quotient ring of R. Then the following s ta tements are equiualenfr
2. For every regular prime ideal P of R, the pair (RLq, [P]R[pl ) is a .Manis d u -
ation pair of AT.
3. For euery regular maximal ideal hf of R; the pair (Rpq, [MI R[,crl) is a Manis
ualuation pair o f K .
4 R is integrally closed and and for al1 a , 6 E R, where a t least o n e of a and b is
regular, ( a , b)" C (an, 6") .
In the non-commutative case, Prüfer rings are defined and studied in [AD901 and
[MMU97].
Definition 4.1.3 ( [AD90]) A prime Goldie ring R is called a right Pmifer ring
every jînitely generated right R-ideal 1 o f R satisfles the equalities
A prime Goldie n'ng R is called a left Prü fer ring i f euery finitely generated lefl
R-ideal J of R satisf ies Lhe equalities
It has been shown in [ADSOI that a prime Goldie ring R is left Prüfer if and only
if it is right Priifer. Also, every Dubrovin valuation ring R in a simple artinian ring
Q is Prüfer ring. For the theory of non-commutative Prüfer rings we refer to [AD901
and [MMUSi'].
The notion of commutative Dedekind domains also has been extended to cornmu-
tative rings with zero divisors.
Definition 4.1.4 A commuta t ive ring R is called Dedekind ring if it is Prüyer
and r-noetherian.
The complete proof of the following characterization can be found in [A090a].
Theorem 4.1.5 ( [AOgOa]) For a commuta t ive ring R the folloz~,ing conditions
are equivalent:
1. Ail regular pr ime ideals o f R are invertible.
2. R is a Dedekind ring.
3. T h e semigroup of regular fractional ideals o f R is a group.
4- Euery regular ideal of R is a product of p r ime ideals.
5. Every regular e lemenl of R is contained on l y in a finite number o f pr ime ideals
of R, and the semigroup of regular ideals can be embedded in a direct product
of ordered cyclic groups
Recall that an R-ideal I of a Dubrovin valuation ring R in a simple artinian ring
Q is called divisorial if I = I', where 1' = n CS, S = O,(I ) and c runs over al1
elements in Q with CS I (Definition 2.3.11). In the case of a rank one Dubrovin
valuation ring R we have the following result:
Proposition 4.1.6 Let R be a rank one Dubrovin valuation ring o f Q and let 1
be a n R-ideal. Then
Proof. Since the only proper overring of R is Q, we have S = O,(1) = R. So,
1- = n CR, where CR 2 1.
Let s E ( R : ( R : I ) [ ) , and c E U(Q) be such that CR 2 1. Then, c-'1 C R, Le.,
C-L E (R : I ) [ . Hence, C-'s E R, Le., s E CR. Therefore, s E 1' and ( R : ( R : l)r), C
1' follows.
Assume that s E 1- and s $ ( R : ( R : I)() , . Then ( R : I ) [ s R, and hence there
exists a regular element c E ( R : I ) [ such that CS 6 R.
Otherwise, for ail regular elements c E ( R : 1)[, we have cs E R- But, by
Lemma 1.1.8, ( R : I )[ is a left R-ideal. Then, by Definition 1-1.7, there exists
c E U(Q) with ( R : I)/c C R. Since ( R : I ) [ n U(Q) # 0 (also by Definition 1.1.7),
(R : I ) / c contains a regular element of R and is therefore an essential left ideal of
R. Thus: by Theorem 1.1.5, (R : I )[c is generated by a set {c i } of regular elements;
so, as a left R-submodule of Q, (R : 1); is generated by the set {tic-') of regular
elements. So, ( R : 1 ) [ ~ C R, a contradiction.
Then, s 6 C-'R. On the other hand, c E (R : I ) [ implies CI C R and 1 c-IR.
Since s E 1': this implies s E c-'R.
O
Remark 4.1.7 Proposition 4.1.6 holds in the more general situation when R is
an order i n a simple artinian ,ring Q and for an R-ideal 1, the +-operation i s dejned
by I* = n CR, where CR > 1.
In the commutative case, an analogous operation is defined in the following way.
Let R be a commutative ring; we denote by K the total quotient ring of R and by
F ( R ) the set of al1 regular fractional ideals of R. If A, B E F ( R ) , then ( A : B) =
{x E I< 1 XB C A) is also in F ( R ) . On the set F ( R) we define an equivalence relation
- by: A - B w ( R : A) = (R : B) . The set of al1 equivalence ciasses is denoted by
D(R), and the class containing A E F(R) is denoted by div(.4), the diuisor of A. If
A E F(R) we define A to be the set (R : (R : A ) ) E F(R) . A regular fractional ideal
A of R is diuisorial if A = A.
Remark 4.1.8 If R is a commutative integral dornain, then A is equal to the inter-
section of al1 nonzero principal fractional ideals containing A. This is no longer true
if R is a commutative ring with zero divisors, see [AM85].
However, ive still have a satisfactory theory of divisors which is sirnilar to the the-
ory of divisors for integral domains. For A, B E F(R) we define div(A) + div(B) =
div(AB). Under this operation, D ( R ) is a commutative semigroup with identity ele-
ment div( R). We Yeso define a relation 5 on D( R) by setting div(A) 5 div( B) if and only if B C - A. Then D ( R ) is a partially ordered semigroup. D(R) is a group if and only if R is
completely integrally closed, see [HucSS], Th.S.4.
R-Kennedy [Ken731 introduced the class of commutative Krull rings with zero
divisors and developed t heir t heory of divisors.
Definition 4.1.9 ( [Ken73]) Let R be a commutatiue ring with the total quotient
ring K such that R # ïï. Then R is called a I<rull ring if there exists a Jamily
{(V,, Pa) 1 a E I } of discrete rank one unluation pairs of K with associated unluations
{va 1 o E I } such that
(K2) v,(a) = O almost everywhere on I for each regular element a E Iir and each
Pa is a regular ideal of Va.
The following theorem provides the main characterization for commutative Kru11
rings with zero divisors.
Theorem 4.1.10 ( [Ken73], Conjec. 3.26 and [Mat82], Th 5 . ) Let R be
a commutative ring which is not equal to its total quotient ring. Then R is a Kmll
ring i f and only i f R is comp le t e i y integrally closed and each nonemp ty collection of
d iv isonal ideals of R h a s a m a x i m a l e k m e n t -
Note that if R is an integral dlomain different from its quotient field, then R is a Iirull
domain if and only if R is a IKrull ring.
Corollary 4.1.11 Everp commutative Dedekind ring is a I\'rull ring.
Pro of. If R is a Dedekind rin:g, then R is r-noetherian and Prüfer. By Theorem 4-12,
R is integrally closed, and h~ence, by Proposition 1.1.14, R is completely integrally
closed. So, by Theorem 4.1.1 0, R is a KruU ring.
O
We mention now some reszults which show that commutative Kru11 rings with zero
divisors not only share many .cornmon properties with Kru11 integral domains but also
show that there are differences. The following result is an immediate consequence of
Proposition 1.1.14 and Theorem 4.1.10.
Proposition 4.1.12 ( [AOC30b], Prop.2.3.) Le t R be a n r-noetherian ring that
k distinct fr0.m i t s total quodient ring. Then R is- a Kru11 ring and o n l y if R is
integrally closed.
Proposition 4.1.13 ( [Bou'72], Propl3, p. 488) Let R be a IiFrull domain
and XI, 2 2 , . . . , Zn be i n d e t e m i n a t e s . Then the r ing R [ x i , rz, . . . , x,] is a l h l f Rng.
Note, that in the case of rings with zero divisors this is not true. For example, the
ring R = Z @ Z/Zpn , where g is a prime and n 2 2 , is a Kru11 ring, but R[X] is not
a Kru11 ring since it is not completely integrally closed.
Recall that a commutative ring R is called a Marot r ing or a ring with the property
(P) if every regular ideal is geonerated by regular elements.
Exarnple 4.1.14 A Kmll ring R which is not Marot.
Proof. Let D = Z [ F 5 ] . Then D is a Dedekind domain with a maximal ideal
144 = (1 + J=j)Z + 2 2 which is not principal but hl2 = 2D is principal. Let A be
the D-module @{D/Q 1 Q a maximal ideal of D , Q # M } , and let R be the ring
D(+)A , the idealization of the D-module -4, Le., (d, a ) + (8, a') = (d + dl, a + a') and
(dl a)(dr, a') = (dd', ad' + a'd) for all a , a' E -4, d, d' E D. For more details see, for
example, [HucSS]. Shen:
1. The ideal P = M ( + ) A of R is not principal.
2. P is the unique regular prime ideal of R.
3. The set of a11 regular ideals of R is the set of the form (Pn}N, .
4. The ideal P is invertible.
5 . The set of al1 regularly generated ideals of R is {tn R):?, , for some t E R.
Hence, by Theorem 4.1.5 aad Corollary 4.1.1 1, R is a Kru11 ring. But. the ideal P is
a regular ideal which is not generated by regular elements since P is not a principal
ideal and the set of al1 regularly generated ideals of R contains only principal ideals.
Hence, R is not a Marot ring.
Finally, at the end of this section we briefly discuss how discrete Dubrovin valu-
ation rings are used in studying non-commutative Iirull rings.
Non-commutative Kru11 rings have been defined and studied by H. Marubayashi,
[Marï5], [Mar76], [Maris], M. Chamarie, [ChaSl] and N. Dubrovin, [DubSlb]. In
[DubSlb], Dubrovin uses discrete Dubrovin valuation rings in a simple artinian ring
to define non-commutative Kru11 rings.
Definition 4.1.15 ( [Dubglb]) A s~br ing R in a simple artinian ring Q is
called a non-commutative I h l l rîng if there exists a family {R; 1 i E A} of discrete
Dubrovin ualuation rings of Q such that
( K 2 ) for each regular element q E Q , the equation qR, = R, holds for almost al1 i in
A;
(K3) fo r any finite set {io, il, - - ,in) in A, there exits an element q E Q such that
q r 1 (rnod ,?(R;,)), q O (mod g(&,)) for 1 < t 5 n, and q E Ri for al1
other j E A.
It follows from the results in [Dubglb] that the class of non-commutative Krull
rings defined in Definition 4.1.15 coincides wit h the class of non-commutative Krull
rings defined in [Mar75], where valuation rings are not used.
4.2 Essential valuations of Krull rings
We denote by R a commutative Kru11 ring with total quotient ring K. Then D ( R )
is a group. Let M(R) be the set of al1 maxima1 divisorial integral ideals of R. If
P E li1 (R) then div(P) is a minimal positive element of the group D(R). We denote
the set {div(P) P E M ( R ) } by P(R) . Each divisor div(.4) E D ( R ) can be written
uniquely as:
If div(.4) = C np!J3 and div(B) = C n$$3, then div(r2) 5 div(B) if and only if
n p 5 rnp for a11 13 E P(R) .
For each divisor E P ( R ) we define a map from F(R) to the set of integers Z
by v p ( A ) = n.p, where div(A) = C nu U. The map vip has the following properties:
a) vg(-4B) = vy(A) +vv(B) for all A, B E F(R) ;
b) u9(-4 + B ) = min{vp(.4),vp(B)) for al1 A, B E F ( R ) ;
c ) A C B is equivalent to vT(A) 2 vp(B) for ali !J3 in P ( R ) , where A, B E F(R) -
and B = B.
The family of the valuations {va : !$l E P ( R ) ) defined by:
( v x E K ) vp(x) = sup { v p ( ~ x + A) 1 A E F(R))
is said to be the family of essential valuations of a Kru11 ring R. The ring of the
valuation v.p is denoted by Vp and the positive ideal by PT. The essential valuations
of a Kru11 ring R are discrete of rank one and they d e h e the ring R, Le., R = n{VP 1 <P E P(R)} and q ( a ) = O for almost al1 !+3 in P(R), for al1 a E C K ( 0 ) , see [MattZ].
Essential valuations of a Krull ring have the following properties:
Proposition 4.2.1 ( [AOgOb], Prop.2.5) If x E C K ( 0 ) a n d 73 E P ( R ) , t h e n
v ~ ( x ) = v ~ ( R x ) .
Proposition 4.2.2 ( [AOSOb], Prop.2.6) Let A b e a divisorial ideal o f R- and
div(i2) = z{np<P 1 E P ( R ) ) . T h e n a E A i f and only ifvp(a) 2 np.
Proposition 4.2.3 ( [AOgOb], Prop.2.7) Let np E % wi th almost all n.p = O
for 73 E P ( R ) , and set A = {x E I< ( vp(x) > np ( V q E P ( R ) ) ) . T h e n A is a
regular divisorial ideal, and div(A) = C{nP'iJ3 1 Q E P ( R ) ) .
Proposition 4.2.4 ( [AOgOb], Prop.2.8) Let = div(P) E P(R), where P
is a max imal diuison'al ideal of R. Then P is a m i n i m a l regular pr ime (r-pr ime)
ideal of B. T h e ualuation r ing of vp 2s equal to R[pl, and the positive ideal of vp is
[Pl R[P]
Coroilary 4.2.5 ( [AOgOb], Cor.2.9) The family {P 1 div(P) E P(R)} o f al1
max imal divisorial ideals o f R is precisely the family of al2 m i n i m a l regular pr ime
ide& o f Rr
4.3 An approximation theorem for Kru11 rings
Approximation theorems are very cornmon in many areas of rnathematics, for exam-
ple, in the valuation theory of fields and commutative rings, in multiplicative ideal
theory and in the theory of partially ordered abelian groups. They are used as a
tool in studying topological structures and play an important role in the description
of the division class group. The Chinese Remainder Theorem is the oldest form of
an approximation theorem for congruences. In this section we prove an approxima-
tion theorem for essential vduations of commutative Kru11 rings mith zero divisors.
Throughout, rings are assumed to be commutative with identity 1.
Theorem 4.3.1 Let R be a commuta t ive I h l l ring wi th to tal quotient ring Ii
such tha t R # I( and {vP 1 73 E P ( R ) } is the family of essential valvations of
R. { u ~ , , v.p,, - - . , vv,) is a finite set of essential valuations of the ring R a n d
(ml,m2, . . . ,m,) E Zn7 then there exists an elernent z E Ii s v c h that vv,(z) = mi
for aM i E {1,2,. . . , n) and up(x) 2 O /or al1 other E P(R).
Proof. It suffices to prove the theorem in the case where at most one of the mi is
not equal to O.
Let m2 = m3 = . . . = rn, = O . If mi = O then x = 1.
Case 1. Let rn > O and pi = div Pi, i = 1,2, . . . , n be minimal positive elements
of the group D(R), where the Pi are maximal divisorial integral ideals of R. By
Proposition 4.2.4, Pi is a minimal regular prime ideal of R? i E {1,2,. . . , n}. Then
P r 1 and PY'+' are divisorial integral ideals of R. Also:
Othenvise, by [Bou7'2, Proposition 2, Ch.11, SI], PrL C P;~I+' or PTL C Pi, for some
i E {2,3 , . . . , n). But then div(fi) 5 O or Pl = Pi, which is impossible.
P,"' . Hence, by the
Assume that vp, (x) 2 ml + 1. Then, there exists an element L E F ( R ) such that
v.pl (Rx + L ) 1 1 + 1 - We can assume that L C R. For, there exists a regular element
d E R such that dL C R. Shen v P ( R r + L) > - V~(P;LL+') for al1 !)? E P(R), Since
Rx + L C R implies uw(Rx f L) 3 O = V ~ ( P ~ ~ + ~ ) for al1 !)? # pl. By the property
c) of the rnap vp, we have Rx + L C PT'+^, i.e., x E P r L + ' , a contradiction.
Therefore, wp,(x) < ml + 1, Le., vp,(s) = ml.
It remains to prove that vpi (x) = O = mi for al1 i E {2,3, . . . n}. Since x E
p;"' C R = n l$ L L$ for al1 (p E P ( R ) , vp(s) 2 O for all 73 E P(R) . t\ssurne that
vp,(x) > O for some i E (2 ; 3 ? . . . , n}. Then x belongs to [Pi] RIPiI, by Proposition 4.2.4.
Hence, x E Pi, which is a contradiction.
Case 2. Let m l < O and let r E Reg(PFm'). By Proposition 4.2.1, v.p,(r) =
vp,(Rr) 2 -mi > O. Then vp,(r-') < O. We prove that the set {<P E P ( R ) 1 vp(r-l) < O} is finite. If not, then the divisor of Rr-' E F ( R ) in its decomposition
div(Rr-') = C (vp(~r- ' ) ) !J3 has infinitely rnany coefficients different from O. WEP(R)
This is impossible since D(R) is a free Z-module with a free bases P(R) .
Let {QI, %?,. . . . %,} be the set of all elements !J3 in P ( R ) such that vP(r-') < 0.
Then vP(r-') = O for al1 E P ( R ) \ {P l , va,, . . . ,Pa,}, since r E Pym' c R implies
vP(r-') 5 O for ail <p E P(R) .
Consider the family { v ~ , , vva,, . - - , vqat) of essential valuations of the ring R and
(upi ( r ) f mi, vp,, ( r ) , . . - , vp., ( r ) ) E Z'. Since vP1 ( r ) + mi > O and upai ( r ) > O for
al1 i E (2,. . . , t ) we can apply Case 1. Hence, there exists an element xi E R such
chat UV, ( x i ) = ugl ( r ) + ml7 u-poj(xl) = vVmi ( r ) for al l i E (2,. . . , t ) and vP(x i ) 2 O
for ail other <p E P ( R ) . Shen x = r-L 11 E K is an element satisfying the required
condition.
O
The element x constructed in the proof of the Theorem 4.3.1 is not necessarily
regular. For the class of additively regular rings it follows from the next result that
the elernent x can be chosen to be regular. This result is also an easy consequence
of Theorem 4.3.1. But first, we recall the definition of an additively regular ring. A
ring R is additively regular if for each c in the total quotient ring A- of R, there exists
u E R such that z + u f &(O).
Theorem 4.3.2 Let R be a n additively regular Km11 ring such that R # K, and
let {vP : !J3 E P ( R ) ) be the Pmi ly of essential valuations of R. If {uv17 v y 2 , . . . , vpn)
is a finite set of essential valuations and if(rni, m 2 , . . . ,m,) E Zn, then there exists a
regular element x E IlF such that vpt(x) = mi for al1 i E {1,2,. . . n) and vp(x) 3 O
for al1 other E P ( R ) .
Proof. In the proof of Theorem 1.3.1, Case 1, if x E PLL \ (p;LLC1 U P2 U P3 U - - U P,),
then, by the additive regularity of R, for b E Reg (P;"~" n P2 P3 n - . - n P,),
there exists an element u E R such that t = x + bu is regular and t E Pr1 \ ( P;"LC' (J PZ U - U P,). The element t satisfies the required conditions.
O
This allows us to characterize divisorial fractional ideals of an additively regular
Krull ring in terms of principal fractional ideals in the same way as in the case of
domains, see [Bou72], Ch. VII, 55, Corollary 2.
Corollary 4.3.3 Let R be an additiuely regular K m l l ring and let -4: B,C be
divisorial fractional ideals of R such that -4 E BI Then there exists a n e lement x E 1ir
such that
Proof. Let {vv 1 !J3 E P(R)) be the family of essential valuations of a Kru11 ring R
and let
Then A C B implies div(A) 2 div(B) arid hence rny 2 n y for al1 73 E P(R). Let
Ji = {<p E P ( R ) ( r n ~ > np}. Also, there exists a finite subset Jz of P ( R ) such
that pp = m p = O for aii <P E P ( R ) \ J2. Let J = J I U J2. Then {vg [!J3 E J ) is a
finite family of essential valuations of the ring R and {ptP - rnp 1 !J3 E J ) is a finite
family of integers. By Theorem 4-32? there exists a regular element x E K' such that
vp(x-') = p p - mg for al1 'J3 E J and ve(x-l) > - O = pp - rnp for al1 !JJ E P(R) \ J.
Hence:
since vp(x) = vv(Rx).
Suppose that a E A. By Proposition 4.2.2, vp(a) 2 m p =
S U P { ~ ~ : V ~ ( R ~ ) + p p ) for al1 E P(R) . Therefore, vg(a) 2 n.p and vy(a) > - ?p(Rx) + p p for al1 73 E P(R) . On the other hand, Rx E F(R) and
Furt hermore, since the fractional ideal R x is invertible, Rx- C is a divisorial ideal of the
ring R. Applying Proposition 4.2% again, we get a E B fi RxC, i.e., A C B n RxC.
Conversely, for a E B n RxC, v y ( a ) 2 nq and v P ( a ) 2 vq(Rz) + pp for al1
E P ( R ) - Hence, vp (a ) 2 sup InT, vg(Rx) + pp) = m p for all !J3 E P ( R ) Le., a E A
by t h e s a m e argument.
O
Corollary 4.3.4 Let R be an additiuely regular fi-mil Rng such that R # I i and
let A be a fractional regular ideal of R. Then A i s a diuisorial ideal of R i f and only
$il is the intersection of two fractional principal ideals of R.
- Proof. I f A i s a divisorial ideal, then A = A C n { R a 1 a E &-(O). A C R a ) . Let
B = R a , a E CA-(O) be any regular principal fractional ideal of R such that A C B
and let C = Rb, b E CA-(O). Then, by Corollary 4.3.3, t here exists a regular element
x E Ii S U C ~ that A = B n RXC = R a n Rxb.
Conversely, if -4 = Ra Rb where a, b E CK (O), then Ra n Rb = A C 2 5 -
n{Ry 1 y E CA-(O), A C Ry) C R a n R b = A, i.e., A= A.
O
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Index
extension
algebra
central simple, 16
division, 20
annihilator, 6
approximation t heorem, 73
common denominator, 6
cone, 17
divisor, 67
dornain
noet herian, 62
Bezout, 22, 24
left Ore, 62
left PID, 62
Ore, 20
PID, 12
Prufer, 23
efement
aimost integral, 11
integral, 11
of vduation ring, 16
total invariant, 21
Goldie
dimension, S, 9
ring, S
Theorem, S
€PUP
linearly ordered, 17
right ordered, 17
universal covering, 41
Holders Theorem, 49
ideal
R-ideal, 9
completely prime, 18, 40
divisorial, 36, 68, 72
essential, S
fractional, 67
Goldie prime, 32, 40, 46
idempotent, 43
integral R-ideal, 9
P-ideal, 18
positive, 13
prime, 1s regular, 12, 69
jump, 52
localization, 23, 3 1
module
essential, S
uniform, S
order, 6
Bezout, 31, 33
local Bezout, LS
Ore
condition, 5 , 63
regular set, 6
set, 5 , 35
prime segment, 45, 51
archimedean, 53, 53
exceptional, 53, 54
simple, 53, 54
ring
additively regular, 12, 75
ari t hrnetic, 1
Bezout, 23
chain, 10
commutative ICrull, 68, 70
completely integraily closed, 11, 12,
6s
Dedekind, 66, 69
Dubrovin valuation, 16, 20, 25, 26,
52
Dubrovin valuation discrete, 60, 61
Dubrovin valuation of r a d one, 56
integrally closed, 12, 69
invariant, 15
large quotient, 11
Local, 22
Marot, 12, 69, 70
n-chain, 10, LS
noetherian, 12
noncommutative arithmetic, 17
of quaternions, 70
PrÜfer, 65
prime Goldie, 31, 31
quotient, 6
r-noetherian, 11
semiprime Goldie, 24
simple, 5
simple artinian, 28, 31, 51
total quotient, 67
total valuation, 15, 10, 31